I working with some url string and i tried to remove "\" from the string to use url for my further use.
But when i tried using strin.gsub its not working as it should. rather then its giving me wrong output.
the String is
nas="\\192.168.1.220\STORAGE_1d1b7\a\b\c"
Code I have tried:
nas=string.gsub(nas,'\\',"")
print(nas)
Output:
192.168.1.220STORAGE_1d1b7??c
Output i need:
192.168.1.220STORAGE_1d1b7_a_b_c
its removing the "\" but it also affecting the "\" with "?"
i don't know where the "?" comes from?
The character \ is used to escape some special characters in a string, for eg.: \n represents a newline character (ASCII code 10) etc. (\a is ASCII code 7 in C/C++)
So, you'd need to define your string as:
nas = "\\\\192.168.1.220\\STORAGE_1d1b7\\a\\b\\c"
Alternatively, lua provides another way to define raw strings:
nas = [[\\192.168.1.220\STORAGE_1d1b7\a\b\c]]
Any ways Figured it out....
NASLocation = NASLocation:gsub('\\\\', ''):gsub('\\', '_',1):gsub('\\','/')
Related
About twelve years ago, I wrote a small VB.NET application that loads strings from files. These strings may contain one or more of the following characters: à, è, é, ì, ò, ù, ä, ö. The application uses a special custom font (JazzText Extended) that does not have those special characters. Yet, I somehow managed to make the application display words correctly in that font, and twelve years later, I have no idea how - thanks for not leaving a line of comment, past me!
The program has the following routine:
Private Sub SetWord(ByVal word() As String)
Dim nword(3) As String
nword(0) = word(0)
nword(1) = word(1)
nword(2) = word(2)
For i As Integer = 0 To 2
nword(i) = nword(i).Replace("à", "")
nword(i) = nword(i).Replace("é", "")
nword(i) = nword(i).Replace("è", "")
nword(i) = nword(i).Replace("ì", "ê")
nword(i) = nword(i).Replace("ò", "")
nword(i) = nword(i).Replace("ù", "")
nword(i) = nword(i).Replace("ä", "")
nword(i) = nword(i).Replace("ö", "")
Next
lblItaWord.Text = nword(0).ToUpper
lblEngWord.Text = nword(1).ToUpper
lblFinWord.Text = nword(2).ToUpper
End Sub
What it does is, it takes an array that contains three words, and for each of those three words, it looks if it contains any of the special characters. If it does, it replaces them with... something, makes the words all caps, and then assigns each of them to one of three labels.
In Visual Studio, the replacement characters look like empty strings. I had to put the cursor in between the quotation marks to realise that it was in fact not an empty string and there was an invisible character there. Here on SO... I'm not sure what you'll see. You might see just a square, or some other weird character. (The ê character is an exception, it seems to display in the same way everywhere.)
If you copypaste any of the invisible/square characters to Google and search for it, you'll get a different representation that uses two characters—for example, the first one translates to ‡. Using this pair in place of the invisible/square character in the Replace method does not produce the correct result. FYI, the encoding I use to read the files (the default one used by IO.StreamReader if you don't specify any encoding) works fine: if I use a more standard font, all special characters display correctly without using the SetWord sub at all.
Now, I have absolutely no idea how those characters, whatever they may be, manage to make the app display correctly the words when the font I use does not have those characters. I have no idea how I found out about this trick, either. Right now, my problem is that I would like to replace those squares/invisible characters with something intelligible, and I have no idea how. Any ideas?
I got attribute from Selenium Element and it contains empty char or spaces:
When I double click the result :
In VS code:
What I tried so far :
string.replace(" ","") #didnt work
So I came with this resolution (I know its bad ):
edit1 = ticketID[:1]
ticketF = ticketID.replace(edit1,"")
edit2 = ticketF[:1]
ticketE = ticketF.replace(edit2,"")
edit3 = ticketE[:1]
ticketD = ticketE.replace(edit3,"")
What Im looking for is what is those blanks ? tabs ? new lines ?
how to make it better ?
Edit:
ticketID.replace("\n","")
ticketID.replace(" ","")
ticketID.strip()
Those are basically whitespaces, Please use .strip() for any trailing spaces.
In Python, the stripping methods are capable of removing leading and trailing spaces and specific characters. The leading and trailing spaces include blanks, tabs (\t), carriage returns (\r, \n), and the other lesser-known whitespace characters.
If you have ele as an web element.
You can use .text to get the text and then on top of that use .strip()
Probably in your code :
ticketID.text.strip()
They look like lines and not spaces to me.
string.replace("\n","")
Something like that is coming in:
str="Hello;this;is;a;text"
What I do want as result is this:
result="72:101:108:108:111;116:104:105:115;..."
which should be the Text in ASCII.
You could use string matching to get each word separated by ; and then convert, concat:
local str = "Hello;this;is;a;text"
for word in str:gmatch("[^;]+") do
ascii = table.pack(word:byte(1, -1))
local converted = table.concat(ascii, ":")
print(converted)
end
The output of the above code is:
72:101:108:108:111
116:104:105:115
105:115
97
116:101:120:116
I'll leave the rest of work to you. Hint: use table.concat.
Here is another approach, which exploits that fact that gsub accepts a table where it reads replacements:
T={}
for c=0,255 do
T[string.char(c)]=c..":"
end
T[";"]=";"
str="Hello;this;is;a;text"
result=str:gsub(".",T):gsub(":;",";")
print(result)
Another possibility:
function convert(s)
return (s:gsub('.',function (s)
if s == ';' then return s end
return s:byte()..':'
end)
:gsub(':;',';')
:gsub(':$',''))
end
print(convert 'Hello;this;is;a;text')
Finding certain character or string (such as ";") can be done by using string.find - https://www.lua.org/pil/20.1.html
Converting character to its ASCII code can be done by string.byte - https://www.lua.org/pil/20.html
What you need to do is build a new string using two functions mentioned above. If you need more string-based functions please visit official Lua site: https://www.lua.org/pil/contents.html
Okay...I got way further, but I can't find how to return a string made up of two seperate strings like
str=str1&" "&str2
Trying to use rstrip() at its most basic level, but it does not seem to have any effect at all.
For example:
string1='text&moretext'
string2=string1.rstrip('&')
print(string2)
Desired Result:
text
Actual Result:
text&moretext
Using Python 3, PyScripter
What am I missing?
someString.rstrip(c) removes all occurences of c at the end of the string. Thus, for example
'text&&&&'.rstrip('&') = 'text'
Perhaps you want
'&'.join(string1.split('&')[:-1])
This splits the string on the delimiter "&" into a list of strings, removes the last one, and joins them again, using the delimiter "&". Thus, for example
'&'.join('Hello&World'.split('&')[:-1]) = 'Hello'
'&'.join('Hello&Python&World'.split('&')[:-1]) = 'Hello&Python'
I'm trying to read a string in a specific format
RealSociedad
this is one example of string and what I want to extract is the name of the team.
I've tried something like this,
houseteam = sscanf(str, '%s');
but it does not work, why?
You can use regexprep like you did in your post above to do this for you. Even though your post says to use sscanf and from the comments in your post, you'd like to see this done using regexprep. You would have to do this using two nested regexprep calls, and you can retrieve the team name (i.e. RealSociedad) like so, given that str is in the format that you have provided:
str = 'RealSociedad';
houseteam = regexprep(regexprep(str, '^<a(.*)">', ''), '</a>$', '')
This looks very intimidating, but let's break this up. First, look at this statement:
regexprep(str, '^<a(.*)">', '')
How regexprep works is you specify the string you want to analyze, the pattern you are searching for, then what you want to replace this pattern with. The pattern we are looking for is:
^<a(.*)">
This says you are looking for patterns where the beginning of the string starts with a a<. After this, the (.*)"> is performing a greedy evaluation. This is saying that we want to find the longest sequence of characters until we reach the characters of ">. As such, what the regular expression will match is the following string:
<ahref="/teams/spain/real-sociedad-de-futbol/2028/">
We then replace this with a blank string. As such, the output of the first regexprep call will be this:
RealSociedad</a>
We want to get rid of the </a> string, and so we would make another regexprep call where we look for the </a> at the end of the string, then replace this with the blank string yet again. The pattern you are looking for is thus:
</a>$
The dollar sign ($) symbolizes that this pattern should appear at the end of the string. If we find such a pattern, we will replace it with the blank string. Therefore, what we get in the end is:
RealSociedad
Found a solution. So, %s stops when it finds a space.
str = regexprep(str, '<', ' <');
str = regexprep(str, '>', '> ');
houseteam = sscanf(str, '%*s %s %*s');
This will create a space between my desired string.