I need to rename hundreds of files in Linux to change the unique identifier of each from the command line. For sake of examples, I have a file containing:
old_name1 new_name1
old_name2 new_name2
and need to change the names from new to old IDs. The file names contain the IDs, but have extra characters as well. My plan is therefore to end up with:
abcd_old_name1_1234.txt ==> abcd_new_name1_1234.txt
abcd_old_name2_1234.txt ==> abcd_new_name2_1234.txt
Use of rename is obviously fairly helpful here, but I am struggling to work out how to iterate through the file of the desired name changes and pass this as input into rename?
Edit: To clarify, I am looking to make hundreds of different rename commands, the different changes that need to be made are listed in a text file.
Apologies if this is already answered, I've has a good hunt, but can't find a similar case.
rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' *.txt
Should work, depending on whether you have that package installed. Also have a look at qmv (rename-utils)
If you want more options, use e.g.
shopt -s globstart
rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' folder/**/*.txt
(finds all txt files in subdirectories of folder), or
find folder -type f -iname '*.txt' -exec rename 's/^(abcd_)old_name(\d+_1234\.txt)$/$1new_name$2/' {} \+
To do then same using GNU find
while read -r old_name new_name; do
rename "s/$old_name/$new_name/" *$old_name*.txt
done < file_with_names
In this way, you read the IDs from file_with_names and rename the files replacing $old_name with $new_name leaving the rest of the filename untouched.
I was about to write a php function to do this for myself, but I came upon a faster method:
ls and copy & paste the directory contents into excel from the terminal window. Perhaps you may need to use on online line break removal or addition tool. Assume that your file names are in column A In excel, use the following formula in another column:
="mv "&A1&" prefix"&A1&"suffix"
or
="mv "&A1&" "&substitute(A1,"jpeg","jpg")&"suffix"
or
="mv olddirectory/"&A1&" newdirectory/"&A1
back in Linux, create a new file with
nano rename.txt and paste in the values from excel. They should look something like this:
mv oldname1.jpg newname1.jpg
mv oldname1.jpg newname2.jpg
then close out of nano and run the following command:
bash rename.txt. Bash just runs every line in the file as if you had typed it.
and you are done! This method gives verbose output on errors, which is handy.
Related
I'm relatively new to bash and I have tried multiples solutions that I could find here but none of them seem to be working in my case. It's pretty simple, I have a folder that looks like this:
- images/
- 0_image_1.jpg
- 0_image_2.jpg
- 0_image_3.jpg
- 1_image_1.jpg
- 1_image_2.jpg
- 1_image_3.jpg
and I would like to move these jpg files into subfolders based on the prefix number like so:
- images_0/
- 0_image_1.jpg
- 0_image_2.jpg
- 0_image_3.jpg
- images_1/
- 1_image_1.jpg
- 1_image_2.jpg
- 1_image_3.jpg
Is there a bash command that could do that in a simple way ?
Thank you
for src in *_*.jpg; do
dest=images_${src%%_*}/
echo mkdir -p "$dest"
echo mv -- "$src" "$dest"
done
Remove both echos if the output looks good.
I would do this with rename a.k.a. Perl rename. It is extremely powerful and performant. Here's a command for your use case:
rename --dry-run -p '$_="images_" . substr($_,0,1) . "/" . $_' ?_*jpg
Let's dissect that. At the right end, we specify we only want to work on files that start with a single character/digit before an underscore so we don't do damage trying to apply the command to files it wasn't meant for. Then --dry-run means it doesn't actually do anything, it just shows you what it would do - this is a very useful feature. Then -p which handily means "create any necessary directories for me as you go". Then the meat of the command. It passes you the current filename in a variable called $_ and we then need to create a new variable called $_ to say what we want the file to be called. In this case we just want the word images_ followed by the first digit of the existing filename and then a slash and the original name. Simples!
Sample Output
'0_image_1.jpg' would be renamed to 'images_0/0_image_1.jpg'
'0_image_2.jpg' would be renamed to 'images_0/0_image_2.jpg'
'1_image_3.jpg' would be renamed to 'images_1/1_image_3.jpg'
Remove the --dry-run and run again for real, if the output looks good.
Using rename has several benefits:
that it will warn and avoid any conflicts if two files rename to the same thing,
that it can rename across directories, creating any necessary intermediate directories on the way,
that you can do a dry run first to test it,
that you can use arbitrarily complex Perl code to specify the new name.
Note: On macOS, you can install rename using homebrew:
brew install rename
Note: On some Ones, rename is referred to as prename for Perl rename.
I am trying to rename all files located in a directory (recursively) with a specific meta data field appended to the end of the png file name.
the meta data field name is "aesthetic_score" with a value range from 1.0-9.0
when I type:
exiftool -Aesthetic_score -G1 -s testn.png
the result is:
[PNG] Aesthetic_score : 7.0
This is how I would like to append the png files recursively within a directory.
Note i would like to swap out the word aesthetic with the word chad in the append, and not all files will have this data field:
input file:
filename001.png (metadata aesthetic_score:7.0)
output:
filename001-chad-score-70.png
I tried to use Digikam and JExifToolGui-2.01, without success.
I am trying to perform this task in the cmd line, although other solutions are welcome. Thank you for your help.
So, this might work for you, I can't really test it; note that you would need to get rid of the echo before the mv for it to actually do something (rename rather than just show what it would do).
while read name
do
newname=$(exiftool -G1 -s "$name"|awk '$2~/FileName/{name=$4}; $2~/Aesthetic_score/{basename=gensub(/^(.+)\....$/,"\\1","1",name);ext=gensub(/^.*\.(...)$/,"\\1","1",name);gsub(/\./,"",$4);print basename"."$4"."ext}')
echo mv "$name" "$newname"
done <<<$( find -iname \*.png )
Basically the find at the very end finds all the pngs.
The while loop takes every name find throws it, and passes each file through exiftool (using your specs) and parses the output using awk, which then outputs the new name, which gets captured in the shell variable by the same name.
And finally the mv (without the echo) renames the files.
I'm sure I had a working oneliner that allowed me to search a directory (or .) for files containing names matching names in a txt file and copying these to a new directory.
Somehow I cannot get it to work - any help please.
Sorry if this is a duplicate - I have really searched for an answer (here and elsewhere), but cannot find a solution.
foo/movehere/sample.txt file:
141516
141619
Files I want to find and move i.e.:
foo/folder/folder2/141516_S2_R1.fastq.gz
foo/folder/folder2/141516_S2_R1.fastq.gz
Where I want to move them:
foo/movehere/
my current (nonfunctioning) oneliner:
while read -r FILE; do find . -name "$FILE*.fastq.gz" -type f -exec cp {} /foo/movehere/ \;;done </foo/movehere/sample.txt
There are some errors in the oneliner. It still does not work.
you can use eval in your code
SEARCH="-name '$FILE*.fastq.gz'"
eval "find . $SEARCH -type f exec cp '{}' /foo/movehere/ \";
security note : do not put user supplied data into eval.
Not sure if I should delete the post - but I'll leave my solution here if anyone else encounter the exact same problem.
Still not 100% sure I understand why it failed, but I got the oneliner working by copying all the sample names from the txt to a unedited file with no suffix.
I guess some (hidden) "\r" editing in the txt file messed up the "$FILE" so that it searched for something like this:
151617*fastq.gz\r
Perhaps someone with a better understanding of terminal scripts may confirm this.
EDIT 190128: happened across my old question, and just in case anyone struggle with something similar, make sure you have UNIX or similar line shifts, my txt files had weird window line shifts.
Ok so I kinda dropped the ball. I was trying to understand how things work. I had a few html files on my computer that I was trying to rename as txt files. This was strictly a learning exercise. Following the instructions I found here using this code:
for file in *.html
do
mv "$file" "${file%.html}.txt"
done
produced this error:
mv: rename *.html to *.txt: No such file or directory
Long story short I ended up going rogue and renaming the html files, as well as a lot of other non html files as txt files. So now I have files labeled like
my_movie.mp4.txt
my_song.mp3.txt
my_file.txt.txt
This may be a really dumb question but.. Is there a way to check if a file has two extensions and if yes remove the last one? Or any other way to undo this mess?
EDIT
Doing this find . -name "*.*.txt" -exec echo {} \; | cat -b seems to tell me what was changed and where it is located. The cat -b part is not necessary but I like it. This still doesn't fix what I broke though.
I'm not sure if terminal can check for extensions "twice", but you can check for . in every name an if there's more than one occurence of ., then your file has more extensions. Then you can cut the extension off with finding first occurence of . in a string when going backwards... or last one if checking characters in string in a normal way.
I have a faster option for you if you can use python. You can strip the extension with:
for file in list_of_files:
os.rename(file,os.path.splitext(file)[0])
which can give you from your file.txt.txt your file.txt
Example:
You wrote that your command tells you what has changed, so just take those changed files and dump them into a file(path to file per line). Then you can easily run this:
with open('<path to list>') as f:
list_of_files = f.readlines()
for file in list_of_files:
os.rename(file.strip('\n'), os.path.splitext(file.strip('\n'))[0])
If not, then you'd need to get the list from python:
import os
results = []
for root, folder, filenames in os.walk(<your path to folder>):
for filename in filenames:
if filename.endswith('.txt.txt'):
results.append(os.path.join(root, filename))
With this you got a list of files ending with .txt.txt like this <your folder>\\<path_to_file>.
Get a path to your directory used in os.walk() without folder's name(it's already in list) so it'll be like this:
e.g. os.walk('/home/me/directory') -> path='/home/me/' and res is item already in a list, which looks like directory/...
for res in results:
path = '' # set the path here
file = os.path.join(path,r)
os.rename(file, os.path.splitext(file)[0])
Depending on what files you want to find change .txt.txt in if filename.endswith('...') to whatever you like and os.rename() will take file's name without extension which in your case means it strips the additional extension you don't want to have.
I have a list of files that I need to copy. I want to recursively search a drive and copy those files to a set location if that filename exists in the list. The list is a text file/
the text file would look something like this:
A/ART-FHKFX1.jpg
B/BIG-085M.jpg
B/BIG-085XL.jpg
L/LL-CJFK.jpg
N/NRT-56808EA.jpg
P/PFE-25.10.jpg
P/PFE-7/60.jpg
P/PFE-7L.20.jpg
P/PFE-8.25.jpg
P/PFE-9.15.jpg
P/PFE-D11.1.tiff
P/PFE-D11.1.tiff
P/PFE-D12.2.tiff
P/PFE-D12.2.tiff
using find will take a lot of time, try to use locate if possible.
what will happen when there's several matches? like searching for foo.bar and having a/foo.bar and also b/foo.bar what would you do in that case?
your csv seems to include a path, given the previous I'll assume those paths are actually valid from where the script is run so in that case just do this:
#!/bin/bash
while read path; do
cp "$path" "$1"
done
then call it like this:
teh_script /path/to/destination < csv-file.csv