I am not very good at Excel. In the NHS (UK) we often schedule activity by looking at the columns on a calendar (e.g. All day theatre list Mondays week 1,3,5). This means on the first Monday, third Monday and if present fifth Monday. Using a printed calendar you can see the columns, for example Mondays in Jan 2023 where there are five.
When planning, it would be great to have a formula that would accept a date, and return the ordinal of the weekday for that month e.g.
Jan 02 2023 = 1
Jan 28 2023 = 4
Jan 29 2023 = 5
Jan 30 2023 = 5
I have searched and found the WEEKNUM function, but this counts rows on the calendar not giving the result I need.
Any help gratefully received
Kind Regards Gavin Holt
This should return those values:
=-INT(-(DAY(YourCellWithTheDate))/7)
I have this table in Google Sheets (or excel). The year is the two last digit of my code.
Code Duration Months
1 AC-26482-17 60
2 AC-26482-18 30
3
I would like to return the date in this format (If no data, just leave blanks).
Code Duration Months Start Expiration
1 AC-26482-17 60 01/01/2017 01/01/2022
2 AC-26482-18 30 01/01/2018 01/07/2020
3
Is there a way to achieve this?
You mean you want to add the duration in months to the start date? If so, your sample has the wrong expiration date. 30 months added to 1/1/2018 is not June 1st, but July 1st.
The formula in Excel is
=EDATE(C2,B2)
If you also want to calculate the start date from the last two characters of the code, given all dates are in this millennium, then you can use this for the start date:
=DATE(RIGHT(A2,2)+2000,1,1)
edit: To handle blank cells, you can check with IsBlank()
=if(isblank(a2),"",DATE(RIGHT(A2,2)+2000,1,1))
use:
=ARRAYFORMULA(IF(A2:A="",,DATE(IF(RIGHT(A2:A, 2)*1>=40,,20)&RIGHT(A2:A, 2), 1, 1)))
=ARRAYFORMULA(IF(A2:A="",,DATE(YEAR(C2:C), MONTH(C2:C)+B2:B, 1)))
The Excel/Google-Sheets/LibreOffice function DAYS360() returns the number of days between two dates based on a 360-day year. 0 (default) is used for the US-based method and here are some examples
A = 30 Apr 2016, B = 29 Feb 2016, DAYS360(A, B) = -61
A = 29 Feb 2016, B = 30 Apr 2016, DAYS360(A, B) = 60
This seems ok according to the rules here
But the Excel/Google-Sheets/LibreOffice function YEARFRAC() returns the number of years, including fractional years, between two dates using a specified day count convention. Even here 0 (default) uses US method, (US (NASD) 30/360) which I presumed will also be equal to the value of number of days calculated by DAYS360 * the number of seconds in a day/number of seconds in 360 days. The values in the sheets are as follows
A = 30 Apr 2016, B = 29 Feb 2016, YEARFRAC(A, B) = 0.1666666667
A = 29 Feb 2016, B = 30 Apr 2016, YEARFRAC(A, B) = 0.1666666667
Since it can be seen that the absolute value of the DAYS360 is different by one, the YEARFRAC value is same and assumes 60 days according to the presumption made above, so are the US-based convention mentioned here is the same as mentioned for DAYS360.
If not, what are the exact rules for this one, or is there some other problem?
NOTE: Tested these values on Google Sheets and Libre Office.
DAYS360 parameter 3:
0 indicates the US method - Under the US method, if start_date is the last day of a month, the day of month of start_date is changed to
30 for the purposes of the calculation. Furthermore if end_date is the
last day of a month and the day of the month of start_date is earlier
than the 30th, end_date is changed to the first day of the month
following end_date, otherwise the day of month of end_date is changed
to 30.
1 or any other value indicates the European method - Under the European method, any start_date or end_date that falls on the 31st of
a month has its day of month changed to 30.
YEARFRAC parameter 3:
0 indicates US (NASD) 30/360 - This assumes 30 day months and 360 day
years as per the National Association of Securities Dealers standard,
and performs specific adjustments to entered dates which fall at the
end of months.
1 indicates Actual/Actual - This calculates based upon the actual
number of days between the specified dates, and the actual number of
days in the intervening years. Used for US Treasury Bonds and Bills,
but also the most relevant for non-financial use.
2 indicates Actual/360 - This calculates based on the actual number of
days between the specified dates, but assumes a 360 day year.
3 indicates Actual/365 - This calculates based on the actual number of
days between the specified dates, but assumes a 365 day year.
4 indicates European 30/360 - Similar to 0, this calculates based on a
30 day month and 360 day year, but adjusts end-of-month dates
according to European financial conventions.
I have xls file in following format
Name 1 2 3 4
John 09:00-21:00 09:00-21:00
Amy 21:00-09:00 09:00-21:00
Where 1,2,3,4 and so on represent days of current month,
09:00-21:00 - working hours.
I want to calculate salary based on the following conditions:
09:00-21:00 - 10$/hour
21:00-00:00 - 15$/hour
00:00-03:00 - 20$/hour
etc.
and so on (every hour can have it's own cost, for example 03:00-04:00 - 20$/hour, 04:00-05:00 - 19$/hour, etc.)
How can i accomplish this using only Excel (functions or VBA)?
P.S. Easy way: export to csv and process in python/php/etc.
Here is a non-VBA solution. It's a pretty nasty formula, but it works. I am sure it could be made even easier to use and understand with some more ingenuity:
Assuming the spreadsheet is set up like this:
Enter this formula in cell G1 and drag down for your data set:
=IF(ISBLANK(B2),"",IF(LEFT(B2,2)<MID(B2,FIND("-",B2)+1,2),SUMIFS($P$2:$P$24,$Q$2:$Q$24,">="&LEFT(B2,2),$Q$2:$Q$24,"<="&MID(B2,FIND("-",B2)+1,2)),SUMIF($Q$2:$Q$24,"<="&MID(B2,FIND("-",B2)+1,2),$P$2:$P$24)+SUMIF($Q$2:$Q$24,">="&LEFT(B2,2),$P$2:$P$24)))
To explain the formula in detail:
IF(ISBLANK(B2),"" will return a empty string if there is no time for a given person / day combination.
LEFT(B2,2) extracts the start-time into an hour.
Mid(B2,Find("-",B2)+1,2) extracts the end-time into an hour.
IF(LEFT(B2,2)<MID(B2,FIND("-",B2)+1,2) will check if the start-time is less than the end-time (meaning no over-night work). If the start-time is less than the end-time, it will use this formula to calculate the total cost per hour: SUMIFS($P$2:$P$24,$Q$2:$Q$24,">="&LEFT(B3,2),$Q$2:$Q$24,"<="&MID(B3,FIND("-",B3)+1,2))
If the start-time is higher than the end-time (meaning overnight work), it will use this formula to calculate: SUMIF($Q$2:$Q$24,"<="&MID(B3,FIND("-",B3)+1,2),$P$2:$P$24)+SUMIF($Q$2:$Q$24,">="&LEFT(B3,2),$P$2:$P$24)
The use of the Find("-",[cell]) splits the start-and- end times into values excel can use to do math against the Time / Cost table.
The formula in column Q of the Time / Cost table is =VALUE(MID(O2,FIND("-",O2)+1,2)) and turns the ending hour to consider the cost into a value Excel can use to add, instead of having the text from your original source format.
Do this in VBA! It is native to excel and is easy to learn. Functionally, I would loop through the table, write a function to calculate the dollars earned based on the info given. If you want your results to be live updating (like a formula in excel) you can write a user defined function. A helpful function might be an HoursIntersect function, as below:
Public Function HoursIntersect(Period1Start As Date, Period1End As Date, _
Period2Start As Date, Period2End As Date) _
As Double
Dim result As Double
' Check if the ends are greater than the starts. If they are, assume we are rolling over to
' a new day
If Period1End < Period1Start Then Period1End = Period1End + 1
If Period2End < Period2Start Then Period2End = Period2End + 1
With WorksheetFunction
result = .Min(Period1End, Period2End) - .Max(Period1Start, Period2Start)
HoursIntersect = .Max(result, 0) * 24
End With
End Function
Then you can determine the start and end time by splitting the value on the "-" character. Then multiply each payment schedule by the hours worked within that time:
DollarsEarned = DollarsEarned + 20 * HoursIntersect(StartTime, EndTime, #00:00:00#, #03:00:00#)
DollarsEarned = DollarsEarned + 10 * HoursIntersect(StartTime, EndTime, #09:00:00#, #21:00:00#)
DollarsEarned = DollarsEarned + 15 * HoursIntersect(StartTime, EndTime, #21:00:00#, #00:00:00#)
I have a method that uses nothing but formulas. First create a lookup table which contains every hour and rate in say columns K & L, something like this:
K L
08:00 15
09:00 10
10:00 10
11:00 10
12:00 10
13:00 10
14:00 10
15:00 10
16:00 10
17:00 10
18:00 10
19:00 10
20:00 10
21:00 15
22:00 15
23:00 15
Make sure you enter the hours as text by entering a single quote before the digits.
Then if your hours were in cell B2 you could then use this formula to calculate the total:
=SUM(INDIRECT("L"&MATCH(LEFT(B2,5),K2:K40,0)&":L"&MATCH(RIGHT(B2,5),K2:K40,0)))
All the formula is doing is getting the left and right text of your work time, using MATCH to find their positions in the lookup table which is used to create a range address which is then passed to SUM via the INDIRECT function.
If you need to worry about minutes all you need to do is create a bigger lookup table which holds every minute of the day. You may need to add some extra logic if your work days span midnight.
For the calculation I'm trying to perform one year = one season and the data I have is start year and end year.
So 1952 1953 needs to add up to 2 (seasons) but if I use =YEAR(A1)-YEAR(A2) the result is 0 - is there a simple way to include the start year and end year as a value in these calculations?
It looks like you have found the problem and rectified it. For the benefit of others who might have found this thread, this is why it was behaving the ways it was.
Background - Excel (and many other applications) treat dates as 1 for every day past Dec 31, 1899. Today happens to be 42,079. Time is a decimal portion of a day so 42,079.75 would be Mar 16, 2015 06:00 PM.
You had the years as numbers in A1:A2; not as full dates. Using the 1-per-day formula, 1952 is May 5, 1905 and 1953 is May 6, 1905. If you peel out the year of each of those with the YEAR() function, you are subtracting 1905 from 1905; resulting in zero.
The solution would be to either type full dates into A1:A2 and format the cells as yyyy so they display 1952 & 1953 but retain their full date nature e.g. =ABS(YEAR(A1) - YEAR(A2)) + 1 , or use the years as numbers only and discard the YEAR() function altogether, e.g. =ABS(A1 - A2) + 1 to get the spanned (inclusive) number of seasons.