How can I assign a new char into a string in Go? - string

I'm trying to alter an existing string in Go but I keep getting this error "cannot assign to new_str[i]"
package main
import "fmt"
func ToUpper(str string) string {
new_str := str
for i:=0; i<len(str); i++{
if str[i]>='a' && str[i]<='z'{
chr:=uint8(rune(str[i])-'a'+'A')
new_str[i]=chr
}
}
return new_str
}
func main() {
fmt.Println(ToUpper("cdsrgGDH7865fxgh"))
}
This is my code, I wish to change lowercase to uppercase but I cant alter the string. Why? How can I alter it?
P.S I wish to use ONLY the fmt package!
Thanks in advance.

You can't... they are immutable. From the Golang Language Specification:
Strings are immutable: once created, it is impossible to change the contents of a string.
You can however, cast it to a []byte slice and alter that:
func ToUpper(str string) string {
new_str := []byte(str)
for i := 0; i < len(str); i++ {
if str[i] >= 'a' && str[i] <= 'z' {
chr := uint8(rune(str[i]) - 'a' + 'A')
new_str[i] = chr
}
}
return string(new_str)
}
Working sample: http://play.golang.org/p/uZ_Gui7cYl

Use range and avoid unnecessary conversions and allocations. Strings are immutable. For example,
package main
import "fmt"
func ToUpper(s string) string {
var b []byte
for i, c := range s {
if c >= 'a' && c <= 'z' {
if b == nil {
b = []byte(s)
}
b[i] = byte('A' + rune(c) - 'a')
}
}
if b == nil {
return s
}
return string(b)
}
func main() {
fmt.Println(ToUpper("cdsrgGDH7865fxgh"))
}
Output:
CDSRGGDH7865FXGH

In Go strings are immutable. Here is one very bad way of doing what you want (playground)
package main
import "fmt"
func ToUpper(str string) string {
new_str := ""
for i := 0; i < len(str); i++ {
chr := str[i]
if chr >= 'a' && chr <= 'z' {
chr = chr - 'a' + 'A'
}
new_str += string(chr)
}
return new_str
}
func main() {
fmt.Println(ToUpper("cdsrgGDH7865fxgh"))
}
This is bad because
you are treating your string as characters - what if it is UTF-8? Using range str is the way to go
appending to strings is slow - lots of allocations - a bytes.Buffer would be a good idea
there is a very good library routine to do this already strings.ToUpper
It is worth exploring the line new_str += string(chr) a bit more. Strings are immutable, so what this does is make a new string with the chr on the end, it doesn't extend the old string. This is wildly inefficient for long strings as the allocated memory will tend to the square of the string length.
Next time just use strings.ToUpper!

Related

Access a string as a character array for using in strings.Join() method: GO language

I am trying to access a string as a character array or as a rune and join with some separator. What is the right way to do it.
Here are the two ways i tried but i get an error as below
cannot use ([]rune)(t)[i] (type rune) as type []string in argument to strings.Join
How does a string represented in GOLANG. Is it like a character array?
package main
import (
"fmt"
"strings"
)
func main() {
var t = "hello"
s := ""
for i, rune := range t {
s += strings.Join(rune, "\n")
}
fmt.Println(s)
}
package main
import (
"fmt"
"strings"
)
func main() {
var t = "hello"
s := ""
for i := 0; i < len(t); i++ {
s += strings.Join([]rune(t)[i], "\n")
}
fmt.Println(s)
}
I also tried the below way.BUt, it does not work for me.
var t = "hello"
s := ""
for i := 0; i < len(t); i++ {
s += strings.Join(string(t[i]), "\n")
}
fmt.Println(s)
The strings.Join method expects a slice of strings as first argument, but you are giving it a rune type.
You can use the strings.Split method to obtain a slice of strings from a string. Here is an example.

How to concatenate follower characters to a string until a defined maximum length has been reached in Golang?

InputOutput
abc abc___
a a___
abcdeabcde_
Attempt
package main
import "fmt"
import "unicode/utf8"
func main() {
input := "abc"
if utf8.RuneCountInString(input) == 1 {
fmt.Println(input + "_____")
} else if utf8.RuneCountInString(input) == 2 {
fmt.Println(input + "____")
} else if utf8.RuneCountInString(input) == 3 {
fmt.Println(input + "___")
} else if utf8.RuneCountInString(input) == 4 {
fmt.Println(input + "__")
} else if utf8.RuneCountInString(input) == 5 {
fmt.Println(input + "_")
} else {
fmt.Println(input)
}
}
returns
abc___
Discussion
Although the code is creating the expected output, it looks very verbose and devious.
Question
Is there a concise way?
The strings package has a Repeat function, so something like
input += strings.Repeat("_", desiredLen - utf8.RuneCountInString(input))
would be simpler. You should probably check that desiredLen is smaller than inpult length first.
You can also do this efficiently without loops and "external" function calls, by slicing a prepared "max padding" (slice out the required padding and simply add it to the input):
const max = "______"
func pad(s string) string {
if i := utf8.RuneCountInString(s); i < len(max) {
s += max[i:]
}
return s
}
Using it:
fmt.Println(pad("abc"))
fmt.Println(pad("a"))
fmt.Println(pad("abcde"))
Output (try it on the Go Playground):
abc___
a_____
abcde_
Notes:
len(max) is a constant (because max is a constant): Spec: Length and capacity:
The expression len(s) is constant if s is a string constant.
Slicing a string is efficient:
An important consequence of this slice-like design for strings is that creating a substring is very efficient. All that needs to happen is the creation of a two-word string header. Since the string is read-only, the original string and the string resulting from the slice operation can share the same array safely.
You could just do input += "_" in a cycle, but that would allocate unnecessary strings. Here is a version that doesn't allocate more than it needs:
const limit = 6
func f(s string) string {
if len(s) >= limit {
return s
}
b := make([]byte, limit)
copy(b, s)
for i := len(s); i < limit; i++ {
b[i] = '_'
}
return string(b)
}
Playground: http://play.golang.org/p/B_Wx1449QM.

golang - how to sort string or []byte?

I am looking for a function, that can sort string or []byte:
"bcad" to "abcd"
or
[]byte("bcad") to []byte("abcd")
The string only contains letters - but sorting should also work for letters and numbers.
I found sort package but not the function I want.
It feels wasteful to create a string for each character just to Join them.
Here's one that is a little less wasteful, but with more boiler plate. playground://XEckr_rpr8
type sortRunes []rune
func (s sortRunes) Less(i, j int) bool {
return s[i] < s[j]
}
func (s sortRunes) Swap(i, j int) {
s[i], s[j] = s[j], s[i]
}
func (s sortRunes) Len() int {
return len(s)
}
func SortString(s string) string {
r := []rune(s)
sort.Sort(sortRunes(r))
return string(r)
}
func main() {
w1 := "bcad"
w2 := SortString(w1)
fmt.Println(w1)
fmt.Println(w2)
}
You can convert the string to a slice of strings, sort it, and then convert it back to a string:
package main
import (
"fmt"
"sort"
"strings"
)
func SortString(w string) string {
s := strings.Split(w, "")
sort.Strings(s)
return strings.Join(s, "")
}
func main() {
w1 := "bcad"
w2 := SortString(w1)
fmt.Println(w1)
fmt.Println(w2)
}
This prints:
bcad
abcd
Try it: http://play.golang.org/p/_6cTBAAZPb
there is a simple way by leveraging function sort.Slice:
package main
import (
"fmt"
"sort"
)
func main() {
word := "1BCagM9"
s := []rune(word)
sort.Slice(s, func(i int, j int) bool { return s[i] < s[j] })
fmt.Println(string(s))
}
(Playground)
package main
import (
"fmt"
"sort"
)
func main() {
word := "1àha漢字Pépy5"
charArray := []rune(word)
sort.Slice(charArray, func(i int, j int) bool {
return charArray[i] < charArray[j]
})
fmt.Println(string(charArray))
}
Output:
15Pahpyàé字漢
Playground
the thing is, golang does not have a convenient function to sort string.
Sort using int
too much conversion i think
still using rune to merge as string
func sortByInt(s string) string {
var si = []int{}
var sr = []rune{}
for _, r := range s {
si = append(si, int(r))
}
sort.Ints(si)
for _, r := range si {
sr = append(sr, rune(r))
}
return string(sr)
}
Implement sort interface for []rune, just remember that
rune equals to int32
byte equals to uint8
func sortBySlice(s string) []rune {
sr := []rune(s)
sort.Slice(sr, func(i int, j int) bool {
return sr[i] < sr[j]
})
return sr
}
You can sort a string array in go like this
// name of the file is main.go
package main
import (
"fmt"
"sort"
)
/*
*This function is used to sort a string array
*/
func main() {
var names = []string{"b", "e", "a", "d", "g", "c", "f"}
fmt.Println("original string array: ", names)
sort.Strings(names)
fmt.Println("After string sort array ", names)
return
}

Position in characters of a substring in Go

How can I know the position of a substring in a string, in characteres (or runes) instead of bytes?
strings.Index(s, sub) will give the position in bytes. When using Unicode, it doesn't match the position in runes: http://play.golang.org/p/DnlFjPaD2j
func main() {
s := "áéíóúÁÉÍÓÚ"
fmt.Println(strings.Index(s, "ÍÓ"))
}
Result: 14. Expected: 7
Of course, I could convert s and sub to []rune and look for the subslice manually, but is there a better way to do it?
Related to this, to get the first n characters of a string I'm doing this: string([]rune(s)[:n]). Is it the best way?
You can do it like this, after importing the unicode/utf8 package:
func main() {
s := "áéíóúÁÉÍÓÚ"
i := strings.Index(s, "ÍÓ")
fmt.Println(utf8.RuneCountInString(s[:i]))
}
http://play.golang.org/p/Etszu3rbY3
Another option:
package main
import "strings"
func runeIndex(s, substr string) int {
n := strings.Index(s, substr)
if n == -1 { return -1 }
r := []rune(s[:n])
return len(r)
}
func main() {
n := runeIndex("áéíóúÁÉÍÓÚ", "ÍÓ")
println(n == 7)
}

How to reverse a string in Go?

How can we reverse a simple string in Go?
In Go1 rune is a builtin type.
func Reverse(s string) string {
runes := []rune(s)
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
runes[i], runes[j] = runes[j], runes[i]
}
return string(runes)
}
Russ Cox, on the golang-nuts mailing list, suggests
package main
import "fmt"
func main() {
input := "The quick brown 狐 jumped over the lazy 犬"
// Get Unicode code points.
n := 0
rune := make([]rune, len(input))
for _, r := range input {
rune[n] = r
n++
}
rune = rune[0:n]
// Reverse
for i := 0; i < n/2; i++ {
rune[i], rune[n-1-i] = rune[n-1-i], rune[i]
}
// Convert back to UTF-8.
output := string(rune)
fmt.Println(output)
}
This works, without all the mucking about with functions:
func Reverse(s string) (result string) {
for _,v := range s {
result = string(v) + result
}
return
}
From Go example projects: golang/example/stringutil/reverse.go, by Andrew Gerrand
/*
Copyright 2014 Google Inc.
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/
// Reverse returns its argument string reversed rune-wise left to right.
func Reverse(s string) string {
r := []rune(s)
for i, j := 0, len(r)-1; i < len(r)/2; i, j = i+1, j-1 {
r[i], r[j] = r[j], r[i]
}
return string(r)
}
Go Playground for reverse a string
After reversing string "bròwn", the correct result should be "nwòrb", not "nẁorb".
Note the grave above the letter o.
For preserving Unicode combining characters such as "as⃝df̅" with reverse result "f̅ds⃝a",
please refer to another code listed below:
http://rosettacode.org/wiki/Reverse_a_string#Go
This works on unicode strings by considering 2 things:
range works on string by enumerating unicode characters
string can be constructed from int slices where each element is a unicode character.
So here it goes:
func reverse(s string) string {
o := make([]int, utf8.RuneCountInString(s));
i := len(o);
for _, c := range s {
i--;
o[i] = c;
}
return string(o);
}
There are too many answers here. Some of them are clear duplicates. But even from the left one, it is hard to select the best solution.
So I went through the answers, thrown away the one that does not work for unicode and also removed duplicates. I benchmarked the survivors to find the fastest. So here are the results with attribution (if you notice the answers that I missed, but worth adding, feel free to modify the benchmark):
Benchmark_rmuller-4 100000 19246 ns/op
Benchmark_peterSO-4 50000 28068 ns/op
Benchmark_russ-4 50000 30007 ns/op
Benchmark_ivan-4 50000 33694 ns/op
Benchmark_yazu-4 50000 33372 ns/op
Benchmark_yuku-4 50000 37556 ns/op
Benchmark_simon-4 3000 426201 ns/op
So here is the fastest method by rmuller:
func Reverse(s string) string {
size := len(s)
buf := make([]byte, size)
for start := 0; start < size; {
r, n := utf8.DecodeRuneInString(s[start:])
start += n
utf8.EncodeRune(buf[size-start:], r)
}
return string(buf)
}
For some reason I can't add a benchmark, so you can copy it from PlayGround (you can't run tests there). Rename it and run go test -bench=.
I noticed this question when Simon posted his solution which, since strings are immutable, is very inefficient. The other proposed solutions are also flawed; they don't work or they are inefficient.
Here's an efficient solution that works, except when the string is not valid UTF-8 or the string contains combining characters.
package main
import "fmt"
func Reverse(s string) string {
n := len(s)
runes := make([]rune, n)
for _, rune := range s {
n--
runes[n] = rune
}
return string(runes[n:])
}
func main() {
fmt.Println(Reverse(Reverse("Hello, 世界")))
fmt.Println(Reverse(Reverse("The quick brown 狐 jumped over the lazy 犬")))
}
I wrote the following Reverse function which respects UTF8 encoding and combined characters:
// Reverse reverses the input while respecting UTF8 encoding and combined characters
func Reverse(text string) string {
textRunes := []rune(text)
textRunesLength := len(textRunes)
if textRunesLength <= 1 {
return text
}
i, j := 0, 0
for i < textRunesLength && j < textRunesLength {
j = i + 1
for j < textRunesLength && isMark(textRunes[j]) {
j++
}
if isMark(textRunes[j-1]) {
// Reverses Combined Characters
reverse(textRunes[i:j], j-i)
}
i = j
}
// Reverses the entire array
reverse(textRunes, textRunesLength)
return string(textRunes)
}
func reverse(runes []rune, length int) {
for i, j := 0, length-1; i < length/2; i, j = i+1, j-1 {
runes[i], runes[j] = runes[j], runes[i]
}
}
// isMark determines whether the rune is a marker
func isMark(r rune) bool {
return unicode.Is(unicode.Mn, r) || unicode.Is(unicode.Me, r) || unicode.Is(unicode.Mc, r)
}
I did my best to make it as efficient and readable as possible. The idea is simple, traverse through the runes looking for combined characters then reverse the combined characters' runes in-place. Once we have covered them all, reverse the runes of the entire string also in-place.
Say we would like to reverse this string bròwn. The ò is represented by two runes, one for the o and one for this unicode \u0301a that represents the "grave".
For simplicity, let's represent the string like this bro'wn. The first thing we do is look for combined characters and reverse them. So now we have the string br'own. Finally, we reverse the entire string and end up with nwo'rb. This is returned to us as nwòrb
You can find it here https://github.com/shomali11/util if you would like to use it.
Here are some test cases to show a couple of different scenarios:
func TestReverse(t *testing.T) {
assert.Equal(t, Reverse(""), "")
assert.Equal(t, Reverse("X"), "X")
assert.Equal(t, Reverse("b\u0301"), "b\u0301")
assert.Equal(t, Reverse("😎⚽"), "⚽😎")
assert.Equal(t, Reverse("Les Mise\u0301rables"), "selbare\u0301siM seL")
assert.Equal(t, Reverse("ab\u0301cde"), "edcb\u0301a")
assert.Equal(t, Reverse("This `\xc5` is an invalid UTF8 character"), "retcarahc 8FTU dilavni na si `�` sihT")
assert.Equal(t, Reverse("The quick bròwn 狐 jumped over the lazy 犬"), "犬 yzal eht revo depmuj 狐 nwòrb kciuq ehT")
}
//Reverse reverses string using strings.Builder. It's about 3 times faster
//than the one with using a string concatenation
func Reverse(in string) string {
var sb strings.Builder
runes := []rune(in)
for i := len(runes) - 1; 0 <= i; i-- {
sb.WriteRune(runes[i])
}
return sb.String()
}
//Reverse reverses string using string
func Reverse(in string) (out string) {
for _, r := range in {
out = string(r) + out
}
return
}
BenchmarkReverseStringConcatenation-8 1000000 1571 ns/op 176 B/op 29 allocs/op
BenchmarkReverseStringsBuilder-8 3000000 499 ns/op 56 B/op 6 allocs/op
Using strings.Builder is about 3 times faster than using string concatenation
Here is quite different, I would say more functional approach, not listed among other answers:
func reverse(s string) (ret string) {
for _, v := range s {
defer func(r rune) { ret += string(r) }(v)
}
return
}
This is the fastest implementation
func Reverse(s string) string {
size := len(s)
buf := make([]byte, size)
for start := 0; start < size; {
r, n := utf8.DecodeRuneInString(s[start:])
start += n
utf8.EncodeRune(buf[size-start:], r)
}
return string(buf)
}
const (
s = "The quick brown 狐 jumped over the lazy 犬"
reverse = "犬 yzal eht revo depmuj 狐 nworb kciuq ehT"
)
func TestReverse(t *testing.T) {
if Reverse(s) != reverse {
t.Error(s)
}
}
func BenchmarkReverse(b *testing.B) {
for i := 0; i < b.N; i++ {
Reverse(s)
}
}
A simple stroke with rune:
func ReverseString(s string) string {
runes := []rune(s)
size := len(runes)
for i := 0; i < size/2; i++ {
runes[size-i-1], runes[i] = runes[i], runes[size-i-1]
}
return string(runes)
}
func main() {
fmt.Println(ReverseString("Abcdefg 汉语 The God"))
}
: doG ehT 语汉 gfedcbA
You could also import an existing implementation:
import "4d63.com/strrev"
Then:
strrev.Reverse("abåd") // returns "dåba"
Or to reverse a string including unicode combining characters:
strrev.ReverseCombining("abc\u0301\u031dd") // returns "d\u0301\u031dcba"
These implementations supports correct ordering of unicode multibyte and combing characters when reversed.
Note: Built-in string reverse functions in many programming languages do not preserve combining, and identifying combining characters requires significantly more execution time.
func ReverseString(str string) string {
output :=""
for _, char := range str {
output = string(char) + output
}
return output
}
// "Luizpa" -> "apziuL"
// "123日本語" -> "語本日321"
// "⚽😎" -> "😎⚽"
// "´a´b´c´" -> "´c´b´a´"
This code preserves sequences of combining characters intact, and
should work with invalid UTF-8 input too.
package stringutil
import "code.google.com/p/go.text/unicode/norm"
func Reverse(s string) string {
bound := make([]int, 0, len(s) + 1)
var iter norm.Iter
iter.InitString(norm.NFD, s)
bound = append(bound, 0)
for !iter.Done() {
iter.Next()
bound = append(bound, iter.Pos())
}
bound = append(bound, len(s))
out := make([]byte, 0, len(s))
for i := len(bound) - 2; i >= 0; i-- {
out = append(out, s[bound[i]:bound[i+1]]...)
}
return string(out)
}
It could be a little more efficient if the unicode/norm primitives
allowed iterating through the boundaries of a string without
allocating. See also https://code.google.com/p/go/issues/detail?id=9055 .
If you need to handle grapheme clusters, use unicode or regexp module.
package main
import (
"unicode"
"regexp"
)
func main() {
str := "\u0308" + "a\u0308" + "o\u0308" + "u\u0308"
println("u\u0308" + "o\u0308" + "a\u0308" + "\u0308" == ReverseGrapheme(str))
println("u\u0308" + "o\u0308" + "a\u0308" + "\u0308" == ReverseGrapheme2(str))
}
func ReverseGrapheme(str string) string {
buf := []rune("")
checked := false
index := 0
ret := ""
for _, c := range str {
if !unicode.Is(unicode.M, c) {
if len(buf) > 0 {
ret = string(buf) + ret
}
buf = buf[:0]
buf = append(buf, c)
if checked == false {
checked = true
}
} else if checked == false {
ret = string(append([]rune(""), c)) + ret
} else {
buf = append(buf, c)
}
index += 1
}
return string(buf) + ret
}
func ReverseGrapheme2(str string) string {
re := regexp.MustCompile("\\PM\\pM*|.")
slice := re.FindAllString(str, -1)
length := len(slice)
ret := ""
for i := 0; i < length; i += 1 {
ret += slice[length-1-i]
}
return ret
}
It's assuredly not the most memory efficient solution, but for a "simple" UTF-8 safe solution the following will get the job done and not break runes.
It's in my opinion the most readable and understandable on the page.
func reverseStr(str string) (out string) {
for _, s := range str {
out = string(s) + out
}
return
}
The following two methods run faster than the fastest solution that preserve combining characters, though that's not to say I'm missing something in my benchmark setup.
//input string s
bs := []byte(s)
var rs string
for len(bs) > 0 {
r, size := utf8.DecodeLastRune(bs)
rs += fmt.Sprintf("%c", r)
bs = bs[:len(bs)-size]
} // rs has reversed string
Second method inspired by this
//input string s
bs := []byte(s)
cs := make([]byte, len(bs))
b1 := 0
for len(bs) > 0 {
r, size := utf8.DecodeLastRune(bs)
d := make([]byte, size)
_ = utf8.EncodeRune(d, r)
b1 += copy(cs[b1:], d)
bs = bs[:len(bs) - size]
} // cs has reversed bytes
NOTE: This answer is from 2009, so there are probably better solutions out there by now.
Looks a bit 'roundabout', and probably not very efficient, but illustrates how the Reader interface can be used to read from strings. IntVectors also seem very suitable as buffers when working with utf8 strings.
It would be even shorter when leaving out the 'size' part, and insertion into the vector by Insert, but I guess that would be less efficient, as the whole vector then needs to be pushed back by one each time a new rune is added.
This solution definitely works with utf8 characters.
package main
import "container/vector";
import "fmt";
import "utf8";
import "bytes";
import "bufio";
func
main() {
toReverse := "Smørrebrød";
fmt.Println(toReverse);
fmt.Println(reverse(toReverse));
}
func
reverse(str string) string {
size := utf8.RuneCountInString(str);
output := vector.NewIntVector(size);
input := bufio.NewReader(bytes.NewBufferString(str));
for i := 1; i <= size; i++ {
rune, _, _ := input.ReadRune();
output.Set(size - i, rune);
}
return string(output.Data());
}
func Reverse(s string) string {
r := []rune(s)
var output strings.Builder
for i := len(r) - 1; i >= 0; i-- {
output.WriteString(string(r[i]))
}
return output.String()
}
Simple, Sweet and Performant
func reverseStr(str string) string {
strSlice := []rune(str) //converting to slice of runes
length := len(strSlice)
for i := 0; i < (length / 2); i++ {
strSlice[i], strSlice[length-i-1] = strSlice[length-i-1], strSlice[i]
}
return string(strSlice) //converting back to string
}
Reversing a string by word is a similar process. First, we convert the string into an array of strings where each entry is a word. Next, we apply the normal reverse loop to that array. Finally, we smush the results back together into a string that we can return to the caller.
package main
import (
"fmt"
"strings"
)
func reverse_words(s string) string {
words := strings.Fields(s)
for i, j := 0, len(words)-1; i < j; i, j = i+1, j-1 {
words[i], words[j] = words[j], words[i]
}
return strings.Join(words, " ")
}
func main() {
fmt.Println(reverse_words("one two three"))
}
Another hack is to use built-in language features, for example, defer:
package main
import "fmt"
func main() {
var name string
fmt.Scanln(&name)
for _, char := range []rune(name) {
defer fmt.Printf("%c", char) // <-- LIFO does it all for you
}
}
For simple strings it possible to use such construction:
func Reverse(str string) string {
if str != "" {
return Reverse(str[1:]) + str[:1]
}
return ""
}
For Unicode strings it might look like this:
func RecursiveReverse(str string) string {
if str == "" {
return ""
}
runes := []rune(str)
return RecursiveReverse(string(runes[1:])) + string(runes[0])
}
A version which I think works on unicode. It is built on the utf8.Rune functions:
func Reverse(s string) string {
b := make([]byte, len(s));
for i, j := len(s)-1, 0; i >= 0; i-- {
if utf8.RuneStart(s[i]) {
rune, size := utf8.DecodeRuneInString(s[i:len(s)]);
utf8.EncodeRune(rune, b[j:j+size]);
j += size;
}
}
return string(b);
}
rune is a type, so use it. Moreover, Go doesn't use semicolons.
func reverse(s string) string {
l := len(s)
m := make([]rune, l)
for _, c := range s {
l--
m[l] = c
}
return string(m)
}
func main() {
str := "the quick brown 狐 jumped over the lazy 犬"
fmt.Printf("reverse(%s): [%s]\n", str, reverse(str))
}
try below code:
package main
import "fmt"
func reverse(s string) string {
chars := []rune(s)
for i, j := 0, len(chars)-1; i < j; i, j = i+1, j-1 {
chars[i], chars[j] = chars[j], chars[i]
}
return string(chars)
}
func main() {
fmt.Printf("%v\n", reverse("abcdefg"))
}
for more info check http://golangcookbook.com/chapters/strings/reverse/
and http://www.dotnetperls.com/reverse-string-go
func reverseString(someString string) string {
runeString := []rune(someString)
var reverseString string
for i := len(runeString)-1; i >= 0; i -- {
reverseString += string(runeString[i])
}
return reverseString
}
Strings are immutable object in golang, unlike C inplace reverse is not possible with golang.
With C , you can do something like,
void reverseString(char *str) {
int length = strlen(str)
for(int i = 0, j = length-1; i < length/2; i++, j--)
{
char tmp = str[i];
str[i] = str[j];
str[j] = tmp;
}
}
But with golang, following one, uses byte to convert the input into bytes first and then reverses the byte array once it is reversed, convert back to string before returning. works only with non unicode type string.
package main
import "fmt"
func main() {
s := "test123 4"
fmt.Println(reverseString(s))
}
func reverseString(s string) string {
a := []byte(s)
for i, j := 0, len(s)-1; i < j; i++ {
a[i], a[j] = a[j], a[i]
j--
}
return string(a)
}
Here is yet another solution:
func ReverseStr(s string) string {
chars := []rune(s)
rev := make([]rune, 0, len(chars))
for i := len(chars) - 1; i >= 0; i-- {
rev = append(rev, chars[i])
}
return string(rev)
}
However, yazu's solution above is more elegant since he reverses the []rune slice in place.

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