The sample for substituting:
hello world (one) hello world (two two) hello world (three three three)
The result I want:
hello world $one# hello world $two two# hello world $three three three#
I've tried to use:
s/(\(\w\\+\s*\))/$\1#/g
but it does not work.
Doing these two simple substitutions is a lot more intuitive and a lot faster than wasting your time trying to come up with a single one:
:s/(/\$/g
:s/)/#/g
Anyway:
:s/(\([^)]\+\))/\$\1#/g
The search part: we are looking for an opening parenthese, followed by one or more characters that are not closing parentheses that we put in a capture group, followed by a closing parenthese.
The replacement part: we replace with a dollar sign, followed by our capture group, followed by an octothorpe.
Thanks very much for everyone. I have woke out it.:s/(\(\(\w*\s*\)*\))/$\1#/g. The preceding command can give the right result I want.
Related
I'm trying to split a given string when two quotes appear and they contain at least 3 characters(I also have to split whenever . or , appear). So, something like hello"example"hello,cat should return [hello;example;hello;cat].
I came up with:
re.split("\'(...+)\'|\.|,","hello'example'hello,cat")
This works fine with the quotes, but whenever it split for . or , this happens:
['hello', 'example', 'hello', None, 'cat']
I found out the capture group is the one that causes it (the None in the middle of the list), but it is the only way I know to keep the content.
Please keep in mind that I have to do as few as possible computations because the program shall work with huge files, also I'm not very experienced with Python so sorry if I did something obvious wrong.
Try just:
re.split("\'|\.|,", "hello'example'hello,cat")
It's tricky because the open quote and close quote is the exact same character. I think you'd have to use a negative look behind to exclude any single quote that is preceded by 0, 1 or 2 characters and another single quote. In addition, you'd have to use a positive lookahead. This works in javascript.
re.split("(?<!'(.?|..))'(?=[^']{3,})|\.|\,", "hello'example'hello,cat")
But it doesn't look like python supports variable-length lookbehinds. Also, this won't work if there is a lone single quote (apostrophe).
I have a million lines text that looks like:
HELLO random1 WORLD
HELLO random2 WORLD
HELLO random3 WORLD
How with the tools Sublime provide, I can extract only the text that I need so the result would be:
random1
random2
random3
Search using regex, with this parameter HELLO (\w+) WORLD and replace it with \1 (or $1)
the \w is regex for a word. And the brackets around it capture it and assign it to the variable $1
use regex option in search and replace. This regex, without quotes, will select both words.
"HELLO | WORLD"
This is probably oversimplified solution. You need to post more realistic examples for us to provide with an exact solution
One of my elder brother who is studying in Statistics. Now, he is writing his thesis paper in LaTeX. Almost all contents are written for the paper. And he took 5 number after point(e.g. 5.55534) for each value those are used for his calculation. But, at the last time his instructor said to change those to 3 number after point(e.g. 5.555) which falls my brother in trouble. Finding and correcting those manually is not easy. So, he told me to help.
I believe there is also a easy solution which is know to me. The snapshot of a portion of the thesis looks like-
&se($\hat\beta_1$)&0.35581&0.35573&0.35573\\
&mse($\hat\beta_1$)&.12945&.12947&.12947\\
\addlinespace
&$\hat\beta_2$&0.03329&0.03331&0.03331 \\
&se($\hat\beta_2$)&0.01593&0.01592&0.01591\\
&mse($\hat\beta_2$)&.000265&.000264&.000264 \\
\midrule
{n=100} & $\hat\beta_1$&-.52006&-.52001&-.51946\\
&se($\hat\beta_1$)&.22819&.22814&.22795\\
&mse($\hat\beta_1$)&.05247&.05244&.05234\\
\addlinespace
&$\hat\beta_2$&0.03134&0.03134&0.03133 \\
&se($\hat\beta_2$)&0.00979&0.00979&0.00979\\
&mse($\hat\beta_2$)&.000098&.000098&.000098
I want -
&se($\hat\beta_1$)&0.355&0.355&0.355\\
&mse($\hat\beta_1$)&.129&.129&.129\\
......................................................................
........................................................................
........................................................................
Note: Don't feel boring for the syntax(These are LaTeX syntax).
If anybody has solution or suggestion, please provide. Thank you.
In sed:
$ sed 's/\(\.[0-9]\{3\}\)[0-9]*/\1/g' file
&se($\hat\beta_1$)&0.355&0.355&0.355\\
&mse($\hat\beta_1$)&.129&.129&.129\\
ie. replace period starting numeric strings with at least 3 numbers with the leading period and three first numbers.
Here is the command in vim:
:%s/\.\d\{3}\zs\d\+//g
Explanation:
: entering command-mode
% is the range of all lines of the file
s substitution command
\.\d\{3}\zs\d\+ pattern you would like to change
\. literal point (.)
\d\{3} match 3 consecutive digits
\zs start substitution from here
\d\+ one or more digits
g Replace all occurrences in the line
Concerning grep and cat they have nothing to do with replacing text. These commands are only for searching and printing contents of files.
Instead, what you are looking is substitution there are lots of commands in Linux that can do that mainly sed, perl, awk, ex etc.
Say I have a file called hello.txt which contains "Hello World!".
If I wanted to make a script which opened the file and read the contents (I know how to do that) and added stuff to the string, how would I go about doing this?
For example: Hello World would have '..' inserted at the start of the string/content, and then every 2 characters later, except at the end. Also consider the contents will not always be "Hello World".
Since you already know how to read from a file, I take it your only real question is how to add .. after every 2 characters of any given string:
my $string = "Hello World";
$string =~ s/^|(..)(?!$)/$1../g;
print "$string\n";
Output:
..He..ll..o ..Wo..rl..d
Though I can't imagine how that would ever be useful.
The regex looks for the start of string or two characters not followed by the end of the string, using negative look-ahead, and replaces all matches with any captured characters followed by two periods.
I am creating a small console app that needs a progress bar. Something like...
Conversion: 175/348 Seconds |========== | 50%
My question is, how do you erase characters already printed to the console? When I reach the 51st percentage, I have to erase this line from the console and insert a new line. In my current solution, this is what happens...
Conversion: 175/348 Seconds |========== | 50%
Conversion: 179/348 Seconds |========== | 52%
Conversion: 183/348 Seconds |========== | 54%
Conversion: 187/348 Seconds |=========== | 56%
Code I use is...
print "Conversion: $converted_seconds/$total_time Seconds $progress_bar $converted_percentage%\n";
I am doing this in Linux using PHP(only I will use the app - so please excuse the language choice). So, the solution should work on the Linux platform - but if you have a solution that's cross platform, that would be preferable.
I don't think you need to apologize for the language choice. PHP is a great language for console applications.
Try this out:
<?php
for( $i=0;$i<10;$i++){
print "$i \r";
sleep(1);
}
?>
The "\r" will overwrite the line with the new text. To make a new line you can just use "\n", but I'm guessing you already knew that.
Hope this helps! I know this works in Linux, but I don't know if it works in Windows or other operating systems.
To erase a previously printed character you have three options:
echo chr(8) . " "; echoes the back character, and will move the cursor back one place, and the space then overwrites the character. You can use chr(8) multiple times in a row to move back multiple characters.
echo "\r"; will return the cursor to the start of the current line. You can now replace the line with new text.
The third option is to set the line and column of the cursor position using ANSI escape codes, then print the replacement characters. It might not work with all terminals:
function movecursor($line, $column){
echo "\033[{$line};{$column}H";
}
\r did the trick.
For future reference, \b does not work in PHP in Linux. I was curious - so I did a couple of experiments in other languages as well(I did this in Linux - I don't know if the result will be the same in Windows/Mac)..
\b Works in...
Perl
Ruby
Tcl - with code puts -nonewline "Hello\b"
\b Doesn't work in
PHP - the code print "Hello\b"; prints out Hello\b
Python - code print "Hello\b" prints out Hello<new line> . Same result with print "Hello\b",
I'm not sure if it's the same in Linux but in Windows console apps you can print \r and the cursor will return to the first left position of the line allowing you to overwrite all the characters to the right.
You can use \b to move back a single character but since you're going to be updating your progress bar \r would be simpler to use than printing \b x number of times.
This seems to be pretty old topic but I will drop my 5 into.
for ($i; $i<_POSITION_; $i--) {
echo "\010"; //issue backspace
}
Found this on the internet some time ago, unfortunately don't remember where. So all credits goes to original author.
to erase a previously printed character, I print a backspace after it:
print "a"
print "\b"
will print nothing (actually it will print and then a backspace, but you probably won't notice it)