I need to collect Sch Code from different columns into one column as shown below.
First priority is by formula or UDF Function if possible.
My Data:
Column A Column B Column C Column D Column E Column F Column G
SCH Code Value SCH Code Value Rating SCH Code Value
C01-3-1 4 C01-4-1 8 300 C02-3-1 8
300 C02-3-5 9
C01-3-2 5 C01-4-2 12 300 C02-3-2 12
C01-3-3 6 C01-4-3 21 300 C02-3-3 21
300 C02-3-6 10
C01-3-4 7 C01-4-4 4 300 C02-3-4 4
Required Result (Only Sch Code required in summary sheet but it is required by formula or VBA UDF function) :
Column A
C01-3-1
C01-3-2
C01-3-3
C01-3-4
C01-4-1
C01-4-2
C01-4-3
C01-4-4
C02-3-1
C02-3-5
C02-3-2
C02-3-3
C02-3-6
C02-3-4
You can collect unique non-blank values from column A with an array formula e.g. =INDEX($A$2:$A$99,MATCH(0, IF(LEN($A$2:$A$99),COUNTIF(I$1:I1,$A$2:$A$99),1),0)). Since this returns #N/A where it has no more values to return from its column, you can pass control over to a similar formula that references another column with IFERROR.
To choose from your three columns of SCH Codes, you would need to stack this 3 deep. The formula in I2 is:
=IF(LEN(I1),IFERROR(INDEX($A$2:$A$99,MATCH(0, IF(LEN($A$2:$A$99),COUNTIF(I$1:I1,$A$2:$A$99),1),0)),IFERROR(INDEX($C$2:$C$99,MATCH(0, IF(LEN($C$2:$C$99),COUNTIF(I$1:I1,$C$2:$C$99),1),0)),IFERROR(INDEX($F$2:$F$99,MATCH(0, IF(LEN($F$2:$F$99),COUNTIF(I$1:I1,$F$2:$F$99),1),0)),""))),"")
This array formula requires Ctrl+Shift+Enter, not just Enter. Once entered correctly, it can be filled down to catch all possible values. I would fill down for at least three times as many rows as you have in order that the blanks would have a place if they were filled in at a later date.
In theory, you could stack this much deeper but for practical purposes, I wouldn't go much deeper than this. Array formulas eat up calculation resources at a logarithmic rate so the size of your data is going to be a key factor on whether this is a suitable solution.
One solution:
Copy and paste all values in column C below column A data. Highlight column A and go to Data>Remove duplicates then Data>Sort.
Related
I am trying to create a formula that gives me the average of the last 12 entries in a given dataset depending on the associated vector.
Let's make an example:
I have in column F2,G2,H2 and I2 dates, Company1, Company2 and Company3 respectively. Then from row3 to row 33 I have months dates starting from May 2016.
Date Company1 Company2 Company3
May-16 2,453,845
Jun-16 13,099,823
Jul-16 14,159,037
Aug-16 38,589,050 8,866,101
Sep-16 63,290,285 13,242,522
Oct-16 94,005,364 14,841,793
Nov-16 123,774,792 7,903,600 41,489,883
Dec-16 93,355,037 12,449,604 69,117,105
Jan-17 47,869,982 13,830,712 83,913,764
Feb-17 77,109,905 10,361,555 68,176,643
The goal is to create a formula that, when I drag it down, correctly calculates the average of the last 12 values for a given company.
So for example i would have, say in table "B2:C5":
Company1 76,856,345
Company2 11,120,859
Company3 65,674,349
And, if a new Company4 is added to the list, then I just have to drag it down the formula, to calculate the average of the last 12 months for Company4.
Until now, I have came up with this formula:
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(G:G),ROW(G:G)),ROW(INDIRECT("1:"&MIN(12,COUNT(G:G))))),ROW(G:G),G:G ))
This formula correctly calculates the average of a given column, considering only the last 12 values. The last step would be to come up with a formula that includes all the columns and then calculates the average for the given company.
Thanks!
I recommend that you use a named range to define your data in columns G:I. When a company is added, just modify the named range's specs. I used the name Target. Of course, you can replace it with $G:$I if you feel so inclined but I would rather recommend reducing the number of rows in the range, which is easier to manage when it is named.
Use the formula below to extract the company names from the first row of Target into the first column of your averages table. This is to ensure that the names are spelled identically in both locations.
=INDEX(Target,1,ROW()-2)
The number 2 indicates the number of rows above the row containing the formula. it is copied here from cell M3. There, ROW()-2 creates the number 1, counting sequentially as the formula is copied down.
Now I have the formula below in my cell N3 and copied down.
=SUM(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))
The formula simply sums up the columns G, H, and I in 3 consecutive rows.
In the final step I inserted the range definition established above, meaning excluding the SUM() function, into your existing formula.
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))),ROW(INDIRECT("1:"&MIN(12,COUNT(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))
I've got a table in excel with 10 rows and 10 columns.
The table contains 100 different values between 1 and 3.
I want to find the highest sum of 10 values using only 1 value from each row and 1 from each column.
Do u guys know a function that finds the highest sum? - I've tried to do i manually, but there are to many combinations!
Hope it makes sense.
Thanks in advance:)
My solution builds on what I wrote in the comment, i.e. you first take the maximum value in the 10x10 array, then the maximum in the 9x9 array (excluding the row/column of the first maximum), etc. My solution tries not to do everything in one formula, but I add a few helper columns, and a bit more helper rows (it is fast and dirty, but it works and is easily audited/understandable). You always can do this on a separate worksheet which you could hide if needed.
The screenshot above goes from cell A1 till Y31.
The key formulas:
3.55 is the result of =MAX(B2:K11)
The first gray cell is =IFNA(MATCH($M12;B2:B11;0);""), and you drag this 9 cells to the left. This tries to find a match with the max result in each column of the table;
The 10 left of the 3.55 is =MATCH(TRUE;INDEX(ISNUMBER(P12:Y12);0);0) , and gives the column number of the max value.
The 2 next to the 10 is =INDEX(P12:Y12;N12) and gives the row number of the max value.
The 1 in cell B12 is =IF(OR(B$1=$N12;$A12=$O12);0;1), and creates a 10x10 matrix with a row and column with zeroes where the previous max value was found.
Then you multiply this with the preceding matrix and create a new 10x10 matrix below (enter {=B2:K11*B12:K21} array formula (ctrl+shift+enter) in B22-K31
You then copy/paste rows 12 till 31 9 times below
The 23.02 is the total sum =SUM($M$12:$M$211) from all 10 maximum values and is the result you are looking for. The 10 is just a check with =COUNT($M$12:$M$211)
I have 7 columns to choose from and I need to pick 4 of those columns and generate a total for each row. I also need every combination of 4, which means I'll have 35 new columns with the totals for each of those combinations showing in each row. I need the code for this and if it can be done only using Excel. Here is an image of the columns and the grayed ones are the 7 columns I'm talking about. My knowledge of Excel is very limited. There are over 1,500 rows if that matters.
multi step approach that is going to use some helper rows. there may be a more elegant formula that will do this, and much slicker options in VBA, but this is a formula only approach.
Step 1 - Generate List of Column Combination
To generate the list 4 helper rows will need to be insert at the top of your data. either above or below you header row. These 4 rows will represent the column number you are going to pick. To keep the math simpler for me I just assumed the 1 for the first column and 7 for the last column. those numbers will get converted to later to account for column in between in your spreadsheet. For the sake of this example The first combination sum will occur in column AO and the first helper row will be row 1. The first combination will be hard coded and it will seed the pattern for the remainder of column combinations. Enter the following values in the corresponding cells:
AO1 = 1
AO2 = 2
AO3 = 3
AO4 = 4
In the adjacent column a formula will be placed and copied to the right. It will automatically augment the bottom value by 1 until it hits its maximum value at which point the value in the row above will increase by 1 and the the value of the current will be 1 more than the cell above. This will produce a pattern that covers all 35 combinations by the time column BW is reached. Place the formulas below in the appropriate cell and copy to the right:
AP1
=IF(AO2=5,AO1+1,AO1)
AP2
=IF(AO2=5,AP1+1,IF(AO3=6,AO2+1,AO2))
AP3
=IF(AO3=6,AP2+1,IF(AO4=7,AO3+1,AO3))
AP4
=IF(AO4=7,AP3+1,AO4+1)
Step2 - Sum The Appropriate Columns
I was hoping to use a some sort of array type operation to read through the column reference numbers above, but I could not get my head around it. Since it was just 4 entries to worry about I simply added each reference manually in a SUM function. Now the important thing to note is that we will be using the INDEX function over the 13 columns that cover the range of your columns so to convert the index number we figured out above, to something that will work to grab every second row, the number that was calculated will be multiplied by 2 and then 1 will be subtracted. That means 1,2,3,4 for the first column combination becomes 1,3,5,7. You can see this in the following formula. Place the following formula in the appropriate cell and copy down and to the right as needed.
AO5
=INDEX($AB5:$AN5,AO$1*2-1)+INDEX($AB5:$AN5,AO$2*2-1)+INDEX($AB5:$AN5,AO$3*2-1)+INDEX($AB5:$AN5,AO$4*2-1)
pay careful attention to the $ which will lock row or column reference and prevent them from changing as the formula is copied.
Now you may need to adjust the cell references to match your sheet.
Column A Has Text & Columns B, C & D contain numbers.
For Ex.)
A... …B C D
John 4 6 2
Dave 4 6 4
Mike 4 5 1
Bill 2 5 9
I would like a cell to return the name in column A that has the Largest Number in Column B. And if there are similar numbers, go to the next column and determine which is highest, and if that is tied go to the next column and so on.
Any help would be appreciated.
We can de-conflict ties.In E1 enter:
=B1 + C1/(10*MAX(C:C))+D1/(100*MAX(D:D))
and copy down. Then in another cell enter:
=INDEX(A:A,MATCH(MAX(E:E),E:E,0))
EDIT#1
This is only good for 3 columns of numbers, but it is very easy to add additional de-confliction terms if necessary:
=B1 + C1/(10*MAX(C:C))+D1/(100*MAX(D:D))+E1/(1000*MAX(E:E))
For an expandable number of rows/columns, use a helper row with the same number of columns as number columns in your data. The formulas below reference the following image (the data are in A1:G7):
B9-->=MAX(B1:B7)
C9 (fill over the remaining columns to G9)-->
=MAX(IF(MMULT(--($B1:B7=$B9:B9),--(ROW(INDIRECT("1:"&COLUMNS($B9:B9)))>0))=COLUMNS($B9:B9),C1:C7))
The following formula will give the answer (shown in A9 above):
=INDEX(A1:A7,MATCH(TRUE,(MMULT(--($B1:G7=$B9:G9),--(ROW(INDIRECT("1:"&COLUMNS($B9:G9)))>0))=COLUMNS($B9:G9)),0))
UPDATE WITH ALTERNATIVE METHOD
Using a helper column instead, again referencing the image below (the data are in A1:G7):
I1 (fill down to I7)-->
=SUM(--(MMULT(SIGN(B1:G1-$B$1:$G$7)*2^(COLUMN(G1)-COLUMN(A1:F1)),--(ROW(INDIRECT("1:"&COLUMNS(B1:G1)))>0))>0))
The following formula will give the answer (shown in J1 above):
=INDEX(A1:A7,MATCH(MAX(I1:I7),I1:I7,))
As a bonus, notice that the helper column corresponds to the order that you would get from sorting the data by each column left-to-right. In other words, you could use the helper column to perform a formula-based multi-column sort on strictly numeric data. For the last image, entering the following array formula into a range with the same dimensions as A1:G7 gives a descending sort on columns B through G:
=IF(A1:A7=A1:A7,INDEX(A1:G7,MATCH(ROW(A7)-ROW(A1:A7),I1:I7,0),))
Assume I have the following table:
A B C
1 Week 1 Week 2
2 Melissa 114.7 82.8
3 Mike 105.5 122.5
4 Andrew 102.3 87.5
5 Rich 105.3 65.2
The names are in column A, the Week values are in Row 1. (So A1 is blank, B1 = Week 1, and A2 = Melissa.)
I'm trying to build a formula that looks at all the values in a known range (in this example, B2:C5), chooses the highest value of the bunch (here, 122.5) and returns the name of the person from Column A that got that value. If I use this formula, it works for the values in range B2:B5:
=INDEX(A2:A5,MATCH(MAX(B2:B5),B2:B5,0))
That returns Melissa but if I expand the range to include more than just column B's values, I get an #N/A returned:
=INDEX(A2:A5,MATCH(MAX(B2:C5),B2:C5,0))
The weird part (to my simple brain) is that the MATCH portion of the formula works fine, if I just put in this formula, it returns the highest value of 122.5 from C3:
=MAX(B2:C5,B2:C5,0)
So clearly something it going wrong when I'm using either the MATCH or INDEX commands.
Hopefully this makes sense and someone can point out my error?
Try this:
=INDEX(A:A,MAX((B2:C5=MAX(B2:C5))*ROW(B2:C5)))
This is an array formula and must be confirmed with Ctrl+Shift+Enter.
Note: Match can only search one vector at a time. It can be one row or one column or one array. It cannot be two or more rows or columns or a 2D array.
Do it "twice"? Please try:
=INDEX(A2:A5,IFERROR(MATCH(MAX(B2:C5),B2:B5,0),MATCH(MAX(B2:C5),C2:C5,0)))
If you are going to have up to 52/53 weeks to cope with I'd suggest instead inserting a helper column with the MAX for each row. Make that an new (inserted) ColumnA (say =MAX(C2:BC2) etc.) and a simple VLOOKUP should serve, say:
=VLOOKUP(MAX(A:A),A:B,2,0)