I have many configuration files ,
the line that start with LINE word have IP address
My target to read the line that start with LINE word from the file and print only the IP address
The problem is that IP address can be in any field in the line so I can’t capture the IP according to field number
example
grep LINE file1.txt
LINE /home/Ariate/run.pl "Voda STS 4 Test - " "102841" && ssh 17.77.170.130 -p 2022
grep LINE file2.txt
LINE /home/Ariate/run.pl 137.77.170.30 "Voda STS 4 Test - " "102841" && ssh ACTIVE
please advice how to capture the IP address from the line ( solution can be also with perl one liner )
expected results
echo $IP_FROM_LINE
17.77.170.130
echo $IP_FROM_LINE
137.77.170.30
perl -MRegexp::Common=net -lne 'print $1 if /^LINE.*\b($RE{net}{IPv4})/'
Using this grep -oE:
grep -oE '\d+\.\d+\.\d+\.\d+' file
17.77.170.130
137.77.170.30
OR else:
grep -oP '\d+\.\d+\.\d+\.\d+' file
The following will get you the desired IP addresses:
grep -oP '^LINE.*\b\K\d+\.\d+\.\d+\.\d+' file
To place the result in a variable as request, you'll need to iterate of the results as follows:
grep -oP '^LINE.*\b\K\d+\.\d+\.\d+\.\d+' file |
while read IP_FROM_LINE ; do
echo $IP_FROM_LINE
done
grep -oE '[0-9]{2,3}(\.[0-9]{2,3}){3}'
matches
17.77.170.130
137.77.170.30
or
grep -oP '\d{2}(\.\d{2}){3}'
if your grep supports -P option.
both of them works with the data you have given.
But if you want really worried of what to be matched, use
grep -Eo '(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)'
which would match excat ip addresses.
Related
I have this file:
this is line 1 192.168.1.1
this is line 2 192.168.1.2
this is line 3 192.168.1.2
this is line 4 192.168.1.1
this is line 5 192.168.1.2
I would like to get, in a bash script, all lines (with tabs) which contains, for example, the pattern "192.168.1.1". By this way, I would get:
this is line 1 192.168.1.1
this is line 4 192.168.1.1
But i don't want this result:
this is line 1 192.168.1.1 this is line 4 192.168.1.1
I tried it with sed without success:
var='192.168.1.1'
body=`sed -n -e '/$var/p' $file`
echo $body
Thanks beforehand!
awk to the rescue!
$ awk -v var='192.168.1.1' '$NF==var' file
this is line 1 192.168.1.1
this is line 4 192.168.1.1
Following sed may help you on same.
var="your_ip"
sed -n "/$var/p" Input_file
Or in awk following will help on same.
var="your_ip"
awk -v var="$var" 'var==$NF' Input_file
A simple grep command could do that:
grep 192.168.1.1 filename
Or a more "complex" grep command could do that and write it to another file:
grep 192.168.1.1 filename > new_filename
Hope this helps!
Assuming the data format is well defined like you said:
"this is line <seq> <ip>"
you could do simply this:
cat file | egrep "192.168.0.1$"
I'm very new to linux and bash. I'm trying to find a domain name for an ip address. When I use nslookup I have a bunch of lines like this
nslookup 204.228.150.3
Output
Server: 198.60.22.2
Address: 198.60.22.2#53
Non-authoritative answer:
3.150.228.204.in-addr.arpa name = www.computerhope.com.
Authoritative answers can be found from:
150.228.204.in-addr.arpa nameserver = ns.xmission.com.
150.228.204.in-addr.arpa nameserver = ns1.xmission.com.
150.228.204.in-addr.arpa nameserver = ns2.xmission.com.
ns.xmission.com Internet address = 166.70.254.2
ns1.xmission.com Internet address = 204.228.159.2
ns2.xmission.com Internet address = 207.135.133.2
I only want to print www.computerhope.com in the second line. How do I do this?
Also I tried to use host command as well. It looks cleaner.
206.153.126.75.in-addr.arpa domain name pointer www.cyberciti.biz.
How do I only print www.cyberciti.biz when I use host command ?
PLease help
$ host 75.126.153.202 |sed -e 's/.* //'
www.cyberciti.biz.
nslookup 204.228.150.3 | \
grep "in-addr.arpa" | \
cut -d '=' -f 2 | \
tr -d '[:blank:]'
With grep you find the line containing the address. With the cut command you split the line by the "=" sign. With tr you remove any remaining spaces.
The command does not have any error handling in case the address is unknown.
If you would provide more information on what you want to achieve maybe other solutions would come up. :-)
Another way to do this is to pipe the host command to awk:
$ host 75.126.153.202 | awk '{print $NF}'
NF is a built-in awk variable which prints the last column of the output of the host command, which in this case is the domain name.
You can also pipe nslookup to awk:
$ nslookup 75.126.153.202 | awk '$2 ~ /^name$/{print $NF}'
awk returns the last column of the line containing the name in its 2nd column.
please advice how to match the following hostname
machine hostname Should be according to the following rule
<a-z word ><number><a-z character/s>
real example
star1a
linux25as
machine2b
linux5a
solaris300C
unix9c
please advice how to machine these hostname with grep
I have for now this syntax
hostname | grep -c '[a-z][1-2][a-z]'
but these syntax not work on all my examples
on solaris the option egrep -E not works
hostname | grep -E '\b[a-z]+[0-9][a-z]+'
grep: illegal option -- E
Usage: grep -hblcnsviw pattern file . . .
Broken Pipe
try the second option ( on solaris machine ):
hostname
swu2a
hostname | grep "^[a-z]\+[0-9][a-z]\+$"
not matched!!!
I also try this:
hostname
swu2a
hostname | grep '[a-z]\+[0-9]\+[a-zA-Z]\+'
NOT MATCHED!!!
Here is an awk using same regex as the grep posted here uses.
awk '/[a-z]+[0-9]+[a-zA-Z]+/'
star1a
linux25as
machine2b
linux5a
solaris300C
unix9c
If you need to make sure there is nothing else in the line, only the words above, use:
awk '/^[a-z]+[0-9]+[a-zA-Z]+$/'
^ marks start of line.
$ marks end of line.
You can use the following pattern:
grep '^[a-z]\+[0-9]\+[a-zA-Z]\+$'
Note that you can use the the return value of grep to decide whether the pattern matches or not, you don't need to use the -c option. Like this:
if [ hostname | grep '^[a-z]\+[0-9]\+[a-zA-Z]\+$' >/dev/null 2>&1 ] ; then
echo "host name OK"
fi
I was just wondering how I would go about writing a shell script to separate proxy IPs from their ports.
The proxies are stored in this format
ip:port
ip:port
ip:port
How can I use a shell script to separate the IP on the left side of the colon from the Port on the right side, and put the IP and Port lists in separate .txt files with the same order? Is this even possible?
If the proxies are listed that way in a file, say proxy.txt, then all you need is cut:
cut -f1 -d: proxy.txt > proxy_ip.txt
cut -f2 -d: proxy.txt > proxy_port.txt
Try something like this:
#!/bin/bash
ips="1.2.3.4:123 2.3.4.5:356 4.5.6.7:576"
# or get IPs from stdin
# split them
ips_array=($ips)
for w in ${ips_array[#]}
do
echo $w | sed -e 's/:.*$//g' >> ips.txt
echo $w | sed -e 's/^.*://g' >> ports.txt
done
Key is using the ($ips) to split the list up.
EDIT:
I just realized that you didn't format your question correctly so it's not a single line with IP:PORTs separated by spaces, but one on a line by itself. You just need this then:
#!/bin/bash
while read w
do
echo $w | sed -e 's/:.*$//g' >> ips.txt
echo $w | sed -e 's/^.*://g' >> ports.txt
done
And you read from stdin.
I am trying to write a script that uses a user-created MAC address when using the wlan0 interface.
To test, I made a file called testFile.txt, which is a copy of /etc/network/interfaces. If there are interfaces after wlan0, I cannot use echo "$var" >> testFile.txt because that simply adds the text to the end.
I am able to find the end of the wlan0 interface text, but I am not sure how to insert there. Below is what I currently have:
#!/bin/bash
echo "Enter MAC Address"
read var
log=$(cat testFile.txt | grep -o "wlan0.*" | grep -o dhcp)
echo $log
echo $log prints dhcp.
I tried adding | echo "hwaddress ether $var" >> testFile.txt to $log but that still appends to the end of the file.
How do I insert directly after $log?
The Problem
Useless use of cat. Don't do that.
You're not using the right tool for the job. Use GNU sed to make life easier on yourself.
The Solution
# Insert hwaddress line into /etc/network/interfaces.
read -p "Enter MAC Address: "
sudo sed -i.bak "/iface wlan0/a\ hwaddress $REPLY" /etc/network/interfaces
# Replace existing hwaddress line in /etc/network/interfaces.
read -p "Enter MAC Address: "
sudo sed -ri.bak "s/(hwaddress).*/\1 $REPLY/"
You may want to use sed to insert the MAC address. If you want to insert it at the end of the line with wlan0, that would be
sed "s/\(wlan0.*\)/\1 $var/" testFile.txt > testFile.txt.tmp
If that works, then
mv testFile.txt.tmp testFile.txt
you need a different tool, SED for example
$ seq 5 | sed '/3/ s/.*/something else/'
1
2
something else
4
5
for example you can Substitute the line with '3' by 'something else' - and there is no limits