There is view listing a certain number of documents having as view selection a form. A column ( Style = Date/Time displaying Time ) has the formula: time_1. The next column is displaying: time_2.
with other words:
time_1 - the time the user was at work.
time_2 - the time the user must be at work ( let's say 08:00 hours ).
There is a view action button:
t1:=#DbColumn("Notes":"NoCache";"server/Company":"Name.nsf";"vwSearchResult";6);
total1:= #Sum(#ToNumber(t1)) ;
t2:=#DbColumn("Notes":"NoCache";"server/Company":"Name.nsf";"vwSearchResult";7);
total2:= #Sum(#ToNumber(t2)) ;
zile:=(total1-total2)/8; // 8 - is the minimun number of hours / day. " I must be at work minimum 8 hours "
#Prompt([Ok];"Time at work";#Text(total1));
#Prompt([Ok];"expected time";#Text(total2));
#Prompt([Ok];"Additional time - in days ";#Text(zile))
Just the 2nd Prompt is calculated correctly. The 1st prompt result is an integer number, and of course, implicitly the 3rd prompt is not displaying the result correctly.
How can I achieve this?
Change your formula to
t1:=#DbColumn("Notes":"NoCache";"server/Company":"Name.nsf";"vwSearchResult";6);
total1:= #Sum(t1 - [00:00]) / 3600;
t2:=#DbColumn("Notes":"NoCache";"server/Company":"Name.nsf";"vwSearchResult";7);
total2:= #Sum(t2 - [00:00]) / 3600;
You can't convert a time value to a number with #ToNumber. Instead, calculate the difference between your time and 00:00. This gives you the number of seconds of your time.
Divide this by 3600 and you get the hours.
I think its better to insert a column to the view which calculates the difference between time_1 and time_2.
Your #DbColum will now run on the new column ans calculates the difference.
Related
I'm looking for a function I can use that returns "Night Off Prime" if the time a programme was on was between 11pm - 5:59am, "Day Off Prime" if it was on between 6am - 5:59pm and "Prime" if it was on between 6pm - 10:59pm.
I've tried using the IFS function with the code being =IFS(OR(G3>=23,G3<6),"Night Off Prime", OR(G3>=6,G3<18),"Day Off Prime", OR(G3>=18,G3,23),"Prime")
The G column is just the hh format of the hour it was on, with the values formatted as Number.
I've also tried =IFS(OR(BK3>=23:00,BK3<06:00),"Night Off Prime", OR(BK3>=06:00,G3<18:00),"Day Off Prime", OR(BK3>=18:00,BK3,23:00),"Prime")
Here the BK column is the time the programme was on in the hh:mm time format
The main trouble I'm finding there is how to label time between two different times such as between 11pm - 5:59am instead of just past 11pm. I used the OR logical but that doesn't seem to have worked.
I've also tried a VLOOKUP function =VLOOKUP(BK2,$AC$899:$AD$901,2, TRUE)
Here the table array is
AC899 Night Off Prime AD899 23:00-05:59
AC900 Day Off Prime AD900 06:00-17:59
AC901 Prime AD901 18:00-22:59
If you prefer the IFS you may want to adjust like this (should work in the similar way for hh:mm as well):
=IFS(G3<6;"Night Off Prime";G3<18;"Day Off Prime";G3<23;"Prime";TRUE;"Night Off Prime")
(may replace ; with , depending on regional setting)
alternatively:
=IFS(G3<0;"#N/A";G3<6;"Night Off Prime";G3<18;"Day Off Prime";G3<23;"Prime";G3<24;"Night Off Prime";TRUE;"#N/A")
"The main trouble I'm finding there is how to label time between two different times such as between 11pm - 5:59am instead of just past 11pm."
Add a column H2 = G2 + 1/24
Then your ranges are 0 to 7/24, 7/24 to 19/24 and 19/24 to 24/24, so you don't have an interval split over a resetting of the clock to zero.
I have a dataset which is amount (parts per million) against time (every minute)
I need to find the peak for each day, so that I can plot that against other data, I can manually do this using =MAX( but I have a lot of data points and I am sure there is a better way
Many Thanks for the help
I don't know where and how you want show this data, but, if you want get a max value amount per day, you can try add an array formula, like that:
=MAX(IF($COL_DATES = $DAY, $COL_VALUE, 0))
Replace $COL_DATES to your column of day date, replace $DAY to value of day what you want get max value and replace $COL_VALUE to your column of values.
After press CTRL + SHIFT + Enter
I managed to get in Excel desired % of time difference from column E, easy job just changed the Data Type to Percentage. What are we calculating is % of these TimeDifferences, one per one (other columns inconsiderable).
The same thing isn't in PowerBI, where I am not able to calculate it properly, always getting "1" before comma and then the result - you can compare it in both tables/columns what I am talking about.
I am looking for the way/DAX/measure how to properly calculate it, no matter in decimals or directly to percentage, as long as the % is the same as in Excel column. Any ideas?
P.S Left is Excel and right is PowerBI!
Seems Excel is basing the percentage on 24 hours, this I used in the calculation (24 hours = 24 * 3600 seconds).
I started combining in power query the date and the time, this has to do with the fact that you go over the day and your calculation still needs to be correct.
Go to query editor. select both columns, combine them. Next change the type to Date/Time, result:
Save and close editor.
In Power Bi, add a column:
NextDate = LOOKUPVALUE(Explog[Date];Explog[Index];Explog[Index] + 1)
This is picking up the next Date based on Index + 1
Add another column TimeDiffSec, calculating the datediff in seconds:
TimeDiffSec = DATEDIFF(Explog[Date];Explog[NextDate];SECOND)
Last step is adding a column for percentage:
% of time difference =
var perc = Explog[TimeDiffSec]/ (24*3600)
return if(perc >= 1; perc - 1; perc)
End result:
Note: If you have a situation you do not want to mix the System (STYRAX - scrubber) you can use the following for the NextDate:
NextDate =
var nextIndex =
CALCULATE(MIN(Explog[Index]);
FILTER(Explog;Explog[Index] > EARLIER(Explog[Index]) && Explog[System] = EARLIER(Explog[System])))
return
LOOKUPVALUE(Explog[Date];Explog[Index];nextIndex; Explog[System];Explog[System])
I'm trying to convert a large time value in excel to a decimal number for hours.
I currently have a column adding up "Ready time" for a call centre which is 3545:20:02 as a SUM. I now want that to show me the same hours in a decimal format e.g. 3545.333 as it's used in another calculation.
For reference, when I convert the above time to a General excel value, it is 147.7222454.
The formula I've been using is: =IFERROR((DAY(M54)*24) + HOUR(M54) + (MINUTE(M54)/60),0) and has been working fine for smaller time values.
Thanks in advance!
Excel counts in days (1 day = 1) so for hours you just multiply by 24, i.e.
=M54*24
format result cell as number with required number of decimals
[the reason your current formula fails is because of DAY function - DAY is day of the month so it fails for you when the time value is >= 32*24 = 768 hours]
I have an Excel 2010 workbook which contains a cell with the value of, say, 9876:54:32 (manually entered) representing 9876 hours, 54 minutes and 32 seconds of, say, phone talk time.
Then I have a cell with the value of, say, 1000 (manually entered) representing 1000 calls.
I want to divide the values to get the average talk time of 592.615 minutes per call.
I'm doing a regular =A1/B1 and it gives me an error.
* EDITED *
Thanks Brain Webster for correcting my math. I mean 9.876 hours. But the point is that Excel gives me an error, not my manual math. Playing around with it I discovered that Excel is fine with me with values up to 9999:59:59. Once I try with 10000:00:00 and up, it doesn't recognize it as a time value.
I love these seemingly easy riddles, so here is my solution as a formula and as a VBA attempt:
my original:
= (LINKS(A38;FINDEN(":";A38)-1)/24)+ZEITWERT("0"&RECHTS(A38;LÄNGE(A38)-FINDEN(":";A38)+1))
translated:
= (LEFT(A38,FIND(":",A38)-1)/24)+TIMEVALUE("0"&RIGHT(A38,LEN(A38)-FIND(":",A38)+1))
This will get you the right value to a given 10k text of a time duration. You would only have to setup the format of the cell to [h]:mm:ss. Then those values will look the same, but one would be a string and the other a number - and that is a major difference ;)
In vba it looks much more easier, and once defined, you can use it as a worksheetfunction.
Public Function GetDurationValue(ByVal strInput As String) As Double
Dim arrResult As Variant
arrResult = Split(strInput, ":") 'saves you parsing
GetDurationValue = (arrResult(0) / 24) + _
TimeSerial(0, arrResult(1), arrResult(2))
End Function
A38 = "10971:12:14"
=GetDurationValue(A38)
=457.13349537037
You can use LEFT and RIGHT function to retreive parts of the time value and then sum and multiply these values by 60 [minutes] (resp. 3600 [hours]).
Something like this for the hours, minutes, seconds (A1 is the cell with time value):
B1=VALUE(LEFT(A1;FIND(":";A1)))*3600
B2=VALUE(LEFT(A1;FIND(":";A1; FIND(":";A1))))*60
B3=VALUE(LEFT(A1;FIND(":";A1; FIND(":";A1; FIND(":";A1)))))
Now you can sum that:
C1=SUM(B1;B2;B3)
Then divede by calls count (A2 is the cell with the calls count):
D1=C1/A2
Finally format it like time:
E1=TEXT(D1/(24*3600);"d \day\s hh:mm:ss")
BTW: I tried that in Excel 2013 and when I enter 111:22:33 into a cell it automatically converts to a time. So then I can divide it like you try...
It appears that hours > 10000 are not recognised as such by Excel. Therefore we need to introduce an IF() to see whether this is the case and determined the alternative formula for the case where hours >10000
=IF(ISERROR(FIND(":",A2)),A2/B2, <SCRIPT IN CASE OF >10000>)
<SCRIPT IN CASE OF >10000> will now be:
VALUE(LEFT(A2,FIND(":",A2)))/24+VALUE(LEFT(A2,FIND(":",A2, FIND(":",A2))))/(24*60)+VALUE(LEFT(A2,FIND(":",A2, FIND(":",A2,FIND(":",A2)))))*(24*60*60)
combine and enjoy!
Assuming you don't exceed 100,000 hours in A1, and you always display hours, minutes and seconds then this formula should suffice
=IFERROR(A1/B1,(LEFT(A1)*10000/24+RIGHT(A1,10))/B1)
format result cell as [h]:mm:ss to get the result as a time value
With 10971:12:14 in A1 and 1000 in B1 that should give a result of 10:58:16 [or format result cell as [m]:ss to get minutes and seconds like 658:16]
This version will work with any number of hours and with or without seconds
=IFERROR(A1/B1,(LEFT(A1,FIND(":",A1)-1)/24+RIGHT(A1&IF(COUNTIF(A1,":*:"),"",":00"),5)/60)/B1)