I am an occasional Excel user and stuck how to create a dynamic range.
After looking up a text in a table, how can I calculate the range next to this cell, up to the next empty row? Not using VBA.
Thanks for your help.
In H4, formula copied down :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):C$1000,MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):B$1000,0)),"")
Should you want a dynamic range,
Change C$1000 to INDEX(C:C,MATCH(9.9E+307,B:B)
and
Change B$1000 to INDEX(B:B,MATCH(9.9E+307,B:B))
Then
The H4 copied down formula become :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):INDEX(C:C,MATCH(9.9E+307,B:B)),MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):INDEX(B:B,MATCH(9.9E+307,B:B)),0)),"")
Edit :
As per Ron Rosenfeld's comment, "should B11 change to 24 and G4 change to 24"
The "Source Table" set up in Excel Table type for dynamic range growing purpose
and
The H4 formula change to :
=IFERROR(LOOKUP(9^9,Table1[price]/(LOOKUP(ROW(Table1[texture]),ROW(Table1[texture])/(Table1[texture]<>""),Table1[texture])=F4)/(Table1[length]=G4)),"")
Combining the Index() and Match() functions usually works well when using two conditions. However, you will need to fill out the entire column A with the "texture" list in order for the below formula to work.
=INDEX(<P1>, MATCH(TRUE, (<T1>=<T2>) + (<L1>=<L2>) > 1,0))
Where <P1> is your entire price column (ex. C2:C15)
Where <T1> is your entire texture column (ex. A2:A15)
Where <T2> is your texture lookup value cell
Where <L1> is your entire length column (ex. B2:B15)
Where <L2> is your length lookup value cell
Let's say that you input your texture value into cell F3, and your length value into cell F4. With the remaining columns remaining as they are in your image, you would use the following formula:
=INDEX(C2:C15, MATCH(TRUE, (A2:A15=F3) + (B2:B15=F4) > 1,0))
Now last time I had to use Index/Match I thought I had to place the formula into an array. However, the above seems to work without it.
If you notice that it's not working as expected, you can place into an array formula by clicking the cell that contains the formula, then clicking the formula box at the top. While in the formula box, simultaneously press Ctrl + Shift + Return. This should then place curly brackets around your entire formula if done properly, as such:
If you have O365 with the SEQUENCE function, you can use, for price:
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2}),2,FALSE))
explanation:
get starting row:
MATCH(F4,$A:$A,0)
ending row will be the first blank row after the starting row:
MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)
Construct the relevant array:
INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2})
The above might reduce (with wavy) to:
index(b:c,{9,10,11},{1,2}
Then it's just a matter of applying the VLOOKUP
A more understandable, but longer with more operations, formula available in O365 makes use of LET. The advantage is that one can use names which indicate what each section of the formula does.
For example:
=IF(G4="","",LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,
arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),price,XLOOKUP(G4,INDEX(arr,0,1),INDEX(arr,0,2)),price))
Or, using VLOOKUP
=IF(G4="","",VLOOKUP(G4,LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),arr),2,FALSE))
Finally, for earlier versions of Excel, you can use this whopper where we replace the SEQUENCE function with a construct like: ROW(INDEX(A:A,firstRow):INDEX(A:A,lastRow))
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,ROW(INDEX($A:$A,MATCH(F4,$A:$A,0)):INDEX($A:$A,MATCH(F4,$A:$A,0)+MATCH(TRUE,INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX($B:$B,ROWS($B:$B))="",0)-2)),{1,2}),2,FALSE))
How do I find either the cell address or preferably the row and column of the value 119, or any other number in the table below?
The table does not contain row or column titles, only the numbers as shown.
I am looking for a worksheet solution (formula) and not a VBA solution.
An Array Formula
This is an array formula and it has to be entered with control shift enter i.e. hold control shift and then press enter.
=MAX(IF(A1:J34=119,ROW(A1:J34)-ROW(A1)+1))
Remarks:
The value is searched by column i.e. A1, A2, ... B1, B2 ... i.e. if you had another 119 in cell D1 the result would still be 2, and if you had a 119 in cell c1 then the result would be
1.
For a column version just replace ROW with COLUMN:
=MAX(IF(A1:J34=119,COLUMN(A1:J34)-COLUMN(A1)+1))
Well, clunky and you can expand it, but it does work:
Row is separate to column but you could put them together in one cell, does depend on how you want to use the results, but you did not specify that so I have done this...
You could use a choose() function or a lookup table with vlookup() to change the column result to a letter...
Please try:
=MOD((K1-50),34)+1&" | "&1+(INT((K1-50)/34))
where K1 is your selected value.
Returns R | C. (Data in A1:J34 is not required.)
Below is a general purpose answer based on VBasic2008's answer.
I modified the formulas to utilize defined names so that the cell references do not have to be hard coded in the formulas. This way both the data table and row / column formulas can be relocated to anywhere on the spreadsheet. It works for both numerical AND text based data.
I also included the =ADDRESS() function to return the absolute reference of the look up value.
For illustration purposes, a step by step example for Data Set 1 is shown replacing the hard coded cell references with defined names.
The Data Set 2 section is the simplified version just using one defined for each the row and column look up value.
You can download an example spreadsheet here: Look_Up_a_Value_in_a_Table.xls
Thanks to all of you: Solar Mike, VBasic2008, and pnuts
Click on the image to enlarge.
My question is related to a question asked earlier, but as I am a new member I was not able to comment on that question.
The earlier question asked how we can dedupe a list in a workbook to create a new list of unique values on another sheet in the same workbook. The top voted solution given by #achaudhr works for me but in that I need to specify the exact cells the formula needs to reference. In the comments on that answer #Dan has mentioned that we must use OFFSET if we are referring to a dynamic range.
This is the formula I am using at the moment:
B2=INDEX($A$2:$A$20, MATCH(0, COUNTIF($B$1:B1, $A$2:$A$20), 0))
I have tried using offset with this formula but I guess I am doing something wrong because it keeps giving me #N/A as a result.
If my data was in column A (as per the above formula), I want to be able to change the ":$A$20" part of the range dynamically. The list in column A changes as per an input I put in the workbook on another sheet (let's call it Sheet 3). Hence I cannot hardcode the cells in the index formula range or else I have to change this range every time my list updates.
Based on the above layout, the cell in E2 calculates the max cell number for the list in column A on sheet 1. This number changes when the input in Sheet 3 changes.
I edited the above formula to use OFFSET to reference E2 in the following way:
B2=INDEX(OFFSET('Sheet 1'!$A$1,'Sheet 1'!$E$2,0), MATCH(0, COUNTIF($B$1:B1, OFFSET('Sheet 1'!$A$1,'Sheet 1'!$E$2,0)), 0))
This formula is returning #N/A (and I did press Ctrl + Shift + Enter so its not because of that).
I hope the group here can help me solve this. Look forward to the inputs and thanks for all your help.
Thanks,
Neha
The way to use OFFSET in a dynamic range determining formula, where it is column length that varies, is to use that value as the [height] parameter.
So, in the case of your example, the formula would look like:
B2: =IFERROR(INDEX(OFFSET($A$1,1,0,$E$2-1), MATCH(0, COUNTIF($B$1:B1, OFFSET($A$1,1,0,$E$2-1)), 0)),"")
Reference: $A$1 (could also set this at $A$2 with a 0 Row offset
Row Offset: 1 (since A1 contains the header)
Column Offset: 0
[height]: Contents of $E$2 minus 1 (since we are not including the header in the list)
[width]: left blank
I have the following formula
=IFERROR(IF(FIND(OFFSET($B$2,1,0),$A3,1),VLOOKUP(OFFSET($B$2,1,0),'Keyword list'!B2:E316533,2,FALSE),""),"n/a")
which looks up a value associated with a word if the word is found and otherwise returns "n/a". I have included the OFFSET() function with the hope of making it so that when I move the formula to another column, say from column B to column C, the reference is not still $B$2, and not C2, but B3. Effectively I am trying to make it so that when the formula is dragged across the reference row changes instead of the column, and when I drag down the reference remains fixed at $B$2, $B$3 and so on. Is it possible to use the offset function to do this? Is there a clear mistake I've made in trying to apply it to the above formula? Thanks!
You could maybe try the following?
=IFERROR(IF(FIND(OFFSET($B$2,COLUMNS($A:A)-1,0),$A3,1),
VLOOKUP(OFFSET($B$2,COLUMNS($A:A)-1,0),'Keyword list'!$B$2:$E$31,2,FALSE),""),
"n/a")
I made a google spreadsheet so that you can try to drag the formula across.
The limitation of that formula is that it will rely on the column of the formula, and it cannot be dragged towards the left in Excel, since that will cause the reference COLUMNS($A:A) to go COLUMNS(#REF!). It can be put in any column then dragged to the right.
This is untested, but I think it does what you want, i.e., shift the reference down one row, for each column you drag to the right. It uses the COLUMNS function anchored at B in one half and relative in another:
=IFERROR(IF(FIND(OFFSET($B$2,COLUMNS($B:B),1),$A3,1),VLOOKUP(OFFSET($B$2,COLUMNS($B:B),1),'Keyword list'!B2:E316533,2,FALSE),""),"n/a")
I'd go with using INDIRECT to build a reference out of a computed string.
INDIRECT("B"&(2+COLUMN(<current cell>)-COLUMN($B$1)))
This way your reference gets calculated dependent from the offset to column B:
In cell D2 the referenced cell is "B"&(2+COLUMN(D2)-COLUMN($B$1)) = "B"&(2+4-2) = "B4"
In cell D3 the reference does not change, as only columns are taken into account.
Same for cell E2: "B"&(2+COLUMN(E2)-COLUMN($B$1)) = "B"&(2+5-2) = "B5"
If your calculation is that fixed, you could even only do with COLUMN(E2) as 2 and COLUMN(B1) cancel each other out: INDIRECT("B"&COLUMN(<current cell>)))
I have this formula in Excel, in row E5:
=SUM(Banco!H$5;Banco!H$6;Banco!H$8;Banco!H$9;Banco!H$10;Banco!H$11)
I need it to change the COLUMN references instead of ROWS when I drag it down (basically behave like I was dragging it across)... For example:
=SUM(Banco!I$5;Banco!I$6;Banco!I$8;Banco!I$9;Banco!I$10;Banco!I$11)
=SUM(Banco!J$5;Banco!J$6;Banco!J$8;Banco!J$9;Banco!J$10;Banco!J$11)
=SUM(Banco!K$5;Banco!K$6;Banco!K$8;Banco!K$9;Banco!K$10;Banco!K$11)
Any clues?
Thanks a lot!
... Use the offset function.
For example - Suppose you had a formula in row 1 and you wanted to reference Banco!H5, you could do something like:
=OFFSET(Banco!$G$5,0,ROW())
Now, as you drag it down, it will offset by the number of rows down you go.
So your new formula would look as follows:
=SUM(OFFSET(Banco!$G$5,0,ROW()),OFFSET(Banco!$G$6,0,ROW()),OFFSET(Banco!$G$8,0,ROW()),OFFSET(Banco!$G$9,0,ROW()),OFFSET(Banco!$G$10,0,ROW()),OFFSET(Banco!$G$11,0,ROW()))
Again, this assumes you are pasting this formula in row 1 (I know it's ugly, but you specified specific cells, so you have to specify each one separately)
Hope this makes sense
Use a combination of the OFFSET and the COUNTA function. The OFFSET function will give the offset of COUNTA columns each time you go down a row. Make the counta function count the number of rows above the row that you're dragging the entire function into (aka each time you drag the function to an extra row, it will add 1)