How do I use command zip so that i can compress specific files and other files that start with "red". They're all in the same directory
I'm trying zip myfiles bookyhs.txt sholah.txt ^"red"
having problems with the last part of the code
You need to use glob pattern instead of regex pattern to match all files starting with red in current directory:
zip myfiles bookyhs.txt sholah.txt red*
Related
I have been using to zip up some icon files.
But for a project I needed to rename some .png files to filenames using only spaces and no extension.
zip -u icons.zip *.*
But now it does not zip those files?
Any fix?
Matches any number of characters. You can use the asterisk (*) anywhere in a character string.
zip -u icons.zip *
I have a folder /home/user/Document/filepath where I have three files namely file1-1.1.0.txt, file2-1.1.1.txt, file3-1.1.2.txt
and another folder named /home/user/Document/backuppath where I have to move files from /home/user/Document/folderpath which has file1-1.0.0.txt, file2-1.0.1.txt and file3-1.0.2.txt
task is to copy the specific files from folder path to backup path.
To summarize:
the below is the files.txt where I listed the files which has to be copied:
file1-*.txt
file2-*.txt
The below is the move.sh script that execute the movements
for file in `cat files.txt`; do cp "/home/user/Document/folderpath/$file" "/home/user/Documents/backuppath/" ; done
for the above script I am getting the error like
cp: cannot stat '/home/user/Document/folderpath/file1-*.txt': No such file or directory found
cp: cannot stat '/home/user/Document/folderpath/file2-*.txt': No such file or directory found
what I would like to accomplish is that I would like to use the script to copy specific files using * in the place of version numbers., since the version number may vary in the future.
You have wildcard characters in your files.txt. In your cp command, you are using quotes. These quotes prevent the wildcards to be expanded, as you can clearly see from the error message.
One obvious possibility is to not use quotes:
cp /home/user/Document/folderpath/$file /home/user/Documents/backuppath/
Or not use a loop at all:
cp $(<files.txt) /home/user/Documents/backuppath/
However, this would of course break if one line in your files.txt is a filename pattern which contains white spaces. Therefore, I would recommend a second loop over the expanded pattern:
while read file # Puts the next line into 'file'
do
for f in $file # This expands the pattern in 'file'
do
cp "/home/user/Document/folderpath/$f" /home/user/Documents/backuppath
done
done < files.txt
I have this structure:
release/folder1/file1
release/folder2/file2
...
release/folderN/fileN
I want to include all those folders (folder1, folder2 ... folderN) in a tar file.
The key is that I want these folders to be in the final tar within another directory named MYAPP so when you open the tar you can see this:
MYAPP/folder1/file1
MYAPP/folder2/file2
...
MYAPP/folderN/fileN
How can I achieve this without renaming the original "release" directory and/or creating new directories.
Is this possible to achive just in the tar process?
Thanks
Add
--transform=s#^release/#MYAPP/#
to your tar command line.
The argument of the --transform command line is a command that is passed to sed together with the file path before it is stored in the archive (use tar -tf to show the names of the files stored in the archive).
The command s#^release/#MYAPP/# tells sed to search (s) release/ at the beginning of the string (^) and replace it with MYAPP/.
The / at the end of the search and replace strings is needed to be sure the complete name of the component is release (to not replace release.txt). The # character is just a regex delimiter. Usually / is used as a regex delimiter but we prefer to use a different delimiter here to avoid the need to escape / (because it is used in the search and replace strings).
Read more in the documentation of tar and sed.
Ok so I kinda dropped the ball. I was trying to understand how things work. I had a few html files on my computer that I was trying to rename as txt files. This was strictly a learning exercise. Following the instructions I found here using this code:
for file in *.html
do
mv "$file" "${file%.html}.txt"
done
produced this error:
mv: rename *.html to *.txt: No such file or directory
Long story short I ended up going rogue and renaming the html files, as well as a lot of other non html files as txt files. So now I have files labeled like
my_movie.mp4.txt
my_song.mp3.txt
my_file.txt.txt
This may be a really dumb question but.. Is there a way to check if a file has two extensions and if yes remove the last one? Or any other way to undo this mess?
EDIT
Doing this find . -name "*.*.txt" -exec echo {} \; | cat -b seems to tell me what was changed and where it is located. The cat -b part is not necessary but I like it. This still doesn't fix what I broke though.
I'm not sure if terminal can check for extensions "twice", but you can check for . in every name an if there's more than one occurence of ., then your file has more extensions. Then you can cut the extension off with finding first occurence of . in a string when going backwards... or last one if checking characters in string in a normal way.
I have a faster option for you if you can use python. You can strip the extension with:
for file in list_of_files:
os.rename(file,os.path.splitext(file)[0])
which can give you from your file.txt.txt your file.txt
Example:
You wrote that your command tells you what has changed, so just take those changed files and dump them into a file(path to file per line). Then you can easily run this:
with open('<path to list>') as f:
list_of_files = f.readlines()
for file in list_of_files:
os.rename(file.strip('\n'), os.path.splitext(file.strip('\n'))[0])
If not, then you'd need to get the list from python:
import os
results = []
for root, folder, filenames in os.walk(<your path to folder>):
for filename in filenames:
if filename.endswith('.txt.txt'):
results.append(os.path.join(root, filename))
With this you got a list of files ending with .txt.txt like this <your folder>\\<path_to_file>.
Get a path to your directory used in os.walk() without folder's name(it's already in list) so it'll be like this:
e.g. os.walk('/home/me/directory') -> path='/home/me/' and res is item already in a list, which looks like directory/...
for res in results:
path = '' # set the path here
file = os.path.join(path,r)
os.rename(file, os.path.splitext(file)[0])
Depending on what files you want to find change .txt.txt in if filename.endswith('...') to whatever you like and os.rename() will take file's name without extension which in your case means it strips the additional extension you don't want to have.
How to shorten the length of the path on the one folder in Matlab?
i.e. I want one directory up.
For example I have 'C:/mydir/folder1/folder2' I want 'C:/mydir/folder1'
If you have the folder path in a string, you can use the function fileparts:
currentFolder = pwd;
parentFolder = fileparts(currentFolder);
Note that this won't work if the folder path string ends in a file separator character (i.e. '/' or '\').
If you simply want to change to the parent directory of the current working directory, use cd:
cd ..
% or
cd('..')
We could also use Java builtin functions:
char(java.io.File(pwd).getParent())
also the Apache Commons IO library that ships with MATLAB:
char(org.apache.commons.io.FilenameUtils.getFullPath(pwd))