GET /easyrtc/easyrtc.js 404 on express js 4 - node.js

Question

i have a 404 problem with EasyRTC on Express.js 4.
The console said : GET /easyrtc/easyrtc.js 404 4.500 ms - 1077
and here's my app.js code :
var express = require('express');
var path = require('path');
var favicon = require('serve-favicon');
var logger = require('morgan');
var cookieParser = require('cookie-parser');
var bodyParser = require('body-parser');
var io = require('socket.io');
var easyrtc = require('easyrtc');
var routes = require('./routes/index');
var users = require('./routes/users');
var staticMiddleware = express.static(__dirname + "/public");
var app = express();
// view engine setup
app.set('views', path.join(__dirname, 'views'));
app.set('view engine', 'ejs');
// uncomment after placing your favicon in /public
//app.use(favicon(__dirname + '/public/favicon.ico'));
app.use(logger('dev'));
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({ extended: false }));
app.use(cookieParser());
app.use(express.static(path.join(__dirname, 'public')));
app.use('/', routes);
app.use('/users', users);
app.get('/easyrtc/*', function (req,res) {
res.sendFile(__dirname + '/static');
})
// catch 404 and forward to error handler
app.use(function(req, res, next) {
var err = new Error('Not Found');
err.status = 404;
next(err);
});
// error handlers
// development error handler
// will print stacktrace
if (app.get('env') === 'development') {
app.use(function(err, req, res, next) {
res.status(err.status || 500);
res.render('error', {
message: err.message,
error: err
});
});
}
// production error handler
// no stacktraces leaked to user
app.use(function(err, req, res, next) {
res.status(err.status || 500);
res.render('error', {
message: err.message,
error: {}
});
});
app.set('port', process.env.PORT || 3000);
var server = app.listen(app.get('port'), function() {
console.log('Express server listening on port ' + server.address().port);
});
var webSockets = io.listen(server);
var rtc = easyrtc.listen(app, webSockets);
please help me, i've been searching for the solution all of this time and i couldnt find the solution at all. thanks before
NB : i'm generate express.js project from Terminal in linux , using command : express -e

Answer 1

Well, you may just to remove the code below:
app.use(function(req, res, next) {
var err = new Error('Not Found');
err.status = 404;
next(err);
});