In my spreadsheet I have the following in cells A5:C12:
ABC 4 B
ABC 5 B
ABC 5 B
ABC 5 C
CBS 4 B
CBS 5 B
CBS 3 C
NBC 4 B
I am trying to see the number of unique occurrence of a “5 B”. Here, there are 3 times a 5 and B appear: in ABC twice and in CBS once. Thus I would like 2 returned, since there are 2 companies (ABC and CBS) that have 5 and B.
I tried =COUNTIFS(B5:B12,5,C5:C12,"B"), but this returned “3” and couldn’t distinguish between the two ABCs.
The formula =SUMPRODUCT(IFERROR((C5:C12="B")/COUNTIFS(A5:A12,A5:A12,C5:C12,"B"),0)) returns “3”, telling us there are 3 unique “B”s.
The formula =SUMPRODUCT(IFERROR((B5:B12=5)/COUNTIFS(A5:A12,A5:A12,B5:B12,5),0)) returns “2”, telling us there are 2 unique “5”s.
Is there a way to somehow combine the above two formulas (or any other way) to see the number of unique “5B”s?
UNTESTED
=SUM(IF(FREQUENCY(IF(B5:B12&C5:C12="5b",IF(A5:A12<>"",MATCH(A5:A12,A5:A12,0))),ROW(A5:A12)-ROW(A5)+1),1))
entered as an array formula (adapted from Barry Houdini).
Related
e.g. I have a list of race results:
A B C D E F...
NAME P. RACE1 RACE2 RACE
abc =? 1 3 3
bcd 3 2 4
cde 4 4 2
def 2 1 1
and another sheet with points for each result:
A B
PLACE POINT
1 10
2 5
3 2
4 1
Is it possible to get the total points in sheet1 column B based on the race results in column C-E..?
Is it a connection from VLOOKUP and SUM?
Yes, that's possible. You can use a SUMPRODUCT formula for that. You may use this one in column B:
=SUMPRODUCT((C2:E2=$A$13:$A$16)*$B$13:$B$16)
Your result will look like this:
This is an array function. The term C2:E2=$A$13:$A$16 will check for race 1 to 3 if it was 1st, 2nd, 3rd or 4th place. This will result in an "imaginary" array of TRUE and FALSE. For name "abc", it will look like that.
Those results are then multiplied with the points from B13:B16 and the sum is formed.
In Excel O365, one could use:
Formula in B2:
=SUM(VLOOKUP(C2:E2,H$2:I$5,2))
I have strings of spreadsheet data that need counting by 'type' but not instance.
A B C D
1 Lin 1 2 1
2 Tom 1 4 2
3 Sue 3 1 4
The correct sum of students assigned to teacher 1 is 3, not 4. That teacher 1 meets Lin in lessons B and D is irrelevant to the count.
I borrowed a formula which works in Excel but not in Google Sheets where I and others need to keep and manipulate the data.
F5=SUMPRODUCT(SIGN(COUNTIF(OFFSET(B$2:D$2, ROW($2:$4)-1, 0), E5)))
A B C D E
2 Lin 1 2 1
3 Tom 1 4 2
4 Sue 3 1 4
5 1 [exact string being searched for, ie a teacher name]
I don't know what is not being understood by Google Sheets in that formula. Does anyone know the correct expression to use, or a more efficient way to get the accurate count I need, without duplicates within rows inflating the count?
So this is the mmult way, which works by finding the row totals of students assigned to teacher 1 etc., then seeing how many of the totals are greater than 0.
=ArrayFormula(sum(--(mmult(n(B2:D4=E5),transpose(column(B2:D4)))>0)))
or
=ArrayFormula(sum(sign(mmult(n(B2:D4=E5),transpose(column(B2:D4))))))
Also works in Excel if entered as an array formula without the ArrayFormula wrapper.
A specific Google Sheets one can be quite short
=ArrayFormula(COUNTUNIQUE((B2:D4=E5)*row(B2:D4)))-1
counting the unique rows containing a match.
Note - I am subtracting 1 in the last formula above because I am assuming there is at least one zero (non-match) which should be ignored. This would fail in the extreme case where all students in all classes are assigned to the same teacher so you have a matrix (e.g.) of all 1's. This would be more theoretically correct:
=ArrayFormula(COUNTUNIQUE(if(B2:D4=E5,row(B2:D4),"")))
I was wondering if there was a way to count the number of values by category. Example:
A 3
A 3
A 3
B 4
B 4
B 4
B 4
C 5
C 5
C 5
C 5
C 5
D 2
D 2
What is happening there is that there are 5 categories "A, B, C, D" and there are different counts of it. Duplicate values. I would like to create a new column and output the number of times it occurs in a different column as shown above. Please no VBA as i don't know it.
Try this...
=IF(A2<>A1,COUNTIF(A:A,A2),"")
If two households share, they create a tie and this tie has a kinship rank that does not change, no matter how often two households share with each other.
KINSHIP RANK EXAMPLE
As you can see, it doesn't matter in which "direction" the tie happened whether it was household 5 who shared to household 3 or vice versa, the kinship rank is still 1
HH1 HH2 RANK
5 3 1
3 5 1
Therefore, I do not need every tie that occurs between two households, but only the first instance that a tie occurred between the two households.
So here is a sample list of many households who shared with each other, sometimes sharing resources with themselves, sharing only once, or sharing multiple times with the same household.
TWO HOUSEHOLD WITH REPEATED TIES
COL.A COL.B
ROW HH1 HH2
1 1 1
2 1 2
3 1 3
4 2 1
5 2 4
6 3 1
7 3 2
8 3 4
9 4 2
This is what I need it to look like:
TWO HOUSEHOLDS WITHOUT REPEATED TIES
COL.A COL.B
ROW HH1 HH2
1 1 1
2 1 2
3 1 3
4 2 4
5 3 2
6 3 4
What I have done
I wrote a simple command for placing the HH1 and HH2 information into the same cell:
=A1&"|"&B1
In the case of the second row, this looks like 1|2 inside cell C2
HH1 and HH2 are combined in column C so how will I be able to compare all of the households in column C to each other? Perhaps a highlighting rule if a repeat happens? Or in another column list if it is a delete or a keep?
Thank you for your assistance everyone.
I suggest a simple COUNTIFS to do the job like this:
=(COUNTIFS(A$1:A1,B2,B$1:B1,A2)+COUNTIFS(A$1:A1,A2,B$1:B1,B2))>0
starting in C2 and then copy down. It will show TRUE for each row which is within the range above it and false if not. Ich checks for both x/y and y/x (the order doesn't matter)
Now simply filter col C to only show rows with TRUE in it. Then simply select and delete it.
This also works with non numerical values like names.
If you still have any questions, just ask ;)
You also can wrap it up to get more informations like this:
=IF((COUNTIFS(A$1:A1,B2,B$1:B1,A2)+COUNTIFS(A$1:A1,A2,B$1:B1,B2)),"",COUNTIFS(A:A,B2,B:B,A2)+COUNTIFS(A:A,A2,B:B,B2))
For C2 and copy down. C1 gets:
=COUNTIFS(A:A,B2,B:B,A2)+COUNTIFS(A:A,A2,B:B,B2)
This will show you only at the first occurrence how many times it is within the whole range.
All done by phone, may contain errors
Use =((A1*B1)/(A1+B1))*((A1*B1)+(A1+B1)) to create unique identifiers. Then use Remove Duplicates in the Data Tools Pane of the Data Tab to remove all rows containing duplicates. Or, alternatively, use something like =IF(IFNA(MATCH(A2,A$1:A1,0),TRUE())=TRUE,"First Share","") dragged and dropped from row 2 to identify First Shares.
I have one sheet that creates a mapping of names to values (Map_Sheet). In another sheet there are values for each name in the mapping table (Data_Sheet). What I am trying to do is add values based on certain conditions in the mapping table. For example: I want to add all counts of dog by bread and color. So in the mapping table I would look for all dogs that are brown and of a certain bread and get their names and manually add them together. I want to have a formula that does the addition based upon multiple conditions from Map_Sheet.
Here is an example of the data:
Map_Sheet-
name|bread|color|age
a x b 2
b y w 3
c x b 2
d z f 4
Data_Sheet -
id|a|b|c|d
0 3 4 2 1
1 1 2 4 2
2 3 5 7 2
3 1 2 6 9
4 1 3 5 7
And for each ID in the data sheet I want a count of bread X with color B. So I would add for ID0 values for A and C, (3+2) - so ID0 = 5, etc for each id.
I cannot use VBA so I was looking into using INDEX and MATCH but I cannot wrap my head around it. Any ideas? Thanks!
If the row headers in the first sheet match the column headers in the second sheet, you can put this formula in (say) G2 of the second sheet.
=SUM(TRANSPOSE(Map!$C$2:$C$5="b")*C2:F2)
If the column headers in the second sheet were in a different order, you would have to use something like:-
=SUM(C2:F2*NOT(ISERROR(MATCH($C$1:$F$1,IF(Map!$C$2:$C$5="b",Map!$A$2:$A$5),0))))
Both of these are array formulae. You can add extra conditions to select breed as well as colour using the same basic pattern:-
=SUM(TRANSPOSE((Map!$C$2:$C$5="b")*(Map!$B$2:$B$5="x"))*C2:F2)
or
=SUM(C2:F2*NOT(ISERROR(MATCH($C$1:$F$1,IF((Map!$C$2:$C$5="b")*(Map!$B$2:$B$5="x"),Map!$A$2:$A$5),0))))