So I'm creating a spreadsheet that determines the cost of materials and the number of each material needed in order to complete a desire project using input from myself. Right now the desired project is a wall that is 250x9 that requires replace all the 4x8 sheets of wood with OSB and install Vinyl Siding. The issue I'm running into is I cannot get it to always round up. By that I mean even if the value is 1.1 it should round up. In this specific case I am buying nails for my nail gun in a box of 2,000 and each sheet of OSB will have 32 nails in it. If 250x9 area requires 70.3125 sheets of OSB it means I still have to buy 71 sheets of OSB. If that OSB is 71 sheets then it require that I have 2272 Nails then the result is I need 1.125 Boxes of nails. However I can't seem to get it to show this as 2 boxes because again I still need to purchase more than one box to complete the project. So with that being said if I take the number of OSB needed 70.3125 and I place it in a formula with a roundup function it still rounds down (gives me a headache that there is a roundup and a rounddown function and it will still round down on me. Perhaps it is the way I am using it in the formula that is incorrect, I'm not sure. So let me translate the formula's used and you can let me know if I'm doing something wrong or if there is a function or set of functions that I can use to solve this issue.
=SUM(((B30*C30)+(B35*C35)+(E30*F30)+(H30*I30))/(E9*G9))
This says that if I added Wall1 L*W with Wall2 L*W with Wall3 L*W with Wall4 L*W and divide it by OSB H*W I get the number of sheets needed. Which in this case is 2250/32 basically. But its programmed in a manner that I can input the information for individual walls to different area's and get it to spit out the total SqFt for each wall and give an individual breakdown per wall of material needed with cost associated per sq ft of material bleh bleh bleh. The point is I take the result that is the 70.3125 and I move it to a different workbook and I say "Sheets OSB Needed" and in that box I have
=ROUNDUP(Sheet1!A9,1)
Whereas I'm asking it to roundup A9 which is the result of the above formula by intervals of 1. But the output is still 70 instead of 71. and much the same case with the nails needed. Which can be calculated in a few different manners but regardless the amount of nails needed divided by 2000 would output the decimal answer which yields a value of less than 1.5 and it too provides me with a value of 1 instead of 2 with much the same formula. I could achieve my desired result I suppose with Trunc and Mod functions collaborating using multiple cells to output the different portions of the data. But is there a way to do this that doesn't involve so many cells being used up?
C7
=Trunc(A9)
Removes Decimal from 70.3125
C8
=MOD(A9)
Outputs decimals from 70.3125
C9
=IF(C8<1,"1",C8)
If Decimals are < a whole number make it a whole number
C3
=SUM(C7+C9)
Add the whole number to the Trunc Number to get value desired.
Which I'm already seeing an issue with this if there is no decimals in the sheets needed then wouldn't it always add one because the decimal place would be 0? How can I handle this issue? Isn't there an easier way to do this or a way to code it so that its all nested into one calculation or at least mostly all into one calculation without making a circular reference of some sort?
You need to change the second parameter to a 0 ROUNDUP(70.3125, 1) is 70.3 the 3 must be getting dropped elsewhere or lost in formatting.
ROUNDUP(70.3125, 0) will give 71.
The second parameter of round up is the decimal place. So to round to integers it should be 0 not 1
Related
so I am a complete excel and math noob and I want to have a cell in excel which will display the "Pelayo number", which is used in calculating bias in a roulette wheel. You can read more about it here: https://www.roulette-bet.com/2015/06/the-roulette-bias-winning-method.html
enter image description here
Let me explain briefly what I want. As you can see on the image there are two columns, in one there are the numbers on a roulette wheel and and in the second one there is the frequency of each number. On top you see number of spins (852). The number on the bottom (23,02.....) is the expected frequency of each number. The table is dynamic, constantly evolving as I enter new data.
Now I want a cell to display the total number of positives. Which is calculated like this:
If there have been 300 spins, each numbers has to have been spun 300/36 = 8.33 in order to be breaking even. This means those which have been spun 8 times are losing a little, and those which have showed 9 times are winning something. If a number has appeared 14 times it is clear it has 14-8.33 = 5.67 which we will express in an abbreviated form like +5. Let’s suppose the exact same situation has occurred for 6 other numbers also, they all will make a total sum of 5.67 + 5.67 + 5.67 + 5.67 + 5.67 + 5.67+ 5.67 = 39.69. as no other number has been spun over 9 times, then we say the amount of total positives at this table at 300 spins is +39.
TLDR So ideally something like: Select all the numbers from (G6:G42) which are bigger than value in (G50) and then substract them one after another from the expected frequency (G50) and then add this all up.
I tried to solve it but just couldnt find a tutorial anywhere
I'll break this down for you, and show you a few helpful Excel concepts along the way.
Especially if you are a beginner, I'd recommend using a helper column. Helper columns are great ways to break down complicated functions into smaller, more manageable parts.
In H6, write =IF(G6>G$50,G6,0). That if statement will set us up for our sum, with either the value in G6 or a 0. The $ will be cleared up in a moment.
Then, hover your mouse over that cell, and a little square box will appear in the lower right corner of H6. Grab that tiny box, and drag it down to H42. This fills in the formula, adjusting all of the numbers relatively as you go. Note that the 50 stayed constant, however - that's what the $ did!
H6 is now your helper column. It doesn't find your answer, but it gets an important, intermediary step done.
Finally, wherever you'd like your answer, write =SUM(G6:G42), and you should be well on your way.
=SUMIF(G6:G42,">"&G50,G6:G42)-COUNTIF(G6:G42,">"&G50)*G50
It sums values that are over in G50 then distracts G50 value as much times as there were values to sum up to.
For example in case G50 is 23.02 and you have values 20, 21, 22, 23, 24, 25.
It would calculate like (22+23+24+25)-4*23.02
I have a excel sheet with a few formulas like this:
A1,A2,A3= 0.13,1.25,2.21
A4: =(A1*A2) =0.16 ( 2 decimal points)
A5: =(A2*A3) =2.76 ( 2 decimal points)
A6: =SUM(A4;A5) =2.93 ( 2 decimal points )
And i want to show 0.16+2.76=2.92
well, there's my problem in bold. i want to add the values from the cells, not the formuls result. How can i do that ? Thank you
Presumably you're working with money which is why you need this.
One way to resolve this is to use =ROUND(A1*A2, 2) etc. and base your subsequent calculations from that.
Do be aware though that you will still occasionally get spurious results due to Excel using a 64 bit IEEE754 floating point double to represent numbers. (Although it does have some extremely clever circumvention techniques - see how it evaluates 1/3 + 1/3 + 1/3 - it will not resolve every possible oddity). If you're building an accounting-style sheet you are best off working in pence, and dividing the final result.
Round the values before you sum, ie:
=ROUND(A1*A2,2)
=ROUND(A2*A3,2)
You could wrap your formulas with the ROUND function:
=ROUND(A1*A2,2)
This will give you 0.16 as opposed to 0.163. Do this for each of your calculations and you'll only be calculating everything to two decimal places. Although I'm not sure why you'd want to do that.
I'm having problems trying to do this formula and it just doesn't work. Can anyone help me?
=IF(JH2="13",CEILING(JD2/0.68+13,0.5)-0.01,""),IF(AND(JH2="6.95",(JD2/0.68))<50,CEILING(JD2/0.68+3,0.5)-0.01,CEILING(JD2/0.68+6.95,0.5)-0.01),IF(AND(M2="CA",ISNUMBER(SEARCH(S2,"INCONTINENCE"))),CEILING(JD2/0.68+6.95,0.5)-0.01,""))
Just a FYI it reads,
IF Freight price is 13 THEN to Divide the Cost price by .68 and ADD the 13.
IF Freight price is 6.95 AND the Cost Price Divide .68 is LESS than $50 THEN add $3.00 ELSE ADD 6.95.
IF M2 (which is Unit of Measurement) has CA AND Column S2 (which is the category) contains the word "Incontinence" THEN calculate Cost Price Divide .68 and add 6.95 Regardless.
Everything is rounded up.
But can't get the Damn thing to work.
First some nagging and whining.
Unreadable source code.
Reference to cells without provided values.
Now the answer (at least a part of it, depending on me missing something else).
If you start breaking up the formula, you'll notice that the first AND has the condition of equality first (that's correct) but then you'll see that the second condition only is a division, whereas the inequality comparison with 50 is put outside.
I believe that's your error. But that's based on the assumption that I got the formula correctly.
As a general suggestion for working with complex formulas in Excel, I usually do a single step at a time (putting the sub-results in separate columns to verify that they're correct). When done and confirmed, I can merge them into a single one.
Try this, it is untested:
=IFERROR(CEILING(IF(JH2=13,JD2/0.68+13,IF(AND(JH2=6.95,JD2/0.68<50),JD2/0.68+3,IF(JH2=6.95,JD2/0.68+6.95,IF(AND(M2="CA",ISNUMBER(SEARCH("INCONTINENCE",S2))),JD2/0.68+6.95,"")))),0.5)-0.01,"")
I have a requirement in Excel to spread small; i.e. pennies, monetry rounding errors fairly across the members of my club.
The error arises when I deduct money from members; e.g. £30 divided between 21 members is £1.428571... requiring £1.43 to be deducted from each member, totalling £30.03, in order to hit the £30 target.
The approach that I want to take, continuing the above example, is to deduct £1.42 from each member, totalling £29.82, and then deduct the remaining £0.18 using an error spreading technique to randomly take an extra penny from 18 of the 21 members.
This immediately made me think of Reservoir Sampling, and I used the information here: Random selection,
to construct the test Excel spreadsheet here: https://www.dropbox.com/s/snbkldt6e8qkcco/ErrorSpreading.xls, on Dropbox, for you guys to play with...
The problem I have is that each row of this spreadsheet calculates the error distribution indepentently of every other row, and this causes some members to contribute more than their fair share of extra pennies.
What I am looking for is a modification to the Resevoir Sampling technique, or another balanced / 2 dimensional error spreading methodology that I'm not aware of, that will minimise the overall error between members across many 'error spreading' rows.
I think this is one of those challenging problems that has a huge number of other uses, so I'm hoping you geniuses have some good ideas!
Thanks for any insight you can share :)
Will
I found a solution. Not very elegant, through.
You have to use two matrix. In the first you get completely random number, chosen with =RANDOM() and in the second you choose the n greater value
Say that in F30 you have the first
=RANDOM()
cell.
(I have experimented with your sheet.)
Just copy a column of n (in your sheet 8) in column A)
In cell F52 you put:
=IF(RANK(F30,$F30:$Z30)<=$A52, 1, 0)
Until now, if you drag left and down the formulas, you have the same situation that is in your sheet (only less elegant und efficient).
But starting from the second row of random number you could compensate for the penny esbursed.
In cell F31 you put:
=RANDOM()-SUM(F$52:F52)*0.5
(pay attention to the $, each random number should have a correction basated on penny already spent.)
If the $ are ok you should be OK dragging formulas left and down. You could also parametrize the 0.5 and experiment with other values. With 0,5 I have a error factor (the equivalent of your cell AB24) between 1 and 2
Is it odd that a pricing matrix is provided without decimals? For example, a product measuring 23 x 42 shows to be 114 but it's actually supposed to be 11.40. Another measurement is 28 x 48 and according to the matrix would be 696 but should be 69.6.
Why would they do this for any reason (just so I understand why to expect this)
Does Excel have an easy way to add a decimal in one space from the right?
I would just do this manually but there are thousands of products.
I figured out a way using Paste Special.
In my case the number worked out if divided by 10. So, I typed the number 10 in any cell, Edit > Copy that number. Select your numbers you'd like to alter. Right-click the number (making sure they're all still selected) and choose Paste Special. Choose Divide as the option.
That takes a number such as 720 and makes it 72.0 If you need 720 to become 7.20 then type 100 in any cell instead of the 10 we did earlier and voila.