how to insert separate lines ( elements ) in parameter - linux

Question

I have the following csv file
more file.csv
1,yes,yes,customer1,1,2,3,4
2,no,yes,customer5,34,56,33,2
3,yes,yes,customer11
4,no,no,customer14
5,yes,no,customer15
6,yes,yes,customer21
7,no,yes,customer34
8,no,yes,customer89
The following (awk) line was written in order to manipulate and take line from the csv and put each element (line) in to the parameter - LINES
declare LINES=` awk -F, 'BEGIN{IGNORECASE=1} $2=="yes" {printf "\"Line number %d customer %s\"\n", $1, $4}' file.csv `
.
echo $LINES
"Line number 1 customer customer1" "Line number 3 customer customer11" "Line number 5 customer customer15" "Line number 6 customer 21”
but when I want to print the number of elemnt in parameter LINES I get 1 ??
echo ${#LINES[*]}
1
While actually I need to get 4 elements ( lines )
Please advice how to fix the awk line in order to get 4 elements?
remark:
please see this example , when I edit manual the LINES , the elements should be 4
declare LINES=( "Line number 1 customer customer1" "Line number 3 customer customer11" "Line number 5 customer customer15" "Line number 6 customer 21” )
echo ${#LINES[*]}
4

Answer 1

The awk output isn't being stored in an array. You’d need declare -a LINES=($(...)) to do that. But even then, bash splits array elements on any whitespace, not only newlines. And if you were to wrap the process substitution in quotes like LINES=("$(...)") you would only have a single element containing the entire output from the command.
You could do the necessary text manipulation with a read loop to preserve the number of elements that contain whitespace.
declare -a lines
while IFS=, read -r line_number answer _ customer _; do
if [[ $answer == #(yes|YES) ]]; then
lines+=("Line number $line_number customer $customer")
fi
done < file.csv
As noted in the comments, depending on the bash version, usage of #(...) inside [[ ... ]] may require shopt -s extglob.
Alternatively, the if could be replaced with a case:
case $answer in
yes|YES)
LINES+=("Line number $line_number customer $customer")
;;
esac

Answer 2

Try this:
a=$(awk -F, 'BEGIN{IGNORECASE=1} $2=="yes" {printf "Line number %d customer %s;", $1, $4}' file.csv)
IFS=';' read -a LINES <<< "${a}"

Answer 3

As #JohnB mentioned, you are populating LINES as a scalar variable, not an array. Try this:
$ IFS=$'\n' LINES=( $(awk 'BEGIN{for(i=1;i<=3;i++) printf "\"Line number %d\"\n", i}') )
$ echo ${#LINES[*]}
3
$ echo "${LINES[0]}"
"Line number 1"
$ echo "${LINES[1]}"
"Line number 2"
$ echo "${LINES[2]}"
"Line number 3"
and tweak to suit your real input/output which would probably result in:
IFS=$'\n' LINES=( $(awk -F, 'BEGIN{IGNORECASE=1} $2=="yes"{printf "\"Line number %d customer %s\"\n", $1, $4}' file.csv) )

Answer 4

If you're using bash, you can just use the mapfile builtin:
$ mapfile -t LINES < \
<(awk -F, 'BEGIN{IGNORECASE=1}
$2=="yes" {printf "\"Line number %d customer %s\"\n", $1, $4}' file.csv)
$ echo "${#LINES[*]}"
4
$ echo "${LINES[#]}"
"Line number 1 customer customer1" "Line number 3 customer customer11" "Line number 5 customer customer15" "Line number 6 customer customer21"