Lua split strings into Keys and Values of a table - string

Question

So I want to split two strings, and be able to return a table with one string equaling the Keys and another the Values.
So if:
String1 = "Key1,Key2,Key3,Key4,Key Ect..."
String2 = "Value1,Value2,Value3,Value4,Value Ect..."
The output would be a table as folows:
Key1 - Value1
Key2 - Value2
Key3 - Value3
Key4 - Value4
Key Ect... - Value Ect...
I have been looking at this split function I found on the Lua wiki
split(String2, ",")
function split(String, pat)
local t = {} -- NOTE: use {n = 0} in Lua-5.0
local fpat = "(.-)" .. pat
local last_end = 1
local s, e, cap = str:find(fpat, 1)
while s do
if s ~= 1 or cap ~= "" then
table.insert(t,cap)
end
last_end = e+1
s, e, cap = str:find(fpat, last_end)
end
if last_end <= #str then
cap = str:sub(last_end)
table.insert(t, cap)
end
return t
end
But of course this only returns:
1 - Value1
2 - Value2
and so on...
I'm going to start trying to modify this code, but I don't know how far I'll get.

Answer 1

You can use it directly like this:
local t1 = split(String1, ",")
local t2 = split(String2, ",")
local result = {}
for k, v in ipairs(t1) do
result[v] = t2[k]
end
Or, create your own iterator:
local function my_iter(t1, t2)
local i = 0
return function() i = i + 1; return t1[i], t2[i] end
end
local result = {}
for v1, v2 in my_iter(t1, t2) do
result[v1] = v2
end

Answer 2

The code below avoids creating two temporary tables:
function join(s1,s2)
local b1,e1,k=1
local b2,e2,v=1
local t={}
while true do
b1,e1,k=s1:find("([^,]+)",b1)
if b1==nil then break end
b1=e1+1
b2,e2,v=s2:find("([^,]+)",b2)
if b2==nil then break end
b2=e2+1
t[k]=v
end
return t
end
String1 = "Key1,Key2,Key3,Key4"
String2 = "Value1,Value2,Value3,Value4"
for k,v in pairs(join(String1,String2)) do
print(k,v)
end