I've had a bit of trouble explaining this so please bear with me. I'm also very new to using excel so if there's a simple fix, I apologize in advance!
I have two columns, one listing number of days starting from 0 and increasing consecutively. The other column has the number of orders delivered. The two correspond to each other. For example, I've typed out how it would look below. It would mean that there were 100 orders delivered in 1 day, 150 orders delivered in 2 days, 800 orders delivered in 3 days, etc.
Is there a way to get summary statistics (mean, median, mode, upper and lower quartiles) for the number of days it took for the average order to get delivered? The only way I can think of solving this is to manually punch in "1" 100 times, "2" 150 times, etc. into a new column and take median, mean, and upper & lower quartile from that, but that seems extremely inefficient. Would I use a pivot table for this? Thank you in advance!
I tried using the data analysis add-on and doing summary statistics that way, but it didn't work. It just gave me the mean, median, mode, and quartiles of each individual column. It would have given me 3 for median number of days for delivery and 300 for median number of orders.
Method 1
The mean is just
=SUMPRODUCT(A2:A6,B2:B6)/SUM(B2:B6)
Mode is the value with highest frequency
=INDEX(A2:A6,MATCH(MAX(B2:B6),B2:B6,0))
The quartiles and median (or any other quantile by varying the value of p) from first principles following this reference
=LET(p,0.25,
values,A2:A6,
freq,B2:B6,
N,SUM(freq),
h,(N+1)*p,
floorh,FLOOR(h,1),
ceilh,CEILING(h,1),
frac,h-floorh,
cusum,SCAN(0,SEQUENCE(ROWS(values)),LAMBDA(a,c,IF(c=1,0,a+INDEX(freq,c-1)))),
xlower,XLOOKUP(floorh-1,cusum,values,,-1),
xupper,XLOOKUP(ceilh-1,cusum,values,,-1),
xlower+(xupper-xlower)*frac)
Method 2
If you don't like doing it this way, you can always expand the data like this:
=AVERAGE(XLOOKUP(SEQUENCE(SUM(B2:B6),1,0),SCAN(0,SEQUENCE(ROWS(A2:A6)),LAMBDA(a,c,IF(c=1,0,INDEX(B2:B6,c-1)+a))),A2:A6,,-1))
=MODE(XLOOKUP(SEQUENCE(SUM(B2:B6),1,0),SCAN(0,SEQUENCE(ROWS(A2:A6)),LAMBDA(a,c,IF(c=1,0,INDEX(B2:B6,c-1)+a))),A2:A6,,-1))
=QUARTILE.EXC(XLOOKUP(SEQUENCE(SUM(B2:B6),1,0),SCAN(0,SEQUENCE(ROWS(A2:A6)),LAMBDA(a,c,IF(c=1,0,INDEX(B2:B6,c-1)+a))),A2:A6,,-1),1)
=MEDIAN(XLOOKUP(SEQUENCE(SUM(B2:B6),1,0),SCAN(0,SEQUENCE(ROWS(A2:A6)),LAMBDA(a,c,IF(c=1,0,INDEX(B2:B6,c-1)+a))),A2:A6,,-1))
and
=QUARTILE.EXC(XLOOKUP(SEQUENCE(SUM(B2:B6),1,0),SCAN(0,SEQUENCE(ROWS(A2:A6)),LAMBDA(a,c,IF(c=1,0,INDEX(B2:B6,c-1)+a))),A2:A6,,-1),3)
9 chairs numbered 1 to 9. 3 women and 4 men wish to occupy one chair each. First the women will choose the chairs from amongst the chair marked 1 to 5, then the men select chairs from amongst the remaining. what is the possible number of arrangements?
The answer should be 150, but i got 1440 instead can someone tell me how to get the correct answer?
First, the 3 women must choose amongst the 5 first chairs. The number of possible ways is given by the binomial coefficient Binomial(n, k) (or "n choose k") with n=5 and k=3, which is equal to 10. This give you the number of ways to seat the 3 women when 5 chairs are available.
After that, there are 6 seats remaining since 3 have are now occupied, and the 4 men must choose among these remaining seats. The number of ways to seat the 4 men when 6 chairs are available is Binomial(6, 4) = 15.
Now these two processes happen one after the other, so that the number of possibilities for your scenario is simply the multiplication of both, i.e., 10*150=150. Indeed, your first find seats for women (10 configurations), and for each possible configuration, there are 15 ways to seat the men, so that 150 configurations in total to accommodate both women and men.
I have set up an optimization problem but i must be doing something wrong and I could use your help. I have three firms: alpha, Bravo, Charlie. They each complete three tasks: Milling, Inspecting, Drilling. They each require different amounts of minutes to complete each task. Alpha requires 12 minutes to mill, 5 minutes to inspect and 10 minutes to drill. Bravo requires 10 minutes to mill, 4 to inspect, and 8 to drill. Charlie requires 8 to mill, 4 to inspect, and 16 to drill. After each firm completes all of these tasks they will earn a certain amount of profit, Alpha will earn $2.40, Bravo will earn $2.50, and Charlie will earn $3.00. All three firms have a maximum allotted time of 1200 minutes to mill, 900 to inspect, and 1440 to drill. The goal is to maximize the profit of these three firms. I have set it up so that the sums of the tasks will take away from the available time left when changed by the solver. I have also set constraints within the solver to cap each task to the allotted time allowed per task. I must be missing a vital step however because it keeps trying to just max out the allotted time for an individual firm, not taking in to account the opportunity cost of the other firms or something. Please help! (shown in photos)
Data
Solver
After executing Solver
I have changed the logic a bit different in order to take the minimum unit into consideration:
UNITS portion are the variable cells. Since the final produced unit will be the minimum of these cells, E9 formula is =MIN(B9:D9) and copied down.
TIME portion is multiplication of Unit Times and Units. So the formula of B14 is =B9*B2 and copied down & right.
I9:I11 are the earnings calculated by multiplying the unit earning with the minimum units
I12 is our total earning and is our Objective cell.
Please also be careful about the constraints since when you do not set an integer constrain, finding a solution becomes more difficult and of course our units should be integer in any case.
And also fill B9:D11 cells with some values such as 100, since otherwise iteration does not start correctly and solver ends up with a very small objective cell.
I have just had a go at this and I get a different answer as I have made the assumption that to achieve the profit the company must complete a milling process, then inspect, then drill and once all are complete then that is 1 unit for the profit - I hope that is valid.
But if not, then this layout may help you anyway. Note I have set this as a Linear model for the solver and also note the use of integer and non-negative.
It was fun anyway !
i would like a list of client names where together they have a combined amount of 1000. so, say if jim and tod's combined amount of money <= 1000 and jim, tod, jill >= 1000 then list jim and tod in a cell, then in the next cell if jill, joy, and pat <=1000 and jill, joy, pat, and tam >= 1000 then list jill, joy, and pat and so fourth until all of the clients are in a list.
Is this possible? I am learning and am not sure where to start so i would greatly appreciate if someone can help point me in the right direction to solve this problem?
Assuming your criterion for a group is that the money sums to less than or equal to 1000, then this is straightforward. Simply accumulate the Money amount down the list of names and start a new group and (reset the accumulator) whenever the cumulative amount exceeds 1000.
This gives you the group number for each name (see column D in picture below). A separate problem is then to list the names for each group number. In the picture, I have allowed for a maximum of 5 names per group but if real data indicates this is insufficient then allowing more is straightforward.
The set of groups obtained using this approach is dependent on the ordering of the rows of input data - change this ordering and the result is a different set of groups.
Perhaps a more interesting and challenging problem is to define a set of groups which meet not only the <=1000 criterion but also other criteria such as: minimise number of groups overall and equalise, as far as possible, the total money allocated to each group. But that is a very different problem!
Ive created a game and in that game played 5 users which collected few points, Ive gived gifts manually but for next games how can i split or make in excel to calculate number of gifts,
this is ok using number format with 0 decimal places, 6+1+1+1 = 9
but in cases like this:
1+6+1+1+1 = 10, how can I make that only 9 gifts results?
You should be comparing their percent (B2/SUM(B2:B6)) against each prize as it relates to the total prize (e.g. 1/9). Since you are comparing decimal numbers with another decimal number and expecting an integer (no. of prizes), you will be rounding either up or down depending on whether you are favoring a wider distribution of the prizes or favoring the top score.
Either way you are going to have to decide whether the lowest score should always receive a prize or if the highest score should benefit from the points awarded.
The three possible formulas to start with would be,
=MROUND(C2, 1/9)*9 ◄ closest to even distribution
=FLOOR(C2, 1/9)*9 ◄ favours wider prize distribution
=CEILING(C2, 1/9)*9 ◄ rewards highest awarded points
Fill down as necessary.
Now you have to either take the highest or lowest score and adjust that to compensate for rounding the division of decimal numbers to an integer. MROUND doesn't play well with SUMPRODUCT but these two may give you a solution that you can live with.
=FLOOR($C2, 1/9)*9-((SUMPRODUCT(FLOOR($C$2:$C$6, 1/9)*9)-9)*($C2=MAX($C$2:$C$6)))
=CEILING($C2, 1/9)*9-((SUMPRODUCT(CEILING($C$2:$C$6, 1/9)*9)-9)*($C2=MAX($C$2:$C$6)))
Fill down as necessary.
If the MROUND solution is best suited to your prize distribution model, use a helper column that can determine the MROUND returns and then adjust the high score according to the sum of the helper column without circular references.