Node Kue and Child Process - get error from spawned process - node.js

Question

I try to spawn a child process performing cpu intensive calculations through a job queue with Kue. My code at the moment looks like this:
consumer.js
var kue = require('kue');
var util = require('util');
var spawn = require('child_process').spawn;
var jobs = kue.createQueue();
jobs.process('calc', 2, function(job, done){
var work = spawn('Rscript', ['opti2.R', job.data.file]);
work.stderr.on('data', function (data) {
job.log('stderr: ' + data);
});
work.stdout.on('data', function (data) {
job.log('stdout: ' + data);
});
work.on('exit', function (code, signal) {
console.log('child process exited with code ' + code + ' with singal ' + signal);
if(code != 0){
done(****How to get the stderr of the child process as an error here***);
} else {
done(Error());
}
});
});
The code somewhat do what i would like it to do, but is there a better way to report the job as failed (to Kue) and get the stderr from the spawned process?

Answer 1

You can use job.log method to send data directly to Kue.
I would also recommend you to switch from .spawn to .exec, because it returns stdout and stderr as strings in its final callback along with a good error, which suits your needs well:
var exec = require('child_process').exec;
jobs.process('calc', 2, function(job, done){
exec('Rscript opti2.R ' + job.data.file, function (error, stdout, stderr) {
if (stdout.length > 0) job.log('stdout: ' + stdout);
if (stderr.length > 0) job.log('stderr: ' + stderr);
done(error);
});
});
Though solution should work with .spawn as well: simply replace each console.log call in your code with job.log.
Though, you may want to bufferize your stderr in order to send it to Kue in one chunk:
jobs.process('calc', 2, function(job, done){
var work = spawn('Rscript', ['opti2.R', job.data.file]);
var stderr = '';
work.stderr.on('data', function (data) {
stderr += data;
});
work.stdout.on('data', function (data) {
job.log(data); // sending arriving `stdout` chunks as normal log events
});
work.on('close', function (code, signal) {
console.log('child process exited with code ' + code + ' with singal ' + signal);
if(code != 0){
done(stderr); // sending all collected stderr as an explanation
} else {
done();
}
});
});
I would also recommend using close event instead of exit, because it waits for child's stdio streams.
For more information see Event: 'exit' docs:
This event is emitted after the child process ends.
Note that the child process stdio streams might still be open.
and Event: 'close' docs:
This event is emitted when the stdio streams of a child process have
all terminated.