I am trying to find all the files of type *.gz and cat them to total.gz and I think I am quite close on this.
This is the command I am using to list all *.gzfiles:
find /home/downloaded/. -maxdepth 3 -type d \( ! -name . \) \
-exec bash -c "ls -ltr '{}' " \
How to modify it so that it will concatenate all of them and write to ~/total.gz
Directory structure under downloaded is as follows
/downloaded/wllogs/303/07252014/SysteOut.gz
/downloaded/wllogs/301/07252014/SystemOut_13.gz
/downloaded/wllogs/302/07252014/SystemOut_14.gz
Use cat in -exec and redirect output of find:
find /home/downloaded/ -type f -name '*.gz' -exec cat {} \; > output
Use echo in -exec and redirect the output:
find /home/downloaded/ -name "*.gz" -exec echo {} \; > output
Related
I need to get all the texts in the matching file in the folder. However, at the same time need to get the matching file path as well. How can I get the matching file path as well using the following command.
find . -type f -name release.txt | xargs cat
try
find . -type f -name release.txt -exec grep -il {} \; | xargs cat
Skip xargs, just do:
find . -type f -name release.txt -exec sh -c 'echo "$1"; cat "$1"' _ {} \;
First one :
We found several files and we have to copy that to kat4 and here is code, but it doesn't seem to work corectly
find /home/imk-prac/ -type f -size -13c -name '*\?plik\?*' -exec cp {} /home/inf-19/aduda/\*kat1\*/\*kat2\*/\*kat4\*/ \; 2> /dev/null
'cp' I assume that it is copy, but I don't know what 'exec' and '{}' do.
Second one:
find /home/imk-prac/ \( -type f -size -13c -name '*\?plik\?*' \) -o\( -type d -name '\[Kolo1\]*' \)2> /dev/null
Generally,I understand this line (except for '2' and '-o') , but I want to add looking for files which were modificated in less that 30 days and here is what I wanted to combine with upper command :
find /home/imk-prac/ -type f -mtime -30 -exec ls -l {} \; > /dev/null
As a result I wrote it down as:
find /home/imk-prac/ \( -type f -size -13c -name '*\?plik\?' -mtime -30 -exec ls -l{}\) -o \( -type d -name '\[Kolo1\]*' \) 2> /dev/null
but it doesn't work
Moreover, I wanted to add looking for files with speciefied quantity of symbols and I found this command:
grep -Po '(^|\s)\S{64}(\s|$)' file
But I have no idea how to combine all of those 3 upper commands.
I will be grateful for any help, thank you for your time!
I have a list of files which I got using find / -type f -size +10M -exec ls -l {} \;
I got this command from here
How can I remove all these files ?
I tried
sudo rm `find / -type f -size +10M -exec ls -l {} \;`
but it doesn't work.
Also, what does {} \ do ? And what's the use of -exec in this command, will the pipe operator not work ?
I think it should be possible to have find run rm on each file found, but I couldn't get it to work.
So here is my solution using a for loop:
for $f in `find / -type f -size +10M`;do rm $f;done
Thanks guys, I finally got it to work with #some-programmer-dude suggestion:
find / -type f -size +10M -exec rm {} \;
I am writing a script which does a checksum (md5sum) on a forum web directory.
It is a bash script. With the idea being to do a checksum on all the files in the directory, and then compare it to a text file which has a list of checksums.
The script works if I pass it into a text file, and then do a diff command between the text file and my list of known checksums, but I would like to not have it write to a text file and then have to remove the text file at the end of the script, hence why I am using a variable
The script below fails with the error:
/usr/bin/diff: Argument list too long
cd /var/www/html/forum/
VAR1=$(find . -type d \( -name store_sitemap \) -prune -o -type f -exec md5sum {} \; | grep -v "files\|that\|change")
/usr/bin/diff "${VAR1}" "/root/scripts/forum_checkum_original.txt"
How can I pass my variable along so that I can runn the diff command on it?
EDIT: with the help of the user devnull (thank you again) here is the completed and working script:
cd /var/www/html/forum/
MAIL=$(/usr/bin/diff <(find . -type d \( -name store_sitemap \) -prune -o -type f -exec md5sum {} \; | grep -v "files\|that\|change") /root/scripts/forum_checkum_original.txt)
if [[ -n $(/usr/bin/diff <(find . -type d \( -name store_sitemap \) -prune -o -type f -exec md5sum {} \; | grep -v "files that change") /root/scripts/forum_checkum_original.txt) ]]; then
echo "$MAIL" | mail -s "Forum Checksum" yourmailaddress#yourdomain.com
else
echo "no files have been changed"
fi
diff compares files, not variables. Use Process Substitution instead.
An equivalent of what you're trying to do would be:
/usr/bin/diff <(find . -type d \( -name store_sitemap \) -prune -o -type f -exec md5sum {} \; | grep -v "bidorbuy.log") /root/scripts/forum_checkum_original.txt
If you want to keep it in a variable you can give diff the variable as a filedescriptor by doing:
diff <(echo "$MAIL") "/root/scripts/forum_checkum_original.txt"
I'm writing a script that would loop over the sub-directories of a given directory, find for ".js" files, compiles with closure. I'm doing this with this commands:
find ./js/ -type f -name "*.js" -exec java -jar compiler.jar --compilation_level SIMPLE_OPTIMIZATIONS --js '{}' --js_output_file '{}'.compiled \;
And then removing the old ".js" files with:
find ./js/ -type f -name "*.js" | xargs rm -f
But, I can't rename the files with the names "foo.js.compiled" to "foo.js".
Please help. Thanks in advance.
Try
for i in `find . -type f -name "*.js.compiled"`; do mv $i ${i%.*} ; done
You can do something like:
find . -name "*.js.compiled" -exec rename -v 's/\.compiled$//' {} +
Test:
$ find . -name "foo*"
./fil/foo.js.compiled
$ find . -name "*.js.compiled" -exec rename -v 's/\.compiled$//' {} +
'./fil/foo.js.compiled' renamed to './fil/foo.js'
$ find . -name "foo*"
./fil/foo.js
use the following code:
find ./js/ -name "*.js.compiled" -print0 | while read -r -d '' filename; do
mv "$filename" "${filename/js.compiled/js}";
done