I want to write a shell-script such that it should ask for a port number then show the process-id and process-name running on that port number. So how can I do this in Linux?
You can use lsof to do so, with the -i option to filter the port you want. The first column is the command name and the second one is its pid.
lsof -i :$port | tail -n +2 | awk '{ print $1" "$2 }'
I'm using tail to remove the header from the output of lsof. Note that there is a simpler solution to get the pid alone, using the -t option:
lsof -t -i :$port
Related
In one of my tools is needed the PID of specyfic process in system. I try do this by following command:
parasit#host:~/# ps -ef | grep beam.smp |grep -v grep |awk '{ print $2 }' |head -n1
11982
Works fine, but when i try use the same command in script in the vast majority of cases got PID of grep instead of target process (beam.smp in this case) despite of 'grep -v grep`.
parasit#host:~/# cat getPid.sh
#!/bin/bash
PROC=$1
#GET PID
CMD="ps -ef | grep $PROC |grep -v grep |awk '{ print \$2 }' |head -n1"
P=`eval $CMD`
parasit#host:~/# bash -x ./getPid.sh beam.smp
+ PROC=beam.smp
+ CMD='ps -ef |grep beam.smp |grep -v grep |awk '\''{ print $2 }'\'' |head -n1'
++ eval ps -ef '|grep' beam.smp '|grep' -v grep '|awk' ''\''{' print '$2' '}'\''' '|head' -n1
+++ head -n1
+++ awk '{ print $2 }'
+++ grep -v grep
+++ grep beam.smp
+++ ps -ef
+ P=2189
Interestingly, it is not deterministic, I know it sounds strange, but sometimes it works OK, and sometimes no, I have no idea what it depends on.
How it is possibile? Is there any better method to get rid of "grep" from results?
BR
Parasit
pidof -s is made for that (-s: single ID is returned):
pidof -s "beam.smp"
However, pidof also returns defunct (zombie, dead) processes. So here's a way to get PID of the first alive-and-running process of a specified command:
# function in bash
function _get_first_pid() {
ps -o pid=,comm= -C "$1" | \
sed -n '/'"$1"' *$/{s:^ *\([0-9]*\).*$:\1:;p;q}'
}
# example
_get_first_pid "beam.smp"
-o pid=,comm=: list only PID and COMMAND columns; ie. only list what we need to check; if all are listed then it is more difficult to process later on
-C "$1": of the command specified in -C; ie. only find the process of that specific command, not everything
sed: print only PID for first line that do not have "defunct" or anything after the base command name
I am getting process id for a process using:
ps -ef | awk '$8=="process name" {print $2}'
How can I use the output of above command as an input to the command below:
ps -p <pid> -o %cpu,%mem,cmd
Basically I needed the above two commands executed as a single command.
Pipe it to xargs:
... | xargs -I {} ps -p {} -o %cpu,%mem
The {} is the default argument list marker which can be used to send to your final command.
Alternatively you can also use command substitution
ps -p $(ps -ef | awk ...) -o %cpu,%mem
I believe this is a simple syntax issue on my part but I have been unable to find another example similar to what i'm trying to do. I have a variable taking in a specific disk location and I need to use that location in an hdparm /grep command to pull out the max LBA
targetDrive=$1 #/dev/sdb
maxLBA=$(hdparm -I /dev/sdb |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*') #this works perfect
maxLBA=$(hdparm -I $1 |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*') #this fails
I have also tried
maxLBA=$(hdparm -I 1 |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*')
maxLBA=$(hdparm -I "$1" |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*')
Thanks for the help
So I think here is the solution to your problem. I did basically the same as you but changed the way I pipe the results into one another.
grep with regular expression to find the line containing LBA48
cut to retrieve the second field when the resulting string is divided by the column ":"
then trim all the leasding spaces from the result
Here is my resulting bash script.
#!/bin/bash
target_drive=$1
max_lba=$(sudo hdparm -I "$target_drive" | grep -P -o ".+LBA48.+:.+(\d+)" | cut -d: -f2 | tr -d ' ')
echo "Drive: $target_drive MAX LBA48: $max_lba"
I want to use ps -ef | grep "keyword" to determine the pid of a daemon process (there is a unique string in output of ps -ef in it).
I can kill the process with pkill keyword is there any command that returns the pid instead of killing it? (pidof or pgrep doesnt work)
You can use pgrep as long as you include the -f options. That makes pgrep match keywords in the whole command (including arguments) instead of just the process name.
pgrep -f keyword
From the man page:
-f The pattern is normally only matched against the process name. When -f is set, the full command line is used.
If you really want to avoid pgrep, try:
ps -ef | awk '/[k]eyword/{print $2}'
Note the [] around the first letter of the keyword. That's a useful trick to avoid matching the awk command itself.
Try
ps -ef | grep "KEYWORD" | awk '{print $2}'
That command should give you the PID of the processes with KEYWORD in them. In this instance, awk is returning what is in the 2nd column from the output.
ps -ef | grep KEYWORD | grep -v grep | awk '{print $2}'
This is available on linux: pidof keyword
I use
ps -C "keyword" -o pid=
This command should give you a PID number.
To kill a process by a specific keyword you could create an alias in ~/.bashrc (linux) or ~/.bash_profile (mac).
alias killps="kill -9 `ps -ef | grep '[k]eyword' | awk '{print $2}'`"
I was looking for the best way to find the number of running processes with the same name via the command line in Linux. For example if I wanted to find the number of bash processes running and get "5". Currently I have a script that does a 'pidof ' and then does a count on the tokenized string. This works fine but I was wondering if there was a better way that can be done entirely via the command line. Thanks in advance for your help.
On systems that have pgrep available, the -c option returns a count of the number of processes that match the given name
pgrep -c command_name
Note that this is a grep-style match, not an exact match, so e.g. pgrep sh will also match bash processes. If you want an exact match, also use the -x option.
If pgrep is not available, you can use ps and wc.
ps -C command_name --no-headers | wc -l
The -C option to ps takes command_name as an argument, and the program prints a table of information about processes whose executable name matches the given command name. This is an exact match, not grep-style. The --no-headers option suppresses the headers of the table, which are normally printed as the first line. With --no-headers, you get one line per process matched. Then wc -l counts and prints the number of lines in its input.
result=`ps -Al | grep command-name | wc -l`
echo $result
ps -Al | grep -c bash
You can try :
ps -ef | grep -cw [p]rocess_name
OR
ps aux | grep -cw [p]rocess_name
For e.g.,:
ps -ef | grep -cw [i]nit
Some of the above didn't work for me, but they helped me on my way to this.
ps aux | grep [j]ava -c
For newbies to Linux:
ps aux prints all the currently running processes, grep searches for all processes that match the word java, the [] brackets remove the process you just ran so it wont include that as a running process and finally the -c option stands for count.
List all process names, sort and count
ps --no-headers -A -o comm | sort | uniq -c
You also can list process attached to a tty
ps --no-headers a -o comm | sort | uniq -c
You may filter with:
ps --no-headers -A -o comm | awk '{ list[$1] ++ } END { for (i in list) { if (list[i] > 10) printf ("%20s: %s\n", i, list[i]) } }'
Following bash script can be run as a cron job and you can possibly get email if any process forks itself too much.
for i in `ps -A -o comm= --sort=+comm | uniq`;
do
if (( `ps -C $i --no-headers | wc -l` > 10 )); then
echo `hostname` $i `ps -C $i --no-headers | wc -l` ;
fi
done
Replace 10 with your number of concern.
TODO: "10" could be passed as command line parameter as well. Also, few system processes can be put into exception list.
You can use ps(will show snapshot of processes) with wc(will count number of words, wc -l option will count lines i.e. newline characters).
Which is very easy and simple to remember.
ps -e | grep processName | wc -l
This simple command will print number of processes running on current server.
If you want to find the number of process running on current server for current user then use -U option of ps.
ps -U root | grep processName | wc -l
change root with username.
But as mentioned in lot of other answers you can also use ps -e | grep -c process_name which is more elegant way.
ps aux | wc -l
This command shows number of processes running on the system by all the users.
For a specific user you can use the following command:
ps -u <username> | wc -l
replace with the actual username before running :)
ps -awef | grep CAP | wc -l
Here "CAP" is the word which is in the my Process_Names.
This command output = Number of Processes + 1
This is why When we are running this command , our system read thats "ps -awef | grep CAP | wc -l " is also a process.
So yes our real answer is (Number of Processes) = Command Output - 1
Note : These processes are only those processes who include the name of "CAP"