I am trying to do an Offset/Match or Index/Match type formula to find the value that matches a cell. The problem is the way the sheet is laid out.
For an example I am trying to match the Job No. to the Project Name under the appropriate client.
I would like to keep it in this format because the project list will grow.
This sheet is where my lists are kept.
*This is just being created hence why the Project lists are tiny.
This sheet will be an ever expanding list of stuff that needs to be done.
You can see the OFFSET formula below that I tried. Is there another way of doing this or can this be done with a simple formula (instead of a long IF statement for each Client)?
=OFFSET(D2,MATCH(D3,Lists!F3:P10,0),MATCH(J2,Lists!F3:P3,0))
Thanks for any feedback.
=VLOOKUP(D3,OFFSET(Lists!$E$4:$E$10,,MATCH(C3,Lists!$F$2:$P$2,0),,2),2,0)
It seems a bit more awkward to do it with INDEX/MATCH because you have to repeat the column lookup, but here it is
IFERROR(INDEX(INDEX($F$4:$P$10,,MATCH(C3,$F$2:$O$2,0)+1),MATCH(D3,INDEX($F$4:$P$10,,MATCH(C3,$F$2:$O$2,0)),0)),"")
So, I have an Excel-file with two sheets. The first sheet contains 7 Columns of different values.
The second sheet contains a list of special customer prices.
What i want to do, is basicly search for the value given in e.g. cell A2, in Sheet2!A:A. If i were to find this value (it's a text value), I want to return the value located in that spesific row containing the value searched for, only 3 colums to the right.
I've done a lot of experiments, but really can't get INDEX and MATCH to do the work properly for me. Anyh suggestions?
Feel free to ask for more information, as I know I can be a challange to understand..
Best regards
try offset() and match(), offset(reference,rows,cols). use match to find the number of rows or columns to move from the reference point.
Using OFFSET is against almost all best practice guides. It is a volatile function, meaning it should be avoided at all costs. Use INDEX+MATCH instead. It can do all the same stuff but has much better performance.
=INDEX(column holding the value you want to return, match to find row #, 1)
=MATCH(value you are looking for, column you are searching in, 0 means exact match)
Result:
=INDEX(Sheet2!$D$2:$D$10,MATCH(A2,Sheet2!$A$2:$A$10,0),1)
I believe the function you are looking for is a vlookup. Try this:
=vlookup(A2, Sheet2!A:D, 4, 0)
Regards,
Windyvation
I don't use excel often, and I haven't really found a good solution to my problem. (which is probably really simple).
I would like to have a cell with a function in my spreadsheet that shows another cell value value that depends on yet another cell value.
Such as:
The Best Deal heading simply uses the formula
=MAX(D3,D1000)
But under Best Deal I would like to display the Name Test1 rather than the numeric value.
Another thing that would be nice to know, is if there is a way to know the maximum row with data in it. So rather than =MAX(D3,D1000) something like =MAX(D3,Max(RowCount_InD))
Obviously that function wouldn't work as I wrote it, but hopefully this pseudo code gives you an idea of what I mean. The purpose is that if more entries are added, it would be able to handle them.
I know this is possible, but I'm having some trouble. Hopefully I can get some help here.
Thanks!
The easiest way to do this is to use a combination of Index and Match. Match will find the position of the maximum value, and then Index will look in column A and return the data in that same position. So, your formula would be:
=INDEX(A$3:A$1000,MATCH(MAX(D$3:D$1000),D$3:D$1000,0))
Put that formula in F3. No hidden columns required.
Sorry, I missed the part about the expanding range. You can do that by using Count or CountA along with Offset. The new formula would be:
=INDEX(A3:OFFSET(A3,COUNTA(A:A)-1,0),MATCH(MAX(D3:OFFSET(D3,COUNT(D:D)-1,0)),D3:OFFSET(D3,COUNT(D:D)-1,0),0))
More complex, but it is basically the same except that it will expand as you add new values at the end.
There is only one 'simple' way I can think of this, but it requires hidden columns (sorry).
set E1 = A1 and fill down all the way (Basically you are making a copy of column A in column E but you are using a formula so it will always be the same)
Then under 'Best deal' - put this formula:
=VLOOKUP(MAX(D3,D1000),$D:$E,2,FALSE)
Then hide column E so it doesn't look like a mess. This way you do not need any fancy macro's and it will work everywhere because it is a normal formula.
"Another thing that would be nice to know, is if there is a way to know the maximum row with data in it. So rather than =MAX(D3,D1000) something like =MAX(D3,Max(RowCount_InD))"
This is a called a dynamic named range. Create a name for the ratio data, and set up the formula for the name range to be this:
=OFFSET($D$3, 0, 0, COUNTA($D$3:$D$1048576), 1)
More info here: http://www.ozgrid.com/Excel/DynamicRanges.htm
Then, assuming you name this named range ratio_data, your function could be referring to =MAX(ratio_data) in combination with index-match as suggested by #Tim Mayes. The range will expand automatically as you add more data.
=INDEX(A$3:A$1000,MATCH(MAX(ratio_data),ratio_data,0))
Ideally, you can replace the A3:A1000 by a dynamic named range as well.
Does anyone know the formula to find the value of the last non-empty cell in a column, in Microsoft Excel?
Using following simple formula is much faster
=LOOKUP(2,1/(A:A<>""),A:A)
For Excel 2003:
=LOOKUP(2,1/(A1:A65535<>""),A1:A65535)
It gives you following advantages:
it's not array formula
it's not volatile formula
Explanation:
(A:A<>"") returns array {TRUE,TRUE,..,FALSE,..}
1/(A:A<>"") modifies this array to {1,1,..,#DIV/0!,..}.
Since LOOKUP expects sorted array in ascending order, and taking into account that if the LOOKUP function can not find an exact match, it chooses the largest value in the lookup_range (in our case {1,1,..,#DIV/0!,..}) that is less than or equal to the value (in our case 2), formula finds last 1 in array and returns corresponding value from result_range (third parameter - A:A).
Also little note - above formula doesn't take into account cells with errors (you can see it only if last non empty cell has error). If you want to take them into account, use:
=LOOKUP(2,1/(NOT(ISBLANK(A:A))),A:A)
image below shows the difference:
This works with both text and numbers and doesn't care if there are blank cells, i.e., it will return the last non-blank cell.
It needs to be array-entered, meaning that you press Ctrl-Shift-Enter after you type or paste it in. The below is for column A:
=INDEX(A:A,MAX((A:A<>"")*(ROW(A:A))))
Here is another option: =OFFSET($A$1;COUNTA(A:A)-1;0)
I know this question is old, but I'm not satisfied with the answers provided.
LOOKUP, VLOOKUP and HLOOKUP has performance issues and should really never be used.
Array functions has a lot of overhead and can also have performance issues, so it should only be used as a last resort.
COUNT and COUNTA run into problems if the data is not contiguously non-blank, i.e. you have blank spaces and then data again in the range in question
INDIRECT is volatile so it should only be used as a last resort
OFFSET is volatile so it should only be used as a last resort
any references to the last row or column possible (the 65536th row in Excel 2003, for instance) is not robust and results in extra overhead
This is what I use
when the data type is mixed: =max(MATCH(1E+306,[RANGE],1),MATCH("*",[RANGE],-1))
when it's known that the data contains only numbers: =MATCH(1E+306,[RANGE],1)
when it's known that the data contains only text: =MATCH("*",[RANGE],-1)
MATCH has the lowest overhead and is non-volatile, so if you're working with lots of data this is the best to use.
Inspired by the great lead given by Doug Glancy's answer, I came up with a way to do the same thing without the need of an array-formula. Do not ask me why, but I am keen to avoid the use of array formulae if at all possible (not for any particular reason, it's just my style).
Here it is:
=SUMPRODUCT(MAX(($A:$A<>"")*(ROW(A:A))))
For finding the last non-empty row using Column A as the reference column
=SUMPRODUCT(MAX(($1:$1<>"")*(COLUMN(1:1))))
For finding the last non-empty column using row 1 as the reference row
This can be further utilized in conjunction with the index function to efficiently define dynamic named ranges, but this is something for another post as this is not related to the immediate question addressed herein.
I've tested the above methods with Excel 2010, both "natively" and in "Compatibility Mode" (for older versions of Excel) and they work. Again, with these you do not need to do any of the Ctrl+Shift+Enter. By leveraging the way sumproduct works in Excel we can get our arms around the need to carry array-operations but we do it without an array-formula. I hope someone out there may appreciate the beauty, simplicity and elegance of these proposed sumproduct solutions as much as I do. I do not attest to the memory-efficiency of the above solutions though. Just that they are simple, look beautiful, help the intended purpose and are flexible enough to extend their use to other purposes :)
Hope this helps!
All the best!
This works in Excel 2003 (& later with minor edit, see below). Press Ctrl+Shift+Enter (not just Enter) to enter this as an array formula.
=IF(ISBLANK(A65536),INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535)))),A65536)
Be aware that Excel 2003 is unable to apply an array formula to an entire column. Doing so yields #NUM!; unpredictable results may occur! (EDIT: Conflicting information from Microsoft: The same may or may not be true about Excel 2007; problem may have been fixed in 2010.)
That's why I apply the array formula to range A1:A65535 and give special treatment to the last cell, which is A65536 in Excel 2003. Can't just say A:A or even A1:A65536 as the latter automatically reverts to A:A.
If you're absolutely sure A65536 is blank, then you can skip the IF part:
=INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535))))
Note that if you're using Excel 2007 or 2010, the last row number is 1048576 not 65536, so adjust the above as appropriate.
If there are no blank cells in the middle of your data, then I would just use the simpler formula, =INDEX(A:A,COUNTA(A:A)).
An alternative solution without array formulas, possibly more robust than that of a previous answer with a (hint to a) solution without array formulas, is
=INDEX(A:A,INDEX(MAX(($A:$A<>"")*(ROW(A:A))),0))
See this answer as an example.
Kudos to Brad and barry houdini, who helped solving this question.
Possible reasons for preferring a non-array formula are given in:
An official Microsoft page (look for "Disadvantages of using array formulas").
Array formulas can seem magical, but they also have some disadvantages:
You may occasionally forget to press CTRL+SHIFT+ENTER. Remember to press this key combination whenever you enter or edit an array formula.
Other users may not understand your formulas. Array formulas are relatively undocumented, so if other people need to modify your workbooks, you should either avoid array formulas or make sure those users understand how to change them.
Depending on the processing speed and memory of your computer, large array formulas can slow down calculations.
Array Formula Heresy.
if you search in Column (A) use :
=INDIRECT("A" & SUMPRODUCT(MAX((A:A<>"")*(ROW(A:A)))))
if your range is A1:A10 you can use:
=INDIRECT("A" & SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10)))))
in this formula :
SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10))))
returns last non blank row number ,and indirect() returns cell value.
=INDEX(A:A, COUNTA(A:A), 1) taken from here
=MATCH("*";A1:A10;-1) for textual data
=MATCH(0;A1:A10;-1) for numerical data
Ive tried all the non-volatile versions but Not one version given above has worked.. excel 2003/2007update. Surely this can be done in excel 2003. Not as an array nor standard formula.
I either get just a blank, 0 or #value error.
So I resort to the volatile methods .. This worked..
=LOOKUP(2,1/(T4:T369<>""),T4:T369)
#Julian Kroné .. Using ";" instead of "," does NOT work! I think you are using Libre Office not MS excel?
LOOKUP is so annoyingly volitile I use it as a last resort only
For Microsoft office 2013
"Last but one" of a non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-2,0)
"Last" non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-1,0)
Place this code in a VBA module. Save. Under functions, User defined look for This function.
Function LastNonBlankCell(Range As Excel.Range) As Variant
Application.Volatile
LastNonBlankCell = Range.End(xlDown).Value
End Function
for textual data:
EQUIV("";A1:A10;-1)
for numerical data:
EQUIV(0;A1:A10;-1)
This give you the relative index of the last non empty cell in the range selected (here A1:A10).
If you want to get the value, access it via INDIRECT after building -textually- the absolute cell reference, eg:
INDIRECT("A" & (nb_line_where_your_data_start + EQUIV(...) - 1))
I had the same problem too. This formula also works equally well:-
=INDIRECT(CONCATENATE("$G$",(14+(COUNTA($G$14:$G$65535)-1))))
14 being the row number of the first row in the rows you want to count.
Chronic Clawtooth
I used HLOOKUP
A1 has a date;
A2:A8 has forecasts captured at different times, I want the latest
=Hlookup(a1,a1:a8,count(a2:a8)+1)
This uses a standard hlookup formula with the lookup array defined by the number of entries.
If you know that there are not going to be empty cells in between, the fastest way is this.
=INDIRECT("O"&(COUNT(O:O,"<>""")))
It just counts the non-empty cells and refers to the appropriate cell.
It can be used for a specific range as well.
=INDIRECT("O"&(COUNT(O4:O34,"<>""")+3))
This returns the last non empty cell in the range O4:O34.
This formula worked with me for office 2010:
=LOOKUP(2;1/(A1:A100<>"");A1:A100)
A1: the first cell
A100: refer to the last cell in comparing
I think the response from W5ALIVE is closest to what I use to find the last row of data in a column. Assuming I am looking for the last row with data in Column A, though, I would use the following for the more generic lookup:
=MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0))
The first MATCH will find the last text cell and the second MATCH finds the last numeric cell. The IFERROR function returns zero if the first MATCH finds all numeric cells or if the second match finds all text cells.
Basically this is a slight variation of W5ALIVE's mixed text and number solution.
In testing the timing, this was significantly quicker than the equivalent LOOKUP variations.
To return the actual value of that last cell, I prefer to use indirect cell referencing like this:
=INDIRECT("A"&MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0)))
The method offered by sancho.s is perhaps a cleaner option, but I would modify the portion that finds the row number to this:
=INDEX(MAX((A:A<>"")*(ROW(A:A))),1)
the only difference being that the ",1" returns the first value while the ",0" returns the entire array of values (all but one of which are not needed). I still tend to prefer addressing the cell to the index function there, in other words, returning the cell value with:
=INDIRECT("A"&INDEX(MAX((A:A<>"")*(ROW(A:A))),1))
Great thread!
If you are not afraid to use arrays, then the following is a very simple formula to solve the problem:
=SUM(IF(A:A<>"",1,0))
You must press CTRL + SHIFT + ENTER because this is an array formula.
INDEX returns a value by index position in an array and ROWS then is used to specify the last position of the array.
=LET(array,A1:A10,INDEX(array,ROWS(array)))
Also works for multiple columns when setting the parameter [column_num] of INDEX to 0:
=LET(array,A1:C10,INDEX(array,ROWS(array),0))
A simple one which works for me:
=F7-INDEX(A:A,COUNT(A:A))
Okay, so I had the same issue as the asker, and tried both top answers. But only getting formula errors. Turned out that I needed to exchange the "," to ";" for the formulas to work. I am using XL 2007.
Example:
=LOOKUP(2;1/(A:A<>"");A:A)
or
=INDEX(A:A;MAX((A:A<>"")*(ROW(A:A))))
For version tracking (adding the letter v to the beginning of the number), I found this one to work well in Xcelsius (SAP Dashboards)
="v"&MAX(A2:A500)