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I Have a column which contains multiple unique and duplicate values and I'm looking to extract only the non repeating values. How do i go about it?
Example:
A2: 28; 33; 34; 37; 44
A3: 28; 34; 37
I'm trying to get:
A4: 33; 44
example
I've tried finding an answer but couldn't find a solution for this exact problem.
=LET(a,TEXTJOIN(";",,B2:B4),UNIQUE(--TEXTSPLIT(a,";"),TRUE,TRUE))
I don´t see a way of doing this using only formulas. The best approach would be to save those values as a .csv file, and importing that csv file into Excel. Then, using Power Query, you would do the necessary transformations in order to get the desired result.
Here is a step by step solution:
Get your data into a .csv file
Import the csv file by going into Data > From Text/CSV,= and selecting the file. Then, select the delimiter "Semicolon" and click "Transform Data" to open Power Query:
With Power Query open, select all columns by pressing Ctrl + A, and then go to the "Transform" tab and click "Unpivot Columns". You should have something like this:
Delete the "Attribute" column
Remove duplicates from "Value" column
Click "Close & Load" in the Home tab
You then will have the desired result:
I have an answer which ignores any spaces between the values and formats the result by putting only one space between the values. Call the function with two parameters, the values of the two cells to be merged:
Public Function Uniques(stra As String, strb As String) As String
'Uniques("11; 12; 13; 14; 15", " 11;11; 14; 15; 88; 16 ") ==> "12; 13; 88; 16"
Dim ar() As String, delim As String, ss As String, s As String, alen As Integer
Dim z As Integer, p As Integer, c As Integer
delim = ";"
s = Replace(stra & delim & strb, " ", "")
ar = Split(s, delim)
s = delim & s & delim
alen = UBound(ar)
For c = 0 To alen
If ar(c) <> "" Then
ss = delim & ar(c) & delim
p = InStr(1, s, ss)
If (p > 0) Then
p = InStr(p + 1, s, ss)
If p > 0 Then
s = Replace(s, delim & ar(c), "")
For z = c + 1 To alen
If ar(z) = ar(c) Then ar(z) = ""
Next
End If
End If
End If
Next
If (s = delim) Then
Uniques = ""
Else
s = Mid(s, 2, Len(s) - 2)
s = Replace(s, delim, delim & " ")
Uniques = s
End If
End Function
if the two cells have the same value returns empty string ("")
Use Reduce, Textsplit and Hstack to split each row and add it to a single-row array, then use Reduce again to check the number of times each element of the array occurs, and concatenate it to the output if it only occurs once.
=LET(
data, DROP(
TOCOL(A:A, 1),
1
),
row, DROP(
REDUCE(
"",
data,
LAMBDA(a, c,
HSTACK(
a,
TEXTSPLIT(
c,
"; "
)
)
)
),
,
1
),
MID(
REDUCE(
"",
row,
LAMBDA(a, c,
IF(
SUM(
N(
c =
row
)
) = 1,
a & "; " &
c,
a
)
)
),
3,
99
)
)
I want to separate a character string using the special characters in that string as cutting lines. After each division the next group of strings should be copied in the next column. The picture below shows how it should work.
My first approach doesn't work and maybe it's too complicated. Is there a simple solution to this task?
Sub SeparateString()
Dim i, j, k, counterA, counterB As Integer
Dim str1, str2 As String
Const Sonderz As String = "^!§$%&/()=?`*'_:;°,.-#+´ß}][{³²"
For i = 1 To Worksheets("Tabelle1").Range("A1").End(xlDown).Row
counterA = 0
For j = 1 To Len(Worksheets("Tabelle1").Range("A" & i))
counterB = 0
For k = 1 To Len(Sonderz)
If Mid(Worksheets("Tabelle1").Range("A" & i), j, 1) = Mid(Sonderz, k, 1) Then
counterA = counterA + 1
End If
If Mid(Worksheets("Tabelle1").Range("A" & i), j, 1) <> Mid(Sonderz, k, 1) And counterA = 0 And counterB = 0 Then
Worksheets("Tabelle1").Range("B" & i) = Worksheets("Tabelle1").Range("B" & i) & Mid(Worksheets("Tabelle1").Range("A" & i), j, 1)
counterB = counterB + 1
End If
Next k
Next j
Next i
End Sub
If you are interested and you do have access to Microsoft 365's dynamic arrays:
Formula in B1:
=LET(X,MID(A1,SEQUENCE(LEN(A1)),1),TRANSPOSE(FILTERXML(CONCAT("<t><s>",IF(ISNUMBER(FIND(X,"^!§$%&/()=?`*'_:;°,.-#+´ß}][{³²")),"</s><s>",X),"</s></t>"),"//s")))
Or nest a SUBSTITUTE() if you need to return string variables:
=LET(X,MID(A1,SEQUENCE(LEN(A1)),1),TRANSPOSE(SUBSTITUTE(FILTERXML(CONCAT("<t><s>'",IF(ISNUMBER(FIND(X,"^!§$%&/()=?`*'_:;°,.-#+´ß}][{³²")),"</s><s>'",X),"</s></t>"),"//s"),"'","")))
If VBA is a must, you could think about a regular expression to replace all the characters from a certain class with a uniform delimiter to use Split() on:
Sub Test()
Dim s As String: s = "CD!02?WX12EF"
Dim arr() As String
With CreateObject("vbscript.regexp")
.Global = True
.Pattern = "[!§$%&\/()=?`*'_:;°,.#+´ß}\][{³²^-]"
arr = Split(.Replace(s, "!"), "!")
End With
For Each el In arr
Debug.Print el
Next
End Sub
The caret has been moved from being the 1st character to any but the first to prevent a negated-character class; also the hyphen has been moved to the back to prevent an array-construct of characters. Funny enough, if you actually want to be less verbose you could throw these character in a more condense class [!#-/:;?[]-`{}§=°´ß³²].
Assuming the first data is in cell A2,
I would go with the simple use of find() with left() mid() and right()
=left(A2,find("!",A2,1)-1)
then:
=mid(A2,find("!",A2,1)+1,find("?",A2,1)-find("!",A2,1)-1)
and:
=right(A2,len(A2)-find("?",A2,1))
Tested and working with one correction done.
You can also do this in Power Query which has a command to split by ANY delimiter.
In the code below, I generate a list of all possible special characters defined as characters NOT in the set of A..Za..z0..9 and you can easily add to that list by editing the code if you want to include other characters in the permitted list.
Edit: If you only have a few special characters, you can just hard-code the list, eg {"!","?"} instead of using List.Generate, but in your question you did not necessarily restrict the list of special characters, even though those are the only two showing in your examples
To use Power Query:
Select some cell in your Data Table
Data => Get&Transform => from Table/Range
When the PQ Editor opens: Home => Advanced Editor
Make note of the Table Name in Line 2
Paste the M Code below in place of what you see
Change the Table name in line 2 back to what was generated originally.
Read the comments and explore the Applied Steps to understand the algorithm
let
//change Table name in next line to reflect actual table name
Source = Excel.CurrentWorkbook(){[Name="Table15"]}[Content],
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Source", type text}}),
//Generate list of "special characters" for splitting
//the List.Contains function contains the non-special characters
splitterList = List.RemoveNulls(
List.Generate(()=>0,
each _ <= 255,
each _ +1,
each if List.Contains({"A".."Z","a".."z","0".."9"}, Character.FromNumber(_)) then null else Character.FromNumber(_))),
splitIt = Table.SplitColumn(#"Changed Type", "Source",
Splitter.SplitTextByAnyDelimiter(splitterList))
in
splitIt
I cannot extract the postal/zip code of a given address cell that comes like this :
"108, avenue du Grand Sud 37 170 CHAMBRAY les TOURS".
I have used :
=RECHERCHE(9^9;--("0"&STXT(A2;MIN(CHERCHE({0.1.2.3.4.5.6.7.8.9};A2&"0 123456789"));LIGNE($1:$100))))
Which sometimes works, sometimes not depending on the street number starting the address (here "108,").
The problem is the space of the pattern "37 170". I would like to remove the blank space in the pattern. Is there a regex way to search this pattern "## ###", and then to remove this poisonous blank space?
Thank you for your tricks.
I have tried this piece of code :
Function toto(r, Optional u = 0)
Application.Volatile
Dim i%, j%, adr$, cp$, loca$, x
x = Split(r)
For i = 0 To UBound(x)
If x(i) Like "#####" Then Exit For
Next
If i > UBound(x) Then
adr = r.Value 'facultatif
Else
cp = x(i)
For j = 0 To i - 1: adr = adr & x(j) & " ": Next
adr = Left$(adr, Len(adr) + (Len(adr) > 1))
For j = i + 1 To UBound(x): loca = loca & x(j) & " ": Next
loca = Left$(loca, Len(loca) + (Len(loca) > 1))
End If
x = Array(adr, cp, loca)
If 0 < u And u < 4 Then toto = x(u - 1) Else toto = x
End Function
The above code works fine for splitting addresses including street number, zip code, and city name. But it does not work when the zip code is ## ### = 2 digit integer - space - 3 digit integer.
Edit: 01 June 2021
Since it seems my question is not clear enough, let's rephrase :
Given an Excel worksheet containing in each cell of column A, from saying A1 down to A10000, complete addresses like this one :
"2 rue Rene cassin Centre Commercial Châlon 2 Sud 71 100 CHALON SUR SAONE"
or this one :
"15, Rue Emile Schwoerer 68 000 COLMAR"
Where "71 100" and "68 000" are a zip code in incorrect format because of the extra space between the 2 first digits and 3 last digits.
I need to split the Ai cell content in order to obtain :
in cell Bi : the text (street, etc.) placed left before the 2 first digits of the "wrong" zip code,
in cell Ci : the zip code with its correct format ("71100" and not "71 100"),
in cell Di : the text (city name) after the zip code.
It's a kind of left and right extraction around the zip code.
The above code that I have posted does not work.
In order to obtain the correct zip code format, I have tried the regex following function :
Function FindReplaceRegex(rng As Range, reg_exp As String, replace As String)
Set myRegExp = New RegExp
myRegExp.IgnoreCase = False
myRegExp.Global = True
myRegExp.Pattern = reg_exp
FindReplaceRegex = myRegExp.replace(rng.Value, replace)
End Function
But I am unable to determine the correct regular expression pattern to get rid of the space in the zip code.
PEH gave me the following pattern :
(.*)([0-9]{2} ?[0-9]{3})(.*)
When using the function, I have tried to define the replacement pattern by:
(.*)([0-9]{2}[0-9]{3})(.*)
But it would not work. Hope this will clarify my question.
Any idea is welcome. Thanks
If these input strings always have the same pattern, try:
=CONCAT(FILTERXML("<t><s>"&SUBSTITUTE(A1," ","</s><s>")&"</s></t>","//s[.*0=0]"))
Depending on your needs/edge-cases, you could add more xpath expressions.
If this is VBA, I have a fix for you (please forgive the crappy naming convention, I'm scribbling this down in work while waiting for SQL to refresh):
Sub test1()
a0 = Cells(1, 1) 'Get the text, in this case "108, avenue du Grand Sud 37 170 CHAMBRAY les TOURS"
aa = Replace(a0, ",", " ") 'Make all delimiters of same type, so removing commas, you may need to add more replace work here?
ab = Application.Trim(aa) 'Reduce all whitespace to single entries, i.e. " " rather than " "
ac = Split(ab, " ", -1) 'Now split by that single whitespace entry
Dim txt()
i2 = 0
lastIsNumeric = False
For i1 = 0 To UBound(ac) - 1 'Step through each entry in our "split" list
If IsNumeric(ac(i1)) = True And IsNumeric(ac(i1 + 1)) = True Then
'Two numbers back to back, join
ReDim Preserve txt(i2)
txt(i2) = ac(i1) + ac(i1 + 1)
i2 = i2 + 1
i1 = i1 + 1
Else
'Not two numbers back to back, don't join
ReDim Preserve txt(i2)
txt(i2) = ac(i1)
i2 = i2 + 1
End If
Next i1
If IsNumeric(ac(UBound(ac))) = False Then
'Need to add last entry to txt()
ReDim Preserve txt(UBound(txt) + 1)
txt(UBound(txt)) = ac(UBound(ac))
End If
End Sub
edit 2021-06-01:
The above will generate a list (txt) of all the entries within your address. You can then reassemble if you wish, or extract out the postcode only.
If you want it as a function, then it would be:
Public Function getPostcode(a0)
aa = Replace(a0, ",", " ")
ab = Application.Trim(aa)
ac = Split(ab, " ", -1)
Dim txt()
i2 = 0
lastIsNumeric = False
For i1 = 0 To UBound(ac) - 1
If IsNumeric(ac(i1)) = True And IsNumeric(ac(i1 + 1)) = True Then
'Two numbers back to back, join
ReDim Preserve txt(i2)
txt(i2) = ac(i1) + ac(i1 + 1)
i2 = i2 + 1
i1 = i1 + 1
Else
'Not two numbers back to back, don't join
ReDim Preserve txt(i2)
txt(i2) = ac(i1)
i2 = i2 + 1
End If
Next i1
If IsNumeric(ac(UBound(ac))) = False Then
'Need to add last entry to txt()
ReDim Preserve txt(UBound(txt) + 1)
txt(UBound(txt)) = ac(UBound(ac))
End If
'Re-assemble string for return
rtnTxt = ""
For i1 = 0 To UBound(txt)
rtnTxt = rtnTxt & " " & txt(i1)
Next i1
getPostcode = rtnTxt
End Function
So i am trying to extract just a specific part of text strings (part numbers) for a vlookup,
I have got a formula that gives me the part number I want for most cases, which stops the LEFT formula after it reaches the last number in the text string. Some of the part numbers have more numbers further in the text string.
I need the formula to return the text string until the last number but to stop once it changes back to Alpha again.
I hope this makes sense I have attached a screenshot to example the issue and my code. If you look in column R and see the FR70YERXX/3, that should stop before the Y but i simply can't get my head round this one.
=LEFT(J2,MAX(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},J2,ROW(INDIRECT("1:"&LEN(J2)))),0)))
Put the following code into a module in Excel
Function LeftCode(s As String) As String
i = 1
While Not ((Mid(s, i, 1) >= "0") And (Mid(s, i, 1) <= "9")) And (i <= Len(s))
i = i + 1
Wend
If i > Len(s) Then
LeftCode = s
Else
While Not ((Mid(s, i, 1) < "0") Or (Mid(s, i, 1) > "9")) And (i <= Len(s))
i = i + 1
Wend
If i > Len(s) Then
LeftCode = s
Else
LeftCode = Left(s, i - 1)
End If
End If
End Function
Then in column R type:
=LeftCode(J2)
and copy this down
Explanation
Create a function to take a string and return a string
Function LeftCode(s As String) As String
Starting at the first character, loop through the string one character at a time until you find a digit (0-9)
i = 1
While Not ((Mid(s, i, 1) >= "0") And (Mid(s, i, 1) <= "9")) And (i <= Len(s))
i = i + 1
Wend
If we have reached the end, with no numbers, then return it all
If i > Len(s) Then
LeftCode = s
Otherwise continue to loop through each character until we find a non digit
Else
While Not ((Mid(s, i, 1) < "0") Or (Mid(s, i, 1) > "9")) And (i <= Len(s))
i = i + 1
Wend
If we reach the end then we want the whole thing
If i > Len(s) Then
LeftCode = s
Else
Otherwise we want up to the last but one character
LeftCode = Left(s, i - 1)
End If
End If
End Function
It seems you want to to truncate until the first combination of digit is followed by non-digit. If so try this:
=LEFT(H2,AGGREGATE(15,6,ROW($1:$98)
/ISNUMBER(VALUE(MID(H2,ROW($1:$98),1)))
/ISERROR(VALUE(MID(H2,ROW($2:$99),1))),1))
Solution 1
Well I can give a long ugly looking formula if you are willing to use. Try this
=-LOOKUP(1,-LEFT(MID(A1,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),LEN(A1)-MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0123456789"))+1),ROW(INDIRECT("1:"&LEN(MID(A1,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),LEN(A1)-MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0123456789"))+1))))))
See image for reference.
Solution 2
Using helper column
In Cell B2 enter the following formula to get the position of first number
=MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A2&"0123456789"))
Then in Cell C2 to get the string after removing alphabets preceding first number, enter
=RIGHT(A2,LEN(A2)-B2+1)
Finally, in Cell D2 enter the below formula
=IFERROR(-LOOKUP(1,-LEFT(C2,ROW(INDIRECT("1:"&LEN(C2))))),"")
Drag/Copy down as required. See image for reference.
I've made this large excel sheet and at the time i didn't know i'd need to sort this table through categories.
I have in a column (J here ) the description of the line and the category joint. (example: "Shipment of tires for usin'ss")
The only way i was able to sort the table the way i wanted was to build a category column using this :
=IF(COUNTIF(J3;"*usi*");"Usins";IF(COUNTIF(J3;"*remis*");"Remise";IF(COUNTIF(J3;"*oe*");"Oenols";IF(COUNTIF(J3;"*KDB*");"KDB";IF(COUNTIF(J3;"*vis*");"cvis";IF(COUNTIF(J3;"*amc*");"AMC";0))))))
usi for instance is a segment of a category name, that i sometimes wrote as
usin'ss
usin
usin's
usins
'cause you know smart.
Anyway, how do i translate =If(If(If...))) into something readable in VBA like:
If...then
If... then
Example of "IF ... ELSE" in EVBA
IF condition_1 THEN
'Instructions inside First IF Block
ELSEIF condition_2 Then
'Instructions inside ELSEIF Block
...
ELSEIF condition_n Then
'Instructions inside nth ELSEIF Block
ELSE
'Instructions inside Else Block
END IF
Example of Case Switch in EVBA
Select Case score
Case Is >= 90
result = "A"
Case Is >= 80
result = "B"
Case Is >= 70
result = "C"
Case Else
result = "Fail"
End Select
Both cases work off a waterfall type logic where if the first condition is met, then it does not continue, but if condition 1 is not met then it checks the next, etc.
Example usage:
Function makeASelectAction(vI_Score As Integer) As String
Select Case vI_Score
Case Is >= 90
makeASelectAction = "A, fantastic!"
Case Is >= 80
makeASelectAction = "B, not to shabby."
Case Is >= 70
makeASelectAction = "C... least your average"
Case Else
makeASelectAction = "Fail, nuff said."
End Select
End Function
Function makeAnIfAction(vS_Destination As String, vS_WhatToSay As String, Optional ovR_WhereToStick As Range, Optional ovI_TheScore As Integer)
If vS_Destination = "popup" Then
MsgBox (vS_WhatToSay)
ElseIf vS_Destination = "cell" Then
ovR_WhereToStick.value = vS_WhatToSay
ElseIf vS_Destination = "select" Then
MsgBox makeASelectAction(ovI_TheScore)
End If
End Function
Sub PopMeUp()
Call makeAnIfAction("popup", "Heyo!")
End Sub
Sub PopMeIn()
Call makeAnIfAction("cell", "Heyo!", Range("A4"))
End Sub
Sub MakeADescision()
Call makeAnIfAction(vS_Destination:="select" _
, vS_WhatToSay:="Heyo!" _
, ovI_TheScore:=80 _
)
End Sub
It will show you how to send variables to functions and how to call said function, it will show you how use optional parameters, how a function and interact with another function or sub, how do write a value to a sheet or spit out a messagebox. The possabilities are endless. Let me know if you need anything else cleared up or coded out.
You seem to be using CountIf just to see if the contents of the cell matches a certain pattern and, if so, give a replacement string. In VBA you can use the Like operator for pattern matching. In any event -- here is a function I wrote which, when passed a string and a series of pattern/substitution strings, loops through the patterns until it finds a match and then returns the corresponding substitution. If no match is found, it returns an optional default value (the last argument supplied). If no default is supplied, it returns #N/A.
The code illustrates that sometimes complicated nested ifs can be replaced by a loop which iterates through the various cases. This is helpful when you don't know the number of cases before hand.
Function ReplacePattern(s As String, ParamArray patterns()) As Variant
Dim i As Long, n As Long
n = UBound(patterns)
If n Mod 2 = 0 Then n = n - 1
For i = 0 To n Step 2
If s Like patterns(i) Then
ReplacePattern = patterns(i + 1)
Exit Function
End If
Next i
If UBound(patterns) Mod 2 = 0 Then
ReplacePattern = patterns(n + 1)
Else
ReplacePattern = CVErr(xlErrNA)
End If
End Function
Your spreadsheet formula is equivalent to
=ReplacePattern(J3,"*usi*","Usins","*remis*","Remise","*oe*","Oenols","*KDB*","KDB","*vis*","cvis","*amc*","AMC",0)