Extract a folder name from file path - excel

Question

I have a file path (which is a connection path for the worksheet) in the following format:
C:\ExcelFiles\Data\20140522\File1_20140522.csv
I want to extract 20140522.
I tried using responses of How to extract groups of numbers from a string in vba, but they don't seem to work in my case.

Answer 1

please find below
Filename = "C:\ExcelFiles\Data\20140522\File1_20140522.csv"
a = Replace(Mid(Filename, InStrRev(Filename, "_") + 1, Len(Filename)), ".csv", "")

Answer 2

Try the following. Folder is selected.
Sub Folder_S()
Dim sFolder As FileDialog
On Error Resume Next
Set sFolder = Application.FileDialog(msoFileDialogFolderPicker)
If sFolder.Show = -1 Then
Folder_Select sFolder.SelectedItems(1), True
End If
End Sub
Sub Folder_Select(ByVal SourceFolderName As String, ByVal IncludeSubfolders As Boolean)
Dim FSO As Object
Dim SourceFolder As Object
Dim FileItem As Object
Dim strFile As String
Dim FileName As Variant
Dim pathParts() As String
Dim pathPart As String
Dim i As Long
Set FSO = CreateObject("Scripting.FileSystemObject")
Set SourceFolder = FSO.GetFolder(SourceFolderName)
pathParts = Split(SourceFolder.Path, Application.PathSeparator)
pathPart = SourceFolder.Path
For i = 0 To UBound(pathParts)
If pathParts(i) = "20140522" Then
pathPart = pathParts(i - 0)
Exit For
End If
Next i
Row = ActiveCell.Row
With CreateObject("Scripting.Dictionary")
For Each FileItem In SourceFolder.Files
strFile = FileItem.Name
.Item(strFile) = Array(FileItem.Name)
Next FileItem
If .Count > 0 Then
For Each FileName In .Items
Cells(Row, 2).Formula = pathPart
Next FileName
End If
End With
End Sub

Answer 3

I found your question by searching a solution how to get a folder path from a file that is inside this folder path. But your question doesn't match exactly what I need. For those who by your question title will find it for the same purpose as I found, below is my function:
Function getFolderPathFromFilePath(filePath As String) As String
Dim lastPathSeparatorPosition As Long
lastPathSeparatorPosition = InStrRev(filePath, Application.PathSeparator)
getFolderPathFromFilePath = Left(filePath, lastPathSeparatorPosition - 1)
End Function
In some solutions for this purpose, I used FSO, but it takes resources, and I think it isn't worthy to create FSO object if you need it only for this simple function.

Answer 4

the accepted answer is not accurate to read the folder name. here is more dynamic code.
use splitter which splits string based on delimeter and makes an array. now read the second last element in array, thats the folder name.
Dim fileName As String
fileName = "C:\ExcelFiles\Data\20140522\File1_20140522.csv"
Dim vPathSplitter As Variant
vPathSplitter = Split(fileName, "\")
MsgBox (vPathSplitter(UBound(vPathSplitter) - 1))

Answer 5

The below answer gets your file path from a range, rather than a fixed string. Much more handy if your planning on getting your filename from your sheets, which I imagine you are.
Sub GetFileDate()
Dim filename As String
filename = Sheets("Sheet1").Range("C9").Value 'Or Wherever your file path is
MsgBox Replace(Right(filename, 12), ".csv", "")
End Sub
This assumes the numbers your extracting will ALWAYS be dates in YYYYMMDD format and the file type is always .csv