Tried the following command, it lists all the lines including file names
which are not matching the given pattern.
grep -nrv "^type.* = .*"
"But what we need is list of file names in a folder with content
which does not have even a single occurrence of above pattern."
Your help will be really appreciated.
You need the -L option:
grep -rL '^type.* = .*' directory_name
From the GNU grep manual:
-L, - -files-without-match
Suppress normal output; instead print the name of each input file from which no output would normally have been printed. The scanning will stop on the first match.
I want to find the count of certain pattern in a text file which contains lot of mixed patterns also using linux shell command.
I have a text file which contains below patterns,
[--------------]
[+--------------+]
[+----------+------------+--------------------+]
[+---------------------+---------------------+]
How to find exact count of only first pattern [--------------]?
Note: Don't include square bracket as a pattern. Only special character inside square bracket is a pattern.
cat ./file | sed -e 's/\]/\]\n/' |grep "\[--------------\]" -c
cat reads file
sed replace ] with ]\n
grep searches every line for your expression and prints the number of lines -c
Input:
Text file: backup_list.txt
/home/common/xyz_V*.txt
/home/common/hello.txt
/home/mutaq/xya_*_logs.txt
/home/mutaq/xygs.txt
Text: /home/mutaq/xya_Juvi_V1.01_logs.txt
Now i want to match this text in the file.
As the file has a line /home/mutaq/xya_*_logs.txt which is similar to the text /home/mutaq/xya_Juvi_V1.01_logs.txt considering asterisk(*) as the character to represent multiple character in between.
now i want to know whether the text exists in the file or not.
Using grep, i cannot differentiate with asterisk.
one way i found that i can first iterate through the backup_list.txt
and invoke ls command for each of the line and store the same in some place then, i can directly match the text with the stored value.
But is there any better way of doing this, such that i can directory search the text withing that file ?
A first answer could be grep -f option, that allow grep to take parttern to search in the file pass in parameter. You could try :
ls /path/to/files/ | grep -f backup_list.txt
But to give backup_list.txt content to grep as pattern, '*' have to be replace by '.*' to say any character 0 or n time and '.' have to be replace by '\.' to match '.' character and not any character.
You can make replacement with sed.
Hope this help.
I have a file "test.txt" with the lines below and also lot bunch of extra stuff after the "version"
soainfra_metrics{metric_group="sca_composite",partition="test",is_active="true",state="on",is_default="true",composite="test123"} map:stats version:1.0
soainfra_metrics{metric_group="sca_composite",partition="gello",is_active="true",state="on",is_default="true",composite="test234"} map:stats version:1.8
soainfra_metrics{metric_group="sca_composite",partition="bolo",is_active="true",state="on",is_default="true",composite="3415"} map:stats version:3.1
soainfra_metrics{metric_group="sca_composite",partition="solo",is_active="true",state="on",is_default="true",composite="hji"} map:stats version:1.1
I tried:
egrep -r 'partition|is_active|state|is_default|composite' test.txt
It's displaying every line, but I need only specific mentioned fields like this below,ignoring rest of the data/stuff or lines
in a nut shell, i want to display only these fields from a line not the rest
partition="test",is_active="true",state="on",is_default="true",composite="test123"
partition="gello",is_active="true",state="on",is_default="true",composite="test234"
partition="bolo",is_active="true",state="on",is_default="true",composite="3415"
partition="solo",is_active="true",state="on",is_default="true",composite="hji"
If your version of grep supports Perl-style regular expressions, then I'd use this:
grep -oP '.*?,\K[^}]+' file
It removes everything up to the first comma (\K kills any previous output) and prints everything up to the }.
Alternatively, using awk:
awk -F'}' '{ sub(/[^,]+,/, ""); print $1 }' file
This sets the field separator to } so the part you're interested in is the first field. It then uses sub to remove the part up to the first comma.
For completeness, you could also use sed:
sed 's/[^,]*,\([^}]*\).*/\1/' file
This captures the part after the first , up to the } and replaces the content of the line with it.
After the grep to pick out the lines you want, use sed to edit the lines:
sed 's/.*\(partition[^}]*\)} map.*/\1/'
This means: "whenever you see anything .*, followed by partition and
any number of non-}, then } map and anything else, grab the part
from partition up to but not including the brace \(...\) as group 1.
The replacement text is just group 1 \1.
Use a pipe | to connect the output of egrep to the input of sed:
egrep ... | sed ...
As far as i understood your file might have more lines you don't want to see, so i would use:
sed -n 's/.*\(partition.*\)}.*/\1/p' file
we use -n p to show only lines where we made substitution. The substitution part just gets the part of the line you need substituting the whole line with the pattern.
This might work for you (GNU sed):
sed -r 's/(partition|is_active|state|is_default|composite)="[^"]*"/\n&\n/g;s/[^\n]*\n([^\n]*)\n[^\n]*/\1,/g;s/,$//' file
Treat the problem as if it were a "decomposed club sandwich". Identify the fillings, remove the bread and tidy up.
I am trying to extract no.s from a file, so I created a script, but grep is giving error:grep: line too long. Can anyone tell me where am I wrong. command is:
echo $(cat filename|grep '\<[0-9]*\>')
Thanks in advance
grep is line-oriented; it will print matching lines to output. Probably you have a huge line in your file, and the resulting line cannot be converted into a string value by shell, as $(...) requires.
First of all, try just cat filename | grep '\<[0-9]*\>' > results and see what is in the results file. Maybe it's enough.
But if you have multiple numbers in a line and you want to extract them all, use -o: grep -o '\<[0-9]*\>'. This will print only matching parts, every match on a new line, even if original matches are on the same line. If you need line numbers, too, add -n.