I have been using nlapiCreateFile() and nlapiSubmitFile() to create a CSV file from an array, and have run in to two problems I cant seem to figure out. When the CSV file is saved excel prints out each element of the array in to its own cell like it should but it prints it all on the same row (1a, 1b, 1c, 1d.. etc) I would rather have the array print downwards in the same column rather then row(1a, 2a, 3a, 4a... etc) if possible. But im not sure how to approach this.
var file1 = nlapiCreateFile('names.csv', 'CSV', names);
file1.setFolder(295767);
nlapiSubmitFile(file1);
The second thing I cant seem to figure out, if I wanted to print a second array in the same file, how would I approach that? For example the names array in the first columns and another array in the 2nd column.
Instead of using an Array for the third parameter of nlapiCreateFile(), try using a string that uses the , for column delimiters, and \n as a line separator.
I know this is rather old, but for those who are trying to figure this out, you want to use the join method:
var file1 = nlapiCreateFile('names.csv', 'CSV', names.join("\n"));
file1.setFolder(295767);
nlapiSubmitFile(file1);
This returns a string of the array, with the elements separated by the provided parameter. In this case, we want one column with all of the elements so we choose \n or new line.
For appending to a file, I believe you will have to load the record again, which will return and nlobjFile Object https://debugger.sandbox.netsuite.com/app/help/helpcenter.nl?fid=section_N3066995.html#bridgehead_N3067099
Then you can add to it, and then submit again.
Related
I have a column containing a string value as shown is the example below :
ZAE/GER-ERT/HEZ/PDC
The idea is to extract the first trigraph (ZAE in this extract) and a second one based a rule.
The rule is, if there is a '-' separating two trigraphs, we don't extract them, we just take the first trigraph after a '/' and without a '-' after it.
We then use a - to separate the two results, here is the aim for the example : ZAE-HEZ
I would like to get this value in a new calculated column.
I've tried to play with the indexes based on the Find() and ExtractRX() functions, but couldn't make it work.
Thanks in advance !
I am not sure this is the simplest way, but it works for your example (assuming the strings are always alphanumeric in chunks of 3).
You can do it via an intermediate column (for sanity, although you could put the [tmp] formula directly into the final column):
[tmp] as
RXReplace(RXReplace([your_column],'\\w{3}-\\w{3}','','g'),'/+','/','g')
This removes any double trigraph like GER-ERT and then removes any leftover double /
Then the final column splits [tmp] by / and concatenates the first and second item
Concatenate(Split([tmp],'/',1),'-',Split([tmp],'/',2))
I'm using the following code:
plugara=['CNPJ', 56631781000177, 21498104000148, 3914296000144, 28186370000184]
plugara=map(str,plugara)
with open(result.csv, 'w') as f:
wr = csv.writer(f,dialect='excel')
wr.writerows(plugara)
The result I'm getting is putting a comma between each character and is breaking into a different column:
I would like it to be without those commas like this:
Any ideas?
The writerows method that you're calling expects its argument to be an iterable containing rows. Each row should be iterable itself, with its values being the items in the row. In your case, the values are strings, which can be iterated upon to give their characters. Unfortunately, that's not what you intended!
Exactly how to fix this issue depends on what you want the output to be.
If you want your output to consist of a single row, then just change your call to writerow to instead of writerows (note the plural). The writerow method will only write a single row out, rather than trying to write several of them at once.
On the other hand, if you want many rows, with just one item in each one (forming a single column), then you'll need to transform your data a little bit. Rather than directly passing in your list of strings, you need to produce an iterable of rows with one item in them (perhaps 1-tuples). Try something like this:
wr.writerows((item,) for item in plugara)
This call uses a generator expression to transform each string from plugara into a 1-tuple containing the string. This should produce the output you want.
I have many Import files, which look like this
So there are sales values per Team Member, but NO period inside.
The period is coded in the Path like:
AllData\201501\Revenues.txt
AllData\201502\Revenues.txt
AllData\201503\Revenues.txt
I want to have the Periode from the path on each data row, so my final output table should look like this:
So I must bring the period from the path inside the file anyway.
The question how to access the path is solved in perfect example here:
How can I save a path criteria when I import from folders?
But there I have still the period on the "whole" text, not on the row.
In the linked question you can change the custom column formula from:
Text.FromBinary([Content])
to
Text.Split(Text.FromBinary([Content]), "#(000a)")
(depending on how line breaks are represented, you may need to use "#(000a)#(000d)" instead).
This will split the text at each new line, and you'll get a list of the name;value pairs. Click on the box with the two arrows next to the column name to expand the column. Each row should now have the period associated with the name;value pair. Finally, split the column by delimiter on the semicolon to separate the name from the value.
There are 2 options, both involve horrible looking equations.
First option, we assume the paths are going to have the period in the same position in the string.
for the example, we want the number between the 1st and 2nd slashes.
=TRIM(LEFT(SUBSTITUTE(MID(A1,FIND("|",SUBSTITUTE(A1,"\","|",1))+1,LEN(A1)),"\",REPT(" ",LEN(A1))),LEN(A1)))
If it's between a different set of slashes, alter the ,1 to tell the formula which slash to start from. If the number of slashes can be different, then we will have to try for the second option.
Second option, we assume that those are the only numbers in the path.
This formula will extract those numbers:
=SUMPRODUCT(MID(0&A1,LARGE(INDEX(ISNUMBER(--MID(A1,ROW($1:$25),1))* ROW($1:$25),0),ROW($1:$25))+1,1)*10^ROW($1:$25)/10)
Note that this will extract all the numbers from the string. If the path contains numbers, then these will get added to the string. e.g. C:\2014Data\201401\Revenues.txt would return 2014201401
If this doesn't take care of it, then it may be easier putting a column into the table yourself
I'm trying to load the following dataset:
Afghanistan,5,1,648,16,10,2,0,3,5,1,1,0,1,1,1,0,green,0,0,0,0,1,0,0,1,0,0,black,green
Albania,3,1,29,3,6,6,0,0,3,1,0,0,1,0,1,0,red,0,0,0,0,1,0,0,0,1,0,red,red
Algeria,4,1,2388,20,8,2,2,0,3,1,1,0,0,1,0,0,green,0,0,0,0,1,1,0,0,0,0,green,white
...
Problem is it contains both integers and strings.
I found some information on how to get out the integers only.
But haven't been able to see if there's any way to get all the data.
My question is that possible ??
If that is not possible, is there then any way to find the numbers on each line and throw everything else away without having to choose the columns?
I need specifically since it seems I cannot use str2num on a whole line at a time.
Almost anything is possible, you just have to define your goal accurately.
Assuming that your database is stored as a text file, you can parse it line by line using textread, and then apply regexp to filter only the numerical fields (this does not require having prior knowledge about the columns):
C = textread('database.txt', '%s', 'delimiter', '\n');
C = cellfun(#(x)regexp(x, '\d+', 'match'), C, 'Uniform', false);
The result here is a cell array of cell array of strings, where each string corresponds to a numerical field in a specific line.
Since the numbers are still stored as strings, you'd probably need to convert them to actual numerical values. There's a multitude of ways to do that, but you can use str2num in a tricky way: it can convert delimited strings into an array of numbers. This means that if you concatenate all strings in a specific line back into one string, and put spaces in between, you can apply str2num on all of them at once, like so:
C = cellfun(#(x)str2num(sprintf('%s ', x{:})), C, 'Uniform', false);
The resulting C is a cell array of vectors, each vector containing the values of all numerical fields in the corresponding line. To access a specific vector, you can use curly braces ({}). For instance, to access the numbers of the second line, you would use C{2}.
All the non-numerical fields are discarded in the process of parsing, of course. If you want to keep them as well, you should use a different regular expression with regexp.
Good luck!
I have the list with like 100,000 site link strings
Each link is unique, but it has consistent ?Item=
Then, it's either nothing or it continues after & symbol.
My question is: How do I pull out the item numbers?
I know replace function can offer similar functionality, but it works with Fixed sizes, in my case string can be different in size.
Link example:
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555
or
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555&sdafsdfsdfsdf
In both cases I need to get JGFGGG55555 only
If this always is the last portion of the string, you can use the following:
=MID(A1, FIND("?Item=", A1) + 6, 99)
This assumes:
no item numbers will be over 99 digits.
no additional fields follow the item number.
Edit:
With the update to your question, it is apparent you have some strings with additional data after the ?Item= field. Without using VBA there is not a simple means of using MID and FIND to extract this.
However you could create a column which acts as a placeholder.
For example, create a column using:
=MID(A1,FIND("?Item=",A1)+6,99)
This gets you the following value: JGFGGG55555&sdafsdfsdfsdf
Next, create a column using:
=IF(ISERROR(FIND("&",B2)),B2,LEFT(B2,FIND("&",B2)-1))
This produces: JGFGGG55555 by searching the first value for a & and using the portion before it. If it is not found, the first value is simply repeated.
This formula should work for both the examples given:
=MID(A1,FIND("=",A1),IFERROR(LEN(A1)-FIND("&",A1,FIND("=",A1))-1,LEN(A1)+1-FIND("=",A1)))