time command output on an already running process - linux

I have a process that spawns some other processes,
I want to use the time command on a specific process and get the same output as the time command.
Is that possible and how?

I want to use the time command on a specific process and get the same output as the time command.
Probably it is enough just to use pidstat to get user and sys time:
$ pidstat -p 30122 1 4
Linux 2.6.32-431.el6.x86_64 (hostname) 05/15/2014 _x86_64_ (8 CPU)
04:42:28 PM PID %usr %system %guest %CPU CPU Command
04:42:29 PM 30122 706.00 16.00 0.00 722.00 3 has_serverd
04:42:30 PM 30122 714.00 12.00 0.00 726.00 3 has_serverd
04:42:31 PM 30122 714.00 14.00 0.00 728.00 3 has_serverd
04:42:32 PM 30122 708.00 16.00 0.00 724.00 3 has_serverd
Average: 30122 710.50 14.50 0.00 725.00 - has_serverd
If not then according to strace time uses wait4 system call (http://linux.die.net/man/2/wait4) to get information about a process from the kernel. The same info returns getrusage but you cannot call it for an arbitrary process according to its documentation (http://linux.die.net/man/2/getrusage).
So, I do not know any command that will give the same output. However it is feasible to create a bash script that gets PID of the specific process and outputs something like time outpus then
This script does these steps:
1) Get the number of clock ticks per second
getconf CLK_TCK
I assume it is 100 and 1 tick is equal to 10 milliseconds.
2) Then in loop do the same sequence of commands while exists the directory /proc/YOUR-PID:
while [ -e "/proc/YOUR-PID" ];
do
read USER_TIME SYS_TIME REAL_TIME <<< $(cat /proc/PID/stat | awk '{print $14, $15, $22;}')
sleep 0.1
end loop
Some explanation - according to man proc :
user time: ($14) - utime - Amount of time that this process has been scheduled in user mode, measured in clock ticks
sys time: ($15) - stime - Amount of time that this process has been scheduled in kernel mode, measured in clock ticks
starttime ($22) - The time in jiffies the process started after system boot.
3) When the process is finished get finish time
read FINISH_TIME <<< $(cat '/proc/self/stat' | awk '{print $22;}')
And then output:
the real time = ($FINISH_TIME-$REAL_TIME) * 10 - in milliseconds
user time: ($USER_TIME/(getconf CLK_TCK)) * 10 - in milliseconds
sys time: ($SYS_TIME/(getconf CLK_TCK)) * 10 - in milliseconds
I think it should give roughly the same result as time. One possible problem I see is if the process exists for a very short period of time.
This is my implementation of time:
#!/bin/bash
# Uses herestrings
print_res_jeffies()
{
let "TIME_M=$2/60000"
let "TIME_S=($2-$TIME_M*60000)/1000"
let "TIME_MS=$2-$TIME_M*60000-$TIME_S*1000"
printf "%s\t%dm%d.%03dms\n" $1 $TIME_M $TIME_S $TIME_MS
}
print_res_ticks()
{
let "TIME_M=$2/6000"
let "TIME_S=($2-$TIME_M*6000)/100"
let "TIME_MS=($2-$TIME_M*6000-$TIME_S*100)*10"
printf "%s\t%dm%d.%03dms\n" $1 $TIME_M $TIME_S $TIME_MS
}
if [ $(getconf CLK_TCK) != 100 ]; then
exit 1;
fi
if [ $# != 1 ]; then
exit 1;
fi
PROC_DIR="/proc/"$1
if [ ! -e $PROC_DIR ]; then
exit 1
fi
USER_TIME=0
SYS_TIME=0
START_TIME=0
while [ -e $PROC_DIR ]; do
read TMP_USER_TIME TMP_SYS_TIME TMP_START_TIME <<< $(cat $PROC_DIR/stat | awk '{print $14, $15, $22;}')
if [ -e $PROC_DIR ]; then
USER_TIME=$TMP_USER_TIME
SYS_TIME=$TMP_SYS_TIME
START_TIME=$TMP_START_TIME
sleep 0.1
else
break
fi
done
read FINISH_TIME <<< $(cat '/proc/self/stat' | awk '{print $22;}')
let "REAL_TIME=($FINISH_TIME - $START_TIME)*10"
print_res_jeffies 'real' $REAL_TIME
print_res_ticks 'user' $USER_TIME
print_res_ticks 'sys' $SYS_TIME
And this is an example that compares my implementation of time and real time:
>time ./sys_intensive > /dev/null
Alarm clock
real 0m10.004s
user 0m9.883s
sys 0m0.034s
In another terminal window I run my_time.sh and give it PID:
>./my_time.sh `pidof sys_intensive`
real 0m10.010ms
user 0m9.780ms
sys 0m0.030ms

Related

Self duplicate background script

This is a background script test.
When run it launch two processes and I don't understand why.
One stop after sleep 20. And other forgets.
#!/bin/bash
back(){
n=0
while [ 1 ]
do
echo $n
n=$(($n+1))
sleep 5
done
}
back &
sleep 20
exit
command "ps -a" in call:
PID TTY TIME CMD
8964 pts/2 00:00:00 backgroundtest
8965 pts/2 00:00:00 backgroundtest
8966 pts/2 00:00:00 sleep
8982 pts/2 00:00:00 sleep
after sleep 20:
PID TTY TIME CMD
8965 pts/2 00:00:00 backgroundtest
9268 pts/2 00:00:00 sleep
then run forever...
why?
while [ 1 ] is an infinite loop. [ 1 ] is always true.
So back & is an infinite loop, started in background (&), then execution continues with sleep 20, which does end after 20 seconds, leaving you with two processes for 20 seconds (& starts a new process in background), then the infinite one after that.

perf : How to check processess running on particular cpu

Is there any option in perf to look into processes running on a particular cpu /core, and how much percentage of that core is taken by each process.
Reference links would be helpful.
perf is intended to do a profiling which is not good fit for your case. You may try to do sampling /proc/sched_debug (if it is compiled in your kernel). For example you may check which process is currently running on CPU:
egrep '^R|cpu#' /proc/sched_debug
cpu#0, 917.276 MHz
R egrep 2614 37730.177313 ...
cpu#1, 917.276 MHz
R bash 2023 218715.010833 ...
By using his PID as a key, you may check how many CPU time in milliseconds it consumed:
grep se.sum_exec_runtime /proc/2023/sched
se.sum_exec_runtime : 279346.058986
However, as #BrenoLeitão mentioned, SystemTap is quite useful for your script. Here is script for your task.
global cputimes;
global cmdline;
global oncpu;
global NS_PER_SEC = 1000000000;
probe scheduler.cpu_on {
oncpu[pid()] = local_clock_ns();
}
probe scheduler.cpu_off {
if(oncpu[pid()] == 0)
next;
cmdline[pid()] = cmdline_str();
cputimes[pid(), cpu()] <<< local_clock_ns() - oncpu[pid()];
delete oncpu[pid()];
}
probe timer.s(1) {
printf("%6s %3s %6s %s\n", "PID", "CPU", "PCT", "CMDLINE");
foreach([pid+, cpu] in cputimes) {
cpupct = #sum(cputimes[pid, cpu]) * 10000 / NS_PER_SEC;
printf("%6d %3d %3d.%02d %s\n", pid, cpu,
cpupct / 100, cpupct % 100, cmdline[pid]);
}
delete cputimes;
}
It traces moments when process is running on CPU and stops execution on that (due to migration or sleeping) by attaching to scheduler.cpu_on and scheduler.cpu_off probes. Second probe calculates time difference between these events and saves it to cputimes aggregation along with process command line arguments.
timer.s(1) fires once per second -- it walks over aggregation and calculates percentage. Here is sample output for Centos 7 with bash running infinite loop:
0 0 100.16
30 1 0.00
51 0 0.00
380 0 0.02 /usr/bin/python -Es /usr/sbin/tuned -l -P
2016 0 0.08 sshd: root#pts/0 "" "" "" ""
2023 1 100.11 -bash
2630 0 0.04 /usr/libexec/systemtap/stapio -R stap_3020c9e7ba76838179be68cd2390a10c_2630 -F3
I understand that perf is not the proper way to do it, although you can limit perf per CPU, as using perf record -C <cpulist> or even perf stat -c <cpulist>.
The close you are going to see is the context-switch event, but, this is not going to provide you the application names at all.
I think you are going to need something more powerful, as systemtap.

run cron every 105 minutes

I'm not great with Linux, my apologies if this is easy.
I need to run 7 different scripts via cron at 15 minute intervals. I have worked out that each script needs to run every 105 minutes (every 1 hour & 45 minutes) as follows :
Script 1 Script 2 Script 3 Script 4 Script 5 Script 6 Script 7
00:15 00:30 00:45 01:00 01:15 01:30 01:45
02:00 02:15 02:30 02:45 03:00 03:15 03:30
etc...
Now I know I can't just put this:
*/105 * * * * something
Because the minutes will only go up to 59.
Other than writing each one in a line separately, is there an easy way to do this?
Any assistance would be greatly appreciated.
No, cron can't do that directly.
What you can do is have a cron job that runs every 15 minutes, invoking a wrapper script. The wrapper script can query the current time and decide which of your 7 scripts to execute.
Doing the math is left as an exercise. Don't assume that your wrapper will start exactly at the top of the minute; there can be some delay between the time a cron job is scheduled to execute and the time it actually runs, depending on system load.
at is a good candidate for this problem.
Write a wrapper (or build into your script):
#!/bin/bash
at -f $0 now + 105 minutes
<program>
Then use at -f <script> <time> for each instance.
Or generate the crontab entries using a script (my first draft was a bit too long to be a oneliner):
#!/usr/bin/perl -Ws
use strict;
use DateTime;
our ($period, $offset, $command);
my ($offh, $offm) = split(/:/, $offset || '0:00');
my %crontab = ();
for (my $i = 0; $i < 1440; $i += $period) {
my ($h,$m) = split /:/, 'DateTime'->today->set('hour', $offh, 'minute', $offm)->add('minutes', $i)->hms;
$crontab{$m}{$h}++;
}
printf("%02d %-15s * * *\t%s\n", $_, join(',', sort keys %{$crontab{$_}}), $command) for sort keys %crontab;
Usage:
$ ./gencrontab -period=105 -offset=1:30 -command=myprogram
00 05,12,19 * * * myprogram
15 00,03,10,17 * * * myprogram
30 01,08,15,22 * * * myprogram
45 06,13,20 * * * myprogram

Segmentation fault while using bash script to generate mobility file

I am using a bash script to generate mobility files (setdest) in ns2 for various seeds. But I am running into this troublesome segmentation fault. Any help would be appreciated. The setdest.cc has been modified, so its not the standard ns2 file.
I will walk you through the problem.
This code in a shell script returns the segmentation fault.
#! /bin/sh
setdest="/root/ns-allinone-2.1b9a/ns-2.1b9a/indep-utils/cmu-scen-gen/setdest/setdest_mesh_seed_mod"
let nn="70" #Number of nodes in the simulation
let time="900" #Simulation time
let x="1000" #Horizontal dimensions
let y="1000" #Vertical dimensions
for speed in 5
do
for pause in 10
do
for seed in 1 5
do
echo -e "\n"
echo Seed = $seed Speed = $speed Pause Time = $pause
chmod 700 $setdest
setdest -n $nn -p $pause -s $speed -t $time -x $x -y $y -l 1 -m 50 > scen-mesh-n$nn-seed$seed-p$pause-s$speed-t$time-x$x-y$y
done
done
done
error is
scengen_mesh: line 21: 14144 Segmentation fault $setdest -n $nn -p $pause -s $speed -t $time -x $x -y $y -l 1 -m 50 >scen-mesh-n$nn-seed$seed-p$pause-s$speed-t$time-x$x-y$y
line 21 is the last line of the shell script (done)
The strange thing is If i run the same setdest command on the terminal, there is no problem! like
$setdest -n 70 -p 10 -s 5 -t 900 -x 1000 -y 1000 -l 1 -m 50
I have made out where the problem is exactly. Its with the argument -l. If i remove the argument in the shell script, there is no problem. Now i will walk you through the modified setdest.cc where this argument is coming from.
This modified setdest file uses a text file initpos to read XY coordinates of static nodes for a wireless mesh topology. the relevant lines of code are
FILE *fp_loc;
int locinit;
fp_loc = fopen("initpos","r");
while ((ch = getopt(argc, argv, "r:m:l:n:p:s:t:x:y:i:o")) != EOF) {
switch (ch) {
case 'l':
locinit = atoi(optarg);
break;
default:
usage(argv);
exit(1);
if(locinit)
fscanf(fp_loc,"%lf %lf",&position.X, &position.Y);
if (position.X == -1 && position.Y == -1){
position.X = uniform() * MAXX;
position.Y = uniform() * MAXY;
}
What i dont get is...
In Shell script..
-option -l if supplied by 0 returns no error,
-but if supplied by any other value (i used 1 mostly) returns this segmentation fault.
In Terminal..
-no segmentation fault with any value. 0 or 1
something to do with the shell script surely. I am amazed what is going wrong where!
Your help will be highly appreciated.
Cheers

How to find user memory usage in linux

How i can see memory usage by user in linux centos 6
For example:
USER USAGE
root 40370
admin 247372
user2 30570
user3 967373
This one-liner worked for me on at least four different Linux systems with different distros and versions. It also worked on FreeBSD 10.
ps hax -o rss,user | awk '{a[$2]+=$1;}END{for(i in a)print i" "int(a[i]/1024+0.5);}' | sort -rnk2
About the implementation, there are no shell loop constructs here; this uses an associative array in awk to do the grouping & summation.
Here's sample output from one of my servers that is running a decent sized MySQL, Tomcat, and Apache. Figures are in MB.
mysql 1566
joshua 1186
tomcat 353
root 28
wwwrun 12
vbox 1
messagebus 1
avahi 1
statd 0
nagios 0
Caveat: like most similar solutions, this is only considering the resident set (RSS), so it doesn't count any shared memory segments.
EDIT: A more human-readable version.
echo "USER RSS PROCS" ; echo "-------------------- -------- -----" ; ps hax -o rss,user | awk '{rss[$2]+=$1;procs[$2]+=1;}END{for(user in rss) printf "%-20s %8.0f %5.0f\n", user, rss[user]/1024, procs[user];}' | sort -rnk2
And the output:
USER RSS PROCS
-------------------- -------- -----
mysql 1521 1
joshua 1120 28
tomcat 379 1
root 19 107
wwwrun 10 10
vbox 1 3
statd 1 1
nagios 1 1
messagebus 1 1
avahi 1 1
Per-user memory usage in percent using standard tools:
for _user in $(ps haux | awk '{print $1}' | sort -u)
do
ps haux | awk -v user=${_user} '$1 ~ user { sum += $4} END { print user, sum; }'
done
or for more precision:
TOTAL=$(free | awk '/Mem:/ { print $2 }')
for _user in $(ps haux | awk '{print $1}' | sort -u)
do
ps hux -U ${_user} | awk -v user=${_user} -v total=$TOTAL '{ sum += $6 } END { printf "%s %.2f\n", user, sum / total * 100; }'
done
The first version just sums up the memory percentage for each process as reported by ps. The second version sums up the memory in bytes instead and calculates the total percentage afterwards, thus leading to a higher precision.
If your system supports, try to install and use smem:
smem -u
User Count Swap USS PSS RSS
gdm 1 0 308 323 820
nobody 1 0 912 932 2240
root 76 0 969016 1010829 1347768
or
smem -u -t -k
User Count Swap USS PSS RSS
gdm 1 0 308.0K 323.0K 820.0K
nobody 1 0 892.0K 912.0K 2.2M
root 76 0 937.6M 978.5M 1.3G
ameskaas 46 0 1.2G 1.2G 1.5G
124 0 2.1G 2.2G 2.8G
In Ubuntu, smem can be installed by typing
sudo apt install smem
This will return the total ram usage by users in GBs, reverse sorted
sudo ps --no-headers -eo user,rss | awk '{arr[$1]+=$2}; END {for (i in arr) {print i,arr[i]/1024/1024}}' | sort -nk2 -r
You can use the following Python script to find per-user memory usage using only sys and os module.
import sys
import os
# Get list of all users present in the system
allUsers = os.popen('cut -d: -f1 /etc/passwd').read().split('\n')[:-1]
for users in allUsers:
# Check if the home directory exists for the user
if os.path.exists('/home/' + str(users)):
# Print the current usage of the user
print(os.system('du -sh /home/' + str(users)))

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