I'm trying to design an excel formula for some golf game scores. Golfers get points based on a random number (0-9) and the last digit of their score. So, if the random number is 0 and the golfers score ends in 0, they get 10 points. Still with a 0 random number, if the golfers score ends in a 1, they get 9 points. 8 points for a last digit of 2. 7 for 3. 6 for 4. 10 for 5. 9 for 6. 8 for 7. 7 for 8. 6 for 9.
Score ends in: Points:
0 10
1 9
2 8
3 7
4 6
5 10
6 9
7 8
8 7
9 6
As long as I come up with one formula for the random number of 0, I can adjust it for the remaining 9 random numbers.
The way I was hoping for this to work was to just be able to enter the scores into one column and then have the points calculated in a separate column. There will also have to be a cell where I enter the random number.
Any help is appreciated!
You can use something like this to get the score if the random number is 0:
=IF(A1=0,10-MOD(RIGHT(B1),5))
This will give the points you mentioned provided:
A1 is the cell containing the random number
B1 is the cell containing the points of the golfer.
The main formula here is:
10-MOD(RIGHT(B1),5)
RIGHT() takes the last digit of the points. MOD(,5) will get the remainder when this digit is divided by 5.
When you have 0, you get no remainder, hence 0.
When you have 1, you get a remainder of 1, hence 1.
When you have 2, you get a remainder of 2, hence 2.
When you have 6, you get a remainder of 1, hence 1 again.
Then 10 minus that remainder gives you the points you're looking for.
You could certainly use =RAND()*10to get a random value in excel. Or to get a value without commas use = ROUNDDOWN(RAND()*10;0)
Then you add something a VLOOKUPto get a value to each players score. RIGHT(A1;1)gives you the last value of a field.
VLOOKUPrequires you to have a table somewhere with the values for each score as you described.
edit: the MOD solution looks even better. Please note that RANDOM gets a fresh value everytime you refresh the XLS sheet. so probably use it to get a value and put that into another field manually.
Related
I have a list of part numbers that are used in 4 different top level assemblies. The parts can be used in 1 to 4 of the top level assemblies. I'm trying to write a formula that will count how many unique top level assemblies a part number occurs in. I had previously written a formula that worked, but it uses UNIQUE and FILTER, and my coworkers don't have Excel 365, so those formulas aren't supported for them. I've been trying to come up with a workaround and would really appreciate any help :)
I have an example (I can't provide any real data) section of our spreadsheet and an image of the formula I had that was working
Top Level Assy
Part Number
Qty
Number of times used
02554
01622
4
3
89975
01622
4
3
95665
01622
4
3
98886
01723
4
1
98886
01723
10
1
98886
01723
4
1
02554
01734
4
3
89975
01734
4
3
95665
01734
4
3
02554
01740
6
3
89975
01740
6
3
95665
01740
6
3
02554
01746
5
3
89975
01746
5
3
95665
01746
5
3
02554
01835
2
3
89975
01835
2
3
95665
01835
2
3
02554
51205
4
3
=SUM(--(LEN(UNIQUE(FILTER(A:A, C:C=C2, "")))>0))
Picture of the excel sheet
Picture of working formula
Use the following formula in row 2: =SUMPRODUCT(--(FREQUENCY(IF($B$2:$B$20=$B2,$A$2:$A$20),$A$2:$A$20)>0))
*I think it doesn't require ctrl+shift-enter in older Excel versions, since SUMPRODUCT is an array formula by default.
The formula checks the frequency of values in column A where column B matches the value in the current row. It returns the count per unique value meeting the condition. Wrapping it in -- & >0 returns 1 for each unique value. SUMPRODUCT sums them.
Edit:
I realized that the top level assembly values are actual text, not numeric values. In that case (since it's all numeric values stored as text) you can use this workaround:
=SUMPRODUCT(--(FREQUENCY(IF($B$2:$B$20=$B2,--($A$2:$A$20)),--($A$2:$A$20))>0))
It converts the text to numbers.
Sidenotes to this workaround:
If any value would contain a character other than numeric it will not get counted.
If you have both values like 02554 and 2554 they'll both get converted to 2554 and counted likewise.
Edit 2:
For text use the following:
=SUMPRODUCT(IF($B$2:$B$20=$B2, 1/(COUNTIFS($B$2:$B$20, $B2, $A$2:$A$20, $A$2:$A$20)), 0))
I'm trying to make a formula that transforms a list decimal numbers to binary, then counts the number of appearances of ones at a certain position. I was trying to build an array formula that went something like this:
{=SUM(MID(DEC2BIN(A1:A10;10);9;1)}
This will return #VALUE. Is there a way to do this?
EDIT: examples added
Input (Binary Equivalent)
2 0000000010
3 0000000101
7 0000000111
7 0000000111
5 0000000101
9 0000001001
Outputs Result
(digit to sum
from the right)
1 5
2 3
3 3
4 1
This was another way e.g. for the second digit from the right
=SUMPRODUCT(--ISODD(A1:A10/2))
Divide by 2^(n-1) where n is digit numbered from the right: the ISODD function ignores any fraction that results from the division.
=SUM(0+MID(DEC2BIN(--A1:A10,10),9,1))
array-entered.
Regards
If you are trying to count have many of the second digits are set in a range of numbers you can do this:
={SUM((MOD(A1:A10,4)>=2)+0)}
To understand this, let's look at some example data
Here I have some decimal numbers with their binary equivalents. In column C I have just extracted the 2nd digit (i.e. your MID(A1,9,1)). Then in column D I just take the modulo by 4. You can see that when the remainder is greater than 2, the second digit is set.
MOD(A1,4) basically divides the number by 4 and gives us the remainder (the numerator of the remainder if it was represented as a fraction over 4). With binary numbers, division by a power of two is just a right shift. Division by 4 is a right shift by 2 and the numbers that 'fall off' are the remainder. In this case it's the first two digits. They can be
00 | 0
01 | 1
10 | 2
11 | 3
so we see that the second digit is set only when the remainder is greater than 2.
Note the +0 in the original formula is to cast the boolean result of = to an integer so we can use SUM i.e. SUM({TRUE,FALSE}) doesn't work but SUM({TRUE,FALSE}+0) computes to SUM({1,0}) which does work.
To make this generic, let's assume you want to do it for the $E$1th digit:
=SUM((MOD(A1:A12,2^$E$1)>=2^($E$1-1))+0)
With bit operations it's not necessary to treat the number as a string.
{=SUM(BITAND(A1:A10;2^(C1-1))/2^(C1-1))}
Assuming the position you are looking for is stored in C1.
I have a list of numbers which are either 1's or 2's. What I'd like to do is count how many 1's there are before a 2 appears, and then keep repeating this down the list (i'm trying to find the average number of 1's between each 2).
What would be the best way of doing this considering I've got over 10,000 rows? (i.e. too many to do manually)
The average number of 1's between each number 2, is the same as the ratio between the number 1 and the number 2.
Example:
1
1
2
1
1
1
1
2
1
1
2
1
1
2
Contains 10 ones and 4 twos.
Or there are five groups of ones, with the following counts: 2, 4, 2, 2
Either way, it will give you and average of 2.5 (10/4 = 2.5)
Note: You have to make a design choice, regarding how to handle beginnings and ends. If you had another one, after the last two, how should it be handled?
You can use the formula as shown in the screenshot below:
Note that the formula in the first row is different.
B C
=IF(A2=1,B1,B1+1) =COUNTIF(B:B,B2)
=IF(A3=1,B2,B2+1) =IFERROR(IF(A4=2,COUNTIF(B:B,B4),"")-1,"")
Then to get the average use:
=AVERAGEIF(C:C,"<>"&0)
Noceo's solution as a formula:
=COUNTIF(A:A,1)/COUNTIF(A:A,2)
The output of all the above:
I have rows of data that contains numbers from 1 to 15, however these numbers can be in any sequence. For example here:
3 2 1 12 13 5 6 7 9 15 10 8 4 15 11
I know from a visual count these numbers above are all correct; as there are no duplicates, and all the numbers have values from 1 to 15. An example of a row of data I found to be wrong:
3 2 1 12 12 5 6 7 9 15 10 8 4 15
You can see this line has duplicated numbers i.e. 12, and number 11 is missing, so this row only has 14 elements in all.
However, I have many rows of data and it is impossible to visually check each row. I need to ensure in each row: there are 15 elements; there are no duplicates, and that the row contains values from 1 to 15 and find which rows are faulty to check these against the original paper data.
Is there a command or function that I can use in Excel to make this process easier?
You could find a set of conditions, each of which is true for rows that contain exactly those 15 numbers in any order and then test several of them. For example, if the row is in A5:O5:
=AND(COUNT(A5:O5)=15,SUM(A5:O5)=120,MIN(A5:O5)=1,MAX(A5:O5)=15,
AVERAGE(A5:O5)=8,ROUND(STDEV(A5:O5),3)=4.472)
This will show TRUE for a row that contains the integers 1 to 15 in any order, and is very unlikely (it could very well be impossible - I haven't checked) to show TRUE for a row that contains any different set of integers.
I'm pretty sure that the only way 15 positive integers less than 16 can add up to 120 other than by all being different is with duplication, so :
Check there are 15 numbers
Check their total is 120
Check the maximum is 15
Check not negative (nor zero):
=IF(OR(COUNT(A5:O5)<>15,SUM(A5:O5)<>120,MAX(A5:O5)>15,MIN(A5:O5)<1),"Error","Plausible")
then check for duplication with Conditional Formatting using a rule such as :
=COUNTIF($A5:$O5,A5)>1
and a distinctive format. Filter to select "Plausible" and then anything with a distnctive format is non compliant.
I have a spreadsheet program which rolls twenty-sided dice. Sheet 1 is Rolls and Sheet 2 is Values.
I want to roll a d20, but if it comes up 2-7, fudge it and assume I got 8 instead.
Rolls!A2's function is =RANDBETWEEN(1,20) which returns a random number between 1 and 20 to represent the d20 roll. Values!7E is function which calculates a (non-random) number (currently 13).
Currently, Rolls!C7's function attempts to calculate my result with =Values!E7+Rolls!A2. But I would like to update Rolls!C7 to reflect the fudging. If Rolls!A2 returns numbers 2, 3, 4, 5, 6, or 7, Rolls!C7 would instead be calculated as if it rolled an 8.
Replace Rolls!A2 in your formula with this: IF(AND(Rolls!A2<8, Rolls!A2>1),8,Rolls!A2) this way it will always be at least 8 unless a 1 is rolled.
Or you could do =IF(Rolls!A2=1,1,MAX(Rolls!A2,8))