I am trying to have a rule which can check if there is any 0 in given string. For example, My string format can be like, 34393903432 or any combination . I should be able to check if there is any 0. I tried using contains function but doesn't work. Any idea?
The contains function should work for this.
i.e contains(field1, "city")
http://office.microsoft.com/en-gb/infopath-help/functions-in-infopath-HP001155281.aspx
Can you add how you used the contains function?
Related
I have this file where I want to make a conditional check for any cell that contains the letter combination "_SOL", or where the string is followed by any numeric character like "_SOL1524", and stop looking after that. So I don't want matches for "_SOLUTION" or "_SOLothercharactersthannumeric".
So when I use the following formula, I also get results for words like "_SOLUTION":
=IF(ISNUMBER(FIND("_SOL",A1))=TRUE,"Yay","")
How can I avoid this, and only get matches if the match is "_SOL" or "_SOLnumericvalue" (one numeric character)
Clarification: The whole strings may be "Blabla_SOL_BLABLA", "Blabla_SOLUTION_BLABLA" or "Blabla_SOL1524_BLABLA"
Maybe this, which will check if the character after "_SOL" is numeric.
=IF(ISNUMBER(VALUE(MID(A1,FIND("_SOL",A1)+4,1))),"Yay","")
Or, as per OP's request and suggestion, to include the possibility of an underscore after "SOL"
=IF(OR(ISNUMBER(VALUE(MID(A1,FIND("_SOL",A1)+4,1))),ISNUMBER(FIND("_SOL_",A1))),"Yay","")
Here is an alternative way to check if your string contains SOL followed by either nothing or any numeric value up to any characters after SOL:
=IF(COUNT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"_","1</s><s>")&"</s></t>","//s[substring-after(.,'SOL')*0=0]")>0),"Yey","Nay")
Just to use in an unfortunate event where you would encounter SOL1TEXT for example. Or, maybe saver (in case you have text like AEROSOL):
=IF(COUNT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"_","</s><s>")&"</s></t>","//s[translate(.,'1234567890','')='SOL']")>0),"Yey","Nay")
And to prevent that you have text like 123SOL123 you could even do:
=IF(COUNT(FILTERXML("<t><s>"&SUBSTITUTE(A1,"_","1</s><s>")&"</s></t>","//s[starts-with(., 'SOL') and substring(., 4)*0=0]")>0),"Yey","Nay")
I would like to find out if a string within a cell in Excel 2010 contains any of the following, and then return a '1'.
?dementia
? dementia
dementia?
dementia ?
I've tried some formulas but they don't seem able to get past the use of the wildcard and the string when combined.
Would anyone have any pointers or advice?
Here is a combination of the suggested answers, and my own work around:
This is the formula you need:
=IF(IFERROR(FIND(A2,$C$3),0)>0,1,0)
where A2 is the string that you are trying to check.
Assuming you don't want to include word ? word and return 1, you can use something like this:
=IF(OR(LEFT(A1,1)="?",RIGHT(A1,1)="?"),1,"")
You will want to use the FIND function (Documentation).
Make sure your search term in in quotation marks.
If you are still having trouble with wildcards, you can try the CHAR function (Documentation). It will return the character as a string. In your case, to get a ?, you would use CHAR(63). I use this chart to keep track of CHAR codes (just use the number and ignore the "Alt")
REVISED:
If I understand the question correctly, you are trying to search long string in a short string list.
The formula you can use is:
=ISTEXT(LOOKUP(99^99,SEARCH(SUBSTITUTE($A$2:$A$5,"?","|"),SUBSTITUTE(C2,"?","|")),$A$2:$A$5))*1
The problem with my prior formula is due to that ? mark because it is being treated as a wild card. Here I have replace it with | (you can change this to a character that you will never use but avoid ? and *). This should work for you now.
I am trying to get a value or all values similar to below in excel:
#123 maybe some text and date 12/17/209
#048309 maybe some text and date 12/17/209
#9385 maybe some text and date 12/17/209
I want to get the value proceeding the # however, I am not sure if there is an easier function? I want it to find the # then get however many numbers proceeds it. I am familiar with regex not with excel functions unfortunately.
Sorry for vagueness:
I was trying to use an IF() supplying a # as the find operation for the character I just couldnt manage to get the number as I was trying to use RIGHT() to filter after the #. What I found with the RIGHT() function is that it expects a parameter for count and so would have to be dynamic so I dropped that idea.
This formula will get the numbers directly after #:
=--MID(A1,FIND("#",A1)+1,FIND(" ",A1,FIND("#",A1))-FIND("#",A1))
I have a sqlite database with a column (Note) and this contains a variety of content.
Some rows have Urls in them and I want to get a list of these.
I can find them like this:
SELECT SUBSTR(Note,'http') FROM PersonTable WHERE Note LIKE 'http%'
But this returns the whole string in the Note column when it finds a Url. What I want is to return only the URL nothing else.
I know this must be simple for anyone familiar with SQL but its new to me.
Thanks
The SUBSTR function expects its second parameter to be the start position; 'http' will just be interpreted as 0.
SQLite has no built-in function that would allow to find the end of the URL; you should split the returned column value in your program.
I have the list with like 100,000 site link strings
Each link is unique, but it has consistent ?Item=
Then, it's either nothing or it continues after & symbol.
My question is: How do I pull out the item numbers?
I know replace function can offer similar functionality, but it works with Fixed sizes, in my case string can be different in size.
Link example:
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555
or
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555&sdafsdfsdfsdf
In both cases I need to get JGFGGG55555 only
If this always is the last portion of the string, you can use the following:
=MID(A1, FIND("?Item=", A1) + 6, 99)
This assumes:
no item numbers will be over 99 digits.
no additional fields follow the item number.
Edit:
With the update to your question, it is apparent you have some strings with additional data after the ?Item= field. Without using VBA there is not a simple means of using MID and FIND to extract this.
However you could create a column which acts as a placeholder.
For example, create a column using:
=MID(A1,FIND("?Item=",A1)+6,99)
This gets you the following value: JGFGGG55555&sdafsdfsdfsdf
Next, create a column using:
=IF(ISERROR(FIND("&",B2)),B2,LEFT(B2,FIND("&",B2)-1))
This produces: JGFGGG55555 by searching the first value for a & and using the portion before it. If it is not found, the first value is simply repeated.
This formula should work for both the examples given:
=MID(A1,FIND("=",A1),IFERROR(LEN(A1)-FIND("&",A1,FIND("=",A1))-1,LEN(A1)+1-FIND("=",A1)))