I am quite new to the shell scripting.
So I am writing the shell script to list all files available in the directory using ls command.
but I am getting the error bad interpreter: Permission denied
#!/home/gaurav
echo "Welcome bash shell scripting"
ls
echo "this complets the listing of directories"
I want to get the list of "/home/gaurav" this path
Thanks
This line...
#!/home/gaurav
... means "instead of using /bin/bash, use /home/guarav as the program to run this file". This is not what you want. What you want is either:
cd /home/gaurav # at the top, or
ls /home/gaurav # between echoes
Problem is this line:
#!/home/gaurav
This is called shebang and it should be the bash/shell interpreter like this:
#!/bin/bash
one that interprets and executes your script. Since /home/gaurav is not a valid interpreter you're getting that error.
You probably want this in your script:
ls /home/gaurav
to list all files/directories in /home/gaurav path.
Either add #!/bin/bash or #!/bin/sh instead of #!/home/gaurav line while starting script.
Because, while running shell script, you have to give path of which bash or sh are you going to run to execute that script.
Related
I want to run this script:
#!/bin/bash
echo <(true)
I run it as:
sh file.sh
And I get "Syntax error: "(" unexpected" . I found some similar situations but still can't solve this.
I'm a beginner at shell scripting , but as I understand:
the shebang I use is correct and chooses the bash shell , so the process substitution syntax should work
I try the same from the command line and it works. I checked with echo $0 and it gives me "bash" , so what's the difference from running the command in the command line and from a script that invokes the same shell?
Maybe it's something simple, but I couldn't find an explanation or solution.
You should run your script with bash, i.e. either bash ./script.sh or making use of the shebang by ./script.sh after setting it to executable. Only running it with sh ./script.sh do I get your error, as commented by Cyrus.
See also: role of shebang at unix.SE
Remove export POSIXLY_CORRECT=1 from your ~/.bashrc or ~/.profile (etc.) files.
The issue is that process substitution is an added bash feature that is not part of the posix standards.
sh file.sh
errorsh: 3: Syntax error: "(" unexpected
solution:
bash file.sh
I am very new to linux and shell scriprting.
I am trying to run a shellscript from secure shell (ssh) on linux using following commands:
chmod +x path/to/mynewshell.sh
sh path/to/mynewshell.sh
I get this error:
path/to/mynewshell.sh: path/to/mynewshell.sh: cannot execute binary file.
Tried using this command:
bash path/to/mynewshell.sh
I get the same error.
Tried with this command: su - myusername sh path/to/mynewshell.sh
It is asking for my password and giving me this error: no such file or directory.
1.The result of cat -v path/to/mynewshell.sh is:
^#^#^#^#^#^#^#^#Rscript "$dir"/diver_script.R
done
2.When tried 'less path/to/mynewshell.sh' i got this on my terminal:
#!/bin/bash/Rscript^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#
^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#
for dir in /path/to/* ; do
^#^#^#^#^#^#^#^#Rscript "$dir"/myRscript.R
done
3.When i ran file path/to/mynewshell.sh : i got this "Bourne-Again shell script text executable"
Please give any advice on how I can try executing the shellscript.
chmod -x removes execution permission from a file. Do this:
chmod +x path/to/mynewshell.sh
And run it with
/path/to/mynewshell.sh
As the error report says, you script is not actually a script, it's a binary file.
I was getting the same error running my shell script through a bash interpreter in PowerShell. I ran dos2unix myscript.sh on the shell script, and now it runs ok.
From a proposed duplicate:
run_me.sh.xz: run_me.sh.xz: cannot execute binary file
This is because the file is compressed, as indicated by the .xz extension. You need to remove the compression before the file can be used.
xz -d ./run_me.sh.xz
chmod +x ./run_me.sh # probably not necessary if you already did that before
./run_me.sh
Other compression schemes like gzip (.gz extension), bzip2 (.bz2 extension) etc behave similarly; you just have to know the name of the command to uncompress it, which is of course usually easy to google.
To anyone else having the problem i had.
i was trying to run a 16 bit unicode text file converted to a shell script, this doesn't work as all 16 bit unicode text files have a 0xFFFE marker at the start making mac os not like the file and this gives the “cannot execute binary file” error.
open the text file click on "Format" at the top, go down to "Make Plain Text" click it.
open your terminal type chmod 777 /path/to/file.sh
put in terminal: /path/to/file.sh to run it
That script is simply not a shell script.
A shell script is usually readable and contains shell code.
The output your cat command shows looks indeed like it's a binary of some sort.
As some note, it might be because of a file conversion issue when copying but it looks more like an actual binary to me.
You can check what it is identified as with the file command so:
file path/to/mynewshell.sh
Just start with a clean script and rewrite the code, it looks like you just want to run some R scripts in a directory?
Make sure the R scripts point to the right R script executioner.
In my case I had a bash script that would not execute. The file was originally generated from a find ... -print0 command. Leaving a \0 character the script, removing that character solved my problem.
I tried to create a script in linux, on a Synology server over SSH
so I wrote a file test.sh
#!/bin/bash
echo "this is a test"
I saved the file.
after that I did
chmod 755 test.sh
the I did
./test.sh
then i got this error
-ash "./test.sh" is not found
the file was created in
/root
I don't understand
Your shell (ash?) is trying to execute your script and is getting an ENOENT (no such file or directory) error code back. This can refer to the script itself, but in this case it refers to the interpreter named in the #! line.
That is, /bin/bash does not exist and that's why the script couldn't be started.
Workaround: Install bash or (if you don't need any bash specific features) change the first line to #!/bin/sh.
This is one of the quirks with hash bang programs. If the interpreter is not found (i.e. the program interpreting the script), you don't get a completely useful error like /bin/bash: no such file, but a completely useless and misleading test.sh: not found.
If this isn't in the Unix Hater's Handbook, it should be. :-)
You can either use #!/bin/sh or #!/path/to/bash or #!/usr/bin/env bash (which searches PATH for bash).
I am trying to learn bash scripting and I'm using Ubuntu Linux. I have written a simple Bash file to count the number of files in current directory. I have written the following script in a file:
#! /bin/bash
ls -1 | wc -l
And saved the file with the name countFile.
But when I am trying to execute the script using ./countFile it is not executing. It shows the following error:
bash: ./countFile: Permission denied
The countFile is in my home directory so why I haven't the permission. Am I doing something wrong or missing some important thing? Moreover, the ls -1 | wc -l command gives me the correct output when I run it from the terminal.
So how can I run the countFile script?
While you are giving like this,
./countfile
You have to make that file as executable using chmod.
chmod +x countfile
Or else you can use the other interpreter like this.
sh countfile
while executing the file we need a execute permission for that file,
we can change the permission or
we just run as
. countfile
hew . will represent the current working shell
I have read other threads enter link description herethat discuss .bat to L/unix conversions, but none has been satisfactory. I have also tried a lot of hack type approach in writing my own scripts.
I have the following example.bat script that is representative of the kind of script I want to run on unix.
Code:
echo "Example.bat"
perl script1 param.in newParam.in
perl script2 newParam.in stuff.D2D stuff.D2C
program.exe stuff.D2C
perl script3 stuff.DIS results.out
My problem is I don't know how to handle the perl and program.exe in the unix bash shell. I have tried putting them in a system(), but that did not work. Can someone please help me?
Thank you!
Provided that you have an executable file named program.exe somewhere in your $PATH (which you well might — Unix executables don't have to end in .exe, but nothing says they can't), the code you've pasted is a valid shell script. If you save it in a file named, say, example.bat, you can run it by typing
sh example.bat
into the shell prompt.
Of course, Unix shell scripts are usually given the suffix .sh — or no suffix at all — rather than .bat. Also, if you want your script to be executable directly, by typing just
example.sh
rather than sh example.sh, you need to do three things:
Start the script with a "shebang" line: a line that begins with #! and the full path to the shell interpreter you want to use to run it (e.g. /bin/sh for the basic Bourne shell), like this:
#!/bin/sh
echo "This is a shell script."
# ... more commands here ...
Mark your script as executable using the chmod command, e.g.
chmod a+rx example.sh
Put your script somewhere along your $PATH. On Unix, the default path will not normally contain the current directory ., so you can't execute programs from the current directory just by typing their name. You can, however, run them by specifying an explicit path, e.g.
./example.sh # runs example.sh from the current directory
To find out what your $PATH is, just type echo $PATH into the shell.