Putting values from one Array into another - visual-c++

Question

I'm at a loss here, so I am looking for any hints to point me in the right direction. I can't figure out how to input the Celsius values that I converted from the Fahrenheit temperatures into the centigrade array. I tried to work in another for loop for that very purpose but it only outputs the last value for C after the calculation from the first for loop. Any ideas? Thanks in advance.
// Temperature Converter
#include <iostream>
#include <iomanip>
using std::cout;
using std::endl;
using std::setw;
int main()
double temps[] = { 65.5, 68.0, 38.1, 75.0, 77.5, 76.4, 73.8, 80.1, 55.1, 32.3, 91.2, 55.0 };
double centigrade[] = { 0 }, C(0);
int i(0);
cout << setw(13) << "Farenheit " << setw(9) << " Centigrade";
cout << endl;
for (double t : temps)
{
C = (t - 32) * 5 / 9;
cout << setw(10) << t << setw(12) << C;
cout << endl;
}
for (i = 0; i <= 12; i++)
{
centigrade[i] = C;
cout << centigrade[i] << endl;
}
return 0;
}

Answer 1

Here is a full working example based on the other answer.
#include <iostream>
using std::cout;
using std::endl;
int main() {
double temps[] = { 65.5, 68.0, 38.1, 75.0, 77.5, 76.4, 73.8, 80.1, 55.1, 32.3, 91.2, 55.0 };
const int count = sizeof(temps) / sizeof(temps[0]);
double centigrade[count];
for (int i = 0; i < count; i++) {
centigrade[i] = (temps[i] - 32) * 5 / 9;
cout << centigrade[i] << endl;
}
return 0;
}
If you want to work without an explicit indexing loop, then replace double centigrade[count]; with std::vector<double> centigrade, and replace the loop with:
for (double t : temps)
centigrade.push_back((t - 32) * 5 / 9);
If you then wanted an array back for some reason, you could use this trick to get an array back:
double* array_version = &centigrade[0];

Answer 2

Store values in the array in the first loop itself..
for (i=0;i<=12;i++)
{
centigrade[i]= (temps[i] - 32) * 5 / 9;
cout << setw(10) << temps[i] << setw(12) << centigrade[i];
cout << endl;
}
U can generalize the for loop by finding the size of temps array dynamically..maybe
sizeof (temps) / sizeof (temps[0]);
Also allocate memory for centigrade array accordingly.

Answer 3

I am adding a new answer based on clarifications to the OP's question, rather than updating my existing answer, because I feel the context is more clear this way.
If you want to use a range-based loop, and avoid std::vector, there is a way to do it, but this solution is more in the spirit of C thanC++, because it uses pointer arithmetic.
#include <iostream>
using std::cout;
using std::endl;
int main() {
double temps[] = { 65.5, 68.0, 38.1, 75.0, 77.5, 76.4, 73.8, 80.1, 55.1, 32.3, 91.2, 55.0 };
const int count = sizeof(temps) / sizeof(temps[0]);
double centigrade[count];
double * walker = centigrade;
for (double t : temps)
*walker++ = (t - 32) * 5 / 9;
// verify results by printing.
for (double t: centigrade)
cout << t << endl;
return 0;
}