I have two cols in Calc and want to compare both and print in col if it's a duplicate. Example:
A B C
1 2
2 2 2
3 3 3
4 5
5 6
6 7
7 7 7
8 8 8
9 9 9
What is the formula I need to print in col c to get this?
The formula to use in column C, to test if columns A and B are equals
=IF(A1=B1;B1;"")
Related
I am having issues trying to modify a value if columnA contains lets say 0,2,12,44,75,81 (looking at 33 different numerical values in columnA. If columnA contains 1 of the 33 vaules defined, i need to then change the same row of colulmnB to "approved".
I have tried this:
df[(df.columnA == '0|2|12|44|75|81')][df.columnB] = 'approved'
I get an error that there are none of index are in the columns but, i know that isn't correct looking at my csv file data. I must be searching wrong or using the wrong syntax.
As others have said, if you need the value in column A to match exactly with a value in the list, then you can use .isin. If you need a partial match, then you can convert to string dtypes and use .contains.
setup:
nums_to_match = [0,2,9]
df
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 f
6 9 a
7 6 i
8 6 a
9 2 h
Exact match:
df.loc[df.A.isin(nums_to_match),'B']='approved'
df:
A B
0 6 e
1 1 f
2 3 b
3 6 g
4 6 i
5 0 approved
6 9 approved
7 6 i
8 6 a
9 2 approved
partial match:
nums_to_match_str = list(map(str,nums_to_match))
df['A']=df['A'].astype(str)
df.loc[df.A.str.contains('|'.join(nums_to_match_str),case=False,na=False),'B']='approved'
df
A B
0 1 h
1 4 c
2 6 i
3 7 d
4 3 d
5 9 approved
6 5 i
7 1 c
8 0 approved
9 5 d
I have three columns, A, B and D
Column A and B have integer numbers that Im trying to map to column D which looks something like this:
A
B
C
D
1
3
7
2
4
9
I want to populate column C with column D's data, but I need to look like bellow:
A
B
C
D
1
3
7
7
2
4
7
9
3
3
7
4
4
7
5
3
7
1
4
9
2
3
9
3
4
9
4
3
9
5
4
9
I need to map column D and duplicate those numbers down to Column A and have Column C change every time Column A repeats to the first number, which in this case is 1
I have two tables with same column names, but different data.
Table1:
A B C D
1 3 4 5 OK
2 6 7 8
3 9 8 7
Table2:
A B C D
1 9 8 7
2 1 2 8
3 3 4 5
I want to write formula in D of Table2, which would copy D-column values by row values from Table1. (I want to find same row in other table and set D-column value for it).
I could use SUMIFS(Table1!$D:$D, Table1!$A:$A, "="&A1, Table1!$B:$B, "="&B1, Table1!$C:$C, "="&C1), but all the rows are unique and I have string value in $D:$D - I don't need SUM exactly, I need only one string value.
Is there any function to find column value by row condition?
The result I want:
A B C D
1 9 8 7
2 1 2 8
3 3 4 5 OK
I want to delete duplicate values in same row and multiple column in excel... i want this
A B C D E F G H I J K RESULT
R1 8 0 1 8 1 5 8 1 9 5 5 80159
R2 7 8 7 7 4 5 0 7 6 8 9 78450689
R3 5 2 0 6 4 2 7 6 1 3 0 52064713
R4 4 3 5 0 7 2 5 3 2 4 8 4350728
If one has the Dynamic Array formula:
=CONCAT(UNIQUE(A1:K1,TRUE))
If not then the assumption is that 0 will never be in the first column and that the data is as you provided, one number per cell:
=MMULT(TRANSPOSE(MODE.MULT(IF(MATCH(A1:K1,A1:K1,0)=COLUMN(A1:K1),A1:K1*{1;1}))),TRANSPOSE(10^(COUNT(MODE.MULT(IF(MATCH(A1:K1,A1:K1,0)=COLUMN(A1:K1),A1:K1*{1;1})))-TRANSPOSE(ROW(INDEX($ZZ:$ZZ,1):INDEX($ZZ:$ZZ,COUNT(MODE.MULT(IF(MATCH(A1:K1,A1:K1,0)=COLUMN(A1:K1),A1:K1*{1;1})))))))))
Depending on ones version this may need to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode.
If it is text or the numbers are more than one digit then vba will probably be needed.
How would I sum vertically the columns that meet a given criteria?
For example:
A B C D E F G
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
If criteria = A, then the formula would give me 4
if B, 8
if C, 12. I would like the criteria input to be a reference-able cell.
Thanks for your help!
Use INDEX to return the correct array. Use MATCH to return the correct column:
=SUM(INDEX(2:5,0,MATCH(J1,1:1,0)))
Assuming you have a sheet like this:
=SUM(INDEX($BF$5:$BI$16,,Match($BC$5,$BF$4:$BI$4,0)))