80I am trying to read a file and replace a placeholder with the content of another file. The problem is the variable contains urls which seems to cause problems in sed. In addition: what to do to keep the new lines from images.txt? Is there a way to make my solution work or is there maybe another solution that is better suited for my problem? I want to overwrite content of a file with the content of a backup file. In addition the step should include replacing a placeholder with the content of a third file. Thank you.
What I currently use:
<images.html
TEXT=$(<images.txt)
sed 's~URLS~$TEXT~g' imagesbu.html > images.html
This does not work and just shows:
sed: -e expression #1, char 80: unknown option to `s'
Content of the file is:
https://cdn.tutsplus.com/vector/uploads/legacy/tuts/165_Shiny_Dice/27.jpg
https://cdn.tutsplus.com/vector/uploads/legacy/tuts/165_Shiny_Dice/27.jpg
IF there is no newline in the file it works.
Try altering your sed delimiter so that it is not a forward slash:
sed "s~URLS~$TEXT~g" imagesbu.html > images.html
Edit: Your original sed command doesn't work because of the above, and because you are trying to replace a single word with multiple lines. Try awk instead:
awk -v u="$TEXT" '{gsub(/URLS/,u)}1' imagesbu.html > images.html
Related
When I try following command, I'd like to rewrite sql.
Day='2020/12/1'
Dir=/home/test/data
sql=`cat $Dir"/"$test".sql" | sed -e "s/Day/$Day/g"`
I suffered following errors.
sed: -e expression #1, char 24: unknown option to `s'
Why the s is recognised as option ? why is this command couldnt work well ?
if someone has opinoin, please let me know
Thanks
The problem is with slashes: your variable contains them and the final command will be something like sed "s/string/path/to/something/g", containing way too many slashes.
Since sed can take any char as delimiter (without having to declare the new delimiter), you can try using another one that doesn't appear in your replacement string like below:
sql=`cat $Dir"/"$test".sql" | sed -e "s|Day|$Day|g"`
Also, you would need to use sed -i to update the file in-place, since it looks like that is what you're trying to do.
I have a configuration file (gpsd.default) containing data with the following format:
# If you must specify a non-NMEA driver, uncomment and modify the next line
GPSD_SOCKET="/var/run/gpsd.sock"
GPSD_OPTIONS=""
GPS_DEVICES=""
I am making a change on the file with sed:
sed -i 's/^GPS_DEVICES="".*/GPS_DEVICES="dev/ttyUSB1"/' /etc/default/gpsd.default
or
sed -i '4s/^.*/GPS_DEVICES="dev/ttyUSB1"/' /etc/default/gpsd.default
The above sed command returns error:
sed: bad option in substitution expression
Because the new line contains "/" in its expression.
How to update my sed command to make it work?
This is because you are using a regex containing /, which is the same character sed uses as delimiter.
Just change the sed delimiter to another one, for example ~:
sed -i 's~^GPS_DEVICES="".*~GPS_DEVICES="dev/ttyUSB1"~' /etc/default/gpsd.default
By the way, since you are changing files in /etc, you may want to use -i.bak, so that the original file gets backed up. It is a good practice to prevent loss of important information.
You should update your sed command to this.
sed -i 's/^GPS_DEVICES=\"\".*/GPS_DEVICES=\"dev\/ttyUSB1\"/' /etc/default/gpsd.default
I have file which contains text at line 30 which is:
Icon="\<some path which we do not know\icon.png"
I want to replace above with:
Icon="\home\user\Img\Icons\icon.png"
What is the best way to do it.?
Thanks.
Best way:
perl -pi -e 's/\\<some path which we do not know/\\home\\user\\Img\\Icons/' text.txt
Perl approach is more preferred than sed, because of Unix compatibility.
You can either use an editor to do this manually or if you prefer to do it non interactively, you can use a small shell pipeline and sed.
sed `3 s/big path/custom path/` input_file.txt
where 3 is the line number, big path is what you want to replace and custom path is what you to want to replace it with. input_file.txt is your input file. This will print the replaced file onto the screen which you can redirect into another file using the > operator.
As a concrete example, suppose I have this file (input_file.txt)
Header
Random test
/bad/path/to/some/directory/icon.png
/bad/path/to/some/directory/icon.png
Footer
Now I'm going to run my command like so.
cat input_file.txt | sed '4 s/\/bad\/path\/to\/some\/directory\//\/home\/noufal\//'
and I get
Header
Random test
/bad/path/to/some/directory/icon.png
/home/noufal/icon.png
Footer
Notice that it has changed only the 4th line. The extra \ characters in the command are to escape the / character which has special meaning for sed.
you can use vim to find and replace your strings http://vim.wikia.com/wiki/Search_and_replace or use 'sed' command
Good-day,
In a Bash shell script I'm putting together, I am trying to find this text: /usr/local/freeswitch/log/freeswitch.log and replace it with: /var/log/freeswitch/freeswitch.log in this file: /etc/fail2ban/jail.local
This is what I have tried so far, both of which result in the error: sed: -e expression #1, char 75: unterminated `s' command
Attempt #1
sed -i 's~usr/local/freeswitch/log/freeswitch.log~var/log/freeswitch/freeswitch.log' /etc/fail2ban/jail.local
Attempt #2
sed -i 's~usr/local/freeswitch/log/freeswitch.log/var/log/freeswitch/freeswitch.log' /etc/fail2ban/jail.local
My research shows that since the text I'm searching for includes the "/" character, I should be using a different delimiter "~" to separate the find and replace strings. But looks like I'm doing something wrong, any assistance would be appreciated, thanks.
The structure of a sed substitution command is s/PATTERN/REPLACEMENT/ (note the delimiter at the end of the command).
You're right, you can change the delimiter to a different character, so if you're going to use ~ you need to put one of those at the end of the command.
I have a file contained \n hidden behind each line:
input:
s3741206\n
s2561284\n
s4411364\n
s2516482\n
s2071534\n
s2074633\n
s7856856\n
s11957134\n
s682333\n
s9378200\n
s1862626\n
I want to remove \n behind
desired output:
s3741206
s2561284
s4411364
s2516482
s2071534
s2074633
s7856856
s11957134
s682333
s9378200
s1862626
however, I try this:
tr -d '\n' < file1 > file2
but it goes like below without space and new line
s3741206s2561284s4411364s2516482s2071534s2074633s7856856s11957134s682333s9378200s1862626
I also try sed $'s/\n//g' -i file1 and it doesn't work in mac os.
Thank you.
This is a possible solution using sed:
sed 's/\\n/ /g'
with awk
awk '{sub(/\\n/,"")} 1' < file1 > file2
What you are describing so far in your question+comments doesn't make sense. How can you have a multi-line file with a hidden newline character at the end of each line? What you show as your input file:
s3741206\n
s2561284\n
s4411364\n
etc.
where each "\n" above according to your comment is a single newline character "\n" is impossible. If those "\n"s were newline characters then your file would simply look like:
s3741206
s2561284
s4411364
etc.
There's really only 2 possibilities I can think of:
You are wrongly interpreting what you are seeing in your input file
and/or using the wrong terminology and you actually DO have \r\n
at the end of every line. Run cat -v file to see the \rs as
^Ms and run dos2unix or similar (e.g. sed 's/\r$//' file) to
remove the \rs - you do not want to remove the \ns or you will
no longer have a POSIX text file and so POSIX tools will exhibit
undefined behavior when run on it. If that doesn't work for you then
copy/paste the output of cat -v file into your question so we can
see for sure what is in your file.
Or:
It's also entirely possible that your file is a perfectly fine POSIX
text file as-is and you are incorrectly assuming you will have a
problem for some reason so also include in your question a
description of the actual problem you are having, include an example
of the command you are executing on that input file and the output
you are getting and the output you expected to get.
You could use bash-native string substitution
$ cat /tmp/newline
s3741206\n
s2561284\n
s4411364\n
s2516482\n
s2071534\n
s2074633\n
s7856856\n
s11957134\n
s682333\n
s9378200\n
s1862626\n
$ for LINE in $(cat /tmp/newline); do echo "${LINE%\\n}"; done
s3741206
s2561284
s4411364
s2516482
s2071534
s2074633
s7856856
s11957134
s682333
s9378200
s1862626