I am a beginner at linux and really enthusiastic to learn the OS. I am trying to launch Firefox(or any other software like Evince) from the command line as follows:
[root#localhost ~]# at 1637
[root#localhost ~]# at> firefox
[root#localhost ~]# at> ^d
The job gets scheduled without any error. But at the specified time it does not run.
I also tried giving the following path:
[root#localhost ~]# at 1637
[root#localhost ~]# at> /usr/bin/firefox
[root#localhost ~]# at> ^d
Still no result. But When I try to use echo to display a text on the screen it appears at the specified time as desired. What might be the issue?
I think you have not set DISPLAY. at will run in separate shell where display is not set.
try the following code.
dinesh:~$ at 2120
warning: commands will be executed using /bin/sh
at> export DISPLAY=:0
at> /usr/bin/firefox > firefox.log 2>&1
at> <EOT>
job 7 at Tue Mar 11 21:20:00 2014
If it is still failing check firefox.log for more information.
1) Its not always recommended to run things as root
2) You can also try ./firefox if you are in the current directory of firefox. In linux you need to pay attention to your path variable. Unless . (the current directory) is in your path you will have to type ./program if the program is in the same directory as you.
Also you need to pay attention to file permissions: In linux you have read-write-eXecute access.
ls -l will do a list of directories and show the file permissions:
drwxr-xr-x 10 user staff 340 Oct 6 2012 GlassFish_Server/
drwx------# 15 jeffstein staff 510 Oct 6 15:01 Google Drive/
drwxr-xr-x 20 jeffstein staff 680 May 14 2013 Kindle/
drwx------+ 67 jeffstein staff 2278 Jan 26 14:22 Library/
drwx------+ 19 jeffstein staff 646 Oct 23 18:28 Movies/
drwx------+ 15 jeffstein staff 510 Jan 3 20:29 Music/
drwx------+ 90 jeffstein staff 3060 Mar 9 20:23 Pictures/
drwxr-xr-x+ 6 jeffstein staff 204 Nov 3 21:16 Public/
drwxr-xr-x 22 jeffstein staff 748 Jan 14 2012 androidTools/
-rwxrwxrwx 1 jeffstein staff 1419 Aug 28 2013 color.sh*
This is an example of ls -l here you can see color.sh has -rwxrwxrwx that means that anybody can read or write or run the file.
Without actually knowing where you installed firefox however I can't be of more help but these are some small pointers which might help.
try finding where firefox is actually installed using "whereis firefox" command.
Then try using that path in at command.
In order to get directions on how to use a command type:
man at
this will display the "manual"
DESCRIPTION
The at and batch utilities read commands from standard input or a speci-
fied file. The commands are executed at a later time, using sh(1).
at executes commands at a specified time;
atq lists the user's pending jobs, unless the user is the superuser;
in that case, everybody's jobs are listed;
atrm deletes jobs;
batch executes commands when system load levels permit; in other words,
when the load average drops below _LOADAVG_MX (1.5), or the value
specified in the invocation of at run.
So obviously you need to schedule a job with at and you can see if it worked with atq
Read the manual and it should help - if i have more time I'll write you a quick example.
Related
When I open terminal, my working directory is a/b/c/
and my shell script is placed under a/b/d/e/f/ which gets triggered through Autosys.
I want to change my working directory from a/b/c/ to a/b/d/e/f/ using relative path.
Currently I'm hard coding cd a/b/d/e/f/. I don't want to do it anymore. Could you please let me know how can this be achieved.
cd ../d/e/f/
The trick being the .. which is the "parent directory" of the one you're in
You can see a reference to it (including its permissions) if you use ls -a or more completely
$ ls -lhaF
total 0
drwxr-xr-x 20 user group xxB Jun 15 00:00 ./
drwxr-xr-x 3 user group xxB Jun 15 00:00 ../
-rw-r--r-- 1 user group xxB Jun 15 00:00 e/
There are two directories that contains these files:
First one /usr/local/nagios/etc/hosts
[root#localhost hosts]$ ll
total 12
-rw-rw-r-- 1 apache nagios 1236 Feb 7 10:10 10.80.12.53.cfg
-rw-rw-r-- 1 apache nagios 1064 Feb 27 22:47 10.80.12.62.cfg
-rw-rw-r-- 1 apache nagios 1063 Feb 22 12:02 localhost.cfg
And the second one /usr/local/nagios/etc/services
[root#localhost services]$ ll
total 20
-rw-rw-r-- 1 apache nagios 2183 Feb 27 22:48 10.80.12.62.cfg
-rw-rw-r-- 1 apache nagios 1339 Feb 13 10:47 Check usage _etc.cfg
-rw-rw-r-- 1 apache nagios 7874 Feb 22 11:59 localhost.cfg
And I have a script that goes through file in Hosts directory and paste some lines from that file in the file in the Services directory.
The script is ran like this:
./nagios-contacts.sh /usr/local/nagios/etc/hosts/10.80.12.62.cfg /usr/local/nagios/etc/services/10.80.12.62.cfg
How can I achieve that another script calls my script and goes through every file in the Hosts directory and does its job for the files with the same name in the Service directory?
In my script I´m pulling out contacts from the 10.80.12.62.cfg in the Hosts directory and appending them to the file with the same name in the Service directory.
Don't use ls output as an input to for loop instead use the built-in wild-cards. See why it's not a good idea.
for f in /usr/local/nagios/etc/hosts/*.cfg
do
basef=$(basename "$f")
./nagios-contacts.sh "$f" "/usr/local/nagios/etc/services/${basef}"
done
It sounds like you just need to do some iteration.
echo $(pwd)
for file in $(ls); do ./nagious-contacts.sh $file; done;
So it will loop over all files in the current directory.
You can also modify it as well by doing something more absolute.
abspath=$1
for file in $(ls $abspath); do ./nagious-contacts.sh $abspath/$file; done
which would loop over all files in a set directory, and then pass the abspath/filename into your script.
I have added the following to the file /etc/sudoers using the visudo command:
nick ALL=(ALL:ALL) ALL
But when I log in as nick and attempt something like mkdir .ssh I get:
mkdir: cannot create directory ‘.ssh’: Permission denied
Likewise, I cannot save files I have edited.
Running ls -la from the home directory gives me:
drwxr-xr-x 5 nick nick 4096 Apr 7 19:07 .
drwxr-xr-x 3 root root 4096 Apr 7 17:32 ..
-rw-r--r-- 1 nick nick 220 Aug 31 2015 .bash_logout
-rw-r--r-- 1 nick nick 3771 Aug 31 2015 .bashrc
drwx------ 2 nick nick 4096 Apr 7 18:29 .cache
drwxr-xr-x 2 root root 4096 Apr 7 19:07 .nano
-rw-r--r-- 1 nick nick 675 Aug 31 2015 .profile
Which if I'm not mistaken is showing that I have no write access to anything. (Correct me if I'm wrong. I'm only passingly familiar with UNIX permissions.)
Why can't this user do anything despite being given full permissions in sudoers?
UPDATE:
This problem fixed itself. I do not know what the problem was but it was no longer a problem when I logged on a couple days later.
For the record, I was attempting to configure a fresh DigitalOcean server running Ubuntu 15.10 x64. My local computer is a MacBook running El Capitan.
My guess is that the remote server restarted or somehow otherwise incorporated the change automatically in the interim. I had already tried running sudo reboot producing no results, so I'm still not sure how this could be.
I was also experiencing some local WiFi connection dropping at the time but as my SSH connection seemed to be operational I'm not sure if this could be related.
I'm also not an expert to Linux, but to me it seems like you have to use sudo mkdir .ssh instead of mkdir .ssh. You allowed your user to behave like root(who has rights to write to directory), but for doing that you have to use sudo command.
Here is the simple explanation of how it works(with pictures): https://www.garron.me/en/linux/visudo-command-sudoers-file-sudo-default-editor.html
Here is the serious documentation: https://help.ubuntu.com/community/Sudoers
What can I do to make this script run daily?
If I manually run the script, it works. I can see that it did what it's supposed to do. (backup files) However, it will not run as a cron.daily script. I've let it go for days without touching it -- and it never runs.
The actual script is here /var/www/myapp/backup.sh
There is a symlink to it here /etc/cron.daily/myapp_backup.sh -> /var/www/myapp/backup.sh
The cron log at /var/log/cron shows anacron running this script:
Aug 19 03:09:01 ip-123-456-78-90 anacron[31537]: Job `cron.daily' started
Aug 19 03:09:01 ip-123-456-78-90 run-parts(/etc/cron.daily)[31545]: starting myapp_backup.sh
Aug 19 03:09:01 ip-123-456-78-90 run-parts(/etc/cron.daily)[31559]: finished myapp_backup.sh
Yet there is no evidence that the script actually did anything.
Here is the security info on these files:
ls -la /var/cron.daily
<snip>
lrwxrwxrwx 1 root root 25 Aug 12 21:18 myapp_backup.sh -> /var/www/myapp/backup.sh
</snip>
ls -la /var/www/myapp
<snip>
drwxr-xr-x 2 root root 4096 Aug 13 13:55 .
drwxr-xr-x 10 root root 4096 Jul 12 01:00 ..
-rwxr-xr-x 1 root root 407 Aug 12 23:37 backup.sh
-rw-r--r-- 1 root root 33 Aug 12 21:13 list.txt
</snip>
The file called list.txt is used by backup.sh.
The script just runs tar to create an archive.
From the cron manpage of a debian/ubuntu system:
the files under these directories have to be pass some sanity checks including the following: be executable, be owned by root, not be writable by group or other and, if symlinks, point to files owned by root. Additionally, the file names must conform to the filename requirements of run-parts: they must be entirely made up of letters, digits and can only contain the special signs underscores ('_') and hyphens ('-'). Any file that does not conform to these requirements will not be executed by run-parts. For example, any file containing dots will be ignored.
So:
file need to be owned by root
if symlink, the source file need to be owned by root
if symlink, the link name should NOT contain dots
I had a similar situation with cron.hourly and awstats processing.
I THINK it is related to SELinux and anacron not having the same powers/permissions as cron.
The ACTUAL solution defeated me (so far).
MY WORKAROUND SOLUTION: Run the job via root's cron entries (crontab -e ) and simply schedule it hourly.
I'm just wondering about this problem:
if I can use something like "ls -al | less", less should have the ability of waiting for input from stdin. What I expected to happen is after running "less" command, the program hang up and wait for input(as a consequence of calling gets() or something like that.)
But why in fact it showed an error message "Missing filename ("less --help" for help)" end exited?
Thank you.
less command can check both argc>1 and stdin be associated with a file(not a tty).
The less command is not designed in that matter. When you execute a command in bash it will display all of the information at once. The less command is used to display the STDOUT of a command or the contents of a file one screen at a time.
$ ls -al | less
total 16
drwxrwxr-x 4 hdante hdante 4096 Nov 24 17:11 .
drwxr-xr-x 88 hdante hdante 4096 Mar 24 22:14 ..
drwxrwxr-x 2 hdante hdante 4096 Nov 25 01:55 new
drwxrwxr-x 3 hdante hdante 4096 Nov 24 18:27 old
(END)
It works. Something is wrong with your less. From less manual pages:
http://www.linuxmanpages.com/man1/less.1.php
https://developer.apple.com/library/mac/#documentation/Darwin/Reference/ManPages/man1/less.1.html
The manual describes the filename as optional.
Hints to diagnose your problem:
try alias | grep less, to see if the command is being modified
try set | grep LESS, and check the scripts being run by LESSCLOSE and LESSOPEN