how to delete line after specific pattern and extract something - linux

Question

UPDATE
This is my file:
<department name="/fighters" id="123879" group="channel" case="none" use="no">
<options index_name="index.html" listing="0" sum="no" allowed="no" />
<target prefix="ttp" suffix=".net" />
<type="effort">
<region="20491" readonly="fs1a" readwrite="fs1a" upload="yes" download="yes" repl="yes" hard="0" soft"0" prio="0" write="no" stage="yes" migrate="no" size="0" >
<read="content" readwrite="content" hard="215822106624" soft="237296943104" prio="5" write="yes" stage="yes" migrate="no" size="0" />
<overflow name="20491-set-writable" />
</replicate>
<region="20576" readonly="fs1a" readwrite="fs1a" upload="yes" download="yes" repl="yes" hard="0" soft"0" prio="0" write="no" stage="yes" migrate="no" size="0" >
<read="content" readwrite="content" hard="215822106624" soft="237296943104" prio="5" write="yes" stage="yes" migrate="no" size="0" />
<overflow name="20576-set-writable" />
</replicate>
</replication>
<user="T:106603" />
<user="T:123879" />
<user="test" />
<user="ele::123456" />
<user="company-temp" />
<user="companymw2" />
<user="bird" />
<user="coding11" />
<user="plazamedia" />
<allow go="123456=abcdefghijklmnopqrstuvwxyz" />
</department>
I wrote a bash like:
awk < test.xml -Fuser= '{ print $2 }' | sed '/^$/d' | cut -d" " -f1
and result is something like:
"T:106603"
"T:123879"
"test"
"ele::123456"
"company-temp"
"companymw2"
"bird"
"coding11"
"plazamedia"
But imagine the result is:
"T:106603" />
"T:123879" />
"test" />
"ele::123456" />
"company-temp" />
"companymw2" />
"bird" />
"coding11" />
"plazamedia" />
first,How can I say remove every thing after second "?
secondly, how can I say extract everything between " "?
I like doing it with sed or awk
Thank you in advance

Answer 1

Try this:
awk -F'"' '/<user=/{ print $2 }' file

Answer 2

Using only sed:
$ sed 's/^<user=\(.*"\).*/\1/' test.xml # With quotes
$ sed 's/^<user="\(.*\)".*/\1/' test.xml # Without quotes

Answer 3

Try this cut,
cut -d'"' -f 2 test.xml
Try this sed,
With quotes("):
sed 's/^.*\("[^"]\+"\).*/\1/g' test.xml
Without quotes("):
sed 's/^.*"\([^"]\+\)".*/\1/g' test.xml
UPDATE:
sed -e '/^<user/!{d}' -e '/^<user/s/^.*"\([^"]\+\)".*/\1/' test.xml

Answer 4

If you want to get rid of the sed and cut in the pipeline, there are many ways to do that, depending on what the corner cases are. The simplest to me would seem to be
awk -F'"' '/<user=/ { print "\"$2\"" }' test.xml
As usual, here's the obligatory don't parse XML with regex link.
Slightly interesting corner cases would be if there can be quoted double quotes in the string (but usually XML would use entities instead) or if the elements can have multiple attributes. If there could be multiple <user=...> elements on a single line, this will quickly become more complex than the proper solution, which is to use XSLT.

Answer 5

Try :
$ awk '/<user=/ && gsub(/<user=|\/>/,x)' file
"T:106603"
"T:123879"
"test"
"ele::123456"
"company-temp"
"companymw2"
"bird"
"coding11"
"plazamedia"
If you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk , /usr/xpg6/bin/awk , or nawk

Answer 6

Using gnu grep
grep -Po 'user=\K"[^"]*"' file