I am not familiar with excel as you can probaly guess by my question so I am sorry if it's a silly question but I have been googling for a long time and I can't do it.
I manage to do it in excel 365 with the function filter, but I can't on excel 2019 (I am required to do it in excel 2019)
I want to identifed the smaller number of a specific combination of cells using two table.
Table1 has name of people and places as well as a number. (the number shows the difference of the last time a person went to a place and the [in months])
(In this project the inspector cannot go to the same place twice unless 4 months have pass, thus why I want the smaller number, using the date of the last visited and the fcuntion now I get teh number of months that have pass)
Table2 has only the name of one person out of these people but has the name of all places. I want to get the smaller number for every place.
This is my table1: (I hided other peoples names so I can show a more compact examlplo)
And this is my table2:
I thought that I could use a function aggregate with a function if inside of it to get only the values that I desire.
It did not worked thou. Was I had miss undertand the fact that function if only gives me true or false. But thought that the aggregate function could wordk. It did not as well
=AGGREGATE(5;3;A2&B2=Table1[#Place]&Table1[#name];1).
overall my question could be summarize to which funtion should I used?
Which function should I use?
obs: In excel 365 I used concat to make a code an thus only used one cell, but I don't see why it wouldn't work if I just select two cells insted of one (teh concat cell)
is there anything i can do to further improve performance of this formula ?
=IF($A3<>"",IF(Jan!$E6<>"",LET(d_patt,IF(Jan!$E6<>"",VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(Jan!$B6<>"",Jan!$B6,0)&IF(Jan!$C6<>"",Jan!$C6,0)&IF(Jan!$D6<>"",Jan!$D6,0),""),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&IF(LEFT(d_patt,3)="OVT",d_patt,"OVT000")&IF(LEFT(d_patt,3)="SSI",d_patt,"SSI000")&IF(LEFT(d_patt,3)="SSO",d_patt,"SSO000")&IF(LEFT(d_patt,3)="SDS",d_patt,"SDS000")&IF(LEFT(d_patt,3)="HOL",d_patt,"HOL000")&IF(LEFT(d_patt,3)="LID",d_patt,"LID000")&IF(LEFT(d_patt,3)="UNP",d_patt,"UNP000")&IF(LEFT(d_patt,3)="FLD",d_patt,"FLD000")&IF(LEFT(d_patt,3)="MAT",d_patt,"MAT000")&IF(LEFT(d_patt,3)="LIS",d_patt,"LIS000")&IF(LEFT(d_patt,3)="CBR",d_patt,"CBR000")&IF(LEFT(d_patt,3)="ABS",d_patt,"ABS000")),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000"),"")
i have this on a sheet for each day of the year x 400 people so 146k+ times. this is therefor taken up 80% of the sheet load time.
The sheet basically gets shift patters from Teams, check if there is any holidays, overtime etc from the relevant month tab and relevant cell for the day, and then will generate a code like below.
ROT080OVT000SSI000SSO000SDS234HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000
i have so far managed to make this faster by using the LET function, but not show if its possible to make any further improvements.
if you need an example file i can send this or upload somewhere, not sure if that is possible via stackoverflow or a preferred site to upload to.
Thanks
The following is a shortened version of your formula to reduce the complexity of computations.
Instead of building the 'OVT000SSI000...' string one piece after another while always checking if the first 3 characters of 'd_patt' match the current piece, we can set the whole string with '000's as default and only replace the section that matches 'd_patt' (see highlighted elements in screenshot below)
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(LEN(Jan!$B6)>0,Jan!$B6,0)&IF(LEN(Jan!$C6)>0,Jan!$C6,0)&IF(LEN(Jan!$D6)>0,Jan!$D6,0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)
If $B6, $C6 and $D6 can only be either empty or a numerical number, in other words, if they are never a letter or special character, the 'd_patt' function can be further shortened as follows:
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&(Jan!$B6+0)&(Jan!$C6+0)&(Jan!$D6+0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)
I'm not too sure how to word this problem so, I apologize for the vagueness. Here is what I am trying to do though:
I have a large Excel table with a ton of values, I however, only care about 3 columns. The three columns I have are "Project Name", "Active/Planned", and "Week of Month". Here is an example of some values I would have:
Project Name
Active/Planned
Week of Month
StoreProj
Active
2021-07 Jul-Wk1
SecProj
Planned
2021-07 Jul-Wk2
StoreProj
Active
2021-07 Jul-Wk1
Now, I have used a formula to get the number of projects based on a specific week month and avoiding duplicate values for the project name. The code I used returns an integer of the number of projects. Here is what I used:
=IFERROR(ROWS(UNIQUE(FILTER(Table[Project Name],Table[Week of Month]=2021-07 Jul-Wk1))), 0)
This works as intended. Now the issue I am running into is that I need to filter through these rows as I did previously, but now I need to include the "Active/Planned" column. So, I want to be able to see how many projects I have based off of the week of the month and return a number of projects (excluding duplicate names), but be able to filter through that integer output based off of the active/planned projects. So in a perfect scenario I can choose the week of month and if the project is "Active" or "Planned" and see the amount of projects I have.
This might be an easy fix so I apologize, I am just stumped, any help would be greatly appreciated. Thanks!
Work through that step by step, you've got the FILTER function which is giving data to the UNIQUE function, to the ROWS function, and then your IFERROR. However, the data about whether each line/row is 'Active' or 'planned' isn't passed out beyond the FILTER function, so can't be used by anything further on in the above sequence.
Boring theoretical advice out the way, try this;
=COUNT(IF(UNIQUE(FILTER( Table[[Project Name]:[Active/Planned]], Table[Week of Month] = "2021-07 Jul-wk1"))= "Active", 1))
Explanation:
FILTER(...) outputs records with the relevant date filter, however it outputs Table[[Project Name]:[Active/Planned]] - both columns, to ensure all relevant data is there.
UNIQUE(...) Then narrows that down to unique values, although by this stage I'm not 100% sure you need this.
IF(... = "Active", 1) then replaces the 'Active' outputs with 1s
COUNT() returns the number of cells in the above that contain a number (the 1s from the IF())
Yes, you can't use COUNTIF on arrays (and all except that last bullet point above are outputting arrays not single values) - and no, I didn't know that before attempting to answer this question, found it over at a different question!
I have an planning exported to Excel which looks like the following (tab ' Data'):
Each production line has a number of people working on it. Now is my goal to show how many people are working on a line per minute. We plan per product group, and several product groups combined form waht a line has to do per minute.
To get the production per minute I created the following (tab 'Conversie'):
=INDEX(Data!$H$2:$H$157;MATCH($N$1&A4;Data!$B$2:$B$157&Data!$C$2:$C$157;1))
In the example it works correct. However, the formula doesn't seem to always return the correct "Artikelomschrijving"(H) every time. I get incorrect return values when I extend this formula to other product groups.
I read that the data needs to be sorted ascending cause I use match_type 1. When I do that I get the right returns for some product groups, but the given example suddenly returns incorrect values.
I can't sort both column C and A in ascending order for the formulas to always return correct items. Can you help me to get past this hurdle?
After a little bit of google translate work, if I'm understanding your question correctly, you need to find the "Item Description" (H) of the record where the "Line" (B) = the value in N1 and the time is between the start and end times.
This is an array formula, you have to confirm it with Ctrl+Shift+Enter
=INDEX(Data!$H$2:$H$157,MATCH(1,(Data!$B$2:$B$157=$N$1)*(Data!$C$2:$C$157<$A2)*(Data!$D$2:$D$157>=$A2),0))
OR with semicolon syntax:
=INDEX(Data!$H$2:$H$157;MATCH(1;(Data!$B$2:$B$157=$N$1)*(Data!$C$2:$C$157<$A2)*(Data!$D$2:$D$157>=$A2);0))
I found the solution, thank you for pointing me in the right direction Valon Miller. This is the formula I fixed it with:
=ALS.FOUT(INDEX(Data!$H$2:$H$154;MATCH(1;(Conversie!L$1=Data!$B$2:$B$154)*((Conversie!$A32>=Data!$C$2:$C$154)*(Conversie!$A32<=Data!$D$2:$D$154));0));"")
I have 5 columns of data with around 50,000 rows. This is the ambulance response times to an incident. I am trying to figure out the total number of incidents as multiple ambulances respond to a single incident. The 'IF' function has been useful upto a certain extent where the multiple ambulances reached at the same time but when it is not at the same time, it considers it as a different incident. I would like to add a buffer of 20 minutes but I am not able to figure out how to incorporate that. The second problem is with the incident number. The incidents 2014-014374-006, 2014-014374-009 are the same, just the ending numbers are different. How do I differentiate? Can I do it in excel or other platforms?
http://imgur.com/a/30VHl
To return the incident number, use a formula like this: "=IF(ISERROR(SEARCH("-",D5,SEARCH("-",D5)+1)),D5,LEFT(D5,SEARCH("-",D5,SEARCH("-",D5)+1)-1))" where D5 is the cell with your incident number.
What this formula does is it first creates an if statement that will allow you to determine if the incident has the second dash or if it doesnt. If it doesn't, then it will return the value in the cell. If it does, it will return the text to the left of that dash. The search function looks for a substring, and by nesting a search and adding "1" to the value of the first search, we are looking for the substring that comes after the first one is found.
It is a rather confusing formula the first time you use it, but it works like a charm once you understand it.
I will see if I can figure the dates out. That might be more difficult. If you can simply use the incident number for this, you will likely have an easier time.