I need to find files i directory and zip them under the same name.
i am trying the following
find . -name "ABC_*.txt" -mtime +30 -exec sh -c zip '{}' '{}' \;"
But something is wrong.
basically if find command finds 3 files say:
./ABC_1.txt
./ABC_2.txt
./ABC_3.txt
I will need 3 zip files:
./ABC_1.txt.zip
./ABC_2.txt.zip
./ABC_3.txt.zip
thanks in advance.
Try this:
find . -name "ABC_*.txt" -mtime +30 -exec zip "{}.zip" "{}" \;
You are likely overwriting your original file and will need to supply an extension to your ZIP.
You can use execdir option:
find . -name "ABC_*.txt" -mtime +30 -execdir sh -c 'zip "$1.zip" "$1"' - '{}' \;
Related
I am using the following command to delete the files that are older than 10 days, but I also want to store(log) the list of files that are being deleted using the below command.
find ./path/delete -type f -name '*' -mtime +10 -exec rm {} \;
If you create a file to log to (touch ./path/to/logfile), just add another -exec to your command. Below is a very basic example, but you can add to it:
find ./path/delete -type f -name '*' -mtime +10 -exec rm {} \; -exec echo {} >> ./path/to/logfile \;
I am honestly nowhere near to be a decent bash scripter, but I made a little research and found a command that seems to be useful
find /path/to/files* -mtime +1 -exec rm {} \;
The question is if this line will remove directories? Because I want to only remove files that are images (actually in a *.jpeg format)
No, rm without the -r flag does not remove directories.
It looks like you want to add some more filters:
-type f to match only files
-name '*.jpeg' to match only files ending with .jpeg
Lastly, instead of -exec rm {} \;, you could use the much simpler -delete.
Putting it together, this looks more appropriate for you:
find /path/to/files* -mtime +1 -type f -name '*.jpeg' -delete
Then narrow your search results to *.jpeg files:
find /path/to/files* -mtime +1 -type f -name "*.jpeg" -exec rm {} \;
It's always better to remove the exec parameter to do a dry run before delete:
find /path/to/files* -mtime +1 -type f -name "*.jpeg"
Each line will be passed to rm command, and nothing more.
I am able to delete lets say all regular files in a folder older than 7 days via:
find /path/to/dir -type f -mtime +7 -exec rm {} \;
with a single problem. There is a file here (.gitignore) which I want to keep. I tried using regex but apparently findutils regex does not have support for negative lookahead (?!gitignore)
Any other ideas?
Use ! -name .gitignore
find /path/to/dir ! -name .gitignore -type f -mtime +7 -exec rm {} \;
You can group multiple arguments within escaped parentheses. Example, to remove all files except .gitignore and javascript files (ending in .js):
find /path/to/dir ! \( -name ".gitignore" -o -name "*.js" \) -type f -mtime +7 -exec rm {} \;
-o means or
Is there a way to write the file names to a file before they are deleted for reference later to check what has been deleted.
find <PATH> -type f -name "<filePattern>" -mtime +1 -delete
Just add a -print expression to the invocation of find:
find <PATH> -type f -name "<filePattern>" -mtime +1 -delete -print > log
I'm not sure if this prints the name before or after the file is unlinked, but it should not matter. I suspect -delete -print unlinks before it prints, while -print -delete will print before it unlinks.
Like William said, you can use -print. However, instead of -print > log, you can also use the -fprint flag.
You'd want something like:
find <PATH> -type f -name "<filePattern>" -mtime +1 -fprint "<pathToLog>" -delete
For instance, I use this in a script:
find . -type d -name .~tmp~ -fprint /var/log/rsync-index-removal.log -delete
You can use -exec and rm -v:
find <PATH> -type f -name "<filePattern>" -mtime +1 -exec rm -v {} \;
rm -v will report what it is deleting.
With something like this you can execute multiple commands in the exec statement, like log to file, rm file, and whatever more you should need
find <PATH> -type f -name "<filePattern>" -mtime +1 -exec sh -c "echo {} >>mylog; rm -f {}" \;
From a shell script named removelogs.sh
run the command sh removelogs.sh in terminal
this is the text in removelogs.sh file.
cd /var/log;
date >> /var/log/removedlogs.txt;
find . -maxdepth 4 -type f -name \*log.old -delete -print >> /var/log/removedlogs.txt
. - to run at this location !!! so ensure you do not run this in root folder!!!
-maxdepth - to prevent it getting out of control
-type - to ensure just files
-name - to ensure just your filtered names
-print - to send the result to stdout
-delete - to delete said files
>> - appends to files not overwrites > creates new file
works for me on CENTOS7
I need to find and archive files with a certain file name e.g. ABC_000.jpg
find ~/my-documents/ -iname "ABC_***.JPG" -type f -exec cp {} ~/my-documents/archive/ \;
however I can not seem to find a way to limit the find function to find only 3 integers as there are files that are named ABC_CBA.jpg that I do not want included
Try this find:
find ~/my-documents/ -iname "ABC_[0-9][0-9][0-9].JPG" -type f -exec cp '{}' ~/my-documents/archive/ \;
EDIT: Or using regex:
find -E ~/my-documents/ -iregex ".*ABC_[0-9]{3}\.JPG" -type f -exec cp '{}' ~/my-documents/archive/ \;