When I execute command line (linux) I want to know what time there were executed when I scroll up my terminal window. I saw this once setup in linux environment but how to do that?
You need to set your prompt variable (PS1). Something like the following should get you going:
<~/temp>$ export PS1="[\$(date +%k:%M)]> "
[12:16]>
You can setup PS1 to always show current time in BASH;
export PS1='\A-\w>'
\A - current time stamp without seconds part
\t - current time stamp with seconds
\w - current directory
1) Open bashrc file
gedit ~\.bashrc
2) Find the following text:
if [ "$color_prompt" = yes ]; then
PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u#\h\[\033[00m\] :\[\033[01;34m\]\w\[\033[00m\]\$ '
3) And replace with:
if [ "$color_prompt" = yes ]; then
PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u\[\033[00m\] [\d|\t]:\[\033[01;34m\]\w\[\033[00m\]\$ '
4) Restart terminal to check.
Sample output in terminal
If you would love to show it in the below format:
YYYY-MM-DD HH:MM:SS {domain}#{userId}:~/{folder1}/{folder2}$
export PS1='\D{%F %T} \$\[\e]0;\u#\h: \w\a\]${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u#\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$'
Right now I have my terminal with this configuration:
[hh:mm:ss] PC#User:~$
This can be achieved putting the following instruction on file ~/.bashrc
export PS1="[\$(date +%k:%M:%S)] [\e]0;\u#\h: \w\a]${debian_chroot:+($debian_chroot)}\u#\h:\w\$ "
I hope it works for you.
more simple solution
export PS1='\D{%F %T} \u#\h:\W\$'
Related
Sorry if I am not giving you enough info, this is my first time posting here.
I am trying to make this in a bash script.
Downloading...............
"run bash commands and when they are done, replace the "Downloading..." text with the text bellow in the same line aka space."
Downloading............... DONE!
go to next line and show
Installing................
"run bash commands again and when they are done, replace the "Installing..." text with the text bellow in the same line aka space."
Installing................ DONE!
I hope you get what I mean. Thanks in advance.
I've tried:
#/bin/bash
tput sc # save cursor
printf "Something that I made up for this string"
sleep 1
tput rc;tput el # rc = restore cursor, el = erase to end of line
printf "Another message for testing"
sleep 1
tput rc;tput el
printf "Yet another one"
sleep 1
tput rc;tput el
But it doesn't make new lines, it just uses one line to show all text.
I'm assuming you pulled the tput code from somewhere, and I'm guessing that 'somewhere' also explained that tput is being used to overwrite the same line multiple times (as your script actually does).
From your description it doesn't sound like you need to overwrite any lines so using tput is the wrong solution.
If I understand your description correctly you should be able to do everything you want with some (relatively) simple printf commands, eg:
printf "Downloading .... " # no '\n' in the output so cursor remains at end of current line
# run your bash commands here
printf "DONE!\n" # append to end of current line and then add a new line (\n)
printf "Installing .... " # no '\n' in the output so cursor remains at end of current line
# run more bash commands here
printf "DONE!\n" # append to end of the current line and then add a new line (\n)
Keep in mind that if any of your 'bash commands' generate any output then the cursor will be moved (probably to a new line) thus messing up your output. Net result is that you'll need to make sure your 'bash commands' do not generate any output to stdout/stderr (alternatively, make sure all output - stdout/stderr - is redirected to files).
If your requirement is to have the 'bash commands' send output to the terminal then you may need to go back to using tput ... but that's going to depend on exactly how you want the output to appear.
NOTE: If this (above) does not meet your requirement then please update the question with more details.
I would like some help to set up my .cshrc to display my current path above my prompt every time I a new prompt displays.
Terminal Example:
/current/directory/path
username#machinename > enter cmd prompt
/current/directory/path
username#machinename > display whatever return
Thanks in advance!
If you are using tcsh, the following should work:
set prompt = "%~\n%n#%m > "
Brief explanation:
%~ shows the current directory, using "~" for home;
\n moves to the next line;
%n is the user name;
%m is the host name up to the first dot.
For more information, refer to the manual page for tcsh(1), section "Special shell variables".
I have a strange problem that I didn't able to find solution for it:
When I login to my environment it configured to work with tcsh (I want to keep it like that), but when I edit the file ".tcshrc" and put the below code (Only these 2 lines), the text is printed correctly in RED, but after that the "less" command is not working anymore.
When I remove this line, less command works properly.
#!/bin/tcsh
echo "THIS LINE IS OK"
Does someone knows what could be the reason? I'm using less version: (less 436)
I create a text file: "dummy.txt" and write the following text inside: "THIS IS A DUMMY FILE"
CMD: cat dummy.txt
OUTPUT:
THIS IS A DUMMY FILE
CMD: less dummy.txt
OUTPUT:
THIS LINE IS OK
dummy.txt (END)
Only less command is not working, other commands: cat, more, vi are working properly.
Thanks in advance to the once who try to assist.
Ok, I found the issue, it is well explained in the following link:
http://www.greenwoodsoftware.com/less/faq.html#profileout
I have moved my code to ".login" instead.
I have a test script which has a lot of commands and will generate lots of output, I use set -x or set -v and set -e, so the script would stop when error occurs. However, it's still rather difficult for me to locate which line did the execution stop in order to locate the problem.
Is there a method which can output the line number of the script before each line is executed?
Or output the line number before the command exhibition generated by set -x?
Or any method which can deal with my script line location problem would be a great help.
Thanks.
You mention that you're already using -x. The variable PS4 denotes the value is the prompt printed before the command line is echoed when the -x option is set and defaults to : followed by space.
You can change PS4 to emit the LINENO (The line number in the script or shell function currently executing).
For example, if your script reads:
$ cat script
foo=10
echo ${foo}
echo $((2 + 2))
Executing it thus would print line numbers:
$ PS4='Line ${LINENO}: ' bash -x script
Line 1: foo=10
Line 2: echo 10
10
Line 3: echo 4
4
http://wiki.bash-hackers.org/scripting/debuggingtips gives the ultimate PS4 that would output everything you will possibly need for tracing:
export PS4='+(${BASH_SOURCE}:${LINENO}): ${FUNCNAME[0]:+${FUNCNAME[0]}(): }'
In Bash, $LINENO contains the line number where the script currently executing.
If you need to know the line number where the function was called, try $BASH_LINENO. Note that this variable is an array.
For example:
#!/bin/bash
function log() {
echo "LINENO: ${LINENO}"
echo "BASH_LINENO: ${BASH_LINENO[*]}"
}
function foo() {
log "$#"
}
foo "$#"
See here for details of Bash variables.
PS4 with value $LINENO is what you need,
E.g. Following script (myScript.sh):
#!/bin/bash -xv
PS4='${LINENO}: '
echo "Hello"
echo "World"
Output would be:
./myScript.sh
+echo Hello
3 : Hello
+echo World
4 : World
Workaround for shells without LINENO
In a fairly sophisticated script I wouldn't like to see all line numbers; rather I would like to be in control of the output.
Define a function
echo_line_no () {
grep -n "$1" $0 | sed "s/echo_line_no//"
# grep the line(s) containing input $1 with line numbers
# replace the function name with nothing
} # echo_line_no
Use it with quotes like
echo_line_no "this is a simple comment with a line number"
Output is
16 "this is a simple comment with a line number"
if the number of this line in the source file is 16.
This basically answers the question How to show line number when executing bash script for users of ash or other shells without LINENO.
Anything more to add?
Sure. Why do you need this? How do you work with this? What can you do with this? Is this simple approach really sufficient or useful? Why do you want to tinker with this at all?
Want to know more? Read reflections on debugging
Simple (but powerful) solution: Place echo around the code you think that causes the problem and move the echo line by line until the messages does not appear anymore on screen - because the script has stop because of an error before.
Even more powerful solution: Install bashdb the bash debugger and debug the script line by line
If you're using $LINENO within a function, it will cache the first occurrence. Instead use ${BASH_LINENO[0]}
I have a textfile (qrs.txt) which contains dir names (one per line) and on my server in the same directory as the script I have those folders with corresponding names from the text file.
This is my script:
#!/bin/bash
while read p; do
if [ ! -d "$p" ];
then
echo "ERROR $p" >> log.txt
else
echo "GOOD" >> log.txt
fi
done < qrs.txt
qrs.txt:
1992300000183805
1992300001176204
1992300002145500
1992300003104507
1992300004104902
1992300005133703
1992300006117802
1992300007144501
1992300008172803
1992300009189005
1992300010146307
1992300011151700
1992300012190007
1992300013126802
1992300014111508
1992300015193908
When that if statement is inside the loop it always returns error which is incorrect because I can see the folders exist. When I take it out of the loop and check for just 1, it works fine... When I echo $p on the same line as error, I can see the file name its checking is indeed correct.
What am I missing here..?
EDIT:
Screenshot of qrs.txt in hex mode:
http://i.snag.gy/25mqJ.jpg
RESOLVED!
My qrs.txt was in [dos] format originally but once converted to unix format using ":set ff=unix" the script worked like a charm!
Your script works fine.
I copied your script to my local machine. When I put blh blah in the qrs.txt file, I got ERROR for each time I ran your script. I ran it four times. I changed the blh blah to a valid path and I received GOOD.
The directory 1992300000183805 for instance, may be not be a valid path. You need the fully qualified path name! For example, /home/user/1992300000183805.
ERROR blh blah
ERROR blh blah
GOOD
GOOD
EDIT
Looking at #chepner comments, I recreated your problem:
Open your qrs.txt file in vi or vim. You should see ^M at the end of your lines. To remove the ^M characters at the end of all lines in vi, use:
:%s/^M//g
This should fix your problem. If not, in vim type this:
:set ff=unix
save the file.
Re-open qrs.txt in vim, then run the regex above again, or manually delete the ^M.
Or you can use perl:
perl -pi -e "s/\r/\n/g;" <file>
OK so looking at your provided file it seems those are relative directory names -- as such current directory is very important when you execute the script. Do you execute the script from its own directory or from the parent directory to all the (sub)directories shown in your example?
In other words have you tried:
cd <parent directory>
/path/to/yourscript.sh
?
Not to mention the location of qrs.txt seems to be specified relative rather than absolute path. So if there's no qrs.txt in the current directory I don't think your script would work.