I have a problem with my shell code. The purpose of the code is to automatically start the server if one is suddenly is offline due to a crash. The code works perfectly when you just simply execute it via ./script.sh & however! When I set a cron job with the script, it begins to start several processes of the srvexecutable
Unfortunately the processes have the same name, so I have to base it off the process ID and the process ID's location. Hence "realpath" is implemented.
Here is the code. I would extremely appreciate it if someone helped me fix this bug.
# Created by Lorenc!
# Server List
srvloc_1="/home/user/srv1"
server_1="/home/user/srv1/srvexecutable"
srvloc_2="/home/user/srv2"
server_2="/home/user/srv2/srvexecutable"
# Loop Iterator And Server Array!
servers=0
declare -a SRV
for word in $(pidof srvexecutable); do
SRV[servers]="$(realpath /proc/$word/exe)"
#echo ${SRV[$servers]}
let servers++
done
if [ "$servers" -ge 2 ]; then
echo "that's $servers processes"
exit
else
if [ "$servers" -le 1 ];
then
echo "Currently $servers processes."
if [ "$servers" -eq 0 ];
then
echo "No servers online! Booting both now."
cd $srvloc_1
nohup $server_1 &
sleep 1
cd $srvloc_2
nohup $server_2 &
exit
else
if ${SRV[0]} == $server_1
then
echo "Starting $server_1 as it is not online!"
cd $srvloc_1
nohup $server_1 &
else
echo "Starting $server_2 as it is not online!"
cd $srvloc_2
nohup $server_2 &
fi
fi
else
echo "Both servers are running. Beautiful."
fi
fi
Related
I want to create script that will check continuously process status running or not. If process will not run, script should catch it and restart it in a seconds. How can I run continuously this script on the system and how should I change the script via ---> Important points: it should take as parameters these: 1-seconds to wait between attempts to restart service, 2- number of attempts and 3- generate logs of events. Nginx is a example for the process. It can be replaceable.
#!/bin/bash
SERVICE="nginx"
if pgrep -x "$SERVICE" >/dev/null
then
echo "$SERVICE is running"
else
echo "$SERVICE stopped"
# start nginx if stopped
echo "$SERVICE starting"
systemctl start $SERVICE
fi
You can try something like this:
#!/bin/bash
service="nginx"
seconds=2
retries=3
until (( retries-- == 0 ))
do
property=$(systemctl show --property MainPID "$service")
if [[ $property == MainPID=0 ]]
then
echo "$service stopped"
echo "$service starting"
systemctl start "$service" >& /dev/null
else
echo "$service is running"
exit
fi
sleep "$seconds"
done
echo "$service is broken"
I am having this script which looks for the process filebeat and restarts it if is not running. Cron runs this script every 5 minutes. Most of the time this works fine except sometime it creates multiple filebeat process. Can someone please point out what is the issue in my script.
#!/bin/bash
PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin
service=filebeat
servicex=/usr/share/filebeat/bin/filebeat
pid=`pgrep -x "filebeat"`
if [ $pid > /dev/null ]
then
echo "$(date) $service is running!!!"
else
echo "$(date) starting $service"
cd /home/hpov/beats/filebeat
./filebeat -c filebeat.yml &
fi
#!/bin/bash
pidof script.x86 >/dev/null
if [[ $? -ne 0 ]] ; then
echo "Restarting script: $(date)" >> /var/log/script.txt
/etc/script/script.x86 &
fi
Super easy :D
I have BBB based custom Embedded Linux based board with busybox shell(ash)
I have a situation where my script must run in background with following condition
There must only one instance of the script.
wrapper script need to know if script started successfully in background or not.
There is another wrapper script which starts and stops my script, wrapper script is as mentioned below.
#!/bin/sh
export PATH=/bin:/sbin:/usr/bin:/usr/sbin
readonly TEST_SCRIPT_PATH="/home/testscript.sh"
readonly TEST_SCRIPT_LOCK_PATH="/var/run/${TEST_SCRIPT_PATH##*/}.lock"
start_test_script()
{
local pid_of_testscript=0
local status=0
#Run test script in background
"${TEST_SCRIPT_PATH}" &
#---------Now When this point is hit, lock file must be created.-----
if [ -f "${TEST_SCRIPT_LOCK_PATH}" ];then
pid_of_testscript=$(head -n1 ${TEST_SCRIPT_LOCK_PATH})
if [ -n "${pid_of_testscript}" ];then
kill -0 ${pid_of_testscript} &> /dev/null || status="${?}"
if [ ${status} -ne 0 ];then
echo "Error starting testscript"
else
echo "testscript start successfully"
fi
else
echo "Error starting testscript.sh"
fi
fi
}
stop_test_script()
{
local pid_of_testscript=0
local status=0
if [ -f "${TEST_SCRIPT_LOCK_PATH}" ];then
pid_of_testscript=$(head -n1 ${TEST_SCRIPT_LOCK_PATH})
if [ -n "${pid_of_testscript}" ];then
kill -0 ${pid_of_testscript} &> /dev/null || status="${?}"
if [ ${status} -ne 0 ];then
echo "testscript not running"
rm "${TEST_SCRIPT_LOCK_PATH}"
else
#send SIGTERM signal
kill -SIGTERM "${pid_of_testscript}"
fi
fi
fi
}
#Script starts from here.
case ${1} in
'start')
start_test_script
;;
'stop')
stop_test_script
;;
*)
echo "Usage: ${0} [start|stop]"
exit 1
;;
esac
Now actual script "testscript.sh" looks something like this,
#!/bin/sh
#Filename : testscript.sh
export PATH=/bin:/sbin:/usr/bin:/usr/sbin
set -eu
LOCK_FILE="/var/run/${0##*/}.lock"
FLOCK_CMD="/bin/flock"
FLOCK_ID=200
eval "exec ${FLOCK_ID}>>${LOCK_FILE}"
"${FLOCK_CMD}" -n "${FLOCK_ID}" || exit 0
echo "${$}" > "${LOCK_FILE}"
# >>>>>>>>>>-----Now run the code in background---<<<<<<
handle_sigterm()
{
# cleanup
"${FLOCK_CMD}" -u "${FLOCK_ID}"
if [ -f "${LOCK_FILE}" ];then
rm "${LOCK_FILE}"
fi
}
trap handle_sigterm SIGTERM
while true
do
echo "do something"
sleep 10
done
Now in above script you can see "---Now run the code in background--" at that point I am sure that either lock file is successfully created or instance of this script is already running. So Then I can safely run other code in background and wrapper script can check for lockfile and find out if the process mentioned in the lock file is running or not.
can shellscript itself make it to run in background ?
if not is there a better way to meet all the conditions ?
I think you can look into job control built-in, specifically bg.
Job Control Commands
When processes say they background themselves, what they actually do is fork and exit the parent. You can do the same by running whichever commands, functions or statements you want with & and then exiting.
#!/bin/sh
echo "This runs in the foreground"
sleep 3
while true
do
sleep 10
echo "doing background things"
done &
I have a shell script that does a backup. I set this script in a cron but the problem is that the backup is heavy so it is possible to execute a second rsync before the first ends up.
I thought to launch rsync in a script and then get PID and write a file that script checks if the process exist or not (if this file exist or not).
If I put rsync in background I get the PID but I don't know how to know when rsync ends up but, if I set rsync (no background) I can't get PID before the process finish so I can't write a file whit PID.
I don't know what is the best way to "have rsync control" and know when it finish.
My script
#!/bin/bash
pidfile="/home/${USER}/.rsync_repository"
if [ -f $pidfile ];
then
echo "PID file exists " $(date +"%Y-%m-%d %H:%M:%S")
else
rsync -zrt --delete-before /repository/ /mnt/backup/repositorio/ < /dev/null &
echo $$ > $pidfile
# If I uncomment this 'rm' and rsync is running in background, the file is deleted so I can't "control" when rsync finish
# rm $pidfile
fi
Can anybody help me?!
Thanks in advance !! :)
# check to make sure script isn't still running
# if it's still running then exit this script
sScriptName="$(basename $0)"
if [ $(pidof -x ${sScriptName}| wc -w) -gt 2 ]; then
exit
fi
pidof finds the pid of a process
-x tells it to look for scripts too
${sScriptName} is just the name of the script...you can hardcode this
wc -w returns the word count by words
-gt 2 no more than one instance running (instance plus 1 for the pidof check)
if more than one instance running then exit script
Let me know if this works for you.
Test both for presence of pid file and status of the running process like this:
#!/bin/bash
pidfile="/home/${USER}/.rsync_repository"
is_running =0
if [ -f $pidfile ];
then
echo "PID file exists " $(date +"%Y-%m-%d %H:%M:%S")
previous_pid=`cat $pidfile`
is_running=`ps -ef | grep $previous_pid | wc -l`
fi
if [ $is_running -gt 0 ];
then
echo "Previous process didn't quit yet"
else
rsync -zrt --delete-before /repository/ /mnt/backup/repositorio/ < /dev/null &
echo $$ > $pidfile
fi
Hope this helps!!!
I have a Perl script that I want to daemonize. Basically this perl script will read a directory every 30 seconds, read the files that it finds and then process the data. To keep it simple here consider the following Perl script (called synpipe_server, there is a symbolic link of this script in /usr/sbin/) :
#!/usr/bin/perl
use strict;
use warnings;
my $continue = 1;
$SIG{'TERM'} = sub { $continue = 0; print "Caught TERM signal\n"; };
$SIG{'INT'} = sub { $continue = 0; print "Caught INT signal\n"; };
my $i = 0;
while ($continue) {
#do stuff
print "Hello, I am running " . ++$i . "\n";
sleep 3;
}
So this script basically prints something every 3 seconds.
Then, as I want to daemonize this script, I've also put this bash script (also called synpipe_server) in /etc/init.d/ :
#!/bin/bash
# synpipe_server : This starts and stops synpipe_server
#
# chkconfig: 12345 12 88
# description: Monitors all production pipelines
# processname: synpipe_server
# pidfile: /var/run/synpipe_server.pid
# Source function library.
. /etc/rc.d/init.d/functions
pname="synpipe_server"
exe="/usr/sbin/synpipe_server"
pidfile="/var/run/${pname}.pid"
lockfile="/var/lock/subsys/${pname}"
[ -x $exe ] || exit 0
RETVAL=0
start() {
echo -n "Starting $pname : "
daemon ${exe}
RETVAL=$?
PID=$!
echo
[ $RETVAL -eq 0 ] && touch ${lockfile}
echo $PID > ${pidfile}
}
stop() {
echo -n "Shutting down $pname : "
killproc ${exe}
RETVAL=$?
echo
if [ $RETVAL -eq 0 ]; then
rm -f ${lockfile}
rm -f ${pidfile}
fi
}
restart() {
echo -n "Restarting $pname : "
stop
sleep 2
start
}
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status ${pname}
;;
restart)
restart
;;
*)
echo "Usage: $0 {start|stop|status|restart}"
;; esac
exit 0
So, (if I have well understood the doc for daemon) the Perl script should run in the background and the output should be redirected to /dev/null if I execute :
service synpipe_server start
But here is what I get instead :
[root#master init.d]# service synpipe_server start
Starting synpipe_server : Hello, I am running 1
Hello, I am running 2
Hello, I am running 3
Hello, I am running 4
Caught INT signal
[ OK ]
[root#master init.d]#
So it starts the Perl script but runs it without detaching it from the current terminal session, and I can see the output printed in my console ... which is not really what I was expecting. Moreover, the PID file is empty (or with a line feed only, no pid returned by daemon).
Does anyone have any idea of what I am doing wrong ?
EDIT : maybe I should say that I am on a Red Hat machine.
Scientific Linux SL release 5.4 (Boron)
Thanks,
Tony
I finally re-wrote the start function in the bash init script, and I am not using daemon anymore.
start() {
echo -n "Starting $pname : "
#daemon ${exe} # Not working ...
if [ -s ${pidfile} ]; then
RETVAL=1
echo -n "Already running !" && warning
echo
else
nohup ${exe} >/dev/null 2>&1 &
RETVAL=$?
PID=$!
[ $RETVAL -eq 0 ] && touch ${lockfile} && success || failure
echo
echo $PID > ${pidfile}
fi
}
I check that the pid file is not existing already (if so, just write a warning). If not, I use
nohup ${exe} >/dev/null 2>&1 &
to start the script.
I don't know if it is safe this way (?) but it works.
The proper way to daemonize a process is have it detach from the terminal by itself. This is how most larger software suites do it, for instance, apache.
The rationale behind daemon not doing what you would expect from its name, and how to make a unix process detach into the background, can be found here in section 1.7 How do I get my program to act like a daemon?
Simply invoking a program in the background isn't really adequate for
these long-running programs; that does not correctly detach the
process from the terminal session that started it. Also, the
conventional way of starting daemons is simply to issue the command
manually or from an rc script; the daemon is expected to put itself
into the background.
For further reading on this topic: What's the difference between nohup and a daemon?
According to man daemon correct syntax is
daemon [options] -- [command] [command args]
Your init script startup should run something like:
daemon --pidfile ${pidfile} -- ${exe}
As said here, it seems that the process needs to be sent to the background using &.
Daemon don’t do it for you.