Zip file is not extracting by crontab - linux

Question

i am using a perl script for unzipping a zip file by crontab. The script is working properly if i execute it manually. but whenever i set it in cron the script does not work any more. i have tested cron setting other script files are working from cron only this zip extracting script is not working .
Script is as follows :
#!/usr/bin/perl
use IO::Uncompress::Unzip qw(unzip $UnzipError);
$dir = '/root/perl';
open (han2, "ls -l $dir/*.zip |awk '{print \$9}'|");
#array1 = <han2>;
chomp(#array1);
for ($i=0;$i<=$#array1;$i++) {
$zipfile = $array1[$i];
$u = new IO::Uncompress::Unzip $zipfile
or die "Cannot open $zipfile: $UnzipError";
die "Zipfile has no members"
if ! defined $u->getHeaderInfo;
for ( $status = 1; $status > 0; $status = $u->nextStream) {
$name = $u->getHeaderInfo->{Name};
warn "Processing member $name\n" ;
if ($name =~ /\/$/) {
mkdir $name;
}
else {
unzip $zipfile => $name, Name => $name
or die "unzip failed: $UnzipError\n";
}
}
}
Crontab setting :
34 14 * * * /root/perl/./unzip.pl > /dev/null 2>&1
Please help me to do this task by cronjob

Answer 1

When cron executes your script, the current directoy probably won't /root/perl. Try chdir($dir) after you set $dir, or use full pathnames where required:
$u = new IO::Uncompress::Unzip "$dir/$zipfile"
or die "Cannot open $zipfile: $UnzipError";
mkdir "$dir/$name";
unzip "$dir/$zipfile" => "$dir/$name" ...
Changing to the correct directory is probably easier.