How to match strings with "like" keyword? - string
I'm prompting the user to enter a SaleLotNumber (string) and I'm having trouble with the formula. I have multiple entries with "20" in the SaleLotNumber but when I enter that in, I don't get anything on the report. When I enter the full SaleLotNumber in the parameter, I get the specific value from the database but I would like to enter only two numbers into the parameter and get all entries with those numbers in that order. Here's what I have:
{viewDealers_Drivetime.SaleLot} like {?SaleLotNumber}
What can I do do fix this?
I'm going to assume that {?SaleLotNumber} is a single-value parameter. To match all strings with a "20" in them, you need to use wildcards. For example, you can match a string like "012056" or "98720" by doing:
{viewDealers_Drivetime.SaleLot} like '*' + {?SaleLotNumber} + '*'
where '*' is Crystal's wildcard and {?SaleLotNumber}="20"
Related
Formula to extract number string between the nth instance of character to the next specific character (retrieving ID from URL)
I need to write a formula that can retrieve the number between the 4th "/" to the next "-"
Here's an example of the URL structure
https://www.example.com/category-name/1234-product-name
I've managed to get it done when the category name is ONE word like following URL with formula below.
https://www.example.com/category/1234-product-name
=MID(LEFT(A2,FIND("-",A2)-1),FIND("#",SUBSTITUTE(A2,"/","#",4))+1,255)
Result = 1234
The problem is that I can't rely on the category name always being one word... And the product name can also vary in characters so i can't start from right counting the "-"
Any tips & tricks? :)
You need the break the problem and then solve it.
=MID(B1,FIND("/",B1)+1, IFERROR(FIND("-",B1,FIND("/",B1)), LEN(B1) + 1) - FIND("/",B1)-1)
Explanation
=MID(TEXT, STARTING CHARACTER, NO OF CHARACTERS)
=MID(TEXT , WHERE FIRST '/' EXISTS , WHERE '-' EXISTS - WHERE FIRST '/' EXISTS )
and for removing the domain
=REPLACE(A1,1,LEN("https://www.example.com/"),"")
how to use like and substring in where clause in sql
Hope one can help me and explain this query for me,
why the first query return result but the second does not:
EDIT:
first query:
select name from Items where name like '%abc%'
second Query:
select name from Items where name like substring('''%abc%''',1,10)
why the first return result but the second return nothing while
substring('''%abc%''',1,10)='%abc%'
If there are a logic behind that, Is there another approach to do something like the second query,
my porpuse is to transform a string like '''abc''' to 'abc' in order to use like statement,
You can concatenate strings to form your LIKE string. To trim the first 3 and last 3 characters from a string use the SUBSTRING and LEN functions. The following example assumes your match string is called #input and starts and ends with 3 quote marks that need to be removed to find a match: select name from Items where name like '%' + SUBSTRING(#input, 3, LEN(#input) - 4) + '%'
How to use #Contains with #Implode in Lotus Formula
I have a document item called Pathname which is Text List containing paths to databases. I need to create a view, with only specific documents, which contain a specific database path in Pathname item.
I have tried these statements but none has worked:
1.#isMember("Databasepath",Pathname)
2.#Contains(#Implode(Pathname);"Databasepath")
Thank You for any suggestion.
There is no need for the "implode" in your code. If Pathname looks like this: apps\database1.nsf; apps\database2.nsf; mail\mailfile1.nsf; and you want to filter out all in "apps" path, then the formula would look like this: #Contains( PathName; "apps\\" ) Don't forget to duplicate the backslashes, if you "hardcode" them, as they are escape characters. But now think about a Pathname containing: localapps\db1.nsf; apps\db2.nsf; local\apps\db3.nsf Then the formula above would select ALL entries. In that case this formula would be better: #Contains( "#" + PathName; "#apps\\" ) Or (if the given path is always at the beginning): #Begins( PathName; "apps\\" )
If it's truly a text list (i.e., "Path1\Db1.nsf" : "Path2\Db2.nsf" : "Path3\Db3.nsf"), then you should just be able to use the equals operator because a comparison of a scalar to a list value returns true if the scalar matches any of the list values. This detail of the semantics of formula language actually makes a lot of uses of #Contains unnecessary! I.e., it should be as simple as SELECT Pathname = "Path1\\Db1.nsf"; or if Pathname is not already case normalized, then SELECT #uppercase(Pathname) = "PATH1\\DB1.NSF";
Lua: Search a specific string
Hi all tried all the string pattrens and library arguments but still stuck.
i want to get the name of the director from the following string i have tried the string.matcH but it matches the from the first character it finD from the string
the string is...
fixstrdirector = {id:39254,cast:[{id:15250,name:Hope Davis,character:Aunt Debra,order:5,cast_id:10,profile_path:/aIHF11Ss8P0A8JUfiWf8OHPVhOs.jpg},{id:53650,name:Anthony Mackie,character:Finn,order:3,cast_id:11,profile_path:/5VGGJ0Co8SC94iiedWb2o3C36T.jpg},{id:19034,name:Evangeline Lilly,character:Bailey Tallet,order:2,cast_id:12,profile_path:/oAOpJKgKEdW49jXrjvUcPcEQJb3.jpg},{id:6968,name:Hugh Jackman,character:Charlie Kenton,order:0,cast_id:13,profile_path:/wnl7esRbP3paALKn4bCr0k8qaFu.jpg},{id:79072,name:Kevin Durand,character:Ricky,order:4,cast_id:14,profile_path:/c95tTUjx5T0D0ROqTcINojpH6nB.jpg},{id:234479,name:Dakota Goyo,character:Max Kenton,order:1,cast_id:15,profile_path:/7PU6n4fhDuFwuwcYVyRNVEZE7ct.jpg},{id:8986,name:James Rebhorn,character:Marvin,order:6,cast_id:16,profile_path:/ezETMv0YM0Rg6YhKpu4vHuIY37D.jpg},{id:930729,name:Marco Ruggeri,character:Cliff,order:7,cast_id:17,profile_path:/1Ox63ukTd2yfOf1LVJOMXwmeQjO.jpg},{id:19860,name:Karl Yune,character:Tak Mashido,order:8,cast_id:18,profile_path:/qK315vPObCNdywdRN66971FtFez.jpg},{id:111206,name:Olga Fonda,character:Farra Lemkova,order:9,cast_id:19,profile_path:/j1qabOHf3Pf82f1lFpUmdF5XvSp.jpg},{id:53176,name:John Gatins,character:Kingpin,order:10,cast_id:41,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:1126350,name:Sophie Levy,character:Big Sister,order:11,cast_id:42,profile_path:null},{id:1126351,name:Tess Levy,character:Little Sister,order:12,cast_id:43,profile_path:null},{id:1126352,name:Charlie Levy,character:Littlest Sister,order:13,cast_id:44,profile_path:null},{id:187983,name:Gregory Sims,character:Bill Panner,order:14,cast_id:45,profile_path:null}],crew:[{id:58726,name:Leslie Bohem,department:Writing,job:Screenplay,profile_path:null},{id:53176,name:John Gatins,department:Writing,job:Screenplay,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:17825,name:Shawn Levy,department:Directing,job:Director,profile_path:/7f2f8EXdlWsPYN0HPGcIlG21xU.jpg},{id:12415,name:Richard Matheson,department:Writing,job:Story,profile_path:null},{id:57113,name:Dan Gilroy,department:Writing,job:Story,profile_path:null},{id:25210,name:Jeremy Leven,department:Writing,job:Story,profile_path:null},{id:17825,name:Shawn Levy,department:Production,job:Producer,profile_path:/7f2f8EXdlWsPYN0HPGcIlG21xU.jpg},{id:34970,name:Susan Montford,department:Production,job:Producer,profile_path:/1XJt51Y9ciPhkHrAYE0j6Jsmgji.jpg},{id:3183,name:Don Murphy,department:Production,job:Producer,profile_path:null},{id:34967,name:Rick Benattar,department:Production,job:Producer,profile_path:null},{id:1126348,name:Eric Hedayat,department:Production,job:Producer,profile_path:null},{id:186721,name:Ron Ames,department:Production,job:Producer,profile_path:null},{id:10956,name:Josh McLaglen,department:Production,job:Executive Producer,profile_path:null},{id:57634,name:Mary McLaglen,department:Production,job:Executive Producer,profile_path:null},{id:23779,name:Jack Rapke,department:Production,job:Executive Producer,profile_path:null},{id:488,name:Steven Spielberg,department:Production,job:Executive Producer,profile_path:/cuIYdFbEe89PHpoiOS9tmo84ED2.jpg},{id:30,name:Steve Starkey,department:Production,job:Executive Producer,profile_path:null},{id:24,name:Robert Zemeckis,department:Production,job:Executive Producer,profile_path:/isCuZ9PWIOyXzdf3ihodXzjIumL.jpg},{id:531,name:Danny Elfman,department:Sound,job:Original Music Composer,profile_path:/pWacZpYPos8io22nEiim7d3wp2j.jpg},{id:18265,name:Mauro Fiore,department:Crew,job:Cinematography,profile_path:null},{id:54271,name:Dean Zimmerman,department:Editing,job:Editor,profile_path:null},{id:25365,name:Richard Hicks,department:Production,job:Casting,profile_path:null},{id:5490,name:David Rubin,department:Production,job:Casting,profile_path:null},{id:52088,name:Tom Meyer,department:Art,job:Production Design,profile_path:null}]}
i have tried string.match(fixstrdirector,"name:(.+),department:Directing")
but it gives me the from the first occurace it find the name to the end of thr string
output:
Hope Davis,character:Aunt Debra,order:5,cast_id:10,profile_path:/aIHF11Ss8P0A8JUfiWf8OHPVhOs.jpg},{id:53650,name:Anthony Mackie,character:Finn,order:3,cast_id:11,profile_path:/5VGGJ0Co8SC94iiedWb2o3C36T.jpg},{id:19034,name:Evangeline Lilly,character:Bailey Tallet,order:2,cast_id:12,profile_path:/oAOpJKgKEdW49jXrjvUcPcEQJb3.jpg},{id:6968,name:Hugh Jackman,character:Charlie Kenton,order:0,cast_id:13,profile_path:/wnl7esRbP3paALKn4bCr0k8qaFu.jpg},{id:79072,name:Kevin Durand,character:Ricky,order:4,cast_id:14,profile_path:/c95tTUjx5T0D0ROqTcINojpH6nB.jpg},{id:234479,name:Dakota Goyo,character:Max Kenton,order:1,cast_id:15,profile_path:/7PU6n4fhDuFwuwcYVyRNVEZE7ct.jpg},{id:8986,name:James Rebhorn,character:Marvin,order:6,cast_id:16,profile_path:/ezETMv0YM0Rg6YhKpu4vHuIY37D.jpg},{id:930729,name:Marco Ruggeri,character:Cliff,order:7,cast_id:17,profile_path:/1Ox63ukTd2yfOf1LVJOMXwmeQjO.jpg},{id:19860,name:Karl Yune,character:Tak Mashido,order:8,cast_id:18,profile_path:/qK315vPObCNdywdRN66971FtFez.jpg},{id:111206,name:Olga Fonda,character:Farra Lemkova,order:9,cast_id:19,profile_path:/j1qabOHf3Pf82f1lFpUmdF5XvSp.jpg},{id:53176,name:John Gatins,character:Kingpin,order:10,cast_id:41,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:1126350,name:Sophie Levy,character:Big Sister,order:11,cast_id:42,profile_path:null},{id:1126351,name:Tess Levy,character:Little Sister,order:12,cast_id:43,profile_path:null},{id:1126352,name:Charlie Levy,character:Littlest Sister,order:13,cast_id:44,profile_path:null},{id:187983,name:Gregory Sims,character:Bill Panner,order:14,cast_id:45,profile_path:null}],crew:[{id:58726,name:Leslie Bohem,department:Writing,job:Screenplay,profile_path:null},{id:53176,name:John Gatins,department:Writing,job:Screenplay,profile_path:/A2MqnSKVzOuBf8MVfNyve2h2LxJ.jpg},{id:17825,name:Shawn Levy
You're searching from the first occurrence of "name:" until the "department:Directing" with everything in between. Instead, you need to restrict what can be between the two strings. Here for example I'm saying that the characters that make up the name can only be alphanumeric or a space: string.match(fixstrdirector,"name:([%w ]+),department:Directing") Alternatively, given that there's a comma separating the parameters, a better approach would be to search for "name:" followed by any characters other than a comma, followed by "department:Directing": string.match(fixstrdirector,"name:([^,]+),department:Directing") Of course that wouldn't work if the name had a comma it in!
Lua patterns provides - modifier for tasks as you have above. As stated on PiL - Section 20.2:
The + modifier matches one or more characters of the original class.
It will always get the longest sequence that matches the pattern.
Like *, the modifier - also matches zero or more occurrences of
characters of the original class. However, instead of matching the
longest sequence, it matches the shortest one.
Next, when you are using . to match, it'll find any and all characters satisfying the pattern. Therefore, you'll get the result from first occurence of name until the ,department:Directing is found. Since you know that it is a JSON data, you can try to match for [^,]; that is, non-comma characters.
So, for your case try:
local tAllNames = {}
for sName in fixstrdirector:gmatch( "name:([^,]-),department:Directing" ) do
tAllNames[ #tAllNames + 1 ] = sName
end
and all your required names will be stored in the table tAllNames. An example of the above can be seen at codepad.
Is there any way when I choose an option not to clear previously typed data in the input
The problem is this:
In my programme at first the user gets options for a first name - so hopefully he likes something from the options and he chooses it -so far everything is OK!
But then when he types space he starts receiving options for second name and a if he likes something and chooses it - then the Autocomplete just erases the first name. Is there any way I can change that?
hello Rich thank you very much or your response - now i've decided to change my task and here is what I made when a user types for example I character i get all the first names that start with I- so far no problem! ANd when he types the white space and K for example I make request to my web service that gets the middle names that starts with K or the last names that start with K (one of them should start with K for Iwelina), so in this case for Iwelina Ive got RADULSKA KOSEWA and KOSEWA NEDEWA! For the source of autocomplete I concatenate iwelina with (radulska kosewa)and iwelina with (KOSEWA NEDEWA) so at the end I've got IWELINA IELINA RADULSKA KOSEWA and IWELINA KOSEWA NEDEWA!!! the only problem is that when i type Iwelina K i get only IWELINA KOSEWA NEDEWA!!!here is the code for autocomlete
$('#input').autocomplete({
source: function(request, response) {
var matcher = new RegExp( $.ui.autocomplete.escapeRegex(request.term, " "));
var data = $.grep( srcAutoComp, function(value) {
return matcher.test( value.label || value.value || value );
});
response(data);
}
});
if you know how i can change it I will be glad for the help
I don't understand how, when the user begines to type the second name, he's getting results that are only the last name. For example, if he types "Joh" and selects "John" from the options, and then continues to type "John Do", then how is it possible that your drop down gives him results for only the last name, like "Doe"? At any rate, assuming this is truly happening, you could just combine all combinations of first and last names in your source data and that will show "John Doe" in the drop down when the user types "Joh" selects "John" and then continues to type "John Do". Another way to do this is with a complicated change to the search and response events to search after a space if it is there, and recombine it with the first string after the search for the last name is complete. If you give me your source data, I could put something together for this.