I've been googling for 30 minutes but I can't find a solution to my problem.
Please help!
import math
amount = input("Enter amount of medicine left: ")
dose = input("Enter dose per day: ")
def convertString(str):
try:
returnValue = int(str)
except ValueError:
returnValue = float(str)
return returnValue
def count_days(amount, dose):
last_days = amount / dose
return last_days
print("Your medicine will run out in ",last_days," days.")
I get this error:
NameError: name 'last_days' is not defined
Why isn't this working?
The variable last_days is local within the count_days function. That means that as soon as the function ends, the variable is no longer available. That is however not a problem as the function actually returns that value, making it available for others.
So when you do my_var = count_days(amount, dose), then the function will execute, and return its last_days result which is then stored in my_var.
last_days = count_days(amount, dose)
print("Your medicine will run out in ", last_days, " days.")
last_days is defined just within count_days. Initialise the variable on top of the file to change the visibility
Related
New to programming. I wrote a program that Asks the user to enter the name, age and shoe size for four people and adds it to a dictionary. In fact, it works even when I don't use one function as an argument for another function. However, when i try to pass get_user_info() to store_user_info it doesnt work. I also tried to pass get_user_info to three separate variables and then passed these variables to store_user_info and it still didn't work. I am probably making a dumb error. Sorry its kind of a basic type of query but I just started learning programming. Any guidance is appreciated.
FOLLOWING CODE DOESN'T WORK: IT RUNS THE FOR LOOP BUT NEVER PROMPTS FOR THE INPUT FOR MORE THAN ONCE
#get user info
def get_user_info():
while True:
try:
user_input_name = (input("What is your name "))
user_input_age = int(input("How old are you "))
user_input_shoesize = float(input("What is your show size "))
break
except (ValueError,IndexError):
print('wrong selection or input')
return user_input_name,user_input_age,user_input_shoesize
#Store user info
def store_user_info(user_info):
user_information = {}
for i in range(3):
name, age, shoesize = user_info
user_information[name] = {"age" : age,"shoesize": shoesize}
print(user_information)
return user_information
=
store_user_info(get_user_info())
YET THE FOLLOWING WORKS and the loop works 3 times as expected:
#get user info
def get_user_info():
while True:
try:
user_input_name = (input("What is your name "))
user_input_age = int(input("How old are you "))
user_input_shoesize = float(input("What is your show size "))
break
except (ValueError,IndexError):
print('wrong selection or input')
return user_input_name,user_input_age,user_input_shoesize
#Store user info
def store_user_info():
user_information = {}
for i in range(3):
name, age, shoesize = get_user_info()
user_information[name] = {"age" : age,"shoesize": shoesize}
print(user_information)
return user_information
store_user_info()
My first file has this code:
def main(self):
age = input("Enter your age: ")
ins = Aged()
ins.ageplus()
main()
*i need to print it when main() is called in main()
My second file:
class Aged():
def ageplus():
print("Your new age is:", age)
You need to pass age as an argument to ageplus function.
Secondly assuming your second file is called age.py.
Add from age import Aged at the top of your first file.
Here I created a module.
class Employee:
def __init__(self):
self.name = input("Enter your name: ")
self.account_number = int(input("Enter your account number: "))
def withdraw(self): # it receives values from for
if withdraw1 > current_balance:
print ("You have entered a wrong number: ")
else:
print ("The current balance is: ", current_balance - withdraw1)
import TASK2 # I am importing the module I created
c = TASK2.Employee()
def for(self):
c.withdraw1 = int(input("enter number: "))
c.current_balance = int(input("Enter the current balance: "))
d = method(c.withdraw) # here I am trying to pass the values to withdraw
print (d)
The problem I get is that although it asks for the values instead of giving me an answer it gives me None.
Here's my take on your code.
# TASK2.py
class Employee:
def __init__(self):
self.name = input("Enter your name: ")
self.account_number = int(input("Enter your account number: "))
# make sure you initialise your member variables!
self.withdraw_val = 0 # withdraw1 is ambiguous, so I use withdraw_val instead
self.current_balance = 0
# receives values from for ### no it doesn't, right now, it GIVES values TO your "for" function
def withdraw(self):
if self.withdraw_val > self.current_balance: # remember to use "self." to
# access members within the class
print ("You have entered a wrong number: ")
else:
# again, remember "self."
print ("The current balance is: ", self.current_balance - self.withdraw_val)
# TASK2sub.py
import TASK2
c = TASK2.Employee()
def for_employee(employee): # (1) don't use "self" outside a class
# it's contextually unconventional
# (2) "for" is a keyword in Python, don't use it for naming
# variables/functions, it'll mess things up
employee.withdraw_val = int(input("Enter value to withdraw: "))
employee.current_balance = int(input("Enter the current balance: "))
return employee.withdraw_val # not entirely sure what you want to return
# but you should definitely return something
# if you're going to assign it to some variable
d = for_employee(c.withdraw()) # "for_employee" function needs a return statement
# ".withdraw()" method should also require a return statement
print(d)
Note: I'll be referring to your original for function as for_employee from now on. Also note that I'm still hazy about what you're trying to accomplish and that there is most probably a more suitable name for it.
Since your original for_employee function didn't return anything, it returns None by default. (This explains the output you saw.)
I think you're misunderstanding how functions work in general. For example,
d = for_employee(c.withdraw())
print(d)
Your comment for the .withdraw() method is inaccurate.
"it receives values from for"
More accurately, c.withdraw() will first be computed, then whatever it returns is passed into the for_employee function as a parameter. Instead of "receiving values from", the withdraw method "gives values to" the for_employee function.
Something more reasonable would be
c.withdraw() # on a line by itself, since it doesn't return anything
d = for_employee(c) # pass the entire object, since you'll be using self.withdraw_val and whatnot
print(d)
Another issue is with conventional naming. This is what I get from the IDLE (with Python 3.7) when defining a function named for
>>> def for(a): return a
SyntaxError: invalid syntax
Again, for is a keyword in Python, don't use it for naming your variables, functions, or classes.
With self, it's less severe (but I could see that it's confusing you). self is more of a convention used in class methods. But for_employee isn't a class method. So conventionally speaking, the parameter shouldn't be named self.
(I find the code spaghetti-ish, it might benefit if you refactor the code by moving the for_employee method into the class itself. Then it would completely make sense to use self.)
Okay, trying to make a simple game of Guessing Numbers but I can't find the mistake in this code. Still pretty new to python so probably the reason why but I can't figure out what is wrong with it.
import random
from time import sleep
def start():
print("Welcome To The Guessing Game \n Try to guess the number I'm thinking of \n Good luck!")
selectRandomNumber()
guessCheck(number, numberInput=1)
def restart():
print("Creating new number ...")
sleep(1)
print("OK")
selectRandomNumber()
guessCheck(number,numberInput=1)
def selectRandomNumber():
number = random.randint(0,1000)
tries = 0
return
def tryAgain():
while True:
try:
again = int(input("Do you want to play again? y/n:"))
except ValueError:
print("Couldn't understand what you tried to say")
continue
if again == "y" or "yes":
print("Awesome! Lets go")
restart()
elif again == 'n' or "no":
print("Goodbye!")
break
else:
print("Not a valid option")
continue
def guessCheck(number,numberInput=1):
while True:
try:
numberInput = int(input("What number do you think it is?: "))
except ValueError:
print("Couldn't understand that. Try again")
continue
if numberInput > number:
print("Too high")
tries += 1
continue
elif numberInput < number:
print("Too low")
tries += 1
continue
elif numberInput == number:
print("Congrats! You got my number")
tryAgain()
number = selectRandomNumber()
print(number)
start()
Every time I try to run the program I keep getting the same mistake.
It tells me:
Traceback (most recent call last):
File "python", line 60, in <module>
start()
File "python", line 8, in start
guessCheck(number, numberInput)
NameError: name 'number' is not defined
Don't quite understand what that means.
Some help would be appreciated. Thanks!
* UPDATE *
Was able to fix the part about defining the variable but now new problem happened where when I try to run
Same code as before but added
guessCheck(number,numberInput=1)
and also added the variable number at the end
number = selectRandomNumber()
print(number)
start()
when I run it I get this
None # this is from `print(number)` so instead of getting a number here I'm getting `None`
Welcome To The Guessing Game
Try to guess the number I'm thinking of
Good luck!
What number do you think it is?:
The Traceback is telling you this:
We got to start().
start() called guessCheck().
We tried to pass two pieces of information to guessCheck(): the variable names number and numberInput.
We don't have those variables defined yet! numberInput doesn't get defined until once we've already started guessCheck(), and number isn't actually defined anywhere.
As Manoj pointed out in the comments, you probably want number to hold the output of selectRandomNumber(). So, instead of just calling selectRandomNumber() in start(), try number = selectRandomNumber() instead.
You can add a print(number) on the line right after that to make sure number has a value assigned to it.
Now number has a value, going into your call to guessCheck(). That still leaves numberInput undefined though. You can set a default value for function arguments like this:
guessCheck(number, numberInput=1)
That way, when guessCheck is called but numberInput hasn't been defined yet, it will automatically give it the value 1 until you set it explicitly.
You may encounter other issues with your code the way it is. My advice would be to start really simply - build up your game from each individual piece, and only put the pieces together when you're sure you have each one working. That may seem slower, but trying to go too fast will cause misunderstandings like this one.
I just deleted my previous question as someone made it embarrassingly obvious that I didn't ask an actual question with a main goal.I apologise for this.
I am only referring to the last part of the code. The "A" option as i cannot figure out why it is incorrect
The full thing works other than the A section it says there is a syntax error. That's it.
I've tried re placing the brackets and playing around with them and so on.
def Jobs():
def Parse_Line(Job_Line):
Job_Line = Job_Line.strip()
Estimate_Number, Estimate_Date, Customer_ID, Final_Total, Job_Status,Amount_Pay= Job_Line.split(",")
Painting_Job = {
'Estimate_Number':Estimate_Number,
'Estimate_Date':Estimate_Date,
'Customer_ID':Customer_ID,
'Final_Total':Final_Total,
'Job_Status':Job_Status,
'Amount_Pay':Amount_Pay,
}
return Painting_Job
Job_List = []
with open("paintingJobs.txt", "r") as Painting_Jobs:
for line in Painting_Jobs:
Job_List.append(Parse_Line(line))
return Job_List
def Accepted(job):
return job['Job_Status'] == "A"
def Outstanding(job):
return int(job['Final_Total']) - int(job['Amount_Pay'])
Job_List = Jobs()
print ("\nOption A: Search for an estimate\n\nOption B: Dislay the outstanding payments\n\nOption C: Display your total revenue\n\nOr Press Q to quit")
Option_Choice = input("Which option do you want to do?")
if Option_Choice == "A" or Option_Choice == "a":
Estimate_no = input("Please enter the required estimate number so we search our database: ")
Estimate_Found = Estimate_no
job in Job_List if ['Estimate_Number'] == Estimate_no
if Estimate_Found:
print (Estimate_Found)