Excel VBA - Set values of Enumerated elements - excel

Question

In a Class Module there is:
Private Enum colType
ID = "A"
SSN = "B"
lName = "H"
fName = "G"
End Enum
as a private member. Whenever the class initializes I get the Compile Error: Type Mismatch message. If I declare colType as Private Enum coltype As String. That gets highlighted red as an error and I get the message:
Compile Error: Expected end of statement
Is specifying the values of enumerated elements Unallowed in Excel VBA?

Answer 1

As written in the comments, this is not possible. There is possible workaround though that I used in the past. Have:
Private Enum colType
ID = 1
SSN = 2
lName = 3
fName = 4
End Enum
And then create a separate String property of function such as:
Public Property Get colType_String(colType) as String
Dim v as Variant
v= Array("A","B", ...)
colType_String = vba.cstr(v(colType))
End Property
This is not the most universal solution, but it is easy to implement and it does the job... If you have this in the class module already you can even use property on private colType variable and there is no need to have colType input into the property.

Answer 2

I quite like ex-man's solution in certain circumstances, for which reason I've upvoted it. The solution more often posited goes along the following lines:
Enum myEnum
myName1 = 1
myName2 = 2
myName3 = 3
End Enum
Function getEnumName(eValue As myEnum)
Select Case eValue
Case 1
getEnumName = "myName1"
Case 2
getEnumName = "myName2"
Case 3
getEnumName = "myName3"
End Select
End Function
Debug.Print getEnumName(2) prints "myName2"

Answer 3

I have been searching for a very long time for the answer to this question. I do not want to have to relist the contents of an Enum in either a Case statement or an array. I couldn't find the answer, but I have managed to do after finding the code somewhere to change Module content. An alteration of that has produced the following working code, to be placed in Module1:
Option Explicit
Enum MensNames
Fred
Trev = 5
Steve
Bill = 27
Colin
Andy
End Enum
Sub EnumStringTest()
MsgBox EnumString(Steve) & " = " & Steve
End Sub
Function EnumString(EnumElement As MensNames) As String
Dim iLineNo As Integer
Dim iElementNo As Integer
iElementNo = 0
EnumString = vbNullString
With ThisWorkbook.VBProject.VBComponents("Module1").CodeModule
' Find the Enum Start
For iLineNo = 1 To .CountOfLines
If InStr(.Lines(iLineNo, 1), "Enum MensNames") > 0 Then
Exit For
End If
Next iLineNo
' Find the required Element
iLineNo = iLineNo + 1
Do While InStr(.Lines(iLineNo, 1), "End Enum") = 0 And .Lines(iLineNo, 1) <> ""
If InStr(2, .Lines(iLineNo, 1), "=") > 0 Then
iElementNo = CLng(Mid(.Lines(iLineNo, 1), InStr(2, .Lines(iLineNo, 1), "=") + 1))
End If
If iElementNo = EnumElement Then
EnumString = Left(Trim(.Lines(iLineNo, 1)), IIf(InStr(1, Trim(.Lines(iLineNo, 1)), " ") = 0, 1000, InStr(1, Trim(.Lines(iLineNo, 1)), " ") - 1))
Exit Do
End If
iElementNo = iElementNo + 1
iLineNo = iLineNo + 1
Loop
End With
End Function

Answer 4

To improve the solution of Rich Harding, I use the enum to improve on readability and make it less prone to mistakes:
Enum myEnum
myName
someOtherName
lastName
End Enum
Function getEnumName(eValue As myEnum) As String
Select Case eValue
Case myName: getEnumName = "myName"
Case someOtherName: getEnumName = "someOtherName"
Case lastName: getEnumName = "lastName"
End Select
End Function

Answer 5

The long integers in the Enum could be Base-10 encodings. The ToAlpha function below converts the number to Base-26, represented with uppercase alphabet characters. To get the number, call the ToLong function with a string.
This would work up to 6 characters (anything above 2,147,483,647 overflows the Enum value).
Private Enum colType
ID = 0 'A
SSN = 1 'B
lName = 7 'H
fName = 6 'G
WORD = 414859
FXSHRXX = 2147483647 'Maximum long
End Enum
Sub test()
Debug.Print "ID: " & ToAlpha(colType.ID)
Debug.Print "SSN: " & ToAlpha(colType.SSN)
Debug.Print "lName: " & ToAlpha(colType.lName)
Debug.Print "fName: " & ToAlpha(colType.fName)
Debug.Print "WORD: " & ToAlpha(colType.WORD)
Debug.Print "FXHRXX: " & ToAlpha(colType.FXSHRXX)
End Sub
Function ToAlpha(ByVal n)
If n < 0 Or Int(n) <> n Then Exit Function 'whole numbers only
Do While n > 25
ToAlpha = Chr(n Mod 26 + 65) & ToAlpha
n = n \ 26 - 1 'base 26
Loop
ToAlpha = Chr(n + 65) & ToAlpha
End Function
Function ToLong(ByVal s)
s = UCase(s)
Dim iC
For i = 1 To Len(s)
iC = Asc(Mid(s, i, 1))
If iC < 65 Or iC > 90 Then 'A-Z only
ToLong = -1
Exit Function
End If
ToLong = ToLong * 26 + (iC - 64) 'base 26
Next
ToLong = ToLong - 1
End Function

Answer 6

My solution of this looks like this:
Private Enum ColType
ID = 1
SSN = 2
lName = 3
fName = 4
End Enum
Private Function GetEnumName(ByVal value As ColType)
GetEnumName = Choose(value, _
"A", _
"B", _
"H", _
"G" _
)
End Function
Using Choose looks more tidy.
Sample usage: ... = GetEnumName(ColType.ID)

Answer 7

I hope this help
Reference: (Microsoft Visual Basic for Application Extensibility 5.3) is required
Public Enum SecurityLevel
IllegalEntry = 0
SecurityLevel1 = 1
SecurityLevel2 = 3
SecurityLevel3
SecurityLevel4 = 10
End Enum
Public Sub Test1()
Cells.Clear
Range("A1").Value = StrEnumVal("SecurityLevel", SecurityLevel.IllegalEntry)
Range("A2").Value = StrEnumVal("SecurityLevel", SecurityLevel.SecurityLevel1)
Range("A3").Value = StrEnumVal("SecurityLevel", SecurityLevel.SecurityLevel2)
Range("A4").Value = StrEnumVal("SecurityLevel", SecurityLevel.SecurityLevel3)
Range("A5").Value = StrEnumVal("SecurityLevel", SecurityLevel.SecurityLevel4)
End Sub
Public Sub AaaTest2()
Cells.Clear
Dim E As Long
For E = SecurityLevel.IllegalEntry To SecurityLevel.SecurityLevel4
Cells(E + 1, 1) = StrEnumVal("SecurityLevel", E)
Next
End Sub
Function StrEnumVal(BEnumName As String, EnumItm As Long) As String
'''''''''''''''''''''''''
' Fahad Mubark ALDOSSARY'
'''''''''''''''''''''''''
Dim vbcomp As VBComponent
Dim modules As Collection
Dim CodeMod As VBIDE.CodeModule
Dim numLines As Long ' end line
Dim MdlNm As String
Dim lineNum As Long
Dim thisLine As String, SpltEnm As String, EnumITems As String, Itm As String
Dim EEnumName As String
Dim Indx As Long
Dim I As Long, s As Long
Dim SpltEI As Variant
Indx = 0
Set modules = New Collection
BEnumName = "Enum " & BEnumName
EEnumName = "End Enum"
For Each vbcomp In ThisWorkbook.VBProject.VBComponents
'if normal or class module
If vbcomp.Type = vbext_ct_StdModule Then
Set CodeMod = vbcomp.CodeModule
With CodeMod
numLines = .CountOfLines
For lineNum = 1 To numLines
thisLine = .Lines(lineNum, 1)
If InStr(1, thisLine, BEnumName, vbTextCompare) > 0 Then
If InStr(thisLine, ":") > 0 Then
' thisLine = Replace(thisLine, BEnumName & ":", "") ' Remove Enum Titel Enum
thisLine = Right(thisLine, Len(thisLine) - InStr(1, thisLine, ":"))
For s = 0 To UBound(Split(thisLine, ":"))
SpltEnm = Split(thisLine, ":")(s)
If InStr(SpltEnm, " = ") > 0 Then
Itm = SpltEnm
Indx = CDbl(Split(SpltEnm, " = ")(1))
Else
Itm = SpltEnm & " = " & Indx
End If
EnumITems = EnumITems & IIf(EnumITems <> "", vbNewLine, "") & Itm '''''
Indx = Indx + 1
Next
If InStr(1, thisLine, EEnumName, vbTextCompare) > 0 Then
EnumITems = Replace(EnumITems, "End Enum", "")
Exit For
End If
Else
'Only Title show if nothing bedside
End If
ElseIf InStr(1, thisLine, EEnumName, vbTextCompare) > 0 Then
If InStr(thisLine, ":") > 0 Then
For s = 0 To UBound(Split(thisLine, ":"))
SpltEnm = Split(thisLine, ":")(s)
If InStr(SpltEnm, " = ") > 0 Then
Itm = SpltEnm
Indx = CDbl(Split(SpltEnm, " = ")(1))
Else
Itm = SpltEnm & " = " & Indx
End If
EnumITems = EnumITems & IIf(EnumITems <> "", vbNewLine, "") & Itm '''''
EnumITems = Replace(EnumITems, "End Enum", "")
Indx = Indx + 1
Next
Else
End If
Exit For
Else
If InStr(thisLine, ":") > 0 Then
For s = 0 To UBound(Split(thisLine, ":"))
SpltEnm = Split(thisLine, ":")(s)
If InStr(SpltEnm, " = ") > 0 Then
Itm = SpltEnm
Indx = CDbl(Split(SpltEnm, " = ")(1))
Else
Itm = SpltEnm & " = " & Indx
End If
EnumITems = EnumITems & IIf(EnumITems <> "", vbNewLine, "") & Itm '''''
Indx = Indx + 1
Next
Else
If InStr(thisLine, " = ") > 0 Then
Itm = thisLine
Indx = Split(thisLine, " = ")(1)
Else
Itm = thisLine & " = " & Indx
End If
EnumITems = EnumITems & IIf(EnumITems <> "", vbNewLine, "") & Itm '''''
End If
Indx = Indx + 1
End If
Next lineNum
If InStr(1, thisLine, EEnumName, vbTextCompare) > 0 Then Exit For
End With 'CodeMod
End If
Next vbcomp
SpltEI = Split(EnumITems, vbNewLine)
For I = LBound(SpltEI) To UBound(SpltEI)
If CDbl(Replace(Split(SpltEI(I), " = ")(1), " ", "")) = EnumItm Then
StrEnumVal = Replace(Split(SpltEI(I), " = ")(0), " ", "")
Exit For
Else
End If
Next
End Function
To active Required Reference copy Below Code then delete it
enter image description here
Sub AddReferenceVBA()
AddRef ThisWorkbook, "{0002E157-0000-0000-C000-000000000046}", "VBIDE", 5, 3
End Sub
Sub AddRef(wbk As Workbook, sGuid As String, sRefName As String, sRefMajor As Long, sRefMinor As Long)
Dim I As Integer
On Error GoTo EH
With wbk.VBProject.References
For I = 1 To .Count
If .Item(I).Name = sRefName Then
Exit For
End If
Next I
If I > .Count Then
.AddFromGuid sGuid, sRefMajor, sRefMinor ' 0,0 should pick the latest version installed on the computer
ThisWorkbook.Save
End If
End With
EX: Exit Sub
EH: MsgBox "Error in 'AddRef'" & vbCrLf & vbCrLf & Err.Description
Resume EX
Resume ' debug code
End Sub

Answer 8

Updated and corrcted
Public Enum SecurityLevelp
IllegalEntry = 1
SecurityLVL1
SecurityLVL2 = 8
SecurityLVL3
SecurityLVL4 = 10
SecurityLVL5
SecurityLVL6 = 15
End Enum
Public Sub Test()
AddRef ThisWorkbook, "{0002E157-0000-0000-C000-000000000046}", "VBIDE", 5, 3 'if need or delete this line. To select required Reference
MsgBox GeEnumValues("SecurityLevelp", 1) 'to replace enum
MsgBox GeEnumValues("SecurityLevelp", SecurityLVL3) 'to replace enum
MsgBox GeEnumValues("SecurityLevelp", 11) 'to replace enum
MsgBox GeEnumValues("SecurityLevelp", SecurityLVL6) 'to replace enum
End Sub
Function GeEnumValues(PrcName As String, EnumItm As Long)
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'Reference:Microsoft Visual Basic for Extensibility 5.3 is required'
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Dim VBProj As VBIDE.VBProject
Dim VBComp As VBIDE.VBComponent
Dim CodeMod As VBIDE.CodeModule
Dim ProcStrLn As Long, ProcAcStrLn As Long, ProcCntLn As Long, N As Long, D As Long, S As Long, PrcCnountLine As Long
Dim DecStrLn As Long, DecEndLn As Long
Dim ThisLine As String, Dec As String, ThisSub As String, Itm As String
Dim DecItm As Variant
Set VBProj = ThisWorkbook.VBProject
For Each VBComp In VBProj.VBComponents
With VBComp
If .Type = vbext_ct_StdModule Then ' Withen Standr Module
With .CodeModule
If InStr(1, .Lines(1, .CountOfLines), PrcName) > 0 Then 'Replace Sub Function
On Error Resume Next
ProcStrLn = .ProcStartLine(PrcName, vbext_pk_Proc) ' Procedure Start Line
ProcAcStrLn = .ProcBodyLine(PrcName, vbext_pk_Proc) ' Actually Procedure Start Line
ProcCntLn = .ProcCountLines(PrcName, vbext_pk_Proc)
PrcCnountLine = ProcCntLn - (ProcAcStrLn - ProcStrLn)
If ProcAcStrLn > 0 Then
'If PrcName = .ProcOfLine(ProcAcStrLn, vbext_pk_Proc) Then 'Get Proce Name
' For N = (ProcAcStrLn + 1) To (ProcAcStrLn + PrcCnountLine - 1) ' Add 1 to avoid chane Procedure Name and -1 to avoid replace Next Procedure
' ThisLine = .Lines(N, 1)
' If InStr(N, ThisLine, Fnd, vbTextCompare) > 0 Then
'ThisSub = ThisSub & vbNewLine & ThisLine
'End If
'Next
' End If
Else '____________________________________________________________________________________________________
' Replce Declaration such as Enum
For D = 1 To .CountOfDeclarationLines
ThisLine = .Lines(D, 1)
If InStr(1, ThisLine, "Enum " & PrcName) > 0 Then
Titl = DecItm(D)
Dec = Dec & vbNewLine & ThisLine: DecStrLn = D
S = InStr(1, ThisLine, "Enum " & PrcName) + Len("Enum " & PrcName) 'Start replace column
ElseIf InStr(1, Dec, "Enum " & PrcName) > 0 And InStr(1, ThisLine, "End Enum") > 0 Then
Dec = Dec & vbNewLine & ThisLine: DecEndLn = D
Exit For
ElseIf InStr(1, Dec, "Enum " & PrcName) Then
Dec = Dec & vbNewLine & ThisLine
End If
Next 'Declaration
' MsgBox .Lines(DecStrLn, DecEndLn - DecStrLn + 1) '=MsgBox Dec 'Declaration
End If '_______________________________________________________________________________________________________
On Error GoTo 0
End If
End With ' .CodeModule
End If ' .Type
End With ' VBComp
Next ' In VBProj.VBComponents
'Declaration
DecItm = Split(Dec, vbNewLine)
For D = LBound(DecItm) To UBound(DecItm)
Itm = DecItm(D)
If Itm <> "" And InStr(1, Itm, "Enum " & PrcName, vbTextCompare) = 0 And InStr(1, Itm, "End Enum") = 0 Then
If InStr(1, Itm, " = ", vbTextCompare) > 0 Then
N = Split(Itm, " = ")(1)
Else
Itm = Itm & " = " & N
End If
If EnumItm = N Then
GeEnumValues = Trim(Split(Itm, " = ")(0))
Exit Function
End If
N = N + 1
End If
Next
End Function
' if needed o delte below code
Sub AddRef(wbk As Workbook, sGuid As String, sRefName As String, sRefMajor As Long, sRefMinor As Long)
Dim i As Integer
On Error GoTo EH
With wbk.VBProject.References
For i = 1 To .Count
If .Item(i).Name = sRefName Then
Exit For
End If
Next i
If i > .Count Then
.AddFromGuid sGuid, sRefMajor, sRefMinor ' 0,0 should pick the latest version installed on the computer
End If
End With
EX: Exit Sub
EH: MsgBox "Error in 'AddRef'" & vbCrLf & vbCrLf & Err.Description
Resume EX
Resume ' debug code
ThisWorkbook.Save
End Sub

Answer 9

Instead of Enum, define a Type(struct)
Public Type colType
ID As String
SSN As String
lName As String
fName As String
End Type
And then create a object of type colType and set desired values to it.
Public myColType As colType
myColType.ID = "A"
myColType.SSN = "B"
myColType.lname = "H"
myColType.fName = "G"