I'm testing the VLOOKUP function with different sheets. I have created a sheet1 as my data reference table and sheet2 as where data is supposed to be filled with reference to the Name. I just don't know what is wrong with the formula. It keeps giving the #ref!.
Below is the formula that I'm using.
=VLOOKUP(A2,Sheet1!$A$2:$A$6,2,FALSE)
SHEET1
SHEET2
The 2nd argument should include the ID column from Sheet1. Like below:
=VLOOKUP(A2,Sheet1!$A$2:$B$6,2,FALSE)
The way Vlookup works is - it looks for the value of A2 in the first column in $A$2:$B$6 and returns the 2nd column with Exact Match (FALSE)
So if you change the 3rd argument(2) to 3, then the range should have a minimum of 3 columns like $A$2:$C$6
You can try change argument 4th to 0 and change $A$2:$A$6 to $A$2:$B$6
=VLOOKUP(A2,Sheet1!$A$2:$B$6,2,0)
#REf occurs when your reference is not valid .See ,You referenced $A$2:$A$6,It is not valid ,As your array in sheet1 is extended to B6 .
Use this:=VLOOKUP(A2,Sheet1!$A$2:$B$6,2,FALSE)
I am having trouble with an Excel-function.
On sheet A I want to get the value of a cell that is located x-columns to the right of cell F2.
X is a variable number and is determined by the value of cell A1. Currently, the value is 5.
=(OFFSET(sheetA!F2,0,sheetA!A1))
This formula works. However, I want to include this function into a MATCH and INDEX function that is located on another sheet (B).
I know that I can use the following formula to get value of $F$2
INDEX(sheetA!F:F,MATCH(sheetB!C4,sheetA!A:A,0))
Combining them, results in the following formula:
=INDEX((OFFSET(sheetA!F2,0,sheetA!A1)),MATCH(sheetB!C4,sheetA!A:A,0))
This formula generates a #REF!-value.
If I evaluate the formula, I see the following steps:
=INDEX((OFFSET(sheetA!$F$2,0,5)),MATCH(sheetB!C4,sheetA!A:A,0))
=INDEX((sheetA!$K$2),MATCH(sheetB!C4,sheetA!A:A,0))
=INDEX((sheetA!$K$2),MATCH("BTC",sheetA!A:A,0))
=#REF!
Why do I want to use MATCH and INDEX?
Because while the values on sheet A are "fixed", the values of sheetB!C4 are floating/variable. Therefore, I need to locate the correct row first. The correct column can be done with the offset-part.
Thank you for your help.
Try this
=INDEX((OFFSET(SheetA!F:F,0,SheetA!A1)),MATCH(SheetB!C4,SheetA!A:A,0))
Syntax of INDEX is
INDEX(array, row_num, [column_num])
where, array is range of cells. When you use =INDEX((OFFSET(sheetA!F2,0,sheetA!A1)),MATCH(sheetB!C4,sheetA!A:A,0)), (OFFSET(sheetA!F2,0,sheetA!A1)) returns sheetA!$K$2 which is a cell not a range.
I am going crazy over this. It seems so simple yet I can't figure this out. I have two worksheets. First worksheet is my data. Second is like an answer key. Upon checking checking, A1:B1 in Sheet 1 is a match with the conditions in Row 52 in SHEET 2, therefore, the value in Column C is "MGC". What is the formula that will perform this function? It's really hard to explain without the data so I pasted a link of the sample spreadsheet. Thank you so much in advance.
sample spreadsheet here. https://docs.google.com/spreadsheets/d/1_AjuNfCdGfEM-XkqPa6W4hSIxQg4NM2Vg4c2C1pQ_vQ/edit?usp=sharing
screenshot here. (wont let me post i have no reputation)
In Sheet2, insert a column in front of Column A and put the formula in A2 =C2&D2.
Then in Sheet1, Cell C2 the formula =vlookup(A2&B2,Sheet2!A:B,2,0).
the first make a concatenated key to lookup, then the second looks up that key.
How about a index(match())? If I've understood correctly you need to match across both the A and B column in sheet one, checking for the relevant values in B and C on sheet 2 to retrun worksheet 2 column a to worksheet 1 column c.
third version try:
=INDEX(Sheet2!$C$1:$C$360,MATCH(Sheet1!A1&Sheet1!B1,Sheet2!$B$1:$B$360&Sheet2!$C$1:$C$360,0))
Basically what this does is use concatenation, the & operator, to specify you are looking for "Criteria A" & "Criteria B" in sheet 1, which makes the string "Criteria A Criteria B", which is supplied in the first part of the match function.
In the second it then says match this against all of my variables in sheet 2 in the same way with concantenation.
The final part of match function (0) specifies you want an 'exact' match
It then supplied this as a reference to the index function, which then finds the row intersecting with the value you want, and returns that.
As noted here https://support.microsoft.com/en-us/kb/59482 this is an array formula, so it behaves differently, and must be input differently. https://support.office.com/en-za/article/Guidelines-and-examples-of-array-formulas-7d94a64e-3ff3-4686-9372-ecfd5caa57c7
There are (at least) 2 ways you could do this without VBA.
USING A SORTED LIST
The first relies on the assumption that your data can be re-sorted, so that everything "Unreported" is in the top, and everything "reported" is together below that (or vice versa). Assuming that this is the case (and it appears to already be sorted like this),we will use the function OFFSET to create a new range which shows only the values that align with either being "Unreported" or "Reported".
Offset takes a given reference to a point on a sheet, and then moves down/up & left/right to see what reference you want to return. Then, it returns a range of cells of a given height, and a given width. Here, we will want to start on Sheet2 at the top left, moving down until we find the term "Unreported" or "Reported". Once that term is found, we will want to move one column to the right (to pull column B from sheet 2), and then have a 'height' of as many rows as there are "unreported" or "reported" cells. This will look as follows in A1 on sheet 1, copied down:
=OFFSET(Sheet2!$A$1,MATCH(A1,Sheet2!A:A,0)-1,1,COUNTIF(Sheet2!A:A,A1),1)
This says: First, start at cell A1 on sheet2. Then find the term in A1 (either "unreported" or "reported", on sheet2!A:A (we subtract 1 because OFFSET starts at A1 - so if your data starts at A1 we need to actually stay at "0". If you have headers on sheet2, you will not need this -1). Then, move 1 column to the right. Go down the rows for as many times as Sheet2 column A has the term found in Sheet1 A1. Stay 1 column wide. Together, this will leave you with a single range on sheet2, showing column B for the entire length that column A matches your term in sheet1 A1.
Now we need to take that OFFSET, and use it to find out when the term in Sheet1 B1 is matched in Sheet2 column B. This will work as follows:
=MATCH(B1,[FORMULA ABOVE],0)
This shows the number of rows down, starting at the special OFFSET array created above, that the term from B1 is matched in column B from sheet2. To use this information to pull the result from column C on sheet 2, we can use the INDEX function, like so:
=INDEX([FORMULA ABOVE],MATCH(B1,[FORMULA ABOVE],0))
Because this would be fairly convoluted to have in a single cell, we can simplify this by using VLOOKUP, which will only require the OFFSET function to be entered a single time. This will work as follows:
=VLOOKUP(B1,[FORMULA ABOVE],2,0)
This takes the OFFSET formula above, finds the matching term in B1, and moves to the 2nd column to get the value from column C in sheet2. Because we are going to use VLOOKUP, the offset formula above will need to be adjusted to provide 2 columns of data instead of 1. Together, this will look as follows:
FINAL FORMULA FOR SHEET1, C1 & COPIED DOWN
=VLOOKUP(B1,OFFSET(Sheet2!$A$1,MATCH(A1,Sheet2!A:A,0)-1,1,COUNTIF(Sheet2!A:A,A1),2),2,0)
OPTION USING ARRAY FORMULAS
The above method will only work if your data is sorted so that the REPORTED and UNREPORTED rows are grouped together. If they cannot be sorted, you can use an ARRAY FORMULA, which essentially takes a formula which would normal apply to a single cell, and runs it over an entire range of cells. It returns an array of results, which must be reduced down to a single value. A basic array formula looks like this [assume for this example that A1 = 1, A2 = 2...A5 = 5]:
=IF(A1:A5>3,A1:A5,"")
Confirm this (and all array functions) by pressing CTRL + SHIFT + ENTER, instead of just ENTER. This looks at each cell from A1:A5, and if the value is bigger than 3, it gives the number from that cell - otherwise, it returns "". In this case, the result would be the array {"";"";"";4;5}. To get the single total of 9, wrap that in a SUM function:
=SUM(IF(A1:A5>3,A1:A5,""))
In your case, we will want to use an array formula to see what row in Sheet2 matches A1 from Sheet1, and B1 from Sheet1. This will look like this:
=IF(Sheet2!$A$1:A$100=A1,IF(Sheet2!$B$1:$B$100,ROW($B$1:$B$100),""),"")
This checks which rows in column A from sheet 2 match A1. For those that do, it then checks which rows in column B from sheet 2 match B1. For those, it pulls the row number from that match. Everything else returns "". Assuming no duplicates, there should only 1 row number which gets returned. To pull that number from the array of results, wrap the whole thing in a MATCH function. Now that you have the row number, you can use an INDEX function to pull the result in Column C with that row, like this:
FINAL ARRAY FORMULA METHOD
=INDEX($C$1:$C$100,MAX(IF(Sheet2!$A$1:A$100=A1,IF(Sheet2!$B$1:$B$100,ROW(Sheet2!$B$1:$B$100),""),"")))
Remember to confirm with CTRL + SHIFT + ENTER instead of just ENTER, when you type this formula. Note that I didn't refer to all of Sheet2!A:A, because array formulas run very slowly over large ranges.
The following formula should work without making any changes to the datasheets.
=INDEX(Sheet2!$A$1:$A$360,MATCH(Sheet1!A1,IF(Sheet2!$C$1:$C$360=Sheet1!B1,Sheet2!$B$1:$B$360),0))
Remember to save this formula as an array with CTRL+SHIFT+ENTER
Documentation on how to use INDEX and MATCH against multiple criteria can be found on Microsoft Support.
It's not clear what you want to do with the multiples that do not have corresponding matches. txed is listed as Unreported twice in Sheet1; kntyctap is listed as Unreported three times. There are only one corresponding match on Sheet2 for each of these.
Non-array Standard Formulas for multiple criteria matches
For Excel 2010 and above use this standard formula in Sheet1!C1:
=IFERROR(INDEX(Sheet2!$A$1:$A$999,AGGREGATE(15,6,ROW(1:999)/((Sheet2!$B$1:$B$999=A2)*(Sheet2!$C$1:$C$999=B1)), COUNTIFS(A$1:A1, A1, B$1:B1, B1))), "")
For version of Excel prior to 2010 use this standard formula in Sheet1!C1:
=IFERROR(INDEX(Sheet2!$A$1:$A$999, SMALL(INDEX(ROW($1:$999)+((Sheet2!$B$1:$B$999<>A1)+(Sheet2!$C$1:$C$999<>B1))*1E+99, , ), COUNTIFS(A$1:A1, A1, B$1:B1, B1))), "")
I've handled error with the IFERROR function in that latter formula. Excel 2003 and previous may have to use an IF(ISERROR(..., ...)) combination.
I have this formula in excel, to return a row number:
=MATCH(INDIRECT(ADDRESS(ROW(),4)),DayOffRequests!$A$1:$A$100,0)
and it works just fine.
I would like to make a new name (DAYS_OFF_ROW) and assign it to this formula.
Here's what I did in the name manager:
But when I write this into a cell: =DAYS_OFF_ROW it says #VALUE! whereas when I write the same formula into the cell, it gives me the row number I am looking for.
Why is does it say #VALUE! and not the row number like the formula does?
First off Row() returns the row on which the cell resides. If you put Row() in indirect you will get an error since there is no cell for which Excel can find a Row(). So right off the bat, your formula is nonsense for a named range.
Second, even if there was some magic way for Excel to know which Row() you cared about here, Match doesn't return a range. Just a position in an array like "5" or "50". When you use a formula to define a named range, the result of the formula MUST be a range. So you could do another Indirect like =Indirect("A" & Match(foo,bar)) or something so that the result out of your formula actually refers to a range in your sheet.
It works if i set the name to this formula: =MATCH(!$D1,DayOffRequests!$A$1:$A$100,0)
Of course i have to be in field A1 when setting the name. Now its reference the fourth column and whichever row i am in.
I have two excel sheets. The first contains a formula for calculation with one input cell (A1), and one output cell (B1). The formula for B1 could be B1 = A1 * 3 (example).
The second sheet contains various values in column A: A1 = 4; A2 = 9; A3 = 5 ... In corresponding column B of this sheet I'd like to get the result of B1 (first sheet) = A1 (second sheet) * 3 for each A (second sheet) input value.
Basically I'd like to treat the first sheet as a function, where A1 is the argument and B1 the result that is passed back to the second sheet's B column.
Sheet 2
A1 4 B1 12 (result from sheet 1)
A2 9 B2 27 (result from sheet 1)
...
Is it possible without macros?
This is built into Excel. In version 2003, use the Data, Table menu.
You can find many examples on the net. Here is one.
You can create such tables with either 1 or 2 entries (parameters).
I don't think so .....
If in B1 Sheet1 you have
3*A1
If you try this in Sheet2 B1
`=SUBSTITUTE(Sheet1!$B$1,"A1",A1)`
it will give
3*4, and Sheet2 B2 will be
3*9etc
But I don't see how you could coerce this to a numberic calculation with formulae without possibly some heavy duty formula string parsing to separate numbers from operators (which is unlikley to flex as desired if you change the entry in B1 Sheet 1)
[Update 2: but fwiw I have done it with a named range]
I used this range name
RngTest
=EVALUATE(3*INDIRECT("rc[-1]",FALSE))
This is a global range name so it will work on any sheet, more powerful than my prior OFFSET effort. It multiplies the cell to the immediate left by 3
so entering =RngTest in B1:B3 (and then in this new example C1:C3 as well)
gives the output you want
I think you want to use this in your sheet two column.
Sheet1!B1 * Sheet2!A1
Entirely without VBA: expect lots of pain, I won't go there. But...
To substantially reduce the amount of pain, you could actually use this one tiny VBA user-defined function (not technically a "macro"), basically just a wrapper to make VBA's Evaluate function available in worksheet formulas:
Function eval(myFormula As String)
eval = Application.Evaluate(myFormula)
End Function
You could then use it like this in cell B1 on sheet 2:
=eval(SUBSTITUTE(Sheet1!$B$1,"A1","A"&ROW()))
Note that this requires Sheet 1 cell B1 to contain A1*3 and not =A1*3, i.e. no equal sign. Maybe with a bit more fiddling around, it can be made to work even with the = sign there...
EDIT: Actually, if you format Sheet 1 cell B1 as Text before typing in the formula, this will work even if your formula starts with a =.
Is it possible without macros?
Yes!
You can now use =LAMBDA for this.
Define your function using the name manager, then reference it in your second sheet's formula.
See syntax at Introducing the LAMBDA function.
For more information about how to use the LAMBDA function, see the support documentation.