lame - Overwrite existing files [closed] - linux

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 9 years ago.
Improve this question
I'm trying to convert a bunch of CBR 320 Kbps Mp3 to VBR 0 (max quality), using lame command in bash. However, it seems like lame can't overwrite existing files. It would be much faster that way, as I could use wildcards to do it on an unique, short terminal command, plus I wouldn't have to delete the old files and rename the new.
What I'm trying is:
lame -h -V 0 *.mp3
But I get the following error message:
lame: excess arg %filename%.mp3
Also, if I try on a single file
lame -h -V 0 %filename%.mp3 %filename%.mp3
I get:
Input file and Output file are the same. Abort.
In the command help there's no option mentioned for forced, overwrite or whatever. I searched in the internet and on Stack Overflow and found nothing too. Can anybody help me?

lame just doesn't support this. Few commands do.
Instead, the Unix philosophy is to not require every program to support every possible mode of invocation, and instead lets the user combine commands to do what they want:
for f in *.mp3; do lame -h -V 0 "$f" tmp && mv tmp "$f"; done
If this is something you do often (though I hope not, since transcoding is bad for quality), you can create your own shortcut for it in .bashrc:
superlame() { for f; do lame -h -V 0 "$f" tmp && mv tmp "$f"; done; }
From then on, you can simply superlame *.mp3

Related

How to get a list of files of a huge size directory without using ls command (90GB) [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 4 years ago.
Improve this question
In linux server, is there a way to get the list of files in a directory
without using commands such as ls-la?
Our log directory size is too huge (almost 90GB) that
when we use ls -la command to get the list of files in that directory,
the command prompt does not come back...
echo *
... will show files in the current folder through file globbing on Bourne compatible shells.
This lists all files down one level:
echo /
In Bash, if globstar is set (set with shopt -s globstar, unset with shopt -u globstar), this will list all files recursively:
echo **
For More info, you may visit This Link
and your following problem why not you use a limit to list file?
this command may help you
ls -U | head -4
Don't know if there are other commands, but you could combine ls with other command like:
ls -la | less
which still lists your files but you can move up and down (and search) easily. less does not load all the content (your 90GB) at once but it loads lines when you move around.
Or you can save output of ls to a file to open it later
ls -la > my_files.txt

How to Rename Files in Linux [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 5 years ago.
Improve this question
I want to rename all files in selected directory using rename command or move command from :
_02_mp3_cbr_320.m4a?anghakamitoken=sc245ae5a454547.5
_02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a?anghakamitoken=sc245.ae5a
to
1.m4a
2.m4a
If those files always have a sheme like this:
_02_mp3_ * _320.m4a?anghakamitoken= *
You can do it like that:
#!/bin/bash
COUNT=0
for f in ./"_02_mp3_"*"_320.m4a?anghakamitoken="*; do
mv $f "$((++COUNT)).m4a"
done
This will result in
1.m4a
2.m4a
Assuming the initial files are in the same directory as the bash script.
Try this with GNU Parallel. it basically uses GNU Parallel's job number ({#}) as the number for renaming:
parallel --dry-run -k mv {} {#}.m4a ::: *m4a*
Sample Output
mv _02_mp3_cbr_320.m4a\?anghakamitoken\=sc245ae5a454547.5 1.m4a
mv _02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a\?anghakamitoken\=sc245.ae5a 2.m4a
If the commands look correct, remove the --dry-run part and run it again. The -k keeps the output in order. The {} refers to the current file.
Make a backup before using any commands you are unfamiliar with...
To rename any file in Linux using mv (move) command:
mv (cfr. "man mv")
In this case, you need to enter the following lines on the command line:
$mv _02_mp3_cbr_320.m4a?anghakamitoken=sc245ae5a454547.5 1.m4a
$mv _02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a?anghakamitoken=sc245.ae5a 1.m4a
It is important that you refer to the manual when you know the command you must use, to understand how to use it.

How to undo "mv file -" command in Ubuntu [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 1 year ago.
Improve this question
As far as you know, - has different usages for in combination with different commands in Linux. For example in combination with cd command, it means "Change directory to the previous location" and in combination mv or cat command it means stdin or stdout.
Unfortunately I wrongly used this character with mv command. I wanted to move my file to the previous location which I have been before the change directory but I moved it to stdin instead.
Is there any way to recover my file?
I run this command:
# mv myfile -
I moved it to stdin instead.
No, you moved to a file literally named by a dash (you'll use /dev/stdin or /proc/self/fd/0 to refer to the stdin, i.e. the file descriptor 0).
You want to
mv -i ./- myfile
this is usual practice (to prefix by ./ a strange path). The -i interactively asks for confirmation.
Sometimes it is not even easy to type a path for a weird file (e.g. for a file name containing a single newline character). You could use globbing (read about shell expansion), e.g. mv -i ./? file.
See mv(1) and path_resolution(7) and glob(7) and proc(5)
The good habit is to avoid strange characters in file paths.

rename multiple filename in linux [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 8 years ago.
Improve this question
I have many files named xxxx.min.js and want to rename the files to xxxx.js so basically want to remove .min only.
Is there a command I can use to do this job?
I thought using rename command would be easy for each single file, but that would take forever since I have many of them.
any idea?
Here's a bash-only command (not requiring Perl)
for i in *.min.js; do a=$(basename $i .min.js); echo mv $i $a.js; done
Explanation
for i in *.min.js; do
loop over all files matching *.min.js
a=$(basename $i .min.js)
extract the base name of the file (i.e. strip off .min.js) and save the result in $a
echo mv $i $a.js
for now, print to the console the command that WOULD be run if you removed the echo
When you are satisfied that it generates the correct commands, remove the echo to actually rename the files.
Ubuntu and Debian linux distribution both have a perl version of mv function called rename or prename, which supports regexp. The manual can be found here.
Go to the folder of the files and run the command as follows:
rename s/\.min\.js$/\.js/ *.min.js

Typed wrong mv command [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 8 years ago.
Improve this question
Hi i worked on Linux server , and was running this command mv matter/*/* .
but instead i have typed this mv matter /*/* .
because of which some errors starts coming on the screen , and then i was not able to login and when we reboot the server its not coming up.
so can you please tell me what this command has done mv matter /*/* .
You can find out for yourself by inserting an echo at the beginning of the command line:
echo mv matter /*/* .
The expanded command looks like this:
mv matter /bin/ash /bin/bash /bin/echo /bin/false [...] /home/yourname [...] .
All files and directories from the top-level directories (echo /*/) have been moved to this one directory where you executed that command. It's hard to separate them from there, but you can try using a rescue CD:
move all executable files to /bin
make /sbin a symlink to /bin
move all files that look like configuration files to /etc
But since you couldn't find out for yourself what the mv command was doing exactly, you should rather ask someone who knows to fix it for you. It's a lot of work, though.

Resources