I need to count the number of unique items (here I have the names of organizations) in the excel-sheet...I used the following script but I cannot introduce multiple inputs to count all of them at once.
=SUMPRODUCT((A27:A128<>"")/COUNTIF(A27:A128,A27:A128&""))
I want to introduce, for instance, A27:A128, A145:A156 lists of cells to be checked and counted.
Does anyone know how I can count them? Is there another function to be called?
Very simple........use a "helper" column, say column D In D1 enter:
=A27 and copy down thru D102.
In D103 enter:
=A145 and copy down thru D114
Finally use:
=SUMPRODUCT((D1:D114<>"")/COUNTIF(D1:D114,D1:D114&""))
The formula you need looks like the following
=SUM( IF( MATCH(A27:A128,A:A,0)=ROW(A27:A128) , 1 , 0 ) ,
IF( MATCH(A145:A156,A:A,0)=ROW(A145:A156) , 1 , 0 ))
and works like this:
For every area you want to check you need the following construct:
IF( MATCH(A27:A128,A:A,0)=ROW(A27:A128) , 1 , 0 )
This tries to match every cell from A27 to A128 to the whole column A and checks, if the row where the value was found is equal to the current row. If this is the case, we found the first occurence, if it is a repeated occurence, the row will be smaller (because MATCH always returns the first row where the value was found). Now if we found a first occurence, IF returns 1, otherwise 0.
SUM just sums up every if (that means, if you have a third area and so on, just keep adding more IF-constructs and you're done), resulting in summing up a 1 for every first occurence of a value and a 0 for every follow-up - and you get your amount of unique values.
Attention: The whole formula is a matrix formula. After you put it in the cell, you must not end the editing with pressing ENTER but with STRG+SHIFT+ENTER simultaneously. This way excel surrounds the formula with {}-brackets that you cannot enter manually. It changes the way excel evaluates the formula and you might get an error if you try it as normal formula.
Also, as the values get checked against the whole column A the formula might or might not fail, if a certain value appears inside and outside of a checked area, depending on the ordering of the values.
Related
So I have data consisting of the following:
there are multiple more rows.
Im trying to retrieve the last 5 values in a row, for further use.
I can do this with a simple INDEX(MATCH()) setup, however that doesn't ignore the blank cells, which I would like it to do. It does successfully detect the first nonblank cell and returns that, however when it's blank in the middle of the 5 most recent, it doesn't remove that.
something like this is what it does now:
however i want it to come back in this format:
and so on. A blank could occur at any position, and there may not always be 5 scores available to retrieve.
TIA
You could use the following array-formula (entered with ctrl+shift+enter in older Excel versions):
=INDEX(1:1,AGGREGATE(14,6,COLUMN(A:G)/(A1:G1<>""),{5,4,3,2,1})) copied down.
Aggregate creates an array of the column numbers divided by 1 or 0 (TRUE or FALSE). Divided by 0 results in an error and gets ignored. It then takes the 5th largest to the largest column number without error and returns that as an array on the indexed row.
Where 1:1 represents the first row and A:G represents the first to last column used.
If you would want it on row 2 and column A:Z you'd have to amend it like this:
=INDEX(2:2,AGGREGATE(14,6,COLUMN(A:Z)/(A2:Z2<>""),{5,4,3,2,1}))
Different approach - using the new Excel 365 formulas:
This will return the values of the last five non-empty cells of row 2
=LET(
data,FILTER(B2:H2,B2:H2<>""),
cntData,COUNT(data),
matrix,SEQUENCE(1,MIN(cntData,5),IF(cntData>5,cntData-4,1)),
INDEX(data,1,matrix)
)
data returns all values except empty cells using the FILTER- formula
cntData holds the number of cells
using SEQUENCE a matrix is build that will return the column-indices to be returned. In case less then 5 values are available, the matrix returns 1 to cntData.
finally this "index-matrix" is used to return the values from the filtered data
This could be enhanced, by storing the number of cells to be returned within a named cell - and referencing this name in the formula. By that you could easily alter the number without altering the formula.
A
B
C
D
4
1
6
5649
3
8
10
9853
5
2
7
1354
I have two worksheets, for example column A in sheet 1 and columns B-D in sheet 2.
What I want to do is to take one value in Column A, and scan both columns B and C and it is between those two values, then display the corresponding value from column D in a new worksheet.
There could be multiple matches for each of the cell in column A and if there is no match, to skip it and not have anything displayed. Is there a way to code this and somehow create a loop to do all of column A? I tried using this formula, but I think it only matches for each row and not how I want it to.
=IF(AND([PQ.xlsx]Sheet1!$A2>=[PQ.xlsx]Sheet2!$B2,[PQ.xlsx]Sheet1!$A2<[PQ.xlsx]Sheet2!$C2),[PQ.xlsx]Sheet2!$D$2,"")
How do I do this?
Thank you.
I'm not positive if I understood exactly what you intended. In this sheet, I have taken each value in A:A and checked to see if it was between any pair of values in B:C, and then returned each value from D:D where that is true. I did keep this all on a single tab for ease of demonstration, but you can easily change the references to match your own layout. I tested in Excel and then transferred to this Google Sheet, but the functions should work the same.
https://docs.google.com/spreadsheets/d/1-RR1UZC8-AVnRoj1h8JLbnXewmzyDQKuKU49Ef-1F1Y/edit#gid=0
=IFERROR(TRANSPOSE(FILTER($D$2:$D$15, ($A2>=$B$2:$B$15)*($A2<=$C$2:$C$15))), "")
So what I have done is FILTEREDed column D on the two conditions that Ax is >= B:B and <= C:C, then TRANSPOSED the result so that it lays out horizontally instead of vertically, and finally wrapped it in an error trap to avoid #CALC where there are no results returned.
I added some random data to test with. Let me know if this is what you were looking at, or if I misunderstood your intent.
SUPPORT FOR EXCEL VERSIONS WITHOUT DYNAMIC ARRAY FUNCTIONS
You can duplicate this effect with array functions in pre-dynamic array versions of Excel. This is an array function, so it has be finished with SHFT+ENTER. Put it in F2, SHFT+ENTER, and then drag it to fill F2:O15:
=IFERROR(INDEX($D$2:$D$15, SMALL(IF(($A2>=$B$2:$B$15)*($A2<=$C$2:$C$15), ROW($A$2:$A$15)-MIN(ROW($A$2:$A$15))+1), COLUMNS($F$2:F2))),"")
reformatted for easier explanation:
=IFERROR(
INDEX(
$D$2:$D$15,
SMALL(
IF(
($A2>=$B$2:$B$15)*($A2<=$C$2:$C$15),
ROW($A$2:$A$15) - MIN(ROW($A$2:$A$15))+1
),
COLUMNS($F$2:F2)
)
),
"")
From the inside out: ROW($A$2:$A$15) creates an array from 2 to 15, and MIN(ROW($A$2:$A$15))+1 scales it so that no matter which row the range starts in it will return the numbers starting from 1, so ROW($A$2:$A$15) - MIN(ROW($A$2:$A$15))+1 returns an array from 1 to 14.
We use this as the second argument in the IF clause, what to return if TRUE. For the first argument, the logical conditions, we take the same two conditions from the original formula: ($A2>=$B$2:$B$15)*($A2<=$C$2:$C$15). As before, this returns an array of true/false values. So the output of the entire IF clause is an array that consists of the row numbers where the conditions are true or FALSE where the conditions aren't met.
Take that array and pass it to SMALL. SMALL takes an array and returns the kth smallest value from the array. You'll use COLUMNS($F$2:F2) to determine k. COLUMNS returns the number of columns in the range, and since the first cell in the range reference is fixed and the second cell is dynamic, the range will expand when you drag the formula. What this will do is give you the 1st, 2nd, ... kth row numbers that contain matches, since FALSE values aren't returned by SMALL (as a matter of fact they generate an error, which is why the whole formula is wrapped in IFERROR).
Finally, we pass the range with the numbers we want to return (D2:D15 in this case) to INDEX along with the row number we got from SMALL, and INDEX will return the value from that row.
So FILTER is a lot simpler to look at, but you can get it done in an older version. This will also work in Google Sheets, and I added a second tab there with this formula, but array formulas work a little different there. Instead of using SHFT+ENTER to indicate an array formula, Sheets just wraps the formula in ARRAY_FORMULA(). Other than that, the two formulas are the same.
Since FALSE values aren't considered, it will skip those.
I have the following formula to return the value of the last value in a column:
=LOOKUP(2,1/(D:D<>""),D:D)
What I need now is to return the value of the cell adjacent to it as well. (It will not necessarily be the last value in that column and the info in Column D could have duplicates.
If your data looks like this:
A 1
A 2
A 3
B 4
B 5
B 6
C 7
To get last value this will do the trick:
=INDIRECT("B"&COUNTA(A:A))
And to get last where value is A:
=INDIRECT("B"&MATCH("A",A1:A7,0)+COUNTIF(A1:A7,"A")-1)
Just use next column:
=LOOKUP(2,1/(D:D<>""),E:E)
Ok, So I have found an answer by playing around with array formulas.
The problem was that this is a stock control sheet where there are changes made at multiple times, each recorded in the next available row. There is always a date (Column E) but not necessarily a Supplier, as it might be stock moving out. When a Supplier delivers, the Supplier name is recorded in Column D. In D1 the last supplier is then shown with the following formula.
=LOOKUP(2,1/(D:D<>""),D:D)
I want to then see what date it was last received. The formula I found that works is as follows (Array Formula):
=INDEX(E:E,MAX(IF(D:D=D1,ROW(D:D)-ROW(INDEX(D:D,1,1))+1)))
This is generally how I do it:
=XMATCH(FALSE,ISBLANK(A:A),0,-1)
This is what each part does:
Parameter
Explanation
FALSE
Instructs Excel to find the first instance of FALSE that it finds
ISBLANK(A:A)
Takes in the column A:A and notionally assigns a value to every item in the column
0
Means we want an exact match. Probably not necessary to put in, but I think it's good practice anyway
-1
Instructs Excel to start the search at the bottom/right of the range and work up/left. If you change this to 1 (the default), Excel will begin the search at the top/left and work down/right
So, taken together, this will search from the bottom of the column A:A, until Excel finds the first cell that is not blank, and return that cell.
Also, yes, this equation can be changed to a row format (e.g. 1:1), and can take a smaller range (e.g. A1:A20), but it cannot take a 2-dimensional range (e.g. A1:B20).
As a practical matter, this approach is much faster than other approaches (and much faster than you'd think, given it's evaluating against every row/column in the range), and won't get fooled by columns that have empty spaces in them (like with a COUNTA style approach).
I have a simple worksheet with 2 columns
I want to get all the results(on column "H") (I can get only the first occurrence,I want to know if I can get the others) that contains the value from cell G1, is that possible without a macro ? any way of doing it would be appreciated...Any ideas?
You can use ROW() and SMALL() to get those instead of MATCH() since this always gets the first match.
=IFERROR(INDEX($C$4:$C$7,SMALL(IF($D$4:$D$7=$G$1,ROW($D$4:$D$7)-(ROW()-1)),ROWS($D$4:D4))),"Null")
So, if the array $D$4:$D$7=$G$1 returns true (i.e. the value equals that in G1), you will get the row numbers of these values, in this case, you will get 4 and 6. All the other will return False.
After some processing with -(ROW()-1), the 4 and 6 become 1 and 3. those two values are what will be fed to the INDEX.
SMALL() then picks the smallest, starting with the 1st (you get 1 from ROWS($D$4:D4)) and when you drag the formula down, the ROWS become ROWS($D$4:D5) which gives 2, and SMALL ends up taking the 2nd smallest value, which is 3.
EDIT: Forgot to mention. You have to array enter the above formula. To do this, type the combination keys of Ctrl+Shift+Enter after typing the formula (edit the formula again if necessary) instead of Enter alone.
I have the following three columns as data:
I am using the formula =IF(COUNTIFS($A:$A;A2;$B:$B;B2;$C:$C;C2)=1;1;0) as my output in the Output column. Basically I am giving a non-unique row a 0 and a unique row a 1.
However as you can see I want to give the first occurency of a unique combination of ART, Date and ISIN an 1 and the rest a 0. Why is my currently used formula wrong?
I appreciate your answer!
That's because your formula currently will put 1 for all unique rows and 0 for all duplicate rows, irrespective of whether they appear for the first time or not.
You can get the behaviour you're looking for by playing around a bit with the range lockings. For instance, you could try this:
=IF(COUNTIFS($A$2:$A2;A2;$B$2:$B2;B2;$C$2:$C2;C2)=1;1;0)
On the first row, the above formula will count only within the first row, so the result is bound to be 1.
When it reaches the second row, it will check the first 2 rows and will find that it's the same as the first one, so will return 2 as count and give you 0.
Notice how I locked the ranges: The first reference is completely locked $A$2:$A2 while the second one has the row variable $A$2:$A2.