I am inside a middleware (function(req, res, next) {...}).
Is there a way to access the HTTP server object from the req?
UPDATE
Let me be more specific. I am trying to find out a port that the server listens on, or unix socket path, if it's listening on that.
How about in your main app file:
var express = require('express');
var http = require('http');
var app = express();
app.use(app.router);
app.get('/', function (req, res, next) {
console.log(req.socket.server);
});
app.server = http.createServer(app);
app.server.listen(3000);
As Brad mentioned, Express does expose something resembling the object returned from #createServer(), however, TJ has been giving serious consideration to dropping any inclusion of the HTTP module in express in future releases. Using the code above will be future safe.
If what you are trying to do is expose the server object inside your routers, then yeah, middleware is the way to go:
var express = require('express');
var http = require('http');
var app = express();
var server = http.createServer(app);
app.use(function(req, res, next){ //This must be set before app.router
req.server = server;
next();
});
app.use(app.router);
server.listen(3000);
The middleware is used to expose the server object. Then, you can just access it in any of your routers like so:
app.get('/', function (req, res, next) {
console.log(req.server.get('port')); // displays 3000
});
Function app.listen returns your http server.
Source express/lib/application.js
app.listen = function listen() {
var server = http.createServer(this);
return server.listen.apply(server, arguments);
};
for some reason, for me request.app.server did not work, probably because I was using express 4, after bit of digging up, I found that req.socket.server works.
Related
I am looking to capture all of the data from any request (images, fonts, css, js, etc) on my website so that I can capture the file details, specifically the file name and file size. I have found almost an identical question/solution:
Node.js : How to do something on all HTTP requests in Express?
But the solution appears to be deprecated with Express v4. Is there a simple solution to do this? As another approach I have tried the below solution with no luck:
var express = require("express");
var path = require("path");
var port = process.env.PORT || 3000;
var app = express();
var publicPath = path.resolve(__dirname, "public");
app.use(express.static(publicPath));
app.get("/", function(req, res){
// I want to listen to all requests coming from index.html
res.send("index.html");
});
app.all("*", function(){
// can't get requests
})
app.listen(port, function(){
console.log(`server listening on port ${port}`);
});
Also I am not looking to do this from Fiddler/Charles because I am looking to display this data on my site.
Express routes are predicated on order. Notice the answer that you linked in your question has the middleware defined, and used before all other routes.
Secondly you're trying to implement something that requires middleware, not a wildcard route. The pattern in link you provided in your question is not deprecated according to their docs.
app.use(function (req, res, next) {
// do something with the request
req.foo = 'testing'
next(); // MUST call this or the routes will not be hit
});
app.get('/', function(req, res){
if (req.foo === 'testing') {
console.log('works');
}
res.send("index.html");
});
I'm making a nodeJS module, and I want to use expressJS as a framework for it.
I'm trying to see, how I could go by, including a function inside and app.get(); and call it via another file, such as the actual app.
var express = require("express");
var app = express();
app.get("/", function (req, res) {
exports.type = function (text) {
console.log(req.ip);
console.log(text);
}
});
now when I use this, and i call it on the actual app like:
var web = require("directory_to_file");
var express = require("express");
var app = express();
var http = require("http").Server(app);
app.get("/", function (req, res) {
web.type("Hello, world");
});
http.listen(10022, function () {
console.log("server is up");
});
I get an error:
TypeError: Property 'type' of object #<Object> is not a function
anyone know a way to make it so I can call the function?
There are generally two things you want to export as a module - an API and a Middleware. The classic example of middleware is an authentication module. To do the middleware, just export the middleware. I tend to do a little more than that so I can configure the middleware later. Something along the lines of this:
module.exports = exports = function(config) {
// Do something with config here
return function(req, res, next) {
// your middleware here
};
};
You can then use your middleware in your main program like this:
var app = require('express')(),
mymodule = require('./mymodule');
var config = {}; // replace with whatever config you need
app.use(mymodule(config));
app.listen(process.env.PORT || 3000);
To implement an API, you will create a Router object, then attach your routes to the Router object. You can then "mount" your router in your main program. For example, you could have a file called 'myroutes.js' with the following contents:
var express = require('express'),
myroutes = express.Router();
myroutes.get('/foo', (req, res) => {
res.status(200).type('application/json').send({ myparam: 'foo' });
});
module.exports = exports = myroutes;
Have the following in your main program:
var app = require('express')(),
myroutes = require('./myroutes');
app.use('/api', require('./myroutes'));
app.listen(process.env.PORT || 3000);
Here, in 'myroutes.js', I'm defining a sub-route of /foo and then in the main program, I'm mounting that on /api - so I would access /api/foo to access that API.
In your directory_to_file you are only exporting on app.get('/') which will never be called.
You could add in your directory_to_file the following code
var express = require('express');
var router = express.Router();
router.get('/', function(req, server) {
console.log(req.ip);
});
module.exports = router;
And in your main file you could use app.use('/', web)
A short explanation:
You are creating a new express app / config in your directory_to_file file which won't be launched or used. So your app.get event won't be fired once.
That's why web.type is not a function. You are not exporting anything.
Use the way I provided. This is a commonly used method.
You could call the code I provided a "route". Create multiple routes / route files and include them in your main method.
Your code just looks confused. If I understand you correctly, what you are really trying to do (at least in Node/express terminology) is write your own middleware.
Express is designed with this in mind and it's pretty straightforward e.g.
ipLogger.js
module.exports = function(req, res, next) {
console.log(req.ip);
next();
}
app.js
var http = require("http")
, express = require("express");
, app = express()
, server = http.Server(app)
, ipLogger = require("./ipLogger.js");
app.use(ipLogger()); // log IP of all requests
// handle routes
server.listen(10022, function() {
console.log("server is up");
});
I'm having some trouble creating a RESTful API in Node/Express. In the app I'm building, a user has many messages, and messages belong to users. I need to be able to make an HTTP requests to retrieve all messages by a particular user. Here's the basic structure of the app, starting with the basic server, which delegates routing to a file called 'config/middleware.js'.
//server.js
var express = require('express');
var bodyParser = require('body-parser');
var app = express();
require('./config/middleware.js')(app, express);
var port = process.env.PORT || 8080;
app.use(bodyParser.json());
app.use(express.static(__dirname + '/../client'));
app.listen(port);
This is the middleware file where we send requests to the appropriate router. A request made to 'users/5/messages' would get routed to the messages router, and a request made to 'users/5' would get routed to the users router.
// config/middleware.js
module.exports = function(app, express) {
var usersRouter = express.Router();
var messagesRouter = express.Router();
app.use('/users/:userId/messages', messagesRouter);
app.use('/users', usersRouter);
require('../routers/users')(usersRouter);
require('../routers/messages')(messagesRouter);
};
This is the messages router. If a get request is made to '/users/5/messages', I want the getAllMessages function to be run, which should return all messages by the user with userId 5.
// routers/messages.js
var messagesController = require('../controllers/messages');
module.exports = function(app) {
app.get('/:messageId', messagesController.getMessage);
app.get('/', messagesController.getAllMessages);
};
The problem is that the getAllMessages function doesn't have access to the 'userId' parameter (with value of 5), which is required in order to make an appropriate query to the database. The getAllMessages function in the controller expects the userId to be stored on req.params.userId. Is there any way to get the userId of 5 to be present on the req.params object inside the getAllMessages function?
The req.params are not passed down the route chain. To do so, you could do something like
In server.js, create a key on req. This will pass on your data between routes. Do this before mounting the routes.
app.use(function (req, res, next) {
req._data = {};
next();
});
In config/middleware.js,
module.exports = function(app, express) {
var usersRouter = express.Router();
var messagesRouter = express.Router();
// attach usedId
app.use('/users/:userId/messages', function (req, res, next) {
req._data.userId = req.params.userId;
next();
});
// mount the router
app.use('/users/:userId/messages', messagesRouter);
app.use('/users', usersRouter);
require('../routers/users')(usersRouter);
require('../routers/messages')(messagesRouter);
};
This way, you would have access to req._data.userId in routers/messages.js.
Side note: A better way to structure the routes would be to use something like, (read shameless plug), https://github.com/swarajgiri/express-bootstrap/blob/master/web/routes.js
You can use app.locals or res.locals to pass some datas.
There is a good explanation about locals.
An usage sample:
app.locals.userid = req.params.userId; //binding userid
app.locals.userid // => '5'
OR: put a global variable.
user_id_tmp = req.params.userId;
Now this is become global variable in app. So you can call user_id_tmp variable from anywhere.
I was looking for same.
Here is modules app example on github and auther site
Also we can change or update structure base on our requirements
What's the best way to reject requests to my web server (running via Node express) that are coming in to an unrecognized hostname? I.e. I only want to respond to requests that are intended for my domain, not for requests that are just aimed at my IP address.
The easiest way would probably be to use the connect vhost middleware.
Where you would normally do this:
var app = express();
app.get('/', function(req, res){
res.send('HI');
});
app.listen(80);
You would do this:
var vhostApp = express();
vhostApp.get('/', function(req, res){
res.send('HI');
});
var app = express();
app.use(express.vhost('example.com', vhostApp));
app.listen(80);
I am building an app with express js which will have different clients like web and mobile. I didnt want to use one app for both as some middleware would be additional burden. For say like session middleware. So is it possible for one project to have two apps. And how would it work?
The app object that you make in express is a function(req,res,next) that is suitable for Express's own middleware chains. So you can use app.use to send requests matching a leading path fragment to an app defined elsewhere.
Docs: http://expressjs.com/api.html#app.use
$ npm install express
//mobile.js
var app = require('express')();
app.get('/', function(req, res){
res.send('Mobile Route')
});
module.exports = app;
//desktopApp.js
var http = require('http');
var express = require('express');
var desktopApp = express();
var mobileApp = require('./mobile.js');
desktopApp.use('/mobile', mobileApp)
desktopApp.use(desktopApp.router);
desktopApp.use(express.errorHandler());
desktopApp.get('/', function(req, res){
res.send('Desktop Route')
});
desktopApp.get('/mobile', function(req, res){
// Because Express respects the order that you set up the middleware chain,
// the mobileApp `/mobile` route gets first dibs to send a response or next()
res.send('Inaccessible Desktop Route')
});
desktopApp.get('/mobile/foobar', function(req, res){
// When mobileApp can't find any suitable route matching this path, it gives
// up, and desktopApp continues to pass the request down the middleware stack.
// It ends up matching this route, where we send a response
res.send('Desktop Route')
});
http.createServer(desktopApp).listen(3000, function(){
console.log('Listening on 3000');
});
// Results
$ curl localhost:3000/
Desktop Route
$ curl localhost:3000/mobile/
Mobile Route
See the vhost example on the express github repository.
You can have a "main" app, which routes the requests to one app or another. You should write a middleware to establish the conditions where one app or another are requested. express.vhost is a good example, but maybe you need other checks than the domain one.
main-app.js
(The file called to start the server.)
// load dependencies
var main = express();
main.use( express.vhost( 'mobile', require( './the-mobile-app' ) );
main.use( express.vhost( '*', require( './the-web-app' ) );
main.listen( /*...*/ )
the-mobile-app and the-web-app.js
var app = express();
//
// setup your application conf, middleware, and routes
//
module.exports = app;
I wanted to share a different approach that I used in a project recently:
function renderAppropriate(template1, template2){
return function(req, res){
if(req.session && req.session.mobileOn){
res.render(template1);
} else {
res.render(template2);
}
};
};
app.get('/', function(req, res, next){
// do some stuff
next()
}, renderAppropriate('someMobileTemplate', 'someDesktopTemplate')
);