I need some help, I've been figuring this for almost an hour and still can't find a way to fix this.
I have a search form to filter data from my CGridView, and I also need a button to view all the records after I finish using search, but I can't figure how to do it. Here's my code for jquery refresh button:
Yii::app()->clientScript->registerScript('initRefresh',<<<JS
$('#refresh-button').on('click',function() {
$('#app-asset-categories-grid').yiiGridView('update');
return false;
});
JS
,CClientScript::POS_READY);
Here's my code for jquery search form:
Yii::app()->clientScript->registerScript('search', "
$('.search-button').click(function(){
$('.search-form').toggle();
return false;
});
$('.search-form form').submit(function(){
$('#app-asset-categories-grid').yiiGridView('update', {
data: $(this).serialize()
});
return false;
});
");
And finally, my grid:
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
'id'=>'app-asset-categories-grid',
'columns' => array(
'category_id',
'label',
'description',
'add_date',
'modification_date',
array(
'name'=>'Status',
'filter'=>array('1'=>'Active', '0'=>'Inactive'),
'value'=>'($data->status=="1")?"Active":"Inactive"'
),
array(
'name'=>'Deletion Status',
'filter'=>array('1'=>'Deactivate','0'=>'Active'),
'value'=>'($data->deletion_status=="1")?"Deactivated":"Activated"'
),
array(
'class'=>'CButtonColumn',
),
),
));
I just wanted a refresh button to display all the data again after I use my search form. I need your help guys, thanks.
You need to handle update action in model and set pagination parameter false. An example how to do it:
Add hidden field in search form _search.php
<?php echo CHtml::hiddenField('show_all', 0, array("id"=>"show_all")); ?>
Then handle it in model's search() function (your grid uses it to get data)
like this:
$criteria=new CDbCriteria;
// some criterias
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
'pagination' => (isset($_GET["show_all"]) && $_GET["show_all"])?false:array(), // add this line
));
Then set update hidden field when you need it.
$('#refresh-button').on('click',function() {
$('#show_all').val(1); // set it to show all
$('#app-asset-categories-grid').yiiGridView('update');
$('#show_all').val(0); // set to 0 for searching with pagination
return false;
});
Thats it.
Related
I could see a lots of question on adding woocommerce product attribute. But doing so, I could see those added attributes in this screen
wp-admin/edit.php?post_type=product&page=product_attributes
My question is how can we add the attributes via PHP code to so that it appears in this above specified woocommerce attribute screen ? My intention is to make these attributes visible under 'Layered Navs' widget to filter out.
Following code will create the attribute programmatically which will be visible on the product_attributes page in the backend.
global $wpdb;
$insert = $wpdb->insert(
$wpdb->prefix . 'woocommerce_attribute_taxonomies',
array(
'attribute_label' => 'name',
'attribute_name' => 'slug',
'attribute_type' => 'type',
'attribute_orderby' => 'order_by',
'attribute_public' => 1
),
array( '%s', '%s', '%s', '%s', '%d' )
);
if ( is_wp_error( $insert ) ) {
throw new WC_API_Exception( 'woocommerce_api_cannot_create_product_attribute', $insert->get_error_message(), 400 );
}
// Clear transients
delete_transient( 'wc_attribute_taxonomies' );
Change name, slug etc with the relevant values.
I'm new to cakephp2 and I need some help here.
The problem is that I have a view that displays a list of items from the database and there is a pagination button below. Instead of moving to the 2nd page by using the pagination, I want to have a single button that will allow you to display(append)10 more data list. But I'm not sure how it is called and how to implement it. Sorry for my bad explanation.
I think, you can play with limit parameter.
Somethink like this:
// in controller
<?php
function items() {
$limit = array_key_exists('n', $this->request->query) ? (int) $this->request->query['n'] : 10;
// some security check you need to add
$this->paginate = array(
'limit' => $limit
);
$items = $this->paginate($this->YourModel);
// some other code
$this->set(array(
'items' => $items,
'next_limit' => $limit + 10
));
}
?>
<?php
// in view file
// items output
foreach($items as $item) ...
// more button
echo "<a href='".$this->here."?n=".$next_limit."'>More</a>";
?>
I have a module Search in my ZF2 application. The user fills in a search form out and gets a list of courses.
Now I'm adding the pagination to the module. The paginator is basically working: I can retrieve data over it and the pagination is displayed correctly (pagelinks 1-7 for 70 found courses with the dafault setting 10 items per page).
But it's still not usable. When I click on a pagelink, the form POST data is lost. I know -- it cannot work the way, how I implemented it (see the code below). But I have no idea, how to do it correctly, in order to eep checking the form data and nonetheless be able to use pagination.
That is my code:
Table class Search\Model\CourseTable
class CourseTable {
...
// without pagination
// public function findAllByCriteria(CourseSearchInput $input) {
// with pagination
public function findAllByCriteria(CourseSearchInput $input, $pageNumber) {
...
$select = new Select();
$where = new Where();
$having = new Having();
...
// without pagination
// $resultSet = $this->tableGateway->selectWith($select);
// return $resultSet;
// with pagination
$adapter = new \MyNamespqce\Paginator\Adapter\DbSelect($select, $this->tableGateway->getAdapter());
$paginator = new \Zend\Paginator\Paginator($adapter);
$paginator->setCurrentPageNumber($pageNumber);
return $paginator;
}
...
}
Search\Controller\SearchController
class SearchController extends AbstractActionController {
public function searchCoursesAction() {
$form = $this->getServiceLocator()->get('Search\Form\CourseSearchForm');
$request = $this->getRequest();
if ($request->isPost()) {
$courseSearchInput = new CourseSearchInput();
$form->setInputFilter($courseSearchInput->getInputFilter());
$form->setData($request->getPost());
if ($form->isValid()) {
$courseSearchInput->exchangeArray($form->getData());
// without pagination
// $courses = $this->getCourseTable()->findAllByCriteria($courseSearchInput);
// with pagination
$page = $this->params()->fromRoute('page');
$paginator = $this->getCourseTable()->findAllByCriteria($courseSearchInput, $page);
} else {
$paginator = null;
}
} else {
$paginator = null;
}
return new ViewModel(array(
'form' => $form,
// without pagination
// 'courses' => $courses,
// with pagination
'paginator' => $paginator,
'cities' => ...
));
}
...
}
How to get it working?
I also have the same problem, and I have solved it. But this is not good way. May be the idea will help you.
I solved it as follow: (Search pagination for Zend tutorial album module)
I build two action in controller named "search" and "index".
Whenever the search form submitted, it always post the value to search action. Search action build the url with search parameters, and redirect to index to disply search result.
And when the pagination links clicked, then posted values are passed through url. So whenever index action ask for search parameters, it always get the values in same format.
I defined route as follows:
'album' => array(
'type' => 'segment',
'options' => array(
'route' => '/album[/:action][/:id][/page/:page][/order_by/:order_by][/:order][/search_by/:search_by]',
'constraints' => array(
'action' => '(?!\bpage\b)(?!\border_by\b)(?!\bsearch_by\b)[a-zA-Z][a-zA-Z0-9_-]*',
'id' => '[0-9]+',
'page' => '[0-9]+',
'order_by' => '[a-zA-Z][a-zA-Z0-9_-]*',
'order' => 'ASC|DESC',
),
'defaults' => array(
'controller' => 'Album\Controller\Album',
'action' => 'index',
),
),
),
There is a parameter named "search_by", which will keep all search parameters as a json string. This is the point, which is not good I know, but have not find any other way yet.
"Search" action build this string as -
public function searchAction()
{
$request = $this->getRequest();
$url = 'index';
if ($request->isPost()) {
$formdata = (array) $request->getPost();
$search_data = array();
foreach ($formdata as $key => $value) {
if ($key != 'submit') {
if (!empty($value)) {
$search_data[$key] = $value;
}
}
}
if (!empty($search_data)) {
$search_by = json_encode($search_data);
$url .= '/search_by/' . $search_by;
}
}
$this->redirect()->toUrl($url);
}
And next index action decode the string, do necessary action, and also send the json string to view.
public function indexAction() {
$searchform = new AlbumSearchForm();
$searchform->get('submit')->setValue('Search');
$select = new Select();
$order_by = $this->params()->fromRoute('order_by') ?
$this->params()->fromRoute('order_by') : 'id';
$order = $this->params()->fromRoute('order') ?
$this->params()->fromRoute('order') : Select::ORDER_ASCENDING;
$page = $this->params()->fromRoute('page') ? (int) $this->params()->fromRoute('page') : 1;
$select->order($order_by . ' ' . $order);
$search_by = $this->params()->fromRoute('search_by') ?
$this->params()->fromRoute('search_by') : '';
$where = new \Zend\Db\Sql\Where();
$formdata = array();
if (!empty($search_by)) {
$formdata = (array) json_decode($search_by);
if (!empty($formdata['artist'])) {
$where->addPredicate(
new \Zend\Db\Sql\Predicate\Like('artist', '%' . $formdata['artist'] . '%')
);
}
if (!empty($formdata['title'])) {
$where->addPredicate(
new \Zend\Db\Sql\Predicate\Like('title', '%' . $formdata['title'] . '%')
);
}
}
if (!empty($where)) {
$select->where($where);
}
$album = $this->getAlbumTable()->fetchAll($select);
$totalRecord = $album->count();
$itemsPerPage = 2;
$album->current();
$paginator = new Paginator(new paginatorIterator($album));
$paginator->setCurrentPageNumber($page)
->setItemCountPerPage($itemsPerPage)
->setPageRange(7);
$searchform->setData($formdata);
return new ViewModel(array(
'search_by' => $search_by,
'order_by' => $order_by,
'order' => $order,
'page' => $page,
'paginator' => $paginator,
'pageAction' => 'album',
'form' => $searchform,
'totalRecord' => $totalRecord
));
}
All the sorting and paging url contain that string.
If you know all the searching paarameters before, then you can define that at route, and pass like the same way without json string. As I have to build a common search, I have build a single string.
Source code for "Album search" is available in git hub at https://github.com/tahmina8765/zf2_search_with_pagination_example.
Live Demo: http://zf2pagination.lifencolor.com/public/album
#Sam & #automatix in the question comments are both right. My suggestion (though I'm looking for a simpler alternative) is to construct a segment route, which covers all of the options that you're likely to need and start with a standard form POST request.
Then, after the request is validated, pass the form data to the paginationControl helper as follows:
$resultsView = new ViewModel(array(
'paginator' => $paginator,
'routeParams' => array_filter($form->getData())
));
Then, in your view template, set the route parameters in the paginationControl view helper:
<?php echo $this->paginationControl($paginator, 'Sliding', 'paginator/default',
array('routeParams' => $routeParams)
) ?>
I've used array_filter here because it's a really simple way of removing any element from the form data that's null, empty or so on. That way you don't pass in extra data that you don't need.
I am using Paul Irish's infinitescroll with masonry js on a wordpress site. It is a site with a lot of content. I want infintescroll to stop adding new content when it reaches post number 40 and to give the "No additional items" message at that point. I tried to customize the wordpress loop to only return 40 posts but that did not seem to work.
I thought that maybe one of the options in infinitecroll might do the trick but the infintescroll documentation is very sparse. For example, there is an infinitescroll option in the "loading" init section called "finished: undefined" Is it possible to change that parameter to stop the scrolling after a certain number of content items?
Is there some other obvious way to control when infinitescroll stops loading new content?
Any assistance would be greatly appreciated.
In the Administration -> Settings -> Reading you can set Blog pages show at most to 40.
With code:
Two ways I've done Masonry by numbers like your question I've had success with the following:
limit posts_per_page in your query arguments
$args = array(
'posts_per_page' => 40,
'offset' => 5,
'orderby' => 'post_date',
'order' => 'DESC',
'exclude' => 'none',
'post_type' => 'post',
'post_status' => 'publish',
'suppress_filters' => true
);
$posts = new WP_Query( $args );
if ( $posts -> have_posts()) {
while ( $posts -> have_posts() ) : $posts->the_post(); {
//do stuff with the posts returned here
}
}
or by incrementing:
$counts = 0 ;
$posts = new WP_Query( $args );
if ( $posts -> have_posts()) {
while ( $posts -> have_posts() ) : $posts->the_post(); {
//do stuff with the posts returned here
$counts = ++;
if($counts == 40) { return }
}
}
I have a simple module which will return a form , but now i have added this to a menu like
admin/settings/
But i want this form in another page ,so i added a hook_block() , my module showed up in the blocks page and i added it to be seen by all in all pages in content area but i dont get that form ? where did i go wrong ? I am new to drupal any help plz
function emp_form_block($op = 'list', $delta = 0, $edit = array()) {
switch ($op) {
case 'list':
$blocks[0]['info'] = t('New Block');
$blocks[0]['cache'] = BLOCK_NO_CACHE;
return $blocks;
}
}
i am using drupal 6
You should also implement the view op, like this:
case 'view':
return array(
'subject' => t('My awesome form'),
'content' => drupal_get_form('my_awesome_form'),
);
break;