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suppose we have following data
23
30
27.5
18
4
11
9
10
16
24
56
90
65
17
19
44
72
and i want to count number of elements in range [10-60] ? sure we can use if for determining if our value is in interval,but is there any function in excel like countrange or something like this which takes input as a vector and also range and returns number of element which fits in that range?thanks very much
This should also work:
=COUNTIF(A1:A17;">=10")-COUNTIF(A1:A17;">60")
A1:A17 is the range of course.
I think you can do this using COUNTIFS function
=COUNTIFS($A$2:$A$9, ">=10",$A$2:$A$9,"<=60")
COUNTIFS
Check out COUNTIF
COUNTIF function counts the number of cells within a range that meet a single criterion (condition) that you specify.
=COUNTIF(range, criteria)
Also there is COUNTIFS
http://office.microsoft.com/en-us/excel-help/count-numbers-greater-than-or-less-than-a-number-HP003056117.aspx
I don't think there is a build in function to do that. You'd need to write one on your own at takes a range of fields, iterates of all elements and increments a predefined return value if a field meets your requirements.
You can read how that's done here: Creating custom functions
Considering the latter part of your question (ie for a number of ranges rather just than a single one) yes, there is an Excel function for this, =FREQUENCY.
The answer for [10-60] is 11, as shown below, but with the upper limits for the bins in ColumnC, one array formula will populate all counts for the ranges selected:
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I am trying to convert text using only Excel data manipulation functions (not Data/Text to Columns).
Column A looks like this:
A1: 10 11 03,-690000,100.163685
A2: 14 11 03,-761000,100.3977
A3: 17 11 03,-682000,100.575887
and so on.
I'd like to get the date (01 11 03 recognised as a date) in column B, the middle data (between the two commas) in column C and the data on the right (after the second comma) in column D using the full accuracy displayed.
Seems you have options that would be easier, but please try in B1:
=DATEVALUE(LEFT(A1,2)&"/"&MID(A1,4,2)&"/"&MID(A1,7,2))
in C1:
=1*MID(A1,FIND(",",A1)+1,FIND(",",MID(A1,FIND(",",A1)+1,99))-1)
in D1:
=1*MID(A1,FIND(",",A1,FIND(",",A1)+1)+1,99)
and copy down to suit.
I believe the easiest way for you to handle this situation is to simply save your current worksheet as a text file, and then reopen it in Excel. When you open the file again in Excel it should automatically separate out the three columns the way you want it. Here is a screen capture from my Excel after I have done this:
Next you can format the A column as a date however you wish.
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Suppose, that I have a vector of cells A1:A5, each with string that is an address of the other cell.
What I want to do, is to have a function, that returns an array of values from these referenced cells. See the example - I want the formula to return 15 (it returns 1).
In production setting, this vector is much longer (ca. 2000 rows).
What would solve the problem, is array-capable INDIRECT().
(I realize, that I might be pushing Excel beyond its the limits)...
My further thoughts on this topic:
Because the INDIRECT() is capable of producing arrays even from a single-cell input, such theoretical "INDIRECTARR()" formula would either require nested (i.e. multidimensional) array computation support in Excel, or will be intrinsically limited to arguments that denote one-dimensional ranges.
Finally I've found a way to solve it. As long as the values are on one sheet, we can take advantage of the fact, that when the second and/or the third argument to INDEX is an array, the result is an array as well:
It is a bit hackish, but it certainly works and doesn't need any VBA nor addons. And it is fast.
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I have an excel sheet with columns A and B populated with numbers, a la:
1 12
13 20
21 30
31 35
This is just as an example, in reality A and B are columns of length 50ish.
In this example, I have another column with values in it between 1 and 30. I want to write a function that returns which range it is between. Perhaps a 1 if it is between the first range (1-12) 2 between the second (13-20) etc.
This is the way the data was presented to me, if it needs to be re-arranged so be it.
Does anyone know any functions that would be useful to solve this problem? I have read that nested if statements are limited to 7 "if's" so I would need to write out a bunch of them.
Thanks folks.
As #Tim has said, =MATCH looks most suitable, without its optional third parameter, so that it “finds the largest value that is less than or equal to lookup_value.” Hence the upper bounds (right-hand column in your question) are not required for this formula. The numbers returned are the relative positions of the ‘match’ in the selected array. If your “another column with values in it between 1 and 30” is say C and starts in Row2 then =MATCH(C2,A:A) copied down is a generalisation that will only return 1, 2, 3 if the population of A:B starts in Row1. In other words, if the 1 in A is say in Row3 then I’d recommend:
=MATCH(C2,A$3:A$6)
copied down to suit.
The last number in A (ie 31) can be anything as long as it is more than the upper bound of your “between 1 and 30”.
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I have a spreadsheet with excel with a column with over 1000 values that looks as follows:
15hrs
12hrs
34hrs
etc..
Can someone please give me a method on how to sum over these values as I have no clue on how to do this..
Change the A1:A3 to be the actual range:
=SUMPRODUCT(--SUBSTITUTE(A1:A3,"hrs",""))
Take a copy, replace hrs with nothing, then sum the result.
You cannot sum over the text values, but you can get what you're looking to do in a different way (if this'll work for you):
Select the column and go Replace all "Hrs" with blanks "" - In effect, making your text numbers
With the column values still highlighted, go to Format Cells and choose the "Custom" format... Change the format to General"Hrs"
Now you can add the values since they are stored as values, but LOOK like text.
I don't know if this'll work for you, but it should accomplish the task at hand if it does...
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I would like to search a row for a string and get the column number if there is such a string.
Is this possible by using worksheet functions in Excel?
You can use MATCH to give the position, e.g. you can search in row 2 for "xyz" like this
=MATCH("xyz",2:2,0)
If "xyz" is found first in J2 you get 10
if you want partial matches then you can use wildcards like
=MATCH("*xyz*",2:2,0)
so if F2 contains [abc xyz 344] you get a match with that and formula returns 6
I believe VLOOKUP is the best for you.
There's also others like HLOOKUP, LOOKUP and SEARCH
If the lookup value is "value" and it is in row 1
=MATCH("value",1:1,0)
Assuming you have something like this:
A1 A2 A3 A4
111 aaa sss bbb,
you could write something of this sort:
=FIND("$", CELL("address",OFFSET($A$2, 0,MATCH(111,A2:D2,1)-COLUMN($A$2)+1)), 2)
Ugly, but works (assuming that's what you were looking for)...