How can i deal a hand in python - python-3.x

Question

im trying to deal a hand in python with random.shuffle and its keeps giving me an error, can some one help me figure out whats wrong with it.
# [import statements]
import q1fun
# [constants]
# [rest of program code]
number = input("howmany cards to you want dealt?")
a = q1fun.deal(number)
print (a)
# [import statements]
import random
# [constants]
def deal(x):
y = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
a = random.shuffle(y(x))
return(a)
howmany cards to you want dealt?5
Traceback (most recent call last):
File "C:\Users\Eddie\workspace\cp104\durb8250_a16\src\q1.py", line 18, in
a = q1fun.deal(number)
File "C:\Users\Eddie\workspace\cp104\durb8250_a16\src\q1fun.py", line 29, in deal
a = random.shuffle(y(x))
TypeError: 'list' object is not callable

Answer 1

random.shuffle(y) shuffles the list y inplace and returns None.
So
def deal(n):
"Return a hand of n cards"
y = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7, 8, 9,
10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6,
7, 8, 9, 10, 11, 12, 13]
random.shuffle(y)
return y[:n]
might be closer to what you want.
Or omit random.shuffle(y) and just use random.sample:
return random.sample(y, n)

Answer 2

You're trying to reference an element of a list with function call parentheses. You want to use square brackets.
function(x) <-- calls the function with parameter x
list[x] <-- gets the x-th element of the list
Also, your input is going to be returning a string. You'll need to convert it to an integer before using it to reference an index. I.e. random.shuffle(y[int(x)])
And finally, your shuffle call won't work. You want to shuffle first (which shuffles the list in place), then get the element
random.shuffle(y)
a = y[int(x)]