How to count number of matches between two columns in Excel?
For example if we have:
1 1
2 1
3 2
4 4
5 3
I need to get either a column like this:
1
0
0
1
0
and then I can sum the ones in there to get the count of matches.
Option 1: IF
=IF(A1=B1;1;0)
This formula will put 1 in the cell if A1 = B1, and 0 otherwise.
Option 2: COUNTIF
Write =A1=B1 in C1, etc., in the column cells. This will fill the C column with TRUE and FALSE values.
At the bottom of that column, add a cell =COUNTIF(C1:C100;TRUE) so that you count the cells between C1 and C100 which have value TRUE.
You may find the TechRepublic article Use COUNTIFS() to compare two data sets in Excel of use. See also Microsoft's documentation on countifs().
Related
Below table describes what I expect for.
The "Count Blank" Column is a counter for counting continuous blank cells in order from Column A to Column C. If any of the following cell has value then stop counting and return current value. (plz see row6 and row7)
Basically, I'm looking for a formula which could return the current counter value if the condition fails.
Count Blank
Column A
Column B
Column C
0
1
2
3
1
2
3
2
3
3
1
2
0
1
These two formulas are just for counting the blank cells in the range:
=COUNTIF(B8:D8,"")
=SUM((IF((B8:D8)="",1,0)))
Hoping anyone can help with the continuous problem.
Count Blank
Column A
Column B
Column C
0
1
2
3
1
2
3
2(should be 1)
2
2(should be 0)
1
I found this: https://exceljet.net/formulas/get-first-non-blank-value-in-a-list
You don't really want to count anything, you just need to find the first non blank cell. You can try this formula:
=IFERROR(MATCH(FALSE;ISBLANK(B2:D2);0)-1;COLUMNS(B2:D2))
This is an array formula, so press ctrl+shift+enter when entering it into a cell.
You can use the new (as of 2020) reduce and lambda functions:
=VALUE(REDUCE(0, B1:D1, LAMBDA(prev, curr, IF(ISTEXT(prev), prev, IF(curr = "", prev + 1, TEXT(prev,"0"))))))
The Excel File is like this
A B
1 0
0 1
1 1
0 1
0 0
1 0
I want to use Countifs function to count how many rows have at least one "1" in any columns, like
=Countifs(A:A+B:B,">=1")
or
=Countifs(or(A:A=1,B:B=1))
I know I can add a Column C, let Column C = Column A + B, and then just count Column C; or I can count the total rows and count rows with "0" in both columns, and then calculate Total Row - Both "0". But in real Scenario, I have more complicated situation, so I prefer not using these two solutions.
Use a SUMPRODUCT function to provide cyclic calculation.
=SUMPRODUCT(--((A1:A6)+(B1:B6)>=1))
SUMPRODUCT does not like trying to calculate text values and full column references slow it down so keep your ranges to a minimum. Using the INDEX function can help isolate a dynamic range of true numbers.
Another solution using array formula:
=SUM(IF(A1:A6=1,1,IF(B1:B6=1,1,0)))
Being an array formula, you'll have to enter this formula by pressing Ctrl+Shift+Enter together.
Use =COUNT(A:A)-COUNTIFS(A:A,0,B:B,0) to count both 0 columns and subtract it from the total rows:
Or you can use:
=COUNTIFS(A:A,1,B:B,1)+COUNTIFS(A:A,0,B:B,1)+COUNTIFS(A:A,1,B:B,0)
if it is not clear what it the total number of rows.
Working a step higher then COUNTIFS, I appose a challenge to write a formula without VBA code. The basic data is combined from 1000s of rows with:
Column A: rows with values from 1 to 3
Column B: rows with values from 1 to 250.
For this purpose lets say, we are looking at all cells of value "1" in column A, that suit value "5" in column B. To find all matches, we'd use COUNTIFS command.
1 1
2 5
1 5
1 7
1 10
3 45
2 12
1 2
2 1
=COUNTIFS(A1:A9;1;B1:B9;5)
The answer here is 1.
Next thing, the "5" in column B belongs to a group, e.g. group from 1 to 9. What would the best way be, to count all the matches in this example, so that for all "1"'s in column A, we'd have to find all matches with values from 1 to 9 in column B?! In the upper example that would result in "4". The obvious solution is with a series of IF commands, but that's unefficient and it easy to make a mistake, that get's easily overseen.
=COUNTIFS(A1:A9;1;B1:B9;"<="&9)
Works only as the upper limit. If I give the third criteria range and condition as ">="&1 it does not work - returns 0.
Gasper
Where the data is in A1:B9, using a lookup table in D1:E10 with letters A-J in column D and numbers 0 to 9 in column E and the following formula in B11 referencing letters entered in A11 and A12:
=COUNTIFS(A1:A9,1,B1:B9,">="&VLOOKUP(A11,$D$1:$E$10,2,FALSE),B1:B9,"<="&VLOOKUP(A12,$D$1:$E$10,2,FALSE))
works, changing the letters in A11 and A12 gives the correct count according to what they correspond to in the looku in D1:E10.
When you say give third criteria range do you mean:
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
If so then try:
=COUNTIFS(A1:A9;1;B1:B9;AND("<="&9,;">=1"))
ie have two conditional ranges with the second range having both conditions combined with AND()
Maybe what you want(ed) is:
=COUNTIFS(A:A;1;B:B;">=1";B:B;"<=9")
Almost there. I noticed that three criteria ranges and conditions work only if I use "=" sign in a condition. As soon as I use
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
it returns 0. My goal is to eventualy replace the number in a condition with a VLOOKUP command, so the final equation should be smth like
=COUNTIFS(A1:A9;1;B1:B9;"<="&VLOOKUP(...),B1:B9;">=VLOOKUP(...)")
But the "<" and ">" signs mess with this. Still looking for a solution.
This is my entire line, if it offers any further indication. The AND() commands is at the end - and it still results in 0
=COUNTIFS(INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));IF(C6="računska";1;0);INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));AND("<="&VLOOKUP($C$5;$K$203:$N$223;4;FALSE);">="&VLOOKUP($C$5;$K$203:$N$223;3;FALSE)))
I have a list like this:
1
2
3
4
5
I am pulling those numbers into another spreadsheet, using vlookup.
I want to create a new list or pattern, that looks like this:
1
1
1
1
1
2
2
2
2
2
3
3
3
3
3
.. etc
How can I do that easily (my first list has 300 items, so dont want to do by hand)
Thanks!
Following the Scheme:
use the formulas:
C2 -> =A2
C3 -> =INDEX(A:A;ROUNDDOWN((ROW(G1)/$B$2)+2;0)) ' And Autocomplete
D2 -> =IF((ROUNDUP(ROW(G1)/($B$2+$B$4);0))-(ROUNDDOWN((ROW(G1)/($B$2+$B$4))+($B$4)/$B$2-$B$4/10;0))=1;INDEX(A:A;ROUNDDOWN((ROW(G1)/($B$2+$B$4))+2;0));"") ' And Autocomplete
The C column it's relevant to repeat without blanks, the column D it's relevant to the repeat with blanks.
In the cells B2 put the number of repetition and in the cell B4 put the blanks cells.
If you have more that one column to copy use the same code for every column...
If you need to have only values, at the end copy and paste with value ...
Warning: The formula in column D work with low number of blanks and Repeat... Eventually you need to recalibrate.
I have a Spreadsheet, and inside this sheet contains a column with numbers, I want to make a formula that will go down that Column and do basically this.. Values: 1 will be 9.50. 2 will be 9.75. 3 will be 10.00. Ect going up to Value of 100? Is that possible for a Formula? I keep playing with it but can't really seem to get it down. Any help would be appreciated.
Column A: 1
1
1
1
1
2
2
2
2
2
2
2
2
2
3
3
3
3
There is not a set amount to how many values are in there.
this should do it supposing that column A has these values 1, 2 ...etc that your computing will be based on
=MIN(9.25+A1*0.25;100)*COUNT(A1)
In A2, enter the formula
=A1 + (9.5-A1)
then in the cell just below it (A3), enter
=A2+0.25
Assuming A1 is the top left. Copy the formula in A3, select the next 399 cells and paste. Then select A2 - A364 and copy. Then select B2 -xx364 and paste. xx is the last column with data. If you want, set the height of your first column to 0 to hide it.
=(A1-1)*0.25+9.5 where A1 contains any number you want