Get the strings before the comma with R - string

Question

I am a beginner with R. Now, I have a vector in a data.frame like this
city
Kirkland,
Bethesda,
Wellington,
La Jolla,
Berkeley,
Costa, Evie KW172NJ
Miami,
Plano,
Sacramento,
Middletown,
Webster,
Houston,
Denver,
Kirkland,
Pinecrest,
Tarzana,
Boulder,
Westfield,
Fair Haven,
Royal Palm Beach, Fl
Westport,
Encino,
Oak Ridge,
I want to clean it. What I want is all the city names before the comma. How can I get the result in R? Thanks!

Answer 1

You can use gsub with a bit of regexp :
cities <- gsub("^(.*?),.*", "\\1", df$city)
This one works, too :
cities <- gsub(",.*$", "", df$city)

Answer 2

Just for fun, you can use strsplit
> x <- c("London, UK", "Paris, France", "New York, USA")
> sapply(strsplit(x, ","), "[", 1)
[1] "London" "Paris" "New York"

Answer 3

You could use regexpr to find the position of the first comma in each element and use substr to snip them at this:
x <- c("London, UK", "Paris, France", "New York, USA")
substr(x,1,regexpr(",",x)-1)
[1] "London" "Paris" "New York"

Answer 4

This works as well:
x <- c("London, UK", "Paris, France", "New York, USA")
library(qdap)
beg2char(x, ",")
## > beg2char(x, ",")
## [1] "London" "Paris" "New York"

Answer 5

If the this was a column in a dataframe, we can use tidyverse.
library(dplyr)
x <- c("London, UK", "Paris, France", "New York, USA")
x <- as.data.frame(x)
x %>% separate(x, c("A","B"), sep = ',')
A B
1 London UK
2 Paris France
3 New York USA